efi and effc of fin
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EFI AND EFFC OF FIN:EFFI OF FIN=actual heat transfr by fin(QFIN)
max het that would be tran if whole sur of the finis mainted at the base temp(Qmax)
;
for a fin which is infinetly long=√¿¿¿=√ k ACS
hPl2=1
ml
for a fin which is insulated at the tip=√Phk ACS (t o−ta ) tanh (ml )
h Pl ( to−t a )=tanh (ml)
ml ,where ml=√ hP
k ACS
.l=
√ h(2b+2 y)k b y
.l;
ml=√ 2hbk by
.l=√ 2hky
.l=√ 2hkyl
.l3 /2=√ 2hk AP
.l3 /2 were y.l= AP profile area of fin.thus fin effi is a fin of ml or
√ 2hk AP
.l3 /2 ;lc=l+y2
;eff fin =tanh ¿¿ ;Q=√ Phk ACS (t o−t a ) tanh ¿
het flow becomes Q=effi fin.√h p lC (t o−t a ); EFFECTIVENESS OF FIN: Q with fin
Q without fin=√Phk ACS (t o−ta )
h ACS (t o−t a )=
√ PKh ACS
; P
ACS=2(b+ y )
b . y=2y
;effictiv fin =√ 2kh y
rel btw effective and effi
efificy fin=√Phk ACS (t o−ta ) tanh (ml )
hPl (t o− ta ) ;;effect fin =√¿¿¿;
ε efctieffi
=pl
ACS;effective=eff.
PLACS
=EFF FIN.SUR AREAOF THE FIN
CROSS SECTION AREA OFTHE FIN
appli:1 economiser for steam power plant,2.convectors for steam and hot water v heating systems 3.radiators of automobiles4.air cooled engine cylinder heds 5.cooli8ng cooils and condensor coils in refrigerators and ac.6.small capacity compressors 7.electric motor bodies 8.trans formers and electronic equipments. ASSUMPTION RECTANGULAR:1.stedy state heat conduction 2. No heat gen within the fin 3.uni het transfer co effi(h) over the entire sur of fin 4.homogenous and isotro[pic fin materials 5.negli contact thermal resi 6.het cond 1D 7.neglibile radiation