c lab programs 3

8/12/2019 C Lab Programs 3

1/32

Display numbers in ascending and descending order

#include< stdio.h >#include< conio.h >void main()

{

int i=0;clrscr();

printf(" \nNumers in ascendin! order \n");

for (;++i


2/32

printf(" \n Numer is odd \n");

brea";

defaul

y=%*;s$ic! (y)&'ase 0

printf(" \n Numer is even \n");

brea";defaul

printf(" \n Numer is odd \n");

}

}

ec!();

}

,r

#include< stdio.h >#include< conio.h >#includevoid main(){

int ;clrscr();

printf(" \n*nter the Numer \n");

scanf("$d"'+);if(%*==0)

goo e#en;else


3/32

goo odd;

even

printf(" \n $d is *ven numer \n");

reurn;

odd

printf(" \n $d is odd numer\n");

}

' program o prin !o$ many prime numbers are !ere from 1 o 0.

,ere is a simple pro!ram to !enerate prime numers upto a !iven specificnumer

/include/include#oid main()&in i2n;prinf(3 4ner !e number upo $!ic! $e !a#e o find !e prime number 3);scanf(3d35n);prinf(36n3);

for(i=*;i


4/32

a=n$i;if(a=0)

{c=c/;

if (c=1){ printf("the !iven numer is prime");

elseprintf("the !iven numer is not prime");

or

#include#include

void main(){int no'i;clrscr();printf(" *nter the Numer 2 3ant to chec-");scanf("$d"'+no);i=1;3hile(i


5/32

a=n$i;if(a=0)

{c=c/;

if (c=1)printf("the !iven numer is prime");

elseprintf("the !iven numer is not prime");

program !a c!ec"s number is -#e or +#e and con#ers o +#e if -#e

1 / include 77:nclude !e sdio! file* #oid main () 77 sar of !e program

& in numbers ; 77 declare !e #ariables prinf (3ype a number3); 77 message o !e user scanf (3d3 5number) ; 77 read !e number from sandard inpu? if (number < 0) 77 c!ec" $!e!er !e number is a negai#e@ numberA number = -number; 77 if i is negai#e !en con#er i ino10 posii#e11 prinf (3!e absolue #alue is d 6n3 number); 77 prin !e1* #alue1 }

Prin !e gi#en numbers along $i! !e larges number of !em

1 /include 77includes !e sdio! file o your program* main () 77sar of main funcion & in abcbig 77declaraion of #ariables prinf (34ner !ree numbers3) 77message o !e user scanf (3d d d3 5a 5b 5c) 77Bead #ariables abc? if (a > b) 77 c!ec" $!e!er a is greaer !an b if rue !en@ if (a > c) 77 c!ec" $!e!er a is greaer !an c

A big = a ; 77 assign a o big10 else11 big = c ; 77 assign c o big1* else1 if (b > c) 77 if !e condiion (a > b) fails c!ec" $!e!er b1 is greaer !an c1 big = b; 77 assign b o big1 else


6/32

1? big = c; 77 assign c o big1@1A prinf (3Carges of d d 5 d = d3 abcbig); 77prin !e*0 gi#ennumers alon! 3ith the lar!est numer1.

Ceap ear program in '

E year $ill be a leap year if i is di#isible by (1AA)bu no leap year if di#isible by 100 (*100):f a year is di#isible by and by 100 i is no a leap year (*100):f i is di#isible by 00 e#en if di#isible by 100 i is leap year(*000)

/include /include #oid main()

&in y;prinf(3ener !e year3);scanf(3d35y);if(y100==0)& if(y00==0) & prinf(3d is leap year3); } else

& prinf(3 d is no a leap year3); }}else & if(y==0) & prinf(3d is a leap year3); } else

& prinf(3d is no a leap year3); }}

gec!();

}


7/32

Fse of 4lse :f Cadder

/include#oid main ()

&in mar"s;clrscr ();prinf (34ner mar"s3);scanf (3d3 5mar"s);if (mar"s>A0)prinf (34%cellen3);else if (mar"s>?)prinf (3Gery good3);else if (mar"s>0)prinf (3ood3);

else if (mar"s>0)prinf (3E#eraged3);elseprinf (3Gery poor3);gec! ();}

4%ample program for generaing H8I 8aural numbers using $!ile loop

/ include < sdio! > 77include !e sdio! file#oid main() 77 9ar of your program

&in n i=0; 77Declare and iniialiJe !e #ariablesprinf(K4ner !e upper limi numberL); 77Message o !e userscanf(KdL 5n); 77read and sore !e number$!ile(i < = n) 77 N!ile saemen $i! condiion& 77 Oody of !e loopprinf(K6dLi); 77 prin !e #alue of ii++; 77incremen : o !e ne% naural number}}

Program prins firs 100 numbers !a are di#idable $i! ?

#include

void main() {

int i=0' n=0;


8/32

3hile (n < 00) {

if (i $ 7 == 0) {

printf ("$d\n"' i); n//;

i//;

ry !e follo$ing program $!ic! as"s for a number be$een 1 and A and

loops around unil a #alid number !as been enered-/include /include

main() &

in num;

do &

prinf(34ner number 1-A 3); scanf(3d35num); } $!ile ((numA));

prinf(3ou c!ose d Press a "ey3num); gec!();

}

8pical output for this mi!ht e4

4ner number 1-A 104ner number 1-A 04ner number 1-A 14ner number 1-A -4ner number 1-A

ou c!ose Press a "eyQ

Fse of brea" saemen


9/32


10/32

for (i = 0; i < =; i++) 77 for loop&

prinf(K4ner !e inegerL); 77Message o !e userscanf(KdL 5num); 77read and sore !e numberif(num < 0) 77c!ec" $!e!er !e number is less !an Jero

&prinf(Kou !a#e enered a negai#e numberL); 77 message o !e userconinue; 77 sars $i! !e beginning of !e loop

} 77 end of for loopsum+=num; 77 add and sore sum o num

}prinf(K!e sum of posii#e numbers enered = dLsum); 77 prin !e sum} 77 end of !e program

Ror loop e%ample program 9um of firs 1 posii#e e#en numbers and!eir sSuares

/include < sdio! > 77:nclude sdio! file#oid main() 77sar main program&in i; 77declare #ariablein sum=0sumQofQsSuares=0; 77declare and iniialiJe #ariablefor(i=0;i < = 0; i+=*) 77for loop

&sum+=i; 77add !e #alue of i and sore i o sumsumQofQsSuares+=iTi; 77find !e sSuare #alue and add i o

sumQofQsSuares} 77end of for loop

prinf(K9um of firs 1 posii#e e#en numbers=d6nLsum); 77Prin sumprinf(K9um of !eir sSuares=d6nLsumQofQsSuares); 77prinsumQofQsSuare}

Nrie your o$n program !a $ill calculae ari!meic middle of n gi#ennumbers

#include

void main() {

int i' n' sum' ; float arit9midd;

printf("Aor ho3 man numers do ou 3ish to calc. their arithmetic middle "); scanf("$d"' +n );


11/32

sum = 0; for(i=0; i


12/32

#include

void main() {

int !rade; printf ("Dnput !rade "); scanf("$d"' + !rade);

s3itch (!rade) {

case printf("Aail (A)\n");rea-;

case 1printf("Ead (F)\n");rea-;

case %

printf("Bood ()\n");rea-; case @printf("Ger Bood (E)\n");rea-;

case Hprintf("*cellent (C)\n");rea-;

default printf("Iou have inputted false !rade\n"); rea-; rea- isnJt necessar here

4%ample program on 9$ic! 'ase

/include /include /include

/define BF4 1/define 9EB4BQ',9 A/define ME:8Q',9 @A/define D4994BQ',9 0

main ()& c!ar c!;floa cosoal;

oal = 00;

do


13/32

&

prinf(3'!oose one of (9)arer (M)ain (D)esser e(U)i 3);

c!=oupper( gec!e() ); prinf(36n3);s$ic!(c!)

& case(V9V) prinf(39arer included3);

cos=9EB4BQ',9;

brea";

case(VMV) prinf(3Main included3);

cos=ME:8Q',9;

brea";

case(VDV) prinf(3Desser included3);

cos=D4994BQ',9;

brea";

case(VUV) prinf(3Program finis!ed3);

brea";

defaul prinf(3:ncorrec c!oice ry again6n6n3);

coninue;

} 7T end of s$ic! T7

prinf(36n3);

if (c!==VUV) brea";

prinf(3'os of c!oice c is *f6n3 c! cos);

oal+=cos;

prinf(3oal cos is *f6n6n3 oal);


14/32

} $!ile (BF4);

gec!();

}

C tpical output from the pro!ram mi!ht loo- li-e this

'!oose one of (9)arer (M)ain (D)esser e(U)i s

9arer included

'os of c!oice 9 is A

oal cos is A

'!oose one of (9)arer (M)ain (D)esser e(U)i m

Main included

'os of c!oice M is @A

oal cos is 1*A0'!oose one of (9)arer (M)ain (D)esser e(U)i d

Desser included

'os of c!oice D is 0

oal cos is 10

'!oose one of (9)arer (M)ain (D)esser e(U)i p

:ncorrec c!oice ry again

!e same abo#e program using :f saemen

/include

/include

/include

/define BF4 1


15/32

main ()

&

c!ar c!;

floa cosoal;

oal = 00;

do

&

prinf(3'!oose one of (9)arer (M)ain (D)esser e(U)i 3);

c!=gec!e(); c!=oupper(c!);

7T alernai#ely c!= oupper( gec!e() ); T7

prinf(36n3);

if (c!==V9V) &

prinf(39arer included3); cos=A;

} else if (c!==VMV) &

prinf(3Main included3); cos=@A;

} else if (c!==VDV) &

prinf(3Desser included3); cos=0;

} else if (c!==VUV) &

prinf(3Program finis!ed3);

brea";

} else &

prinf(3:ncorrec c!oice ry again3);


16/32

coninue;

}

prinf(36n'os of c!oice c is *f6n3 c! cos);

oal=oal+cos;

prinf(3oal cos is *f6n6n3 oal);

} $!ile (BF4);

gec!();

}

7T Program o coun !e no of posii#e and negai#e numbers enered in anarrayT7

/include< sdio! >#oid main( )&in aW0XncounQneg=0counQpos=0:;prinf(K4ner !e siJe of !e array6nL);scanf(KdL5n);

prinf(K4ner !e elemens of !e array6nL);for :=0;: < n;:++)scanf(KdL5aW:X);for(:=0;: < n;:++)&if(aW:X < 0)counQneg++;elsecounQpos++;}prinf(K!ere are d negai#e numbers in !e array6nLcounQneg);prinf(K!ere are d posii#e numbers in !e array6nLcounQpos);}

7T e%ample program o add $o marices 5 sore !e resuls in !e rdmari% T7#include< stdio.h >#include< conio.h >void main()


17/32

{int aK0LK0L'K0LK0L'cK0LK0L'i'M'm'n'p';clrscr();

printf(enter the order of the stmatri\n&);

scanf($d$d&'+m'+n);

printf(enter the order of the 1nd matri\n&);scanf($d$d&'+p'+);

if(m==p ++ n==){printf(matri can e added\n&);printf(enter the elements of the matri a&);for(i=0;i < m;i//)

{

for(M=0;M < n;M//)scanf($d&'+aKiLKML);

printf(enter the elements of the matri &);for(i=0;i < p;i//)

{

for(M=0;M < ;M//)scanf($d&'+KiLKML);

printf(the sum of the matri a and is&);for(i=0;i < m;i//)

{

for(M=0;M < n;M//)cKiLKML=aKiLKML/KiLKML;printf($d\t&'cKiLKML);

printf(\n&);

Program o prin sring in !e re#erse order

#include< stdio.h >#include< conio.h >void main()


18/32

{static char sKHL;Dnt i;clrscr();puts(*nter a trin!&);

!ets(s);

puts(Oeverse trin!J);

for(i=H;i>=0'i44)

printf($c&'sKiL);

Nrie a program o e#aluae !e follo$ing series

9=1Y+*Y+Y+ZZ

#include< stdio.h >#include< conio.h >#includevoid main(){static int srKHL;Dnt M.n.s=0;clrscr();prinf(K4ner !e #alue of n6nL);

scanf(KdL5n);for(i=0;i < n;i//)

srKiL=po3(i/'1);for(i=0;i < n;i//)

{

printf($d\t&'srKiL));

=s/srKiL;

prinf (3!e sum of sSuares is d 6n3 s);


19/32

Nrie a program o display !e elemens of * dimensional array

#include< stdio.h >#include< conio.h >

void main(){Dnt i'M;int aK%LK%L={{'1'%'{@'H'P'{7'Q'R;clrscr();prinf (34lemens of an array 6n6nL);

for(i=0;i < %;i//){ for(i=0;M < %;M//)

printf($Hd\t&'aKiLKML);

printf(\n&);

Bead !e mari% of order up o 10%10 elemens and display !e same in !emari% form


void main()

{

Dnt D'M'ro3'col'aK0LK0L;clrscr();prinf (34ner !e order of !e mari% upo 10%10 6n6nL);scanf(KddL5ro$5col);prinf (34ner !e order of !e mari% 6nL);for(i=0;i < ro3;i//)

for(i=0;i < col;i//)

scanf(KdL5aWiXW2X);

prinf (3Mari% is 6n6nL);

for(i=0;i < ro3;i//){for(i=0;i < col;i//)


20/32

printf($Pd\t&'aKiLKML);printf(\n&);

Bead !e mari% of order up o 10%10 elemens and ranspose is elemens


void main(){

Dnt i'M'ro3'ro31'col'col1'aK0LK0L'K0LK0L;clrscr();prinf (34ner !e order of !e mari% upo 10%10 6n6nL);

scanf(KddL5ro$15col1);prinf (34ner !e elemens of !e mari%6nL);for(i=0;i < ro3;i//)

{for(M=0;M < col;M//)scanf(KdL5aWiXW2X);

Bo$*=col1;

'lo*=ro$1;

for(i=0;i < ro3;i//){

for(M=0;M < col;M//)bW2XWiX=aWiXW2X);

prinf (3Mari% ranspose is 6n6nL);for(i=0;i < ro31;i//)

{for(M=0;M < col1;M//)prinf(KdLbWiXW2X);printf(\n&);


21/32

Program o perform addiion and subracion of $o marices $!ose order

are upo 10%10#include< stdio.h >#include< conio.h >

void main(){

Dnt i'M'ro3'col'aK0LK0L'K0LK0L;clrscr();prinf (34ner !e order of !e marices upo 10%10 6n6nL);scanf(KddL5ro$15col1);

prinf (34ner !e elemens of !e mari% E66n6nL);

for(i=0;i < ro3;i//){

for(M=0;M < col;M//)scanf(KdL5aWiXW2X);

prinf (34ner !e elemens of !e mari% O66n6nL);

for(i=0;i < ro3;i//){

for(M=0;M < col;M//)scanf(KdL5bWiXW2X);

prinf (3Mari% Eddiion 6n6nL);

for(i=0;i < ro3;i//){

for(M=0;M < col;M//)printf($Pd\t&'aKiLKML/KiLKML);printf(\n&);

prinf (3Mari% 9ubracion 6n6nL);


22/32

for(i=0;i < ro3;i//){

for(M=0;M < col;M//)printf($Pd\t&'aKiLKML4KiLKML);printf(\n&);

Betch();

Program o perform muliplicaion of $o marices $!ose order are upo10%10


void main(){Dnt i'M'ro3'col'aK0LK0L'K0LK0L;clrscr();prinf (34ner !e order of !e marices upo 10%10 6n6nL);scanf(KddL5ro$15col1);prinf (34ner !e elemens of !e mari% E66n6nL);

for(i=0;i < ro3;i//){

for(M=0;M < col;M//)scanf(KdL5aWiXW2X);

prinf (34ner !e elemens of !e mari% O66n6nL);

for(i=0;i < ro3;i//){

for(M=0;M < col;M//)scanf(KdL5bWiXW2X);

prinf (3Mari% Muliplicaion 6n6nL);

for(i=0;i < ro3;i//)


23/32

{for(M=0;M < col;M//)printf($Pd\t&'aKiLKMLSKiLKML);printf(\n&);

}

gec!();

}

'ompue facorial of any number using do $!ile loop and also $!ile loop

#include< stdio.h >#include< conio.h >void main(){

int a'fact=clrscr();


scanf("$d"'+a);

do {

printf($dS&'a);

fact=factSa;

a44;

} $!ile(a>=1);

printf(\t=$d&'fact);

printf(" \nAactorial of the Numer is $d\n"'fact);

}

,r



24/32

void main(){

int a'fact=clrscr();


scanf("$d"'+a);

$!ile(a>=1)

{

printf($dS&'a);

fact=factSa;

a44;

}

printf(\t=$d&'fact);

printf(" \nAactorial of the Numer is $d\n"'fact);

}

Nrie a c program o e#aluae !e follo$ing series Essume suiable #aluesfor %

=1+%*7*[+%7[+%7[+ZZupo 10 erms

/include/include/include#oid main()&in in%;

floa s;clrscr();prinf(3ener !e #alue of "n 6n3);scanf(3dd35%5n);=1;s=1;for (i=1;i


25/32

=((po$(%*)T(Ti))7((*Ti)T((*Ti-1)Ti));s=s+;prinf(3s=f 5 =*f6n3s);}prinf(36n sum of !e series=f6n3s);

gec!();}

7T'program o add subrac and muliply $o comple% numbers

in main (#oid)&

in aQrealaQimaginary2;in bQrealbQimaginary;in comple%Qnumber;

c!ar enerQoperaor;prinf (3a real = 3);scanf (3d35aQreal);

prinf (3a imaginary = 3);scanf (3d35aQimaginary);

prinf (3b real = 3);scanf (3d35bQreal);prinf (3b imaginary = 3);scanf (3d35bQimaginary);prinf (34ner operaor = 3);scanf (3c35enerQoperaor);if (enerQoperaor == V+V)

comple%Qnumber = (aQreal+bQreal)+2(aQimaginary+bQimaginary);

prinf (36ncomple% number is d6n3comple%Qnumber);else if (enerQoperaor == V-V);comple%Qnumber = (aQreal-bQreal)+2(aQimaginary-bQimaginary);prinf (36ncomple% number is d6n3comple%Qnumber);

else if (enerQoperaor == V7V);comple%Qnumber = ((aQrealTbQreal+aQimaginaryTbQimaginary)7(bQrealTbQreal)+(bQimaginaryTbQimaginary))+2((aQimaginaryTbQreal-


26/32

aQrealTbQimaginary)7(bQrealTbQreal+bQimaginaryTbQimaginary));prinf (36ncomple% number is d6n3comple%Qnumber);

else if (enerQoperaor == VTV);comple%Qnumber = ((aQrealTbQreal)-(aQimaginaryTbQimaginary))

+2((aQrealTbQimaginary)+(aQrealTbQreal));prinf (36ncomple% number is d6n3comple%Qnumber);reurn 0;}

!is program is o c!ec" a gi#en number is prime or no#include< stdio.h >#include< conio.h >

#oid main()&int i'=1;clrscr();

printf("\n*N8*O CNI N2TE*O"); scanf("$d"'+i);do{ if(i$==0)

&

printf(" \n Numer $d is not prime \n"'i);

!etch();

eit(0);

}

U//;

3hile (


27/32

Program o prin !e enered number in re#erse order


void main(){int n'd'=;int i;

clrscr();

printf(" \n*nter the Numer of di!its\n");

scanf("$d"'+d);

printf(" \n*nter the Numer to e reversed \n");

scanf("$d"'+n);

printf(" \nOeversed Numer is \n");

3hile (#include< conio.h >void main(){


28/32

int '=@0;clrscr();

printf(" \n*nter the decimal Numer \n");

scanf("$d"'+);printf(" \nEinar Numer \n");

3hile (V=0)

{

Boto(44'%); Einar its correspondin! to the decimal numers 3hich areotained are ta-en in the reverse order usin! !oto() function 'first ar!umentprovides the column position and the second provides the ro3 numer 3hereoutput is to e displaed.

printf(\t$d&'$1);

=1;

}

}

'on#er binary number o decimal number

#include< stdio.h >

#include< conio.h >#includeint a''WK0L'i;clrscr();

void main(){printf(" \n*nter the Numer of its \n");

scanf("$d"'+);

printf(" \n*nter the inar its \n");

scanf("$d"'+WKiL);

a=JW0X;

for (i=0;i


29/32

a=aS1/WKi/L;printf(\n$d&'a);

}

printf(" \n decimal Numer is$d\n"'a);

!etche();


=%-%7[+%7[-%?7?[+ZZ%n7n[

/include/include/include#oid main()&in in%c=f=1l;floa sum;clrscr();prinf(3ener !e #alue of %5n 6n3);scanf(3dd35%5n);sum=%

for (i=;i


30/32

'++

}

prinf(36n sum of !e series=f6n3sum);gec!();}


=%+%*7*[+%7[+%7[+ZZ%n7n[

/include/include/include#oid main()&in f=1li%y;floa sum;clrscr();prinf(3ener !e #alue of %5y 6n3);

scanf(3dd35%5y);sum=%for (i=*;i


31/32

MEB:U MFC:PC:'E:,8

/include

/include

#oid main()

&

in aW*XW*XbW*XW*XcW*XW*Xi2";

clrscr();

prinf(36n6n ener !e elemen of firs mari%6n6n3);

for(i=0;i


32/32

for(i=0;i

c lab programs 3

Documents