Exercise 1

Solving problems such as temperature conversion, student grading, income tax calculation, etc which expose the students to use basic C operators.

a) Temperature Conversion from Fahrenheit to Celsius.

Program

#include<stdio.h>#include<conio.h>void main(){ float f,c; clrscr(); printf("\n Enter Temperature in F: "); scanf("%f",&f); c=5.0/9*(f-32); printf(" Temperature in C: %f",c); getch();}

Output

Enter Temperature in F: 98 Temperature in C: 36.666668

b) Student grading based on his percentage.

Program

#include<stdio.h>#include<conio.h>void main(){ int p; clrscr(); printf("\n Enter Percentage: "); scanf("%d",&p); if(p>=70) printf(" Distinction"); else if(p>=60&&p<70) printf(" First class"); else if(p>=50&&p<60) printf(" Second class"); else if(p>=40&&p<50)

1

printf(" Third class"); else printf(" Fail"); getch();}

Output

Enter Percentage: 73 Distinction

c) Average of three numbers

Program

#include<stdio.h>#include<conio.h>void main(){ int a,b,c; float avg; clrscr(); printf("\n Enter a,b,c: "); scanf("%d%d%d",&a,&b,&c); avg=(float)(a+b+c)/3; printf(" Avg: %f",avg); getch();}

Output

Enter a,b,c: 62 45 90 Avg: 65.666664

2

d) Largest among three numbers

Program

#include<stdio.h>#include<conio.h>void main(){ int a,b,c; clrscr(); printf("\n Enter a,b,c: "); scanf("%d%d%d",&a,&b,&c);

if(a>b) { if(a>c) printf(" a is large"); else printf(" c is large"); } else if(b>c) printf(" b is large"); else printf(" c is large"); getch();}

Output

Enter a,b,c: 5 9 3 b is large

3

e) Income Tax calculation

0 – 200000 0%200000 – 300000 10%300000 – 500000 20%Above 500000 30%

Program

#include<stdio.h>#include<conio.h>void main(){ long int a,tax=0; clrscr(); printf("\n Enter amount: "); scanf("%ld",&a); if(a<=200000) tax=0; else if(a>200000&&a<=300000) tax=(a-200000)*10/100; else if(a>300000&&a<=500000) tax=10000+(a-300000)*20/100; else if(a>500000) tax=50000+(a-500000)*30/100; printf(" Tax: %ld",tax); getch();}

Output

Enter amount: 600000 Tax: 80000

4

Exercise 2

2’s complement of a number is obtained by scanning it from right to left and complementing all the bits after the first appearance of a 1. Thus 2’s complement of 11100 is 00100. Write a C program to find the 2’s complement of a binary number.

Program

#include<stdio.h>#include<conio.h>#include<string.h>#include<stdlib.h>void main(){ char a[20]; int i,j,k,len; clrscr(); printf("\n Enter Binary string: "); gets(a); len=strlen(a); for(k=0;a[k]!='\0';k++) { if(a[k]!='0'&&a[k]!='1') { printf(" Incorrect Binary number..."); getch(); exit(0); } } for(i=len-1;a[i]!='1';i--); for(j=i-1;j>=0;j--) { if(a[j]=='1') a[j]='0'; else a[j]='1'; } printf(" 2's complement: %s",a); getch();}

Output

Enter Binary string: 110101010 2's complement: 001010110

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Exercise 3

a) Write a C Program to find the sum of individual digits of a positive integer Program

#include<stdio.h>#include<conio.h>void main(){ int n,sum=0; clrscr(); printf("\n Enter n: "); scanf("%d",&n); if(n<0) { printf("Enter positive integer.."); } else { while(n!=0) { sum=sum+n%10; n=n/10; } printf(" Sum of individual digits: %d",sum); } getch();}

Output

Enter n: 2346 Sum of individual digits: 15

6

b) A Fibonacci sequence is defined as follows: the first and second terms in the sequence are 0 and 1. Subsequent terms are found by adding the preceding two terms in the sequence. Write a C program to generate the first n terms of the sequence.

Program

#include<stdio.h>#include<conio.h>void main(){ int a=0,b=1,c,n,i; clrscr(); printf("\n Enter n: "); scanf("%d",&n); printf("\n The Fibonacci sequence...\n"); printf(" %d\n %d",a,b); for(i=3;i<=n;i++) { c=a+b; printf("\n %d",c); a=b; b=c; } getch();}

Output

Enter n: 10

The Fibonacci sequence… 0 1 1 2 3 5 8 13 21 34

7

c) Write a C program to generate all the prime numbers between 1 and n, where n is a value supplied by the user.

Program

#include<stdio.h>#include<conio.h>void main(){ int i,j,n,count=0; clrscr(); printf("\n Enter n: "); scanf("%d",&n); printf(" Prime numbers between 1 and %d are...",n); for(i=2;i<=n;i++) { count=0; for(j=2;j<=i-1;j++) { if(i%j==0) count++; } if(count==0) printf("\n %d",i); } getch();}

Output

Enter n: 45 Prime numbers between 1 and 45 are... 2 3 5 7 11 13 17 19 23 29 31 37 41 43

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d) Write a program which checks a given integer is Fibonacci number or not

Program

#include<stdio.h>#include<conio.h>void main(){ int n,i,a[20],count=0; clrscr(); a[0]=0; a[1]=1; for(i=2;i<20;i++) { a[i]=a[i-1]+a[i-2]; } printf("\n Enter n: "); scanf("%d",&n); for(i=0;i<20;i++) { if(n==a[i]) { count++; break; } } if(count>0) printf(" Fibonacci number..."); else printf(" Not a fibonacci number..."); getch();}Output

Enter n: 144 Fibonacci number...

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Exercise 4

a) Write a C program to calculate the following Sum:Sum=1-x2/2! +x4/4!-x6/6!+x8/8!-x10/10!

Program

#include<stdio.h>#include<conio.h>#include<math.h>void main(){ long int i,t,f=1,k=1; float sum=1.0,x; clrscr(); printf("\n Enter x: "); scanf("%f",&x); for(i=2;i<=10;i=i+2) { t=i; while(t!=0) { f=f*t; t--; } sum=sum+(pow(-1,k)*pow(x,i))/(float)f; k++; f=1; } printf("\n The Sum of Series: %f",sum); getch();}

Output

Enter x: 2 The Sum of Series: -0.416155

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b) Write a C program toe find the roots of a quadratic equation.

Program

#include<stdio.h>#include<conio.h>#include<math.h>void main(){ float a,b,c,d,p,q,x1,x2; clrscr(); printf("\n Enter a,b,c: "); scanf("%f%f%f",&a,&b,&c); d=b*b-4*a*c; if(d==0) { printf(" Roots are real and equal..."); printf("\n x1=x2=%f",-b/(2*a)); } else if(d>0) { printf(" Roots are real..."); x1=(-b+sqrt(d))/(2*a); x2=(-b-sqrt(d))/(2*a); printf("\n x1=%f \n x2=%f",x1,x2); } else //if(d<0){ printf(" Roots are imaginary..."); p=-b/(2*a); q=sqrt(-d)/(2*a); if(q<0) printf("\n x1=%f+i%f x2=%f-i%f",p,-q,p,-q); else printf("\n x1=%f+i%f x2=%f-i%f",p,q,p,q); } getch();}

Output Enter a,b,c: 4 4 1 Roots are real and equal... x1=x2=-0.500000

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Exercise 5

a) The total distance traveled by vehicle in ‘t’ seconds is given by distance = ut+1/2at2 where ‘u’ and ‘a’ are the initial velocity (m/sec.) and acceleration (m/sec2). Write C program to find the distance traveled at regular intervals of time given the values of ‘u’ and ‘a’. The program should provide the flexibility to the user to select his own time intervals and repeat the calculations for different values of ‘u’ and ‘a’.

Program

#include<stdio.h>#include<conio.h>void main(){ float s,a,u; int t,n; clrscr(); printf("\n Enter Time Intervals: "); scanf("%d",&n); for(t=0;t<=n;t++) { printf(" Enter u and a: "); scanf("%f%f",&a,&u); s=u*t+0.5*a*t*t; printf(" Distance traveled at %d time interval: %f \n",t,s); } getch();}

Output

Enter Time Intervals: 2 Enter u and a: 2 7 Distance traveled at 0 time interval: 0.000000 Enter u and a: 4 9 Distance traveled at 1 time interval: 11.000000 Enter u and a: 3 4 Distance traveled at 2 time interval: 14.000000

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b) Write a C program, which takes two integer operands and one operator form the user, performs the operation and then prints the result. (Consider the operators +,-,*, /, % and use Switch Statement)

Program

#include<stdio.h>#include<conio.h>void main(){ int a,b,c; char op; clrscr(); printf("\n Enter a,b: "); scanf("%d%d",&a,&b); printf(" Enter Operator (+,-,*,/,%): "); op=getche(); switch(op) { case '+': c=a+b; break; case '-': c=a-b; break; case '*': c=a*b; break; case '/': c=a/b; break; case '%': c=a%b; break; default : printf("\n Enter correct operator..");

getch(); exit(0);

} printf("\n Result: %d",c); getch();}

Output

Enter a,b: 87 34 Enter Operator (+,-,*,/,%): % Result: 19

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Exercise 6

a) Simple programming examples to manipulate strings.

Program

#include<string.h>void main(){ char a[10]="srinivas",b[10]="KRISHNA",c[10]="srinivas",d[10],e[20]; int len; clrscr(); len=strlen(a); printf("\n Length=%d",len); strcpy(d,a); printf("\n %s",d); strcpy(e,a); strcat(e,b); printf("\n %s",e); strrev(d); printf("\n %s",d); strlwr(b); printf("\n %s",b); strupr(a); printf("\n %s",a); if(strcmp(a,c)==0) //compares with case sensitivity printf("\n Two strings are equal "); else printf("\n Two strings are not equal"); if(stricmp(a,c)==0) //compares without case sensitivity printf("\n Two strings are equal"); else printf("\n Two strings are not equal"); getch();}

Output

Length=8 srinivas srinivasKRISHNA savinirs krishna SRINIVAS Two strings are not equal Two strings are equal

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b) Verifying a string for its palindrome property

Program

#include<stdio.h>#include<conio.h>#include<string.h>void main(){ char a[20]; int len,i; clrscr(); printf("\n Enter String: "); gets(a); len=strlen(a); for(i=0;i<len/2;i++) { if(a[i]==a[len-1]) len--; else { printf("\n Not Palindrome..."); getch(); exit(); } } printf("\n Palindrome…"); getch();}

Output

Enter String: srinirs

Palindrome…

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Exercise 7

Write a C program that uses functions to perform the following operations

i) To insert a sub-string in to given main string from a given position.

Program

#include<stdio.h>#include<conio.h>#include<string.h>void main(){ int i,p,n,r,k,j=0; char a[20],b[10],c[30]; clrscr(); printf("\n Enter the Main String: "); gets(a); printf(" Enter the String to insert: "); gets(b); printf(" Enter position to insert: "); scanf("%d",&p); n=strlen(a); r=strlen(b); for(i=0;i<p-1;i++) c[i]=a[i]; k=i; for(i=p-1;i<p+r-1;i++) c[i]=b[j++]; for(i=p+r-1;i<n+r;i++) c[i]=a[k++]; c[i]='\0'; printf(" Resultant String: %s",c); getch();}

Output

Enter the Main String: srinivas Enter the String to insert: Hari Enter position to insert: 4 Resultant String: sriHarinivas

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ii) To delete n Characters from a given position in a given string.

Program

#include<stdio.h>#include<conio.h>#include<string.h>void main(){ char a[20]; int i,p,len,n,k; clrscr(); printf("\n Enter String: "); gets(a); len=strlen(a); printf(" Enter Position: "); scanf("%d",&p); printf(" Enter Number of chars to delete: "); scanf("%d",&n); k=p+n-1; for(i=p-1;i<len-n;i++) a[i]=a[k++]; a[i]='\0'; printf(" Resultant String: %s",a); getch();}

Output

Enter String: srinivas Enter Position: 4 Enter Number of chars to delete: 2 Resultant String: srivas

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iii) To replace a character of a string either from beginning or ending or at a specified location.

Program

#include<stdio.h>#include<conio.h>#include<string.h>void main(){ char a[20],ch; int choice,pos,len; clrscr(); printf("\n Enter string: "); gets(a); printf(" 1.At Begin \n 2.At End \n 3.At position \n"); printf(" Enter choice: "); scanf("%d",&choice); switch(choice) { case 1: printf(" Enter character to replace at begin: ");

ch=getche(); a[0]=ch; printf("\n New string: %s",a); break;

case 2: printf(" Enter character to replace at end: "); ch=getche(); len=strlen(a); a[len-1]=ch; printf("\n New string: %s",a); break;

case 3: printf(" Enter character to replace at given position: "); ch=getche(); printf("\n Enter position: "); scanf("%d",&pos); a[pos-1]=ch; printf(" New string: %s",a); break;

default:printf(" Enter correct choice"); break;

} getch();}

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Output

Enter string: sri nivas 1.At Begin 2.At End 3.At position Enter choice: 1 Enter character to replace at begin: Q New string: Qri nivas

Enter string: sri nivas 1.At Begin 2.At End 3.At position Enter choice: 2 Enter character to replace at end: W New string: sri nivaW

Enter string: sri nivas 1.At Begin 2.At End 3.At position Enter choice: 3 Enter character to replace at given position: Z Enter position: 4 New string: sriZnivas

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Exercise 8

Write a C program that uses functions to perform the following operations:i) Reading a complex numberii) Writing a complex numberiii) Addition of two complex numbersiv) Multiplication of two complex numbers

Program

#include<stdio.h>#include<conio.h>

struct complex add(struct complex a,struct complex b);struct complex mul(struct complex a,struct complex b);void write(struct complex s);struct complex read();

struct complex{ float r,i;};

void main(){ struct complex a,b,c; int ch; clrscr(); printf("\n Enter Real and Imag for 1st Complex Number: "); a=read(); printf("\n Enter Real and Imag for 2nd Complex Number: "); b=read(); printf("\n 1.Add \n 2.Multiplication "); printf("\n Enter choice: "); scanf("%d",&ch); switch(ch) { case 1 : c=add(a,b);

write(c); break;

case 2 : c=mul(a,b); write(c); break;

default: printf("\n Enter Correct choice.."); break;

}

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getch();}struct complex read(){ struct complex s; scanf("%f%f",&s.r,&s.i); return s;}struct complex add(struct complex a,struct complex b){ struct complex s; s.r=a.r+b.r; s.i=a.i+b.i; return s;}struct complex mul(struct complex a,struct complex b){ struct complex s; s.r=a.r*b.r-a.i*b.i; s.i=a.r*b.i+a.i*b.r; return s;}void write(struct complex s){ if(s.i>0) printf("\n Result=%f+i%f",s.r,s.i); else printf("\n Result=%f-i%f",s.r,-1*s.i);}

Output

Enter Real and Imag for 1st Complex Number: 3-2

Enter Real and Imag for 2nd Complex Number: -56

1.Add 2.Multiplication Enter choice: 2

Result=-3.000000+i28.000000

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Exercise 9

a) Addition of two matrices

Program

#include<stdio.h>#include<conio.h>void main(){ int a[4][4],b[4][4],c[4][4],i,j,m,n,p,q; clrscr(); printf("\n Enter Order for 1st Matrix: "); scanf("%d%d",&m,&n); printf("\n Enter Order for 2nd Matrix: "); scanf("%d%d",&p,&q); if((m==p)&&(n==q)) { printf("\n Enter 1st Matrix elements: "); for(i=0;i<m;i++) { for(j=0;j<n;j++) { scanf("%d",&a[i][j]); } } printf("\n Enter 2nd Matrix elements: "); for(i=0;i<p;i++) { for(j=0;j<q;j++) { scanf("%d",&b[i][j]); } } printf("\n Addition of two matrices: \n"); for(i=0;i<m;i++) { for(j=0;j<n;j++) { c[i][j]=a[i][j]+b[i][j]; printf("%d \t",c[i][j]); } printf("\n"); } }

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else { printf("\n Addition not possible..."); } getch();}

Output

Enter Order for 1st Matrix: 3 2

Enter Order for 2nd Matrix: 3 2

Enter 1st Matrix elements: 123456

Enter 2nd Matrix elements: 654321

Addition of two matrices:7 77 77 7

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b) Calculating transpose of matrix in-place manner

Program

#include<stdio.h>#include<conio.h>void main(){ int a[4][4],b[4][4],i,j,m,n; clrscr(); printf("\n Enter Order for matrix: "); scanf("%d%d",&m,&n); printf(" Enter Matrix elements: "); for(i=0;i<m;i++) { for(j=0;j<n;j++) { scanf("%d",&a[i][j]); b[j][i]=a[i][j]; } } printf(" Transpose of Matrix: "); for(i=0;i<n;i++) { printf("\n"); for(j=0;j<m;j++) { printf("%d \t",b[i][j]); } }getch();}

Output

Enter Order for matrix: 3 4 Enter Matrix elements:1 2 3 45 6 7 89 10 11 12 Transpose of Matrix:1 5 92 6 103 7 114 8 12

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c) Matrix Multiplication by checking compatibility

Program

#include<stdio.h>#include<conio.h>void main(){ int a[4][4],b[4][4],c[4][4],i,j,m,n,p,q,k; clrscr(); printf("\n Enter Order for 1st Matrix: "); scanf("%d%d",&m,&n); printf("\n Enter Order for 2nd Matrix: "); scanf("%d%d",&p,&q); if(n==p) { printf("\n Enter 1st Matrix elements: "); for(i=0;i<m;i++) { for(j=0;j<n;j++) { scanf("%d",&a[i][j]); } } printf("\n Enter 2nd Matrix elements: "); for(i=0;i<p;i++) { for(j=0;j<q;j++) { scanf("%d",&b[i][j]); } } printf("\n Multiplication of two matrices: \n"); for(i=0;i<m;i++) { for(j=0;j<q;j++) { c[i][j]=0; for(k=0;k<n;k++) c[i][j]=c[i][j]+a[i][k]*b[k][j]; printf("%d \t",c[i][j]); } printf("\n"); } }

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else { printf("\n Multiplication not possible..."); } getch();}

Output

Enter Order for 1st Matrix: 3 3

Enter Order for 2nd Matrix: 3 2

Enter 1st Matrix elements: 1 2 3 4 5 6 7 8 9

Enter 2nd Matrix elements: 6 5 4 3 2 1

Multiplication of two matrices:20 1456 4192 68

26

Exercise 10

a) Write C programs that use both recursive and non-recursive functions.

i) To find the factorial of a given integer.

Program using Non-Recursive

#include<stdio.h>#include<conio.h>void main(){ int f=1,i,n; clrscr(); printf("\n Enter n: "); scanf("%d",&n); for(i=1;i<=n;i++) { f=f*i; } printf("\n Factorial of %d is: %d",n,f); getch();}

Output

Enter n: 7

Factorial of 7 is: 5040

Program using Recursive

#include<stdio.h>#include<conio.h>void main(){ int f,i,n; clrscr(); printf("\n Enter n: "); scanf("%d",&n); printf("\n Factorial of %d is: %d",n,fact(n)); getch();}

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int fact(int n){ int p; if(n==1) return 1; else p=n*fact(n-1); return p;}

Output

Enter n: 7

Factorial of 7 is: 5040

ii) To find the GCD (greatest common divisor) of two given integers.

GCD using Non-Recursive

#include<stdio.h>#include<conio.h>void main(){ int a,b,gcd,i,m; clrscr(); printf("\n Enter a,b: "); scanf("%d%d",&a,&b); if(a>b) m=b; else m=a; for(i=1;i<=m;i++) { if(a%i==0&&b%i==0) gcd=i; } printf("\n GCD of %d and %d is: %d",a,b,gcd); getch();}

Output

Enter a,b: 36 24 GCD of 36 and 24 is: 12

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GCD using Recursive

#include<stdio.h>#include<conio.h>void main(){ int a,b; clrscr(); printf("\n Enter a,b: "); scanf("%d%d",&a,&b); printf("\n GCD of %d and %d is: %d",a,b,gcd(a,b)); getch();}int gcd(int a,int b){ if(b>a) return gcd(b,a); if(b==0) return a; else return gcd(b,a%b);}

Output

Enter a,b: 36 24GCD of 36 and 24 is: 12

iii) To solve Towers of Hanoi problem.

Program using Recursive

#include<stdio.h>#include<conio.h>void towers(int n,char src, char target, char temp);void main(){ int n; clrscr(); printf("\n How Many disks: "); scanf("%d",&n); towers(n,'A','C','B'); getch();}

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void towers(int n, char src, char target, char temp){ if(n==1) { printf("\n Move top disk from %c to %c",src,target); return; } towers(n-1,src,temp,target); printf( "\n Move top disk from %c to %c",src,target); towers(n-1,temp,target,src);}

Output

How Many disks: 4

Move top disk from A to B Move top disk from A to C Move top disk from B to C Move top disk from A to B Move top disk from C to A Move top disk from C to B Move top disk from A to B Move top disk from A to C Move top disk from B to C Move top disk from B to A Move top disk from C to A Move top disk from B to C Move top disk from A to B Move top disk from A to C Move top disk from B to C

30

Exercise 11

a) Write a C Function to find both largest and smallest numbers of an array of integers.

Program

#include<stdio.h>#include<conio.h>void main(){ int a[10],n,i,max,min; clrscr(); printf("\n Enter n: "); scanf("%d",&n); printf(" Enter elements: "); for(i=0;i<n;i++) scanf("%d",&a[i]); min=max=a[0]; for(i=0;i<n;i++) { if(a[i]<min) min=a[i]; if(a[i]>max) max=a[i]; } printf(" Largest=%d \n Smallest=%d ",max,min); getch();}

Output

Enter n: 6 Enter elements: 1 5 -65 8 936 421 Largest=936 Smallest=-65

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b) Write a C function that uses functions to perform the following.

i) Write a C program that displays the position or index in the string S where the string T begins, or – 1 if S doesn’t contain T.

Program

#include<stdio.h>#include<conio.h>#include<string.h>void main(){ char s[20],t[10],*found; clrscr(); printf("\n Enter String: "); gets(s); printf(" Enter Substring to find: "); gets(t); found=strstr(s,t); if(found) printf(" Found at %d position...",found-s+1); else printf(" Substring not found..."); getch();}

Output

Enter String: srinivas Enter Substring to find: iva Found at 6 position

ii) Write a C program to count the lines, words and characters in a given text.

Program

#include<stdio.h>#include<conio.h>#include<string.h>void main(){ char a[80],ch; int i,k,end=0,nc=0,nw=0,nl=0; clrscr();

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printf("\n Enter the Text and press ENTER at end..\n");

while(end==0) { k=0; while((ch=getchar())!='\n')

a[k++]=ch; a[k]='\0'; if(a[0]=='\0') break; else { nw++; for(i=0;a[i]!='\0';i++) { if(a[i]==' '||a[i]=='\t') nw++; } } nl=nl+1; nc=nc+strlen(a); }

printf("\n Number of Lines : %d",nl); printf("\n Number of Words : %d",nw); printf("\n Number of Characters: %d",nc);

getch();}

Output

Enter the Text and press ENTER at end..Hello WorldHow are you !!!!

Number of Lines : 2 Number of Words : 6 Number of Characters: 27

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Exercise 12

a) Write a C function to generate Pascal’s triangle.

Program

#include<stdio.h>#include<conio.h>void main(){ int p=1,y=0,i,r,x; clrscr(); printf("\n Rows you want to input: "); scanf("%d",&r); printf("\n Pascal's Triangle:\n"); while(y<r) { for(i=40-3*y;i>0;i--) printf(" "); for(x=0;x<=y;x++) { if((x==0)||(y==0)) p=1; else p=(p*(y-x+1))/x; printf("%6d",p); } printf("\n"); y++; } getch();}

Output

Rows you want to input: 6

Pascal's Triangle: 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1

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b) Write a C function to construct a pyramid of numbers.

Program

#include<stdio.h>#include<conio.h>void main(){ int n,i,y,x=35; clrscr(); printf("\n Enter n: "); scanf("%d",&n); printf("\n Pyramid Triangle \n"); for(y=0;y<=n;y++) { gotoxy(x,y+4); for(i=-y;i<=y;i++) printf("%2d",abs(i)); x=x-2; } getch();}

Output

Enter n: 4

Pyramid Triangle

0 1 0 1 2 1 0 1 2 3 2 1 0 1 2 3 4 3 2 1 0 1 2 3 4

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Exercise 13

Write a C program to read in two numbers, x and n, and then compute the sum of this geometricprogression: 1+x+x2+x3+………….+xn

Program

#include<stdio.h>#include<conio.h>#include<math.h>void main(){ int i,x,n; long int sum; clrscr(); printf("\n Enter the values for x and n: "); scanf("%d%d",&x,&n);

if(n<=0||x<=0) { printf("\n Value is not valid.."); getch(); main(); } else { sum=1; for(i=1;i<=n;i++) { sum=sum+pow(x,i); } printf("\n Sum of series: %ld",sum); } getch();}

Output

Enter the values for x and n: 5 3

Sum of series: 156

36

Write a C function to read in two numbers, x and n (number of terns) and then compute sin(x) and cos(x).

cos(x)=1-x2/2!+x4/4!-x6/6!+x8/8!-…….

Program

#include<stdio.h>#include<conio.h>#include<math.h>void main(){ long int i,t,f=1,k=1,n; float sum=1,x; clrscr(); printf("\n Enter x: "); scanf("%f",&x); printf(" Enter n: "); scanf("%ld",&n); for(i=2;i<n*2;i=i+2) { t=i; while(t!=0) { f=f*t; t--; } sum=sum+(pow(-1,k)*pow(x,i))/f; k++; f=1; } printf("\n cos(x)= %f",sum); getch();}

Output

Enter x: 2 Enter n: 6 cos(x)= -0.416155

37

sin(x)=x-x3/3!+x5/5!-x7/7!+x9/9!-…….

Program

#include<stdio.h>#include<conio.h>#include<math.h>void main(){ long int i,t,f=1,k=1; float sum,x; clrscr(); printf("\n Enter x: "); scanf("%f",&x); printf(" Enter n: "); scanf("%ld",&n); sum=x; for(i=3;i<n*2;i=i+2) { t=i; while(t!=0) { f=f*t; t--; } sum=sum+(pow(-1,k)*pow(x,i))/f; k++; f=1; } printf("\n sin(x)= %f",sum); getch();}

Output

Enter x: 2 Enter n: 4 sin(x)= 0.907937

38