building materials for construction
DESCRIPTION
Building Materials for constructionTRANSCRIPT
Building MaterialsBuilding MaterialsBuilding MaterialsBuilding Materials
Lecture 2Lecture 2
P ti f B ildiP ti f B ildiProperties of Building Properties of Building M t i lM t i lMaterialsMaterials
B i h i l tiBasic physical properties
= related to mass and volume of the t i lmaterial
• density (specific gravity, specific weight)• bulk densitybulk density• porosity
l t• granulometry• fineness
MassMassChoice of suitable scales:• capacity (max. range)p y ( g )• readability
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ScalesScalesMechanical , digitalec a ca , d g a• analytical (readability 10-4 g, capacity to
200g)200g)• milligram (0,01 g)• laboratory (0,1 - 0,2 g, 200 – 1000 g)• commercial (2 5 5 25 k )• commercial (2 - 5 g, 5 - 25 kg)• industrial (hundreds of kg)
SizeSize
Length measuring devices: calibrable
• Steel rule• Steel measuring tape• Calliper• Calliper• Micrometer• Sieves
VolumeVolumeSolids:Solids:• Count from sizes • Immersion in liquid
– graduated cylinderg y– pycnometre– hydrostatic scaleshydrostatic scales
Liquids:volumetric flask– volumetric flask
– pipetteb tt– burette
DensityBulk density Density(specific gravity)X
m =
V
[ kg.m-3 ]
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DensityBulk density Density(specific gravity)
m =
m =v =
Vh + Vp
= Vhp
m mass of material m mass of materialm… mass of materialVh… volume of solid
material
m… mass of material
Vh volume of solidmaterialVp… volume of voids
i i l
Vh… volume of solid material
pin material
Bulk density x Density
v = 500 kg.m-3 v = 2400 kg.m-3
2400 k 3 = 2500 kg m-3 = 2400 kg.m-3 = 2500 kg.m-3
AAC tAAC(aerated autoclaved concrete)
concrete
Bulk density determinationBulk density determinationmm
v = V + V
• mass m by weighing
Vh + Vp
• mass m by weighing• volume (Vh+Vp)h p
– counting from sizes (regular shape)shape)
– in graduated cylinderb h d t ti l b l– by hydrostatical balance
By graduated cylinderBy graduated cylinderm
ABm
vρ
BB
mρ C
water
1
ρm)(mAB
vρ
m m
Awaterρ
(m )Cm)(mAB
mvρ 1 m (m1)
ρwater
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Hydrostatical balanceHydrostatical balance
• irregular shape – volume?
Hydrostatical balanceArchimedes principle:
Hydrostatical balancep p
„Any object, wholly or partially immersed in a fluid, is buoyed up by a force equal to the weight of theby a force equal to the weight of the fluid displaced by the object.“
mass of material, weighted under water is lower than that weighted in the air From thatlower than that weighted in the air. From that difference the volume of the displaced water can be count (its density is known). m( y )
Vm
OH2
volume of displaced water = volume of material
Wire basket methodWire basket method EN 1097 6• EN 1097-6
[M 3]M [Mg.m-3]1Mg.m-3 =1000kg.m-3)MM(M
M321
4Wa
)( 321
M1 mass of the wet sample, dryed on the surface (g)M2 mass of the sample in the basket under water (g)2
M3 mass of the empty basket under water (g)M4 mass of dry sample (g)4 y p (g)w water density at testing temperature (Mg.m-3)
Bulk density of building materialsBulk density of building materials
kg.m-3
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Specific gravity (density)determination
mv =v
Vh
• Mass m by weighing
• Volume Vh by pycnometerVolume Vh by pycnometer– material have to be grounded !
PycnometerPycnometer• (glass) bottle with a close fitting stopper with• (glass) bottle with a close-fitting stopper with
a capillary tube through it allowing excessliquid to escapeliquid to escape
• the volume of the liquid in the pycnometer isl thalways the same
• allows repeated obtaining a given volume ofliquid with a high accuracy
Determination of density byDetermination of density by pycnometric method
m1 m2 m3 m4
)(34
k12
mm)m(mρ)-m(m ρ
3412 mm)m(m
Helium pycnometerHelium pycnometer• the size of helium atoms is very small• helium, under precisely-known pressure, is , p y p ,
used to fill small voids within a specimen • the volume change of helium in a constant• the volume change of helium in a constant
volume chamber allows determination of solid volumevolume
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Density of building materialsDensity of building materials
kg.m-3
PorosityPorosity
• ratio of the volume of the voids to the total volume of the material
︶. ︵VVp vh 10011
• usually expressed as a percentageusually expressed as a percentage
Types of poresTypes of poresl d• closed • open
p = pclosed + popen
P ti l t d t itProperties related to porosity
• Water absorption → frost resistancep
• Gas and liquid transport
• Acoustic absorptivity
• Thermal conductivity
M h i l i h• Mechanical properties - strength
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Pore size distributionPore size distributionMercury porosimetryy p y• the intrusion of a mercury at high
pressure into a pores• the pressure needed to fill the pores
increases with decreasing pore didiameters
• 400 MPa Ø1,5 nm1000.7
60
70
80
90
0.4
0.5
0.6
d)e/cm
3 g-
1
20
30
40
50
0.2
0.3
0.4
dV/d
(log
mul
ativ
e po
re v
olum
e
0
10
20
0
0.1
0.001 0.010 0.100 1.000 10.000 100.000
Cum
Pore diameter/mm
Properties of bulk materialsProperties of bulk materialsBulk material = solid material dividedBulk material = solid material divided
into many small particles • an assembly of solid particles that is large
enough for the statistical mean of any property to be independent of the number of particles
Void ratioVoid ratio
• ratio between the total volume and the volume occupied only by the particles p y y p
• the amount of void space is a function of the gradation particle shape andof the gradation, particle shape and texture, and the amount of compaction of the material
CompactingCompacting
Uncompacted voids - Compacted voids -pthe amount of void space present when the
pthe amount of void space present when the
material is in an uncompacted, unconsolidated state
material is in an maximally compacted, stateunconsolidated state. state.
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Loose bulk densityLoose bulk densitym
mph VVVm
smph VVV
• in the uncompacted state
• in the consolidated state (compacted)
Loose bulk density determination
• Standard container (volume according maximum particle size) + tamping rod
Procedure:• Loose weight:g
– fill the container– struck off the surplusstruck off the surplus
• Compact weight:– fill the container in equal layersfill the container in equal layers – each layer being subjected to
strokes with the tamping rodp g– struck off the surplus
AggregatesAggregates
• granular material used in construction
• inorganic rocklike material• inorganic rocklike material
• various sizes and shapesvarious sizes and shapes
• particle size < 125 mmp
Size gradationSize, gradationGradation = the particle size distributionGradation = the particle size distribution• Amount of various particle sizes present
in an aggregatedetermined by sieve analysis– determined by sieve analysis
– expressed as the percentage p p gby mass passing a specified set of sieves
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Standard sieves (EN 933-2)Standard sieves (EN 933 2) 125 mm63 mm
31,5 mm16 mm8 mm4 mm 2 mm1mm
0,500 mm0250 mm0,125 mm0,063 mm
Type of aggregates according sizeType of aggregates according size
125stone
12563
31 5 coarse (gravel)31,5168
coarse (gravel)
ll i842
all-in aggregate aggregate
10,5
0,250,125
fine (sand)
0,0630 fines
Sieve analysis (EN 933 1)Sieve analysis (EN 933-1)
di iding p a material into si e• dividing up a material into size fractions by passing it through sieves with decreasing apertures
Aggregate size (fraction)Aggregate size (fraction)d i ti f t i t• designation of aggregate in termsof lower (d) and upper (D) sievesizes expressed as d/D*– 16/64 aggregate will be that aggregate16/64 aggregate will be that aggregate
which passes the 64 mm sieve and isretained on the 16 mm sieve
* this designation accepts the presence ofthis designation accepts the presence ofsome particles which are retained on theupper sieve (oversize) and some which passpp ( ) pthe lower sieve (undersize)
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Sieve analysis - definitions• Individual retained – the mass or
Sieve analysis - definitions
percentage retained on one sieve after test• Cumulative retainedCumulative retained
– sum of the mass or percentages retained onpercentages retained on the sieve and on all coarser sievescoarser sieves
• Cumulative passing – sum of the mass or percentage passing– sum of the mass or percentage passing the sieve (e.g. sum of the retained on all finer sieves and pan)finer sieves and pan)
Particle size distribution curveParticle size distribution curve
hi l li ti f 100
9585
70
80
90
100
ive
pass
ing
[%]• graphical listing of
the amount of ti l di 60
40
50
60
70
cum
ulatparticles according
to particle size 20
101050
0
10
20
30
64321684210 50
ranges
64321684210.50
sieve size [mm]• continuous line– axe X – sieve size (particle size)(p )– axe Y – cumulative passing (percent passing
by weight)
Example:pAggregate with the size 4/16 - 1000 g
Aft i l i th t i d• After sieve analysis these retained wereobtained:
Sieve aperture size
Individual retained
g %
Cumulative retained Cumul. passing
% %64 0 032 50 516 100 10
0 1005 95
15 8516 100 108 250 254 400 40
15 8540 6080 2000 0
2 100 101 0 0
80 090 1090 10
0,5 50 5 0,5 (pan) 50 5
95 5100 0
Particle size distribution curve100
9590
100
sing
[%]
40 % ti l 85
70
80
ativ
e pa
ss
•40 % particles bigger than
8 mm60
50
60
Cum
ula 8 mm
30
4060 % particles smaller than
fraction 1/2 omitted (gap grading)
20
101050
10
20smaller than
8 mm5
064321684210.50
Particle size [mm]• only rising (decreasing) character Particle size [mm]only rising (decreasing) character• missing fraction – horizontal line• vertical line – never!
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Particle size distribution curve45
Particle size distribution curve
35
40
45
25
30
35
15
20
25
5
10
064321684210,50
Fineness modulusFineness modulus• to determining the degree of uniformity of the• to determining the degree of uniformity of the
aggregate gradationsingle number• single number
• obtained by adding the total percentages of i l i l h hmaterial in a sample that are coarser than
each of a specified series of sieves ( l i i d) d(cumulative percentages retained) and dividing the sum by 100.
% sieves specified on retained cumulativeFM% 100
FM
%100
% sieves specified on retained cumulative FM
Z16
% 100
Z16
Z
16+
Z16 + Z8
Z4
Z816 8
+Z16 + Z8 + Z4Z4
Z2
+Z16 + Z8 + Z4 + Z2
Z1
+Z16 + Z8 + Z4 + Z2 + Z1
+Z0,5
+Z16 + Z8 + Z4 + Z2 + Z1 + Z0,5
+Z0
+Z16 + Z8 + Z4 + Z2 + Z1 + Z0,5 + Z0
Fineness modulusEN 12620
Specified sieves: (4 2 1; 0,5 0,25 0,125)
0,125)] ( 0,25) ( 0,5) ( 1) ( 2) ( 4) [(FM
100
FM
1 FM 6
• the bigger FM is, the coarser is aggregategg , gg g
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FinesFines
ti l i f ti hi h th 0 063= particle size fraction which passes the 0,063 mm sieve
l th d f d t i i ( hi- several methods for determining (washing, sand equivalent test, methylene blue test, air jet sieving)jet sieving)
- maximum value: fi t 3 %- fine aggregate 3 %
- coarse aggregate 1,5 %higher content of fines:- higher content of fines: - higher consumption of cement
lower strength- lower strength
Shape of particlesShape of particlesParticles:a c es• shape – rounded, angular, elongated,
flatflat
• surface – smooth, abraded (rough)
Flakiness indexFlakiness index (EN 933-3)
• particles are flakey when their thickness is less than 0 6 ofthickness is less than 0.6 of their mean size
i l i ith l t d• special sieves with elongated apertures
• the flakiness index - the weight of the flakey aggregate as a percentage of the aggregate tested
Shape indexShape index(EN 933-4)
• a ratio between the weight of particles with L/E > 3 and weight of all measured particlesL/E > 3 and weight of all measured particles in percents.
shape ratio L/E the length L and the– shape ratio L/E – the length L and thethickness E of each particle
– L/E 3 – non-cubic particles
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Shape ratio L/EShape ratio L/E
LE
L
Specific surfaceSpecific surface
• finenesst t l f it f• total surface area per unit of mass
• units: m2/ kg (cm2/g)units: m / kg (cm /g)
• the higher the specific surface is, the finer t i l ill bmaterial will be
Specific surface2 cm
Specific surface8 cm
2 cm
8 cm
8 cm
a) Surface b) Surface
8 cm
a) Surface6 x 8 x 8 cm =
384 cm2
b) Surface64 x (6 x 2 x 2) =
1536 cm2384 cm2 1536 cm2
1/4 S 4 Sab = 1/4 aa Sb = 4 Sa
Specific surface of some materials
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S ifi f d t i tiSpecific surface determination
• sieving
• gas permeability• gas permeability
• adsorption
Air permeability methodAir permeability method
Coarse material Fine material
• the specific surface is derived from the resistance to flow of air through a porous bed of the powder
Blain apparatusBlain apparatus Blain apparatusBlain apparatus
STARTSTART
STOP
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Specific surface calculationSpecific surface calculation
teKS3
1,0)e1(
S
K t t t• K apparatus constant • e porosity of the bed (usually e = 0,500)• t measured time s• cement density g.cm-3• air viscosity at the test temperature [Pa.s]
Apparatus calibrationApparatus calibration• apparatus must be calibrated using a known• apparatus must be calibrated, using a known standard material
000
1,0)e1(SK
0300
teS K
• S0 specific surface of the reference cement cm2.g-1• 0 density of the reference cement g.cm-30 y g • t0 measured time s• 0 air viscosity at the test temperature Pa.s0 a scos ty at t e test te pe atu e a s
Fineness of grindingFineness of grinding• cements and similar materials• cements and similar materials• described by the specific surface• finer cement offers a greater surface area for
hydration and hence faster the development of strength
• specific surface of common cements:p
250 – 350 m2/ kg (2500 - 3500 cm2/g)
Mechanical propertiesMechanical propertiesp pp p
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Solid materials
• structural rigidity • resistance to changes of shape or volume • atoms are tightly bound to each other g y
Atomic vibration in crystalline solidcrystalline solid
Mechanical propertiesMechanical propertiesd ib t i l' b h i h f i• describe a material's behavior when force is applied
• describe characteristics such as their strength and resistance to deformation
Mechanical propertiesMechanical propertiesd f ti ti (b f d t ti )• deformation properties (before destruction)
• strength properties (at the moment of break)
Type of loadingType of loading
compression bending shearcompressiontension
bendingtorsion
shear
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Force x StressForce x Stress• stress is a measure of the internal forces• stress is a measure of the internal forces
which are a reaction to external forces
Force F stress
[N] [Pa][ ] [ ]
Isaac Newton Blaise Pascal
Compressive stressCompressive stress
FSF
S
005,0 x 005,0S 2m 000025,0
Units of stressUnits of stressSI units: Pascal
N N2
m
NPa 2
mm
NMPa
Imperial units: pound-force per square inch
lbfpsi ksi = 1000 psi2inpsi ksi 1000 . psi
1 psi = 6 894,76 Pa
Strength propertiesg p p
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StrengthStrengthabilit to ithstand an applied load• ability to withstand an applied load without failure
• the maximum stress sustained by a material loaded to failurematerial loaded to failure
StrengthStrength
According the way of obtaining:g y g
– theoretical (structural)– technical– statistical– statistical
Theoretical strengthTheoretical strength• Counted from the number and strength of• Counted from the number and strength of
the bonds between atomsXX • defects in the crystal lattice – real strength is
distinctively lower (ca 1000x)
T h i l t thTechnical strength• from the testing of the real material
samplesample
– material have to be homogenous– test samples in the appropriate– test samples in the appropriate
shape (cylinder strength, cubic t th )strength...)
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Test samplesTest samples• shaping from the materialshaping from the material
– cutting, carving, drilling• directly made in the required shape
– cubes, cylinders.., y• whole products
b i k bl k– bricks, blocks
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