Practice Quiz 3Hurley 4.3 – 4.6

For the quiz …I will provide you with a categorical proposition,

like…No apples sold in Minnesota are mushy weapons

I’ll ask you for its quality qualifier quantity quantifier copula distribution letter name terms

1

Consider:No non-A are B (T) Obversiona.Some non-A are B. (F)b.All A are non-B. (Und.)c.All non-A are non-B. (T)d.Some non-A are not B. (T)e.No B are non-A. (T)

2

Consider:All A are non-B. (F) Contrapositiona.All A are non-B. (F)b.All non-B are A. (Und.)c.No non-A are B. (Und.)d.All B are non-A. (F)e.Some non-A are not B. (T)

3

Consider:Some A are not non-B. (T) Some A are B.a.Contraposition (T)b.Contrary (F)c.Conversion (T)d.Obversion (T)e.Subcontrary (Und.)

4

Consider:Some non-A are B. (F) Some B are non-A.a.Subcontrary (T)b.Conversion (Und.)c.Contraposition (Und.)d.Conversion (F)e.Contraposition (F)

5Assume Aristotle (Traditional standpoint).Consider:Some A are non-B. (F) Some A are not non-

B. (F)a. Illicit, contraryb. Illicit, subalternationc. Subcontraryd. Illicit, subcontrarye.Contraposition

6No S are P. (Aristotelian standpoint)

After filling in the diagram …a.Area 2 is shaded, and there is a circled X in area 1.b.Areas 1 and 3 are shaded.c.Area 1 is shaded, and there is a circled X in area 2.d.There is an X in area 2.e.Area 1 is shaded, and there are no other marks.

7All S are P. (Boolean standpoint)

After filling in the diagram …a.Areas 1 and 3 are shaded.b.Area 2 is shaded, and there are no other marks.c.Area 1 is shaded, and there is a circled X in area 2.d.There is an X in area 2.e.Area 1 is shaded, and there are no other marks.

8Shade area 2 and place an X in area 1.

Which of the following would be valid inferences:a.shaded area 2.b.an X in area 3.c.an X in area 1.d.shaded 1.e.no X’s or shadings.

9Shade area 1 and place an X in area 2.

Which of the following would be valid inferences:a.shaded area 2.b.an X in area 3.c.shaded area 1, and X in area 2.d.shaded 1.e.no X’s or shadings.

10Assume Aristotle (Traditional standpoint).Consider:No non-A are B. (T) Some non-A are not B.

(F)a. Illicit, subalternationb. Illicit, contradictoryc. Contradictoryd. Illicit, subcontrarye.Conversion

11

Assume Boole (Modern standpoint).Consider:No A are B. (T) Some A are B. (F)a.Existential fallacyb.Illicit, contradictoryc. Contradictoryd.Illicit, subcontrarye.Conversion

12

Assume Boole (Modern standpoint).Consider:No A are B. (T) All A are B. (F)a.Existential fallacyb.Illicit, contraryc. Contradictoryd.Illicit, subcontrarye.Conversion

13

Assume Aristotle (Traditional standpoint)All square circles are happy shapes.

Some square circles are happy shapes.a.Existential fallacyb.Valid, contradictoryc. Valid, subcontraryd.Invalid, subalternatione. Invalid, contrary

Conditional ValidityRemember, if asked to test for conditional

validity, assume Aristotelian standpoint (put a circled X in any unshaded area of the subject circle of a universal proposition).

Test for validity.If valid, check to see whether the subject matter

of the proposition exists. If so,Conditionally Valid.If not,Existential Fallacy.

Example on next slide:

Conditionally Valid?No Moms are Tired Workers Some Moms are not Tired Workers

Conditionally Valid, orExistential Fallacy?

M T

X

M T

X

Answer Key …I will provide you with a categorical proposition, like…

No apples sold in Minnesota are mushy weapons

I’ll ask you for its quality (Negative) qualifier (‘No’) quantity (Universal) quantifier (‘No’) copula (‘are’) distribution (both Subject and Predicate) letter name (‘E’) terms (apples sold in Minnesota=subject term …

mushy weapons=predicate term)

Answer Key

1=C, 2=D, 3=D, 4=D, 5=D, 6=A, 7=E, 8=A and C, 9=C and D, 10=A, 11=C (valid inference), 12=A, 13=A

Final slide: Conditionally valid because ‘moms’ exist.