c lab programs 1

7/27/2019 C Lab Programs 1

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LAB 1

ALGORITHMS AND FLOWCHARTS

A typical programming task can be divided into two phases:

Problem solving phaseo produce an ordered sequence of steps that describe solution of

problemo this sequence of steps is called an algorithm

Implementation phase

o implement the program in some programming language

Pseudocodeis an artificial and informal language that helps programmersdevelop algorithms. Pseudocode is very similar to everyday English.

Write an Pseudocode & A!orit"# to deter#ine a student$s %ina !rade and

indicate "et"er it is 'assin! or %aiin!( T"e %ina !rade is cacuated as t"ea)era!e o% %our #ar*s(

Pseudocode+

Input a set of 4 marks

Calculate their average by summing and dividing by 4

if average is below 50Print FI!"

else Print P##"

Detaied A!orit"#

Step 1: nput !1"!#"!$"!%

Step #: &'A(E )!1*!#*!$*!%+,%

Step $: if )&'A(E - /+ then Print 0A23 else Print 0PASS3 endif


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E4ample

PRINT

,PASS-

Step 1: nput !1"!#"!$"!%

Step #: &'A(E )!1*!#*!$*!%+,%Step $: if )&'A(E -./+ then

Print 0A23

else

Print 0PASS3

endif

START

In'ut

M1.M/.M0.M

GRAD2 3M14M/4M04M56

IS

GRAD2789

PRINT

,FAIL-

STOP

:N

Dra a %oc"art to %ind t"e su# o% %irst 89 natura nu#;ers(


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Dra a %oc"art to %ind t"e ar!est o% t"ree nu#;ers A.B. and C(

3Correct t"e ;eo one5


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Write an a!orit"# and dra a %oc"art to con)ert t"e en!t" in %eet to centi#eter

Pseudocode+

Input the length in feet (Lft) Calculate the length in cm (Lcm) by multiplying LFT with 30 Print length in cm (LCM)


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A!orit"#

Step 1: nput 2ft

Step #: 2cm 2ft 4 $/

Step $: Print 2cm

START

In'ut

L%t

Lc# L%t < 09

Print

Lc#

STOP

Fo&c"art

Write an a!orit"# and dra a %oc"art t"at i read t"e to sides o% a rectan!eand cacuate its area(

Pseudocode

Input the width (W) and Length (L) f a rectangle

Calculate the area (!) by multiplying L with W

Print !A!orit"#

Ste' 1+ In'ut W.L

Ste' /+ A L < W Ste' 0+ Print A

FLOW CHART


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Write an a!orit"# and dra a %oc"art t"at i cacuate t"e roots o% a=uadratic e=uation

Hint+ d > s=rt 3 5. and t"e roots are+ "1 > 3?b4 d56/a and"/ > 3?b? d56/a

Pseudocode+#$ Input the cefficient% (a& b& c) f the 'uadratic e'uatin/( Calculate d0( Calculate "1( Calculate


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Dra a %oc"art %or co#'utin! %actoria N 3N@5

5here 67 8 1 9 # 9 $ 9 6 .

START

In'uta. ;. c

d s=rt3b " b? < a


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Assi!n#ent +

A!orit"# and %oc"art to %ind t"e roots o% =uadratic e=uationa


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IF?TH2N?2LS2 STRCTR2 ;he algorithm for the flowchart is as

follows:

If !)* then

print !

el%e

print *

endif

isAB

Print BPrint A

: N

Write an a!orit"# t"at reads to )aues. deter#ines t"e ar!est )aue and 'rints t"ear!est )aue it" an identi%in! #essa!e(

ALGORITHM

Ste' 1+ InputAL21. AL2/Ste' /+ if (AL21 AL2/5 then

MAE AL21el%eMAE AL2/endif

Ste' 0+ Print +The large%t ,alue i%-& M!


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Write an a!orit"# t"at reads t"ree nu#;ers and 'rints t"e )aue o% t"ear!est nu#;er(

ALGORITHM

Ste' 1+ Input N1. N/. N0Ste' /+ if (N1N/5 then

if (N1N05 thenMAE N1 N1N/. N1N0

el%eMAE N0 N0N1N/

endifel%e

if (N/N05 then

MAE AL21

Print+The large%t ,alue i%-&

M!

STOP

: N

START

In'utAL21.AL2/

MAE AL2/

isAL21AL2/


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MAE N/ N/N1. N/N0 el%eMAE N0 N0N/N1

endifendif

Ste' 0+ Print +The large%t number i%-& M!

IF?TH2N?2LS2 STRCTR2

;he algorithm for the flowchart is asfollows:

If !)* then

print !

el%e

print *

endif

is

AB

Print BPrint A

: N

Dra %o c"art to t"e a;o)e e


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9 "ours09 ;ut 9 "ours

/9 ;ut 09 "ours

19 ;ut /9 "ours

19 "ours

89909/919

Ste' 1+ InputNAM2.O2RTIM2.ABS2NTSte' /+ if 3O2RTIM2?3/605ABS2NT 95 then

PA:M2NT 89 el%e if (O2RTIM2?3/605ABS2NT 095 then

PA:M2NT 9el%e if (O2RTIM2?3/605ABS2NT /95 then

PA:M2NT 09el%e if (O2RTIM2?3/605ABS2NT 195 thenPA:M2NT /9el%e

PA:M2NT 19endif

Ste' 0+ Print ,Bonus %or-. NAM2 ,is -. PA:M2NT

Dra %o c"art to t"e a;o)e e


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int #ain3)oid5 'rint%3QQHeo ord@n$$5return />>>>>>>>>>>>>>>>>>>>>>>>>$include %stdio&h'

main()

* int sum6 value/

sum 1 30/value 1 35/

printf(+d-td-n+6 sum6 value)/


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Pro!ra# out'ut oo*s i*e1/ 1

JJJJJJJJJJJJJJJJJJJJJJJJJJJJJ

$include %stdio&h'

main()*

int value36 value76 sum/

value3 1 85/value7 1 39/sum 1 value3 2 value7/

printf(+he sum of d and d is d-n+6 value36 value76 sum)/

JJJJJJJJJJJJJJJJJJJJJJJJJ

$include %stdio&h'

main()*

int count/char letter/

printf(+Count 1 d-n+6 count)/printf(+!etter 1 c-n+6 letter)/

Sa#'e 'ro!ra# out'ut=ount 8 #>%?%2etter 8 f

t can be seen from the sample output that the values which each of the variablestake on at declaration time are noJero. n =" this is common" and programmersmust ensure that variables are assigned values before using them.

f the program was run again" the output could well have different values for eachof the variables. 5e can never assume that variables declare in the mannerabove will take on a specific value.

JJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJ


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include %stdio&h'

$define :;/

balance 1 ?7&30/ta> 1 balance @ :; on &7f is &7f-n+6 balance6 ta> )/

JJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJ

6 Printin! Lar!e Boc* Letters6

Kincude 7stdio("

66)oid ;oc*!3)oid5 6Protot'e %or ;oc*! %unction 6

int #ain 3)oid5 'rint%3n5 ;oc*!35 'rint%3n5

6 Print out t"e Boc* etter ! 6)oid ;oc*!3)oid5 'rint%3!!!!!!n5 'rint%3! !n5 'rint%3!n5 'rint%3! !!!n5 'rint%3! !n5 'rint%3!!!!!!n5

6 It 'rints out+

!!!!!!! !!! !!!! !
http://www.cis.temple.edu/~ingargio/cis71/code/homework1.chttp://www.cis.temple.edu/~ingargio/cis71/code/homework1.c


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!!!!!!

6

JJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJ

Write a 'ro!ra# to 'rint su# and a)era!e o% t"ree nu#;ers@

@include -stdio.h

int main)+ ,, no need to have int if no returnBfloat a"b"c"sum"avgCprintf)DPlease enter $ numbers and press enterD+Cscanf)DfffD"Fa"Fb"Fc+sum 8 a * b * cC

avg 8 sum,$Cprintf)DSum: f Avg: fD"sum"avg+Creturn /C /)a return 9

6 It 'rints out +

n /Un

>>>>>>>>>>>>>>>> 9 1 1 /

/ 0 1V 8 0/ V V X 1/ /8V

Y 81/19 19/11 /91/ 9YV10 1Y/1 1V018 0/XV1V V880V

6

6 add/(c JJ Add to nu#;ers and 'rint t"e# out to!et"er

it" t"eir su# ATHOR+ ZNTC2H DAT2+ 1/6906/919

6

Kincude 7stdio("

int #ain3)oid5


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int %irst. second

'rint%32nter to inte!ers 5 scan%3d d. &%irst. &second5 'rint%3T"e to nu#;ers are+ d dn. %irst. second5

'rint%3T"eir su# is dn. %irst4second5

6 addn(c JJ Read a 'ositi)e nu#;er N( T"en read N inte!ers and 'rint t"e# out to!et"er it" t"eir su#(6

Kincude 7stdio("

int #ain3)oid5 int n 6 T"e nu#;er o% nu#;ers to ;e read 6

int su# 6 T"e su# o% nu#;ers aread read 6 int current 6 T"e nu#;er [ust read 6 int c) 6 Loo' contro )aria;e. it counts t"e nu#;er o% nu#;ers aread read 6

'rint%32nter a 'ositi)e nu#;er n 5scan%3d.&n5 6 We s"oud c"ec* t"at n is rea 'ositi)e6

su# > 9 %or 3c)>9 c) 7 n c)445 'rint%3n2nter an inte!er 5 scan%3d.&current5

6 'rint%3nT"e nu#;er as dn. current5 6 su# > su# 4 current 'rint%3T"e su# is dn. su#5 return 9

Assi!n#ent+

Na#e )arious "eader %ies 'resent in C

W"at are 're'rocessor co##ands and t"eir use \eords in C

Loca )s Go;a )aria;es in C

Data t'es in C 3in detai5

,H addn.c II 'ead a positive number 6. ;hen read 6 integers and


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H print them out together with their sum.H,

@include -stdio.h

int main)void+ B int nC ,H ;he number of numbers to be read H, int sumC ,H ;he sum of numbers already read H, int currentC ,H ;he number Just read H, int lcvC ,H 2oop control variable" it counts the number of numbers already read H,

printf)DEnter a positive number n D+Cscanf)DdD"Fn+C ,H 5e should check that n is really positiveH,

sum 8 /C for )lcv8/C lcv - nC lcv**+ B

printf)DKnEnter an integer D+C scanf)DdD"Fcurrent+C ,H printf)DKn;he number was dKnD" current+C H, sum 8 sum * currentC < printf)D;he sum is dKnD" sum+C return /C dn. su#5

return 9

Kincude directi)es+incudes decarations o% %unctions %ro# "eader %ies %or standardi;raries( For e> Sunda ]] T"eDa >> Saturda5'rint%3Hurra it is t"e ee*endn5ese'rint%3Curses sti at or*n5

return 9


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,HHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH H 2nu#eration e


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6 2nu#eration e


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printf)D ;rue has a value of dD" ;'WE+Ca4;'rint%3d.c5!etc"3566getch)+ statement is a get character statement. t pause the output untiluser presses a key from the keyboard.

c 'ro!ra# to !enerate nu#;er ;eteen 1 to 199

@include-stdio.hmain)+Bint a81Cclrscr)+Cwhile )a-81//+

Bprintf)DKndD"a+Ca8a*1C

c lab programs 1

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