vectors

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Vectors

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Vectors. Objectives:. Find the magnitude of the vector Find component form Add and subtract vectors. A vector has both direction and magnitude . A vector begins with an initial point, usually P, to a terminal point, usually Q. - PowerPoint PPT Presentation

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Page 1: Vectors

Vectors

Page 2: Vectors

Objectives: • Find the magnitude of the vector• Find component form• Add and subtract vectors

Page 3: Vectors

Find the magnitude of a vector

• A vector has both direction and magnitude.

• A vector begins with an initial point, usually P, to a terminal point, usually Q.

• A little reminder for terminal point: to terminate is to end, so the terminal point ends the line.

• Graph it as you would a ray.

• For example at right, the initial point is P(0, 0), and the terminal point is Q(-6, 3).

4

2

-2

-4

-6

-5 5 10

Q(-6, 3)

P(0, 0)

Page 4: Vectors

Write the component form

• Write the following Component Form =‹x2 – x1, y2 – y1› or

<u,v><-6 – 0, 3 – 0><-6, 3> is the component form.Next, use the distance formula to find the

magnitude.

|PQ| = √(-6 – 0)2 + (3 – 0)2 = √62 + 32

= √36 + 9 = √45 or 3√5 ≈ 6.7

4

2

-2

-4

-6

-5 5 10

Q(-6, 3)

P(0, 0)

Page 5: Vectors

Graph Vector

• Initial point is P(0, 2). Terminal point is Q(5, 4).

• Graph the ray starting at P, and go through Q. See picture. Then start looking for component form and magnitude.

8

6

4

2

-2

5 10 15

Q(5, 4)

P (0, 2)

Page 6: Vectors

Write the component form

• Write the following Component Form =‹x2 – x1, y2 – y1› or

<u,v><5 – 0, 4 – 2><5, 2> is the component form.Next use the distance formula to find the

magnitude.

|PQ| = √(5 – 0)2 + (4 – 2)2 = √52 + 22

= √25 + 4 = √29 ≈ 5.4

8

6

4

2

-2

5 10 15

Q(5, 4)

P (0, 2)

Page 7: Vectors

Graph Vector

• Initial point is P(3, 4). Terminal point is Q(-2, -1).

• Graph the ray starting at P and going through Q. See picture. Then you can start looking for component form and magnitude.

4

2

-2

-4

-6

5 10

P(3, 4)

Q(-2, -1)

Page 8: Vectors

Write the component form

• Write the following Component Form =‹x2 – x1, y2 – y1› or

<u,v><-2 – 3, -1 – 4><-5, -5> is the component form.Next use the distance formula to find the

magnitude.

|PQ| = √-2 – 3)2 + (-1– 4)2 = √(-5)2 + (-5)2

= √25 + 25 = √50 or 5√2 ≈ 7.1

4

2

-2

-4

-6

5 10

P(3, 4)

Q(-2, -1)

Page 9: Vectors

Adding Vectors• Two vectors can be added to form a

new vector. • To add u and v on a graph, place

the initial point of v on the terminal point of u.

• ♫ Take note! The sum of the vectors is a new vector from the initial point of u to the terminal point of v.

• You can also add vectors algebraically.

• You may put the initial point of u on the terminal point of v. This has lead to the name “the parallelogram rule”.

Page 10: Vectors

What does this mean?

• Adding vectors:

Sum of two vectors

The sum of u = <a1,b1> and v = <a2, b2> is

u + v = <a1 + a2, b1 + b2>• In other words: add your x’s to get the

coordinate of the first number in component form, and add your y’s to get the coordinate of the second number in component form.

Page 11: Vectors

• Let u = <3, 5> and v = <-6, 1>• To find the sum vector u + v, add the x’s and

add the y’s of u and v.

u + v = <3 + (-6), 5 + (-1)>

= <-3, 4>

There are 6 of these on the test Wednesday!!!

Example:

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