efi and effc of fin

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EFI AND EFFC OF FIN:EFFI OF FIN= actual heattransfr by fin ( Q FIN ) max het that wouldbe tran if whole sur of the fin is maintedat the base temp ( Q max ) ; for a fin which is infinetly long=¿¿¿= kA CS hP l 2 = 1 ml for a fin which is insulated at the tip= Phk A CS ( t o t a ) tanh ( ml ) hPl ( t o t a ) = tanh ( ml) ml ,where ml= hP kA CS .l= h ( 2 b +2 y) kb y .l; ml= 2 hb k by .l= 2 h ky .l= 2 h kyl . l 3/ 2 = 2 h kA P . l 3/ 2 were y.l= A P profile area of fin.thus fin effi is a fin of ml or 2 h kA P . l 3/2 ; l c =l+ y 2 ;eff fin =tanh ¿¿ ;Q= Phk A CS ( t o t a ) tanh ¿ het flow becomes Q=effi fin. hpl C ( t o t a ) ; EFFECTIVENESS OF FIN: Q with fin Q without fin = Phk A CS ( t o t a ) hA CS ( t o t a ) = PK hA CS ; P A CS = 2( b +y) b.y = 2 y ;effictiv fin = 2 k hy rel btw effective and effi efificy fin= Phk A CS ( t o t a ) tanh ( ml ) hPl ( t o t a ) ;;effect fin =¿¿¿; εefcti effi = pl A CS ;effective=eff. PL A CS =EFF FIN. SUR AREA OF THE FIN CROSS SECTION AREA OFTHE FIN appli:1 economiser for steam power plant,2.convectors for steam and hot water v heating systems 3.radiators of automobiles4.air cooled engine cylinder heds 5.cooli8ng cooils and condensor coils in refrigerators and ac.6.small capacity compressors 7.electric motor

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Page 1: EFI AND EFFC OF FIN

EFI AND EFFC OF FIN:EFFI OF FIN=actual heat transfr by fin(QFIN)

max het that would be tran if whole sur of the finis mainted at the base temp(Qmax)

;

for a fin which is infinetly long=√¿¿¿=√ k ACS

hPl2=1

ml

for a fin which is insulated at the tip=√Phk ACS (t o−ta ) tanh (ml )

h Pl ( to−t a )=tanh (ml)

ml ,where ml=√ hP

k ACS

.l=

√ h(2b+2 y)k b y

.l;

ml=√ 2hbk by

.l=√ 2hky

.l=√ 2hkyl

.l3 /2=√ 2hk AP

.l3 /2 were y.l= AP profile area of fin.thus fin effi is a fin of ml or

√ 2hk AP

.l3 /2 ;lc=l+y2

;eff fin =tanh ¿¿ ;Q=√ Phk ACS (t o−t a ) tanh ¿

het flow becomes Q=effi fin.√h p lC (t o−t a ); EFFECTIVENESS OF FIN: Q with fin

Q without fin=√Phk ACS (t o−ta )

h ACS (t o−t a )=

√ PKh ACS

; P

ACS=2(b+ y )

b . y=2y

;effictiv fin =√ 2kh y

rel btw effective and effi

efificy fin=√Phk ACS (t o−ta ) tanh (ml )

hPl (t o− ta ) ;;effect fin =√¿¿¿;

ε efctieffi

=pl

ACS;effective=eff.

PLACS

=EFF FIN.SUR AREAOF THE FIN

CROSS SECTION AREA OFTHE FIN

appli:1 economiser for steam power plant,2.convectors for steam and hot water v heating systems 3.radiators of automobiles4.air cooled engine cylinder heds 5.cooli8ng cooils and condensor coils in refrigerators and ac.6.small capacity compressors 7.electric motor bodies 8.trans formers and electronic equipments. ASSUMPTION RECTANGULAR:1.stedy state heat conduction 2. No heat gen within the fin 3.uni het transfer co effi(h) over the entire sur of fin 4.homogenous and isotro[pic fin materials 5.negli contact thermal resi 6.het cond 1D 7.neglibile radiation