Name : _________________________________________ Form : ________________Stat_01

November 2003

1. The data below shows the donations, in RM, of 40 families to their children’s school welfare fund.

40 24 17 30 22 26 35 1923 28 33 33 39 34 39 2827 35 45 21 38 22 27 3530 34 31 37 40 32 14 2820 32 29 26 32 22 38 44

(a) Using the data above and a class interval of RM5, complete the following table.

Donation (RM) Upper boundary Frequency Cumulative Frequency

11 – 15

16 – 20

(b) For this part of question, use a graph paper.By using a scale of 2 cm to RM5 on the x-axis and 2 cm to 5 families on the y-axis,draw an ogive based on the data.

(c) From your ogive in (b),

(i) find the third quartile, [34.75] [ Q1 = 25.5 median =30.5 Q3 = 35.0 based on ogive ]

(ii) hence, explain briefly the meaning of the third quartile.

[they are 10 families who donate more then RM34.75]

(d) Using the data above and a class interval of RM 5, complete the following table.Class Interval Frequency Midpoint

6 – 10 9 811 – 1516 – 20

(e) (i) estimate the mean of the distribution [ estimated mean = 1200/40 = 30 ]

(ii) By using a scale of 2 cm to RM5 on the x-axis and 2 cm to 1 family on the y-axis, draw a histogram and a frequency polygon based on the (d)

1. mean =1200/40=30 2(a) Q1 = 20.5 +(6/6)5 =25.50 2(b) median =25.5 +(10/10)5=30.502(c) Q3 = 30.5 + (10/11)5 =35.05 3(a) 2 = 48.50 3(b) = Var = 6.964

4. estimated mode from the histogram =31.50.

1

July 2004

2. The data in Diagram 2 shows the number of durian trees planted by 44 farmers.

Diagram 2(a) (i) Based on the data in Diagram 2 and by using a class interval of 10, complete Table 2 provided in the answer space.

(ii) Hence, state the modal class. [modal class = 51 – 60]

Answer : Class Interval Upper Boundary Frequency Cumulative

Frequency11 – 20 20.5 0 021 – 30

(b) For this part of the question, use a graph paper..

By using a scale of 2 cm to 10 trees on the x-axis and 2 cm to 5 farmers on the y-axis, draw an ogive for the data. [ Q1 = 44.5 median = 55.5 Q3 = 62.5 based on ogive ]

(c) Based on the ogive in (b), Ahmad concludes that 50% of the farmers planted less than 52 durian trees. Determine whether the conclusion is correct or not and give a reason.

[From the ogive the median = 54.5 , thus the conclusion 50 % planted less than 52 tree is incorrect]

(d) Using the data above and a class interval of RM5, complete the following table.Class Interval Frequency Midpoint

11 – 2021 – 30

(e) (i) estimate the mean of the distribution [ estimated mean = 2432/44=53.23]

(ii) By using a scale of 2 cm to 10 trees on the x-axis and 2 cm to 1 farmer on the y-axis, draw a histogram and a frequency polygon based on the (d)

1. mean = 2342/44=53.23 2(a) Q1 = 40.5 +(3/8)10 =44.25 2(b) median =50.5+(6/15)10=54.502(c) Q3 = 60.5 + (2/10)10 =62.50 3(a) 2 = 48.50 3(b) = Var = 6.964

52 33 48 22 34 42 57 51 51 65 4166 54 66 53 53 34 46 52 65 75 5225 68 48 63 62 43 52 56 59 49 5843 58 36 72 68 54 62 40 73 38 63

2

Table 2

4. estimated mode from the histogram =56.33.

Name : _________________________________________ Form : ________________Stat_02 November 2004

3. The data below shows the masses, in kg, of suitcases for a group of tourists. Each tourist has one suitcase.

27 10 22 28 21 14 29 2529 18 22 13 20 21 24 2727 25 16 19 16 24 26 2729 19 33 25 23 24 26 31

(a) Based on the data above and by using a class interval of 3, complete the table below.

Class Interval Frequency Midpoint10 – 1213 – 15

(b) Based on the table in (a), calculate the estimated mean mass of the suitcases. [742/32=23.19]

(c) For this part of the question, use a graph paper.

By using a scale of 2 cm to 3 kg on the x-axis and 2 cm to 1 suitcase on the y-axis, draw the histogram for the data.

(d) State one information obtained based on the histogram in (c).[The maximum frequency is 9 for 25 – 27 kg suitcase]

(e) (i) Complete the table below based on data above.

Class Interval Upper Boundary Frequency Cumulative Frequency

7 – 9 9.5 0 010 – 1213 – 15

(ii) By using a scale of 2 cm to 3 kg on the x-axis and 2 cm to 5 suitcases on the y-axis, draw the ogive for the data. Find the number of suitcases which is heavier than 26.0 kg.

1. mean = 742/32 =23.19 2(a)Q1= 19.70 2(b)media = 24.00 2(c)Q3=26.833(a)2= 26.40 (26.29) 3(b) =5.138 (5.127)4. [estimated mode = 25.63 base on histogram

3

Name : _________________________________________ Form : ________________Stat_03 December 2005

4. The data in Diagram shows the marks for an English Language monthly test for 42 pupils.

(a) Using data in diagram and a class interval of 5 marks, complete Table in the answer space.

Marks Midpoint Frequency20 – 24 2225 – 29

(b) Based on your table in (a),(i) state the modal class, [modal class = 35 – 39]

(ii) calculate the mean mark for the English Language monthly test and give your answer correct to 2 decimal places. [estimated mean =1469/42 = 34.98 ]

(c) For this part of the question, use the graph paper provided . By using a scale of 2cm to 5 marks on the horizontal axis and 2 cm to 1 pupil on the vertical axis, draw a histogram for the data. Construct also the frequency polygon on the histogram.

(d) (i) Complete the table below

Marks Upper Boundary Frequency Cumulative Frequency

20 – 2425 – 29

(ii) By using a scale of 2 cm to 5 marks on the horizontal axis and 2 cm to 5 pupils on the vertical axis, draw a ogive for the data. If 12 % of the candidate will be awarded with distinction, find the minimum marks to qualify for distinction.

1. mean =1469/42 =34.98 2(a) Q1 = 28.43 2(b)median= 35.002 (c)Q3 =40.75 3(a)2 = 67.93 (67.66) 3(b) = 8.243 (8.226)

4.estimated mode = 36.17 base on histogram

51 20 45 31 26 40 30 25 32 37 41 21 36 38 46 38 28 37 39 23 39 33 35 42 29 38 31 23 42 34 26 35 43 28 22 25 47 31 48 44 34 54

4

July 2006

5. Table 6a shows the distribution of age for a group of 40 tourists who visited a museum in a particular day.

Age(Year) 20 – 24 25 – 29 30 – 34 35 – 39 40 – 44 45 – 49 50 – 54Frequency 2 6 9 10 7 4 2

Table 6a(a) Based on the distribution of age in Table 6a, complete Table 6b in the answer space.

Answer:

Age (Year) frequency Upper Boundary Cumulative Frequency20 – 2425 – 2930 – 3435 – 3940 – 4445 – 4950 - 54

Table 6b

(b) Calculate the estimated mean age of the tourists. [mean = 1450/40 =36.25 ]

(c) For this part of the question, use the graph paper .

By using the scale of 2 cm to 5 years on the horizontal axis and 2 cm to 5 tourists on the vertical axis, draw an ogive for the data in table 3.

(d) From your ogive constructed in (c),(i) find the first quartile, [30.5]

Q1 = 31.0 median = 36.0 Q3 = 41.0 based on ogive drawn ]

(ii) state one piece of information about the first quartile[10 tourists has age less than 30.5 years old]

(e) For this part of the question, use the graph paper . By using a scale of 2cm to 5 years on the horizontal axis and 2 cm to 1 tourist on the vertical axis, draw a histogram for the data. Construct also the frequency polygon on the histogram.

Age Midpoint Frequency

20 – 2425 – 29

(f) estimate the age of the tourists. [ estimated mean = 1450/40 =36.25 ]

1. mean = 1450/40 =36.25 2(a) Q1 = 30.61 2(b)median = 36.002(c)Q3 =41.64 3(a)2 = 56.94 (56.94) 3(b) =7.546 (7.546)

4. Estimated mode based on histogram = 35.75

5

Name : _________________________________________ Form : ________________Stat_04 November 2006

6. The data in Diagram 7 show the donations, in RM, collected by 40 pupils.

49 26 38 39 41 45 45 43

22 30 33 39 45 43 39 31

27 24 32 40 43 40 38 35

34 34 25 34 46 23 35 37

40 37 48 25 47 30 29 28 Diagram 7

(a) Based on the data in Diagram 7 and by using a class interval of 5, complete Table 7 in the answer space.

Answer:

Class Interval Midpoint Frequency21 – 2526 – 30

Table 7

(b) Based on Table 7 in (a), calculate the estimated mean of the donation collected by a pupil [mean = 1420/40 = 35.50]

(c) For this part of the question, use the graph paper provided.By using a scale of 2 cm to RM5 on the horizontal axis and 2 cm to 1 pupil on the vertical axis, draw a frequency polygon for the data.

(d) Based on the frequency polygon in (c), state one piece of information about the donations.

[11 donations is less than RM31]

(e) Based on the collection of donation in diagram (a), complete Table below in the answer space. Answer:

Age (Year) Upper Boundary frequency Cumulative Frequency

21 – 2526 – 30

(i) By using a scale of 2 cm to RM5 on the horizontal axis and 2 cm to 5 pupils on the vertical axis, draw a ogive for the data. (ii) determine the inter quartile range.

1. mean =1420/40 =35.50 2(a) Q1=29.67 2(b)median = 36.002(c)Q3 = 41.21 3(a) 2= 56.25 (56.25) 3(b)= 7.500 (7.500)

4. Estimated mode based on histogram = 37.50

6

July 2006

7. Diagram 8 shows the mass, in kg, of newspapers collected over the period of 40 days.

79 70 75 79 83 74 66 58

65 85 84 76 56 80 64 57

78 67 52 59 72 58 57 75

69 76 55 75 60 73 83 63

74 65 78 58 73 64 75 59Diagram 8

(a) Based on the data in Diagram 8, complete Table 8 in the answer space.(b) Hence, calculate the estimated mean of the mass of the newspapers collected. [mean=2770/40 =69.25]

(c) For the part of the question, use a graph paper and by using the scale of 2 cm to 5 kg on the horizontal axis to 1 day on the vertical axis, draw a histogram for the data.

(d) Based on your histogram in 8(c) , give one information about the modal class of the data.[ the modal class is 72 – 76 and has 11 days that have the collection of newspaper range between 72 and 76 kg]

(a) Mass (kg) Frequency Midpoint 52 – 56 57 – 61

Table 8

(e) Based on the masses of the newspaper collected in diagram a, complete Table below in the answer space. Answer:

Mass (kg) Upper Boundary Frequency Cumulative Frequency

52 – 56 57 – 61

(e) (i) For the part of the question, use a graph paper and by using the scale of 2 cm to 5 kg on the horizontal axis and 2 cm to 5 pupils on the vertical axis, draw an ogive for the data.

(ii) Based on the ogive drawn estimated the percentage of student whom collected more than 68.0 kg.

1. mean =2770/40 =69.25 2(a) Q1=60.88 2(b)median = 71.50 2(c)Q3 =76.04 3(a)2 =82.44 3(b) = 9.080

4. estimated mode based on histogram = 74.36

7

Name : _________________________________________ Form : ________________Stat_05 SPM 2007

8. Table 9a shows the frequency distribution of the mass, in kg, of a group of 80 students.

Mass ( kg) Frequency30 - 34 535 - 39 840 - 44 1145 - 49 2150 - 54 2255 - 59 1060 - 64 3

Table 9a(a) (i) State a modal class. [50-54]

(ii) Calculate the estimated mean of the mass of the group of students. [mean = 3805/80=47.56]

(b) Based on table 9a, complete Table 9b in the answer space to show the cumulative frequency distribution of the masses.

Upper Boundary Cumulative frequency29.5 034.5

Table 9b

(c) For this part of the question, use the graph paper provided . By using the scale of 2 cm to 5 kg on the horizontal axis and 2 cm to 10 students on the vertical axis, draw an ogive for the data.

[ Q1 = 43.0 Mean = 48.5 Q3 = 52.5 ]

(d) 25% of all the students in the group have a mass of less than p kg. These students will be supplied with nutritional food.

Using the ogive you had drawn in 16(c), find the value of p. [p = 42.7]

(f) (e) Based on data in 9(a) , complete the table below (i) Mass (kg) Frequency Midpoint

30 – 3435 – 39

1. mean = 3805/80 = 47.56 2(a) Q1=42.68 2(b)median = 48.312(c)Q3 = 52.91 3(a)2=55.24 (54.996) 3(b)= 7.432 (7.416)

4. estimated mode from histogram = 49.88

8

9. July 2008

Data in Diagram 10 shows the number of books read by 40 students in a reading programme in a particular class.

(a) Based on the data in Diagram 10 and by using a class interval of 3, complete Table 10 in the answer space. (b) Based on Table 10 in 10 (a), calculate the estimated mean of the books read by a student. [576/40=14.4] (c) For this part of the question, use a graph paper . By using the scale of 2 cm to 3 books on the horizontal axis and 2 cm to one student on the vertical axis,

draw the frequency polygon for this data.

(d) Based on the frequency polygon 14(c), give one information about this reading programme. [ The majority 27 of the students read between 11 – 19 ]Answer (a)

Class interval Frequency Midpoint

5 – 7

8 – 10

(e)(i) Complete the table below base on data in diagram 10Number of books Upper Boundary Frequency Cumulative Frequency

5 – 78 – 10

(ii) By using the scale of 2 cm to 3 books on the horizontal axis and 2 cm to 10 students on the vertical axis, draw the ogive for this data. (iii) If a silver medal is going to award to an student who reads between 15 to 20 books, use your ogive to estimate the number of student who will be awarded with silver medal.

9

18 14 11 16 13 17 12 23

12 19 17 15 11 21 7 14

15 11 5 18 9 22 24 19

17 9 14 12 6 15 10 13

19 15 20 10 14 8 12 16

Diagram 10

Table 10

1. mean = 3805/80 = 47.56 2(a) Q1=11.17 2(b)median = 14.402(c)Q3 = 17.63 3(a)2=20.79 3(b)= 4.5604. [ estimated mode = 11.5 based on histogram drawn ]

10

Name : _________________________________________ Form : ________________Stat_06 SPM 200810. The data below shows the payment, in RM, by 40 drivers at a toll booth. Data di bawah menunjukkan bayaran, dalam RM, oleh 40 pemandu di sebuah pondok tol.

38 34 41 25 19 32 28 42

32 25 32 27 42 23 18 46

21 42 36 30 33 37 43 25

24 18 26 35 47 22 38 33

30 23 37 48 39 34 41 27

Table 11(a) Based on the data, complete Table 11 in the answer space. Berdasarkan data itu, lengkapkan Jadual 11 di ruang jawapan.

Class intervalSelang kelas

MidpointTitik tengah

FrequencyKekerapan

15-19 17

Table 11 / Jadual 11

(b) Based on Table 11 in 11 (a), calculate the estimated mean of the toll paid by a driver. [1290/40=32.25] Berdasarkan Jadual 11 di 11 (a), hitung min anggaran bayaran tol bagi seorang pemandu.

(c) By using the scale of 2 cm to RM5 on the horizontal axis and 2 cm to 1 driver on the vertical axis, draw a frequency polygon for the data. Dengan menggunakan skala 2 cm kepada RM5pada paksi mengufuk dan 2 cm kepada 1 pemandu pada paksi mencancang, melukis satu polygon kekerapan bagi data tersebut.(d) Based on the frequency polygon in 11 (c), state the number of drivers who paid more than RM34 for the toll. [16 ]

Berdasarkan polygon kekerapan di 11 (c), nyatakan bilangan pemandu yang telah membuat bayaran tol lebih daripada RM34.(e) (i) complete the table below

Upper Boundary Cumulative frequency14.5 019.5

(ii) By using the scale of 2cm to RM5 on the horizontal axis and 2 cm to 5 driver on the vertical axis, draw a ogive for the data. (iii) find the number of driver who paid less than RM 28.

1. mean = 1290/40 = 32.25 2(a) Q1=25.93 2(b)median = 32.282(c)Q3 = 38.79 3(a)2=69.94 3(b)= 8.363

4. estimated mode = 32.00 based on histogram ]

11

June 200911. Table 12.1 shows the frequency distribution of marks obtained by a group of 48 students in a test. Jadual 12.1 menunjukkan taburan kekerapan markah yang diperolehi sekumpulan 48 orang murid dalam satu ujian.

Marks Frequency

65 – 69 2

70 – 74 6

75 – 79 8

80 – 84 12

85 – 89 10

90 – 94 7

95 – 99 3

Table 12.1

(a) Based on Table 12.1 ,complete Table 12.2 in the answer space . [1 mark] Berdasarkan Jadual 12.1 lengkapkan Jadual 12.2 di ruang jawapan..

(b) Calculate the estimated mean mark of the group of the students. [3971/48 = 82.73] Hitungkan min anggaran markah bagi kumpulan murid itu.

(c) Using the scale of 2 cm to 5 marks on the horizontal axis and 2 cm to 5students on the vertical axis, draw an ogive for the data. Dengan menggunakan skala 2 cm kepada 5 markah pada paksi mengufuk dan 2 cm kepada 5 murid pada paksi mencanvang, lukiskan satu ogif bagi data tersebut.

[4 marks]Q1 = 77.5 Median = 82.5 Q3 = 87.75 based on Ogive drawn

(d) Using the ogive drawn in 14(c) menggunakan ogif yang dilukis di 14 (c)(i) find the third quartile [88.5]

cari kuartil ketiga ,(ii) state one information regarding the third quartile . nyatakan satu maklumat tentang kuartil atas

[ they are 12 students obtained marks more than 88.5 ]

Answer

Number of books Upper Boundary Frequency Cumulative Frequency

65 – 6970 – 74

Table 12.2

1. mean = 3971/48 = 82.73 2(a) Q1=77.00 2(b)median = 82.832(c)Q3 = 88.50 3(a)2= 59.36 3(b) = 7.7054. estimated mode from histogram = 82.83

12

Name : _________________________________________ Form : ________________Stat_07 SPM 2009

12. A group of 30 students are attending a motivation camp. The data in Diagram 13 shows the distance, in km,

between their house and the camp.

Sekumpulan 30 orang murid sedang menghadiri kem motivasi. Data di Rajah 13 menunjukkan jarak, dalam

km, antara rumah mereka dengan kem itu.

81 21 90 67 34 60

41 55 59 51 65 61

54 68 49 71 74 37

62 46 63 45 71 85

41 76 74 58 66 61

Diagram 13 / Rajah 13

(a) Based on the data in Diagram 13, complete Table 13.2 in the answer space.

Berdasarkan data di Rajah 13, lengkapkan Jadual 13.2 di ruang jawapan.

Distance (km)

Jarak (km)

Frequency

Kekerapan

Midpoint

Titik tengah

21 – 30

31 – 40

41 – 50

51 – 60

61 – 70

71 – 80

81 – 90

Table 13.2 / Jadual 13.2

(b) State the size of the class interval used in Table 13. [ 10 ]

Nyatakan saiz selang kelas yang digunakan dalam jadual 13.

(c) Based on Table 13, calculate the estimated mean of the distance between the students’ houses and the camp.

Berdasarkan Jadual 13, hitung min anggaran jarak antara rumah murid-murid itu dengan kem tersebut.

(d) For this part of the question, use the graph paper provided on page 29.

Untuk ceraian soalan ini, guna kertas graf yang disediakan pada halaman 29.

By using the scale of 2cm to 10 km on the horizontal axis and 2 cm to 1 student on the vertical axis, draw a

histogram for the data.

Dengan menggunakan skala 2 cm kepada 10 km pada paksi mengufuk dan 2 cm kepada 1 murid pada paksi

mencancang, melukis satu histogram bagi data tersebut.

(e) State one information based on the histogram in 13(d). [ The modal class is 61- 70 ]

Nyatakan satu maklumat berdasarkan histogram di 13 (d).

[ Q1 = 25.5 median =30.5 Q3 = 35.0 based on ogive ]

1. mean = 1815/30 = 60.5 2(a) Q1=49.5 2(b)median = 61.752(c)Q3 = 71.50 3(a)2= 231.67 3(b) = 15.22

ADD_maths [ estimated Q1 = 49.5 Median = 61.75 Q3 = 71.50 ] estimated mode = 62.50 based on histogram

13

June 201013. Diagram 14 shows the number of tickets sold by a group of 32 students in a fund raising project.

Rajah 14 menunjukkan bilangan tiket yang telah dijual oleh sekumpulan 32 orang murid dalam suatu projek mengumpul dana.

51 45 73 56 98 65 42 75

62 53 80 78 58 76 55 84

76 48 65 54 60 89 71 36

84 34 71 85 70 68 75 79

Diagram 14/ Rajah 14

(a) Based on the data in Diagram 14, complete Table 14 in the answer space. Berdasarkan data di Rajah 14, lengkapkan Jadual 14 di ruang jawapan. [4 marks] (b) Calculate the estimated mean for the number of tickets sold by the group of students.

Hitungkan min anggaran bagi bilangan tiket yang telah dijual oleh kumpulan murid itu. [ 53.94 ] [3 marks]

(c) For this part of the question, use the graph paper provided on page 19.Untuk ceraian soalan ini, gunakan kertas graf yang disediakan di halaman 19.

By using the scale of 2 cm to 10 tickets on the horizontal axis and 2 cm to 1student on the vertical axis, draw a frequency polygon for the data. Dengan menggunakan skala 2 cm kepada 10 tiket pada paksi mengufuk dan 2 cm kepada 1 murid pada paksi mencancang, lukiskan satu poligon kekerapan bagi data tersebut.

[4 marks]

(d) State one information about the sale of tickets based on the frequency polygon in 14(c).Nyatakan satu maklumat tentang jualan tiket itu berdasarkan poligon kekerapan di 14(c).

[ the frequency of class 51-60 is the same as 61 – 70 ] [1 mark]

Answer :(a)

Class intervalSelang kelas

FrequencyKekerapan

MidpointTitik tengah

21 – 30 0 25.5

31 – 40

101 – 110 0 105.5

Table 14

1. mean = 2116/32 = 66.13 2(a) Q1=54.79 2(b)median = 68.502(c)Q3 = 77.50 3(a)2=224.61 3(b)= 14.99 4. estimated mode based on histogram = 65.05

14

Name : _________________________________________ Form : ________________Stat_08 SPM 2010

14 Table shows the frequency distribution of the ages of 88 workers in a factory. Jadual menunjukkan taburan kekerapan umur bagi 88 orang pekerja di sebuah kilang

Age(years)Umur (Tahun)

FrequencyKekerapan

26 – 30 331 – 35 936 – 40 2741 – 45 3146 – 50 1151 – 55 556 - 60 2

a) Calculate the estimated mean of the ages of a worker. Hitung min anggaran umur bagi seorang pekerja itu. [ mean = 3649/88 = 41.47 ]b) Based on table above, complete answer table by writing down the values of the upper boundary and the cumulative frequency. Berdasarkan Jadual atas , lengkapkan Jadual Jawapan dengan menulis nilai=nilai sempadan atas dan kekerapan longgokan.c)For this part of the question , use the graph paper. You may use a flexible curve rule. By using a scale of 2 cm to 5 years on the horizontal axis and 2 cm to 10 workers on the vertical axis , draw an ogive for the data. Untuk ceraian soalan ini, gunakan kertas graf. Anda boleh menggunakan pembaris fleksibel. Dengan menggunakan skala 2 cm kepada 5 tahun pada paksi mengufuk dan 2 cm kepada 10 pekerja pada paksi mencancang , lukis satu ogif bagi data tersebut.d)The factory plans to organize a motivational camp for the workers whose age are above 47 years old. Using the ogive in 15c) , find the number of workers who will attend the motivational camp. Kilang itu bercadang untuk menganjurkan satu kem motivasi kepada pekerja-pekerja yang berumur lebih daripada 47 tahun. [ 88 – 74 = 14 ] Menggunakan ogif di 15c) , cari bilangan pekerja yang akan menghadiri kem motivasi tersebut.a)b)

Upper boundarySempadan atas

Cumulative FrequencyKekerapan Longgokan

25. 5 030. 5

60.5 88

c)Refer graph/Rujuk graf d)

1. mean = 3649/88 = 41.47 2(a) Q1=37.35 2(b)median = 41.312(c)Q3 = 44.85 3(a)2=37.14 3(b)= 6.0944. estimated mode based on histogram = 41.33

15

SPM 2011

15. Diagram 16 shows the number of boks read by a group of 24 students in a reading programme in the year 2009. Rajah 16 menunjukkan bilangan buku yang dibaca oleh sekumpulan 24 orang murid dalam satu program membaca

pada tahun 2009

35 41 50 26 27 2722 31 33 40 45 2324 35 30 38 39 3644 34 28 29 30 35

Diagram 16/ Rajah 16

(a) based on data in diagram 16, complete table 16 in the answer space.Berasaskan data dirajah 16, lengkapkan jadual 16 dalam ruang jawapan

(b) State the modal class. Nyatakan kelas mod. [ [ 27 – 31 ] (c) Calculate the estimated mean for the number of book read by a student. Hitung min anggaran bagi bilangan buku yang dibaca oleh seorang murid. [ 796/24 = 33.17 ] (d) By using a scale of 2 cm to 5 books on the horizontal axis and 2 cm to 1 student on the vertical axis , draw a histogram for the data. Dengan menggunakan skala 2 cm kepada 5 buah buku pada pada mengufuk dan 2cm kepada 1 murid pada paksi mencancang , lukis atu histogram bagi data tersebut. (e) based on histogram drawn in 14(d) , state the number of students who read less than 32 books in that programme. Berasaskan histogram yang dilukis pada 16(d), nyatakan bilangan murid yang membaca kurang daripada 32 buah buku dalam program tersebut.

Class interval/Selang kelas Frequency/ Kekerapan Midpoint/Titik tengah22 – 2627 – 31

47 – 51 Table/Jadual 16

1. mean = 796/24 = 33.17 2(a) Q1=27.93 2(b)median = 32.332(c)Q3 = 37.75 3(a)2=4.514 3(b)= 6.7194. estimated mode based on histogram = 30.25

16

17