ms1 trig ratio

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Trigonometry 24 May 2022 Learning Objective: To be able to describe the sides of right-angled triangle for use in trigonometry. Trigonometry is concerned with the connection between the sides and angles in any right angled triangle. Angle

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Page 1: Ms1 trig ratio

Trigonometry13 April 2023

Learning Objective:

To be able to describe the sides of right-angled triangle for use in trigonometry.

Trigonometry is concerned with the connection between the sides and angles in any right angled triangle.

Angle

Page 2: Ms1 trig ratio

A

A

The sides of a right -angled triangle are given special names:

The hypotenuse, the opposite and the adjacent.

The hypotenuse is the longest side and is always opposite the right angle.

The opposite and adjacent sides refer to another angle, other than the 90o.

Page 3: Ms1 trig ratio

There are three formulae involved in trigonometry:

sin A=

cos A=

tan A =

S O H C A H T O A

Page 4: Ms1 trig ratio

Using trigonometry on the calculator

All individual angles have different sine, cosine and tangent ratios (or decimal values).

Scientific calculators store information about every angle.

We need to be able to access this information in the correct manner.

13 April 2023

Learning Objective:

To be able to use a scientific calculator to find decimal values and angles in trigonometry.

Page 5: Ms1 trig ratio

Finding the ratios

The simplest form of question is finding the decimal value of the ratio of a given angle.

Find:

1) sin 32 =

sin 32 =

2) cos 23 =

3) tan 78 =

4) tan 27 =

5) sin 68 =

Page 6: Ms1 trig ratio

Using ratios to find angles

We have just found that a scientific calculator holds the ratio information for sine (sin), cosine (cos) and tangent (tan) for all angles.

It can also be used in reverse, finding an angle from a ratio.

To do this we use the sin-1, cos-1 and tan-1 function keys.

Page 7: Ms1 trig ratio

Example:1. sin x = 0.1115 find angle x.

x = sin-1 (0.1115)x = 6.4o

2. cos x = 0.8988 find angle x

x = cos-1 (0.8988)x = 26o

sin-1 0.1115 =

shift sin( )

cos-1 0.8988 =

shift cos( )

Page 8: Ms1 trig ratio

Trigonometry13 April 2023

Learning Objective:

To be able to use trigonometry to find the unknown angle in a triangle.

Page 9: Ms1 trig ratio

Finding an angle from a triangle

To find a missing angle from a right-angled triangle we need to know two of the sides of the triangle.

We can then choose the appropriate ratio, sin, cos or tan and use the calculator to identify the angle from the decimal value of the ratio.

Find angle C

a) Identify/label the names of the sides.

b) Choose the ratio that contains BOTH of the letters.

14 cm

6 cmC

1.

Page 10: Ms1 trig ratio

C = cos-1 (0.4286)

C = 64.6o

14 cm

6 cmC

1.H

A

We have been given the adjacent and hypotenuse so we use COSINE:

Cos A = hypotenuseadjacent

Cos A = ha

Cos C =146

Cos C = 0.4286

Page 11: Ms1 trig ratio

Find angle x2.

8 cm

3 cmx

A

O

Given adj and oppneed to use tan:

Tan A = adjacentopposite

x = tan-1 (2.6667)

x = 69.4o

Tan A = ao

Tan x =38

Tan x = 2.6667

Page 12: Ms1 trig ratio

3.

12 cm10 cm

y

Given opp and hypneed to use sin:

Sin A = hypotenuseopposite

x = sin-1 (0.8333)

x = 56.4o

sin A = ho

sin x =1210

sin x = 0.8333

Page 13: Ms1 trig ratio

Trigonometry

13 April 2023

Learning Objective:

To be able to use trigonometry to find an unknown side in a triangle.

Page 14: Ms1 trig ratio

Finding a side from a triangle

To find a missing side from a right-angled triangle we need to know one angle and one other side.

Cos45 = 13x

To leave x on its own we need to move the ÷ 13.

It becomes a “times” when it moves.

Note: If

Cos45 x 13 = x

Page 15: Ms1 trig ratio

Cos 30 x 7 = k

6.1 cm = k

7 cm

k30o

1.

H

A

We have been given the adj and hyp so we use COSINE:

Cos A = hypotenuseadjacent

Cos A = ha

Cos 30 =7k

Page 16: Ms1 trig ratio

Tan 50 x 4 = r

4.8 cm = r

4 cm

r

50o

2.

A

O

Tan A = ao

Tan 50 = 4r

We have been given the opp and adj so we use TAN:

Tan A =

Page 17: Ms1 trig ratio

Sin 25 x 12 = k

5.1 cm = k

12 cm k

25o

3.

H

O

sin A = ho

sin 25 =12k

We have been given the opp and hyp so we use SINE:

Sin A =

Page 18: Ms1 trig ratio

Finding a side from a triangle

There are occasions when the unknown letter is on the bottom of the fraction after substituting.

Cos45 = u13

Move the u term to the other side.

It becomes a “times” when it moves.

Cos45 x u = 13

To leave u on its own, move the cos 45 to other side, it becomes a divide.

u = 45 Cos13

Page 19: Ms1 trig ratio

When the unknown letter is on the bottom of the fraction we can simply swap it with the trig (sin A, cos A, or tan A) value.

Cos45 = u13

u = 45 Cos13

Trigonometry

13 April 2023

Learning Objective:

To be able to use trigonometry to find an unknown side when the unknown letter is on the bottom of the fraction.

Page 20: Ms1 trig ratio

x =

x

5 cm30o

1.

H

A

Cos A = ha

Cos 30 = x5

30 cos5

m 8 cm

25o

2.

H

O m =

sin A = ho

sin 25 = m8

sin258

x = 5.8 cm

m = 18.9 cm

Page 21: Ms1 trig ratio

Trigonometry

13 April 2023

Learning Objective:

To be able to use trigonometry to find unknown sides and unknown angles in a triangle.

Page 22: Ms1 trig ratio

x =

x

5 cm30o

1.

H

A

Cos A =ha

Cos 30 =x5

30 cos5

x = 5.8 cm

4 cm

r

50o

2.

A

O

Tan 50 x 4 = r

4.8 cm = r

Tan A = ao

Tan 50 =4r

3.

12 cm10 cm

y

y = sin-1 (0.8333) y = 56.4o

sin A = ho

sin y =1210

sin y = 0.8333

Page 23: Ms1 trig ratio