vectors (1) units vectors units vectors magnitude of vectors magnitude of vectors

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Vectors (1) Vectors (1) Units Vectors Units Vectors Magnitude of Vectors Magnitude of Vectors

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Page 1: Vectors (1) Units Vectors Units Vectors Magnitude of Vectors Magnitude of Vectors

Vectors (1)Vectors (1)•Units VectorsUnits Vectors

•Magnitude of VectorsMagnitude of Vectors

Page 2: Vectors (1) Units Vectors Units Vectors Magnitude of Vectors Magnitude of Vectors

A

B

The vector AB

The vector a

a

Notation

( )85

… as a column vector

8 across, 5 up

Page 3: Vectors (1) Units Vectors Units Vectors Magnitude of Vectors Magnitude of Vectors

The vector a

a

The vector 2 a

a

Notation

Is twice as long as a,but in the same direction

2a a

a

This bit is a scaler

Page 4: Vectors (1) Units Vectors Units Vectors Magnitude of Vectors Magnitude of Vectors

Displacement“a measure of distance and direction”

60o

50m

NAn object moves 50m at 60o to the East-West x-axisHow far East has it gone?

How far North has it gone?

N

E

Cos 60o = adj/hyp = E/50E = 50 cos 60o = 25m

Sin 60o = opp/hyp = N/50N = 50 sin 60o = 43.3m (1 d.p.)

This can be expressed as a column vector:-

Displacement = [ ]2543.3

Page 5: Vectors (1) Units Vectors Units Vectors Magnitude of Vectors Magnitude of Vectors

Unit Vectors (1)

-1

0

1

2

3

-1 0 1 2 3

X

Y

ii is the unit vector in

the x-direction

jj is the unit vector in

the y-direction

i = [ ]10

j = [ ]01

All vectors can be expressed as a linear combination of these 2 vectors

[ ] = 25 + 43.3e.g. displacement = 2543.3 [ ]1

0 [ ]01

Page 6: Vectors (1) Units Vectors Units Vectors Magnitude of Vectors Magnitude of Vectors

Unit Vectors (2)

i = [ ]10 j = [ ]0

1

All vectors can be expressed as a linear combination of these 2 vectors

[ ] = 25 + 43.3e.g. displacement = 2543.3 [ ]1

0 [ ]01

= 25 i + 43.3 jThis is the standard way displacement vectors are presented

Page 7: Vectors (1) Units Vectors Units Vectors Magnitude of Vectors Magnitude of Vectors

Magnitude of a vectorThe displacement of a boat is given

by :- -10 i + 15 j

What is it’s magnitude ?

10

15

-10 i + 15 j By Pythagoras, the magnitude = (152 + 102) = 325 = 18.0 (1 d.p.)

The displacement is 18.0m

Page 8: Vectors (1) Units Vectors Units Vectors Magnitude of Vectors Magnitude of Vectors

Magnitude

a = -10 i + 15 j

a

-10 i + 15 j By Pythagoras, the magnitude = (152 + 102) = 325 = 18.0 (1 d.p.)

a is notation for magnitude

a = 18.0

Page 9: Vectors (1) Units Vectors Units Vectors Magnitude of Vectors Magnitude of Vectors

10

3

4

a

4

3

10a

Magnitude of a 3D Vector (1)

x

y

z

o

Page 10: Vectors (1) Units Vectors Units Vectors Magnitude of Vectors Magnitude of Vectors

x

y

z

10

3

4

a

4

3

10a

Magnitude of a 3D Vector (2)

o B

3

By Pythagoras, OB = (32 + 42)

Page 11: Vectors (1) Units Vectors Units Vectors Magnitude of Vectors Magnitude of Vectors

x

y

z

10

3

4

a

4

3

10a

Magnitude of a 3D Vector (3)

o B

3

By Pythagoras, OB = (32 + 42) A

(32 + 42)

By Pythagoras, OA2 = AB2 + OB2

AB2 = 102

OB2 = (32 + 42) OA2 = 102 + 32 + 42

OA = (102 + 32 + 42)

|a| = OA= 11.2

Page 12: Vectors (1) Units Vectors Units Vectors Magnitude of Vectors Magnitude of Vectors

x

y

z

t

s

r

a

r

s

ta

Magnitude of a 3D Vector (General)

o|a| = (r2 + s2 + t2)

“the magnitude is the square root of the sum of the squares of the 3 components.”

[Pythagoras in 3D]