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PART-III

i'�rol.51UJ6\) / PHYSIC$ .. , ,,\

( �u51� LD!I)IDI LO �IBJc61ru rukQ1 / Tamil & English Versions)

Time Allowed : 3 Hours ]

[ GlLDrr�� LD�uQu�s;ro : 150

[Maximum Marks : 150

(1) � � 6m" � � @S1 � rr 8; s; (§ LO a= if1 lLI rr s; u � ru rr c61 � ro ro � rr 6f 6bT u � � 6m"a=if1 u rrrr��8; Qs;rrroro� LO. �a=aru u�@S1 GD ®�Wu51@ul516b'r ��!!)8;s;��rr66bf1uurrroif1Ltp �L6m"Lq-lLirrs;� Q�rfl@S1t9;s;�LD.

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Instructions : (1) Check the qqestion paper for fairness of pr�ting. If there is any lack of

®!Qh.JLI :

Note:

fairl}ess, info:,;m the Hall Supervisor imm,ediately.

(2) Use Blue or Black ink to write and underline and pencil to draw diagrams.

LI@)� - 1/PART- I

(i) ��61JT�� �6m"IT�$®8;@5LO ��LllJ6fT18;s;�LO .

(ii) a=if1lUrr6m" @S1�L�llJ� a�rrJbG�®�� 6f@��L.D.

(i) Answe� all tl\e questions.

(ii) Choose and write the correct answer.-

30�1=30

[ �@uys; /Turn over

Tamilnadu Board Class 12 Physics Previous year Question Paper Sept/Oct 2016

6228 2

1. �® �·6?lrh.o�� 6bT a JD rh.6l 6m a;� IT a;ro, Q u u516mt5l rf1 L� JBl 6m !D JBl !D LO IT6m ru LO 1T615tl u51 GD @®aru IDJ U LL Br6tl ® 856m 61T � a� ITU) IDJ � 8;$) 6m"!!) 6bT. c@Jt� a JD IT� 6m � LU 615fl a;ro

(�) �arr JB16m!D�LO aruIDJULL �6ma=arua;�6m��LO Qa;ITOOLq-@$@)LO'

( qb) �arr JBl 6m !D LO ti) ID! LO � 6m a= aru a;� 6m�8; Q a; IT OOLq-@$(§ LO

(@) aruIDJULL JB16m!D LOU)IDJLO �arr �6m5 arua;�6m�8; Qa;ITOOLq-@$(§1..D

. ( r-F) aru IDJ U LL JBl 6m !D LOU) IDJ LO � 6m5 aru a;� 6m�$ Q a; IT OOLq-(!!5$ (§ LO

Positive rays of the same element produce two different traces in a Bainbridge mass spectrometer. The positive ions have :

(a) same mass with different velocity

(b) same mass with same velocity

(c) different mass with same velocity

( d) different mass with different velocity

2. @® �rom®a;�LO 8T�llJITffi '®@$(§LO aulT� LDL®aLO QruG1flLO® LO�L.I� '1' qbffi$$16mL$(§LO Q)IT�$ aa;L ·:

(�) OR (qb) NAND (@) EXOR (r-r-) NOR

The Logic gate for which the output is '1', only when both the inputs are '0' is

(a) OR (b) ' NAND (c) EXOR (d) NOR

3. @® �roG1fl u516mWJfLLffi.Jffi6TT, tr

= 6 Qa;ITOOL 2filL8J��G\),, 'd' Q�ITGmQ)@SlGl) t5lrf1��6m 6t1 $85 LI u ® 6t1 � IT GD �® 6t1 IT@) LO JBl � 60 u516m 615fl lU GD � 6m5 0 .3 N . Q 6tl ti) p5l L�� GD�a� G��6mQ)�G\) t5lrfl�� 6m6t1$85LJULLITGD �LOu516m"WJfLLffi1ffi®$®@6l5)LalLJWIT6UT 6>516ma=

(�) 20 N (@) 1.8 N (r-r-) 2 N

The electrostatic force between two point charges kept at a distance 'd' apart, in amedium t

r

= 6, is 0.3 N. The force between them at the same separation in vacuum is:

(a) 20 N (b) 0.5 N (c) 1.8 N (d) 2 N

3 4. @® �GTTGTTl u5l6m@ITLLffi185GTT +4q LDjDIDJLD +q 30 cm G1f!,rT6IDQ)@5160 LS1rf1��6ID 6lJ s; 85 u u L ® GTT GIT� � LO u5l 6l5T @If LL ffi1 85 6ID GIT @ 6ID 6lITT c$ @5 LO cg 85 rr L t.q. 6l5T LO�

6T" LJ � GTTGTTl u5l 6b u5l 6m � Q) LO 8r w1 LU rT (§LO?( �) u5llol5T@ITLLLO + q 601@�� 15 cm

( �) u5l6m@ITLLLD + q 601@Ji>� 7.5 cm

(@) u5l6m@ITLLLO + 4q 601@�� 20 cm

(r-r-) u5llol5T@ITLLLD +q 601@�� 5 ·cm

Two point charges + 4q and + q are placed 30 cm apart. At what point on the linejoining them the electric field is zero ?(a) 15 cm from the charge + q(b) 7.5 cm from the charge +q( c) 20 cm from the charge + 4q( d) 5 cm from the charge + q

2 n.._____ 3 n

A•9--------'--I C: 7�•B Sil

( �) 2.5 fl (�) 10 n , (@) o.4 n ( r-r-) 11 nThe·effective resistance between points A and Bin the given network is:

2 n,_______

3 n

A____,• C: ::J�•B sn

(a) . 2.5 il (b) 10 n (c) 0.4 il (d) 11 n

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6. a; w tS1 B= Bi-@rol Q) @®JB� q!I) 8=8i-£D IDJ B>® L.6l 6irrG6m ITL.L�Gm� u u ITW B= Q a:u:..i � LDLO If IDJ � GmB= L.6l 6irr6nfl W !I) pSl uS) 615T �IDJ lJ q

( �) qGDa;a;rrfe�LD ( �) tS1w� UL.L @JGmGTTWffi.1$6TT

The part of the AC generator that passes the current- from the coil to the external ci_rcuit is:

(a) field magnet

( c) slip rings

(b) split rings

(d) brushes

1. �WJ85$@6l516irr �Lrr��ffi®LD urr�ira:��6irr �Lrr��85®LD �roro 6lSl$l�LO Bi-LDrrirrra; :

(�)1.3xl010 (�)1.3 (@) 1.3xio13 (r-r-) 1.3xl04

The ratio of nuclear density to the density of mercury is about :

(a) 1.3 x 1010 (b) 1.3 (c) 1.3 x 1013 (d) 1.3 X 104

8. soHg198 + X➔ 79Au 198.+ 1H1 GT6ITT!!) �WJ85$@ @S1Gm6m"u.sl6U X GT6ITTU� GT�6'6)6ITT$

@j pSl 85@5 L.D ?

In the nuclear reaction 80Hg198 + X➔ 79A�

198 + 1H1, X stands for :

(a) proton (b) electron (c)· neutron (d) deutron

9. �® Q ru u u L.6l 6irr 6Uf1 1J L.Gm Lu.sl 6irr ®ffil rr a: Jt� u.s16irr Q ru u u J5l Gm Q) 6'6) w ��a; rfl 85 ® LOQurrQ:g� (�6mrrQ) �@uq Qruuu �GmGDa;® @)Gm!I)rurra;) qirL@ Qruuu �Gmruug}6irrLO�LJUITaT�:

( �) ��5;rflffi@5ili

(@) LO If!!) IT�

( �) @)66>fD� D, . -

( r-r-) @�G\SlQ) ��a;rfl�� tS16irrq @jGm!I)�LO

In a thermocouple, when the temperature of cold junction is increased (but less than neutral temperature) the temperature of inversion :

(a) increases

( c) does not change

(b) decreases

( d) first increases and then decreases

10. �® ��ruL6huci)p5l 6f6m"U� :

( � ) � 6m"®JTLLLD 2-.GTTGTT �® Q UQ98'$l

5

( qb) ac- �UJ de qbO)!!)GUITB; LDITO)IDJLD ��LDULJ

(@) GQJQ!!)IT6lITIDJLD �Q)Q), QUQ!)8'$lGUJ qb@jlD

( r-r-) tS16br®JTLLLD @6Drurr� �® Gu@8Jffi1An oscillator is

( a) an amplifier with feedback

(b) converter of a.c. to d.c. energy

(c) nothing but an amplifier

( d) an amplifier without feedback

11. ��c..-'1836bT �@�QJ �Lq- ��ruu516Dl@Jt� $lGTTrr5MUJrr8Ja;� G��QJUJIT6m" ®�!DJt�UL...8= qb0)!!)6D (�6D6U�) (Y)�6D $lGTTrr8=51UJIT8JB; u5l6m6nT@�� �0)!!)6D :

(�) 13.6 eV (�) 10.2 eV (@) 3.4 eV (r-r-) 1.89 eVThe first excitation potential energy or the minimum energy required to excite thehydrogen atom from ground state(a) 13.6 eV (b) 10.2 eV (c) 3.4 eV (d) 1.89 eV

12. £w8' 8;00LQJO)!!)IGTT 6f � u5l6ma;rrJt� ��GU @6D�6U?.

(�) x- 8'�rra;ro (�) -y- a;rrL.Orr a;�rra;ro

(@) LJ!D ��rr a;fElrr8'ro (UV a;�rr8'ro) ( r-r-) � - a;�rra;ro ( QLLrr a;�rra;ro) I

'

Which one of the following is not an electromagnetic wave ? (a) X - rays (b) -y - rays(c) Ultra Violet rays· (UV rays) (d) � - rays

13. ��LIJ"�6m" �WJ@516D tS16bTQJQ!)LO QuUJrr6l.ja;GTf16D 6f�6D Qu®LD ��ruiGTTLDG� rr 6bTIDJ LD?

(�)2➔1 (�)4➔1 (@)6➔5 (r-r-) 5➔2In hydrogen atom, which of the following transitions produces spectral line of maximumwavelength ?(a) 2 ➔ 1 (b) 4 ➔ 1 ( c) 6 ➔ 5 ( d) 5 ➔ 2

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�--

6228 6

14. 91J1T6bl LJ516n"T�GD��6D, �GD��!D@) @� 6lITTWrr85, ��6n"T �5Sr ��LD�L.Drr.Q)J �@ LJ516n"T'®®@�6bl �QJ$85ULJL...Lrr6D, �� �6lITTITQJ�( �) Gh.orr�� GlSl�cr�w LDL(b)LD( �) �@I.J� @Sl�lf�W L.DL..{b)l.D(@) GIL.Orr�� GlSl�cr LD!D.Q)ILD �®u� GBl�cr @floo�L�LD( r-r:) GIL.Orr�� @Sl�cr�LD �6Dru, �®u� 61S1�cr�LD �6DruA dipole is placed in a uniform electric field, with its axis parallel to the field, itexperiences(a) only a net force(b) only a torque( c) both a net force and· torque(d) neither a net force nor a torque

15. �® �lU u516b"r��Lq- 'toL...{1)(gLD ��)-W LDrr.Q)J��lf LJ516n"TSr!Dr6)6U 6rj5�GIQ.lrr@8561ITT���LD �roGTT u516n"Tcg6blrTLLLD i = I0sinwt Gr60Tl6D GrjB�GIQJrr@ 856lITT���LD �GTTGTTLJ516n"f 60Tl WB;@) @S1 �lf W rT6bl �

( �) e = Ea sin ( wt - ; )

(@) e = E0

sin (wt-1T) ( r-r:) e = E0

sin ( wt + '1T)The instantaneous current in an AC drcuit containing a pure inductor is i == I

0sinwt.

The instantaneous emf is(a) e = Ea sin ( wt + ; )

(c) e = E0

sin (wt-'lT)

(b) e = Ea sin ( wt - ; )

(d) e = E0

sin (wt+ '1T)

16. a�rrGrurr$)1JrrL51 (Y)�!!)u516D $�B;B;OOLQJ !Dn516D 6T"�QJ UL5SrC!96fll6D LJ�6l.jGlcrUJ w u u (1) LD?( �) 6D58rl.D ��ITGIQJ�@l!LD ( �) B;LLQPLD ��ITGIQJ�@)JLD(@) B;LLQPLD 6D5Srl.D ( r-r:) 6D5Sr, 85LLLD LD!IJIDJLD ��frQQJOOIn holography, which of the· following are recorded-on the photographic film?(a) amplitude and frequency (b) phase and frequency(c) phase and amplitude (d) amplitude, phase and frequency

i2 ' (�) H= ..c- t

R

Joule's law of heating is:

(a) i2

H=-t R

· (b) H=V2Rt

7

(@) H=Vlt (r-r-) H=IR2t

'(c) H=Vlt

18. 6 µC u516bTWifLL��� �® LjGTTGltlu51601@Ji>� w!bGwrr@ LjGTT61fl85@) ff>85rTf£t£Qa=Q.JLUUU(bhb aru�GU 1.2x10- 5J 6T"6nr1GU, �LJLjGTTGltl85®85@> @�LGLU u5l 6br60T@�f£ aruWJ U rr@ GT6br60T?

(�)2V . (@) 12V ,,(r-r-) 72V

The work done in moving 6 µC charge between two points is 1.2xl0- 5J. Find the potential difference between two points :

(a) 6 V (b) 2 V

19. u5l6bra;rrJh� ��ro�Gltlru,. qi,!I)!I)GU ::

(c) 12 V (d) 72 V

( �) uSlGbrLjro��!D@)LD LD!I)IDJLD a;rrp;f£ULIGD��!D@).LD �Go- �rorurra;u UIJ�$16br!I)60T

(qi,)@® Lj6UIB.J85®85@)1.D G5IB.J@)��rra;u UIJ�$16bl!I)60T

(@) u516bTLjGD��GU U IJ�$)!D§J

( r-r-) BiffP,f£U LjGD��ru UIJ�$)!D�

In an electomagnetic wave

(a)

(b)

(c)

power is equally transferred along the electric and magnetic· fields.

power is transmitted in a direction perpendicular to both the fields. I ,

power is transmitted along electric field.

( d) power is transmitted along magnetic field.

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20. �@.JQQJrr@ B=LL�601�U.p.n @JJ""6l5lITG) �Q)IBJ$ ITTIT $U tSlrf1�� �® Gl5$00G)c$ @j

50 $ITL§1$601ITT ��u�QJ�6m GJorra;$LD( �) LJL��Q) 61L.61L.L601Q)� �GlSlfra;Bj( �) 2-LLJ rrJb� �� rrG 6ll 6m $60) ITT a; 60)8j lLJ rr(§QJ � GTcll� GT6m"u � rrro(@) 50 Hz GT6ITTLJ� @Jb�LLlrrGlSlro u516ITT60Tff!I)fl)GU �®JU��rol6ITT-��ITQQJ6m"

GT 6ITTLJ � ff GU( r:F) 60)560)8j u5l GU 2-GTT <off a� 60) QJ u5l GU Q) ff� @601 f,f S:B=Q)ffi 601 ITT }]'9lffiThe purpose of dividing each frame into two fields so as to transmit 50 views of thepicture per second is :(a) to avoid flicker in the picture(b) the fact that handling of higher frequencies is easier( c) that 50 Hz is the power line frequency in Inµia(d) to avoid unwanted noises in the signals

21. ���� �!k!,Lr,rrr�6m" §1601�6tj LDrrpSlrol ___ �@)LD.( �) 0.013 � L.6l LLD -l ( �) 0.053 J51 uSl LLD -l

(@) 3 � L.6l LffiJffiGTT ( r:r-) 0.069 � L.6l LLD -l

The decay constant of a free neutron is : (a) 0.013 minute-1 (b) 0.053 minute-1

(c) 3 minutes (d) 0.069 minute-1

22. (Y)6ITTG60Trr'9l@j B=rrrr� §)�u� QJ6011)"u5lGU 601LGLLJrr® .GlB=LLJGULJG)ru� :( �) �® 2-LLJrr u516m"�601LLLJrr$ ( �) �® L.616m" G�a;efilLLJrrffi(@) �® ]:5l!J)I�� (OFF) Br61SlLB=rr$ (r:r-) �® @LLld>@) (ON) Br61SlL.B=rrffi•· In the forward bias char':1-cteristic curve, a diode app�ars as : (a) a high resistance (b) a capacitor(c) an OFF switch (cl) an GN switch- · · ·

23. $!!)fl)� e!j)Q)��6ITT �Q)@j --­( �) �ru® @ro601ru(@) LOLLrr-1 (metre-1)

The unit of grating element is :(a) no unit(c) metre-1

(�) LOLLJT (metre) ( r:r-) Lq-efil rf1 (degree)

(b) metre(d) degree

'. ( .

.i,

9

24. ��trGGtJ6m- U6mGU,ID!!)��6U, �IT� �6"6>GUu516irr ��irGru6m �6"6>GU6lS16irr (carrierswing) ��8:iULa= LD�uurr6ITT� :

.\

(�) 455 kHz (�) 10.7 MHz (@) 75 kHz (r-F) 150 kHzThe maximum carrier swing <:1-llowed in frequency modulation is(a) 455 kHz (b) 10.7 MHz (c) 75 kHz (d) 150 kHz

25. Gu,nfl6irr G8:irrGTT6"6>8:iu5l6irr Ulq- (§n5)UL§1LL �60fl��60flUJrr6ITT L.D�Ll�$66)61TLJ Quww�61T61.t( �) @UJ8l8:i �f1)!!)6U

(@) G8:irrmT �Jfi�LDAccording to Bohr's postulates, which of the following quantities take discrete values ?(a) Kinetic energy (b) Potential energy(c) Angular momentum (d) Momentum

26. 2 A �66>GUJ]61TLD G8:irr6mL GT6U8'Lryrr60116irr �Jfi�LD.

(�) 3.3x1024 kgms- 1 - (�) 6.6x1024 kgms- 1

C@) 3.3xrn- 24 kgms- 1 (r-F) 6.6x10- 24 kgms- 1

The momentum of the electron having wavelength 2 A is (a) 3.3xl024 kgms- 1 ·

(b) 6.6x1024 kgms- 1

(c) 3.3 x 10- 24 kgms- 1 _ (d) 6.6 x 10- 24 kgms- 1

27. a=rrirt§1UJGD16m"ut.q., @UJ8l8'��wroro �Gior�6irr J]61TLD :

( �) J6166>ruLUrr8:i �wro Gurr� @®Jb� JB61T��!D@58= a=L.Dw( �) J6166>ruuJits; -�GTT61T Gurr� @®J5� J]ITT�66>� 6lS1L ��a;LOrra; �6"6'>LDLLjW

(@) JBl@j)ruUJrra; �roro Gurr@ @®Jb� JB61T�@l)� 6lS1L @j@l)!!)GtJrra; �@j)LOlLjLD( r-F) �6lfurt.q.6irr GGtJ8j�@j)�I.J Qwrrw��. Jfil@l)6UUJrrc6 2-ffiGl

T Gurr� i@Jt� Jh6TT�@l)� @S1 L � �-a; LO rr a; G GU rr � GU 6i) � @)@)) !D ru rr a; G ru rr � ro GU� a= LO LO rr a; G rurr �@l)LOLLjl.O.

According to relativity, the length of a rod in motion : (a) is same as its rest length(b) is more than its rest length(c) is less than its rest length( d) may be more or less than or equal to rest length depending on the speed of the

rod

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28. Q GU 6l5f Gm @S)� ' @S1 � u5) 6i5r <�Hq..U U 66) LW rr 615T � ( �) u5l6i5r®JTLL ��@S16i5r66)LD ( �) urrw ��@S)Q5T66)LD

(@) @-.JI}� �-wl @S) Q5f 66) LD ( �) �!I) !J) Q) � wl @S) 6l5T 66) LD Lenz' s law is in accordance with the law of : (a) �onservation of charges(c) Conservation of momentum

(b) Conservation of flux ( d) Conservation of energy

2 9. @1;nw 6br @S166) GIT @S1 ro u © 8i� tfl GnT � 66) ru �WLD 5890 A 6f 6nll ro oo cg LIT 8>0U LD !D Wl LO � OOL.Lq..Gm cg ur 8>Gm 61..1 tfl 8J Glf16i5r � 66) ru �GTTffiJ 8J ro @66) 1D cg w

( �) 5885 A LD!I)JJ)JLD 5880 A ( �) 5895 A LD!I)JJ)JLD 5900 A

(@) 5�85 A LD!I)JJ)JLD 5895 A (�) 5895 A LD!!)JJ)JLD 5885 A

In Raman effect, wavelength of incident light is 5890 A. The wavelength of stokes and anti.stokes lines are respectively : . (a) 5885 A and 5880 A (b) 5895 A and 5900 A

(c) 5885 A and 5895 A (d) 5895 A and 5885 A

30. �® Q�rrLrr RLC LDITJJ)l�66)5 u5lGnTBr!!),a5lGU, ���66)5� �66)6\)u5)Q) :

( �) u5l6l5f�66)L arw)

( qb) Q�rr@5Ul1JQ5T u5l6l5TLDJJ)ll.J� Br�

(@ ) u5l 6i5rQ 615T � �u � Q u ® LD w

In RLC series AC circuit at resonance

(a)

(b)

(c)

(d)

Resistance is zero

Net reactance is zero

impedance is maximum

'TTvoltage leads the current by a phase angle 2

11 6228

LI@")� -II/PART - II

®pSiuy <or �6LI G lLI@l LD LI� 6l5>6lIT,ffi� @S160T rr 855> (_§85 ® 6£1 � LLLJ <oTf1 . Answer any fifteen questions.

15x3==45 Note:

31. u516bl G�85$lu5l6bl LILLJ6blurr@s;�GIT <or@�d>.What are the applications of capacitors ?

32. @t.q-6!S16Urr 6t!rrl L.6l6m®fTLLLD, 2 cm Q�rr�6U6£1GU 9 x 104 Nc- 1 L.6l6m�6U����@6tl rr 85@)$1 !D� <or6ml GU L.6l 6bl®ff LL jGir �LIT��� LLJ85 S>60TI 85$1 (b)d>.An infinite line charge produces a field of 9 x 104 Nc- 1 at a distance of 2 cm . .; Calculatethe linear charge density.

33. u516bTG60lrrLL �LIT���UJ 6tl�l)"UJg)I. ��601 �6U@) LLJrr�?Define current density ? Give its unit.

34. 0°c GU L51GITrrLt.q-60TLD d>LDL9lu5l6m u5l6b-r��L 4 n L51GITrrLt.q-60T��6m" u516bl��L G6tluuJ£1�6U <or6in"r 0.0038/°C <or6mlGU 100°c GU s;LDL5lu5l@rr u5l6b-r��L. <or6b"r60l? The resistance of a platinum wire at 0°C is 4 f!. What will be the resistance of the wire, at 100°C if the temperature coefficient of resistance of platinum is 0.0038 / °C ?

3 5. (Y)� 6bT � LO L.6l 6b-r s; 6U 6irr 8,GTT LO ti) ID) LD � � 60m-L.6l 6irr $6\) 6irr a; GTfl 6hr G6LI g)I u rt(b) �(!98'. Distinguish between primary cell and secondary cell.

__ .,,

36. GL6ITT�6ITTL @Sl��UJ85 �IDJ8'.State tangent law.

3 7. L.6l 6ITT d> rrJh�� � 6inTLGU <or 6ITT!!) rr Q) <or 6bT 601? What is electromagnetic induction?

38. 11,000 W L.6l6ITT�!!)6ITT, 220 V u516ITT60TQ:g����GU �@ILJULJLJLLrrGU G6tluu �!D!!J6Urf85LO rrw w � !D 6irr @w u 6b"> U85 8,60n 8;$1 ®a;.

Calculate the power loss in the form of heat when a power of 11,000 w· is transmittedat 220 V.

[ �®u�s; / Turn over

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What are emission and absorption spectra ?

40. ]Bl� L.L6irr ru Gm GTTLU riiJ 8l m16irr Gm LD LU LO 8l@Gm LD LU rr 8l � Gm LD LU ffi 8l rro-6oi5TLO LU rr � ?

Why the centre of Newton's rings is dark?

41. Grua= IT 8;� IT 8lGIT16irr LD ®�� ru u u LU 6irr 8lGIT1 ru Gr Gm ru G LU®] LO e!J) 6irr!J51 Gm 6m ffi 8in.!PJ 8;,

Write any three uses of Laser in medical field.

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A Coolidge tube operates at 24,800 V. What is the 1?1-aximum frequency of X-radiationemitted from Co�lidge tube ?

43. Gr GUffi LIJrr 6irr ID,J 6m"G6oi5Trr 8'£1 � 6irr u LU 6irr 8l ITT (Y) 6irr!J51 Gm 6ITT Gr@� 8l.

Write three uses of �lectron microscope.

44. (3 - 8;�1T8lm16Ul" U 6lf0Ty8lm1ru G,n;-�ruGLU�,LD ,(Y)6irr!!)1Gm6ITT Gf@�8l.

Write any three properties of (3 rays,.

45: !£1 Gm,[) ru@ Gr 6ITT,[) rrru Gr 6irr 6m? .

What is mass defect ?

46. �m) 2-uS1k9 6l5)LGLUrrL (LED) Gf6ITT,[)rf6t) 6f6l5T6ITT? ��6ITT @t61to@ Gf6lrr6ITT?

What is Light Emitting Diode (LED)? Give its symbol.

4 7. � Gm ru 6LI 8l {§ffi8l rr 6ITT u 1TG 8l GTT a=6irr � u Jb� Gm 6ITT 8l ITT LU rr Gm ru ? ,

Give the Barkhausen conditions for oscillation.

13

48. Qu®a;�u5l6lIT LJL6l5)L �a;roLD 6f6lIT!l)rrru 6f6m"6m"?Define bandwidth of an amplifier.

49. UL��ru a;rrLLLJUL{b)wro 6Drr�a; 8T!I)!}5)!I)a;rrQIT �Gl51UJ6lIT 6LD6brurr® UJrr@? A= 1,B = 1 LD !D IDJ LD C = 1 6f 6m" a; Q a; rr 6ffl{b) Q QJ 6lfl LI.) L6l5) L85 856ffl 85$1 Cb) a;.What is the Boolean expression for the logic diagram shown in figure. Evaluate itsoutput if A=1, B=1, C=1.

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LI®� - 111/P ART - III .

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6228

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(ii) LO�@ ITT ro 11 61Sl 6m" rr 85 a; 6ITl Q) 6T 6l5) QJ � UJ ®I LD �©.I · � � rr 8l a;� 85@)� 6l5) LUJ ml 858; a6)J oo® L.D.

( iii) a�6l5) QJ LJ U {b) L.D @ LffiJ 6.i 6rfl Q) LI Lr&J c$6lT QJ 6l5) IJ"i$.

(i) Answer to question no. 59 is compulsorily.

(ii) Answer any six of the remaining 11 questions.(iii) Draw diagrams wherever necessary.

51. �® LjITTGlfl�ru uSl6lIT6m"@��LD 6)J6l5)1)"UJJJ)I �® �QTITT) uSl6N®JTLL��rrGU �® � w6lfl t61 GU GT!D u ® LD u5l 6irr Gm@���� !!)6.i rr 6m" aa; rr 6l5) ru 6l5) � u -Q u IDJ s;. Define electric potential at a point. Obtain an expression for electric potential at a point due to a point charge.

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6228 14

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State and verify Faraday's second law of electrolysis through an experiment.

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State and explain kirchhoff� s voltage law for electrical networks.

54. ffirrd),a51ro 10 cm @�LG6Lloou51Q) 5 m }Bffi(Y)Wffi @® ffiL��ffiQT @�6mrrUJrrffi�6LI ffiffi u u L(b) Wffi601. @IJ"� lrJ-@tl LO �G ir � G1T@Sl GU rr601 uS16l5rG601rrLL LO, �Gir��a=u51ru urr�LOGurr� 3.6 x 10-4 N ffi6Llrra:5' @Sl�a= Ga=WQ)ULLrrQ), ffiL��u51Q)u rr� LO uS16ITTG601rr LLfliJ a; 6l5) ffi 85 ffi 6mIT 85$l (1) ffi.

Two parallel wires each of length 5 m are placed at a distance of 10 cm apart in air.They carry equal currents along the same direction and experience a mutually attractiveforce of 3.6 x 10-4 N. Find the current through the conductors.

55. @® JB�L 6Llrf1B=SrQ!jWffi(_§85@) @�LGUJUJrf601 urfhorrd)w - uS16ITT �6fflL Q)� 6ffl 6ml d) a; rr 615T a= LO 6ITT u rrL�L Q u ID! ffi.

Obtain an expression for the coefficient of mutual induction between two long solenoids.

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81 : 1 � � Q) Q u ® LO LO !I) IDJ LO <!fl IDJ LO a= Q a= t!5l Q.J 8,00 6ITT @Sl $l � LO � 6l5r 601?

In Young's double slit experiment, the intensity ratio oftwo cqherent sources is 81 : 1. Calculate the ratio between maximUII\ and µrinimum inte;nsities.

Explain the spectral series of hydrogen atom (diagram is not necessary).

Write any five applications "of photoelectric cell.

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15

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�6\)6')� �aGDrrffiL.IUIJ"LIY �6bTIDJ 3333 A �6o)6DJ]GTT �GJflwrrro �GJfl�LLUU(b)LD aurr � �� 0. 6 e V ru 6o> IJ" qi,!!) !D ro Q a; rr 615nl"L 6r 6\)8, LIJ" rr 6bT ffi6o) ro Q 6)J GJfl @S1Cb)ffi16lIT!!) � . gL a6\) rr a;�� 6irr.G 6)J GJfl aw !b IDJ qb!D !D6o>6D85 ffi6'm 85$1 ffi' a;.

The time interval measured by an observer at rest is 2.5 x 10- 8s. What is the time interval as measured by an observer moving with a velocity V =0.73C?

OR

A metallic surface when illuminated with light of wavelength 3333 A emits electrons with energies upto 0.6 eV. Calculate the work function of the metal.

60. �6o)6lml"LIY �!D !D Q) 6)J6o)Gll"affirrLlq-!!)ffifT6nl @S1G1T8;8;�6o)�� �@ffi, ( 6)J6IDIJULLDa�6o)6)Ju5)Q)6o)6\))Explain the binding energy curve (graph ,is not necessary).

61. �® Q5wrourrL@L.1. Glu®8185lu5l6irr 2fil� Qf> 6o)Gnl (Pin-out) Q6)Jm)Uj@ �6o)l.DL.16o)LJULLO 6)J6o)l)"Jfi� �ITTffi(§ffi.Explain the pin-out configuration of an op�rational amplifier with the diagram ..

62. ��'ri-Glru615nr U615nraU!!)!D��6br �6l)T6o)l.Dffi61T LD�IDJ LD @j6o)!!)LJIT(b)8>61T wrr��? .What are the advantages and disadvantages of Frequency Modulation?

LI®� - IV/PART -·IV

6228

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Note : (i) Answer any four questions in detail.(ii) Draw diagrams wherever necessary .

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State Gauss's law. Using this, derive an expression for electric field due to an infinitelylong straight charged wire with uniform charge density.

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64. 19,rr��LJ�GU��wroro uSlGmG6lrrrrLLLD urr�LD 8,;L��u51Gm LO� G6UJ6DU @LD@51 �68;$ rr6lIT qs.; rr�6l..l u51 � 6lITLJ Q U IDJ8'. @51 �5u5l Gm <i,f"6l5of LD� u t.51 �6lITLJ Q UIDJ8'.Derive an expression for the force on a current carrying conductor placed in a magneticfield. Fin� the magnitude of the force.

65. �UJ uSlGm�6l5orlq- LDL®GLD g>_�LUJ �® LDrrWJ��6 _ uSlGmar!I)n5lGOu51GmG6lrrrrLL��!Ds.;rr� 5L06m"UrrL�L� �®6)51. Lql��@��LD LD!DIDJLDu51GmG6lrrrrLL��!D@5 @�LGUJ g)_GfTGTT 8:iLL� Q�rrLrr�ua; ffirr6l5of8'. �(§��6l..l�IJ"ULI.D 6l..l�IJ"8'.Obtain an expression for the current in an AC circuit containing a pure inductanceonly. Find the phase relationship between voltage and current. Draw the necessarygraph.

66. ��GU8' Qs.;rr��8'u.S1Gmutq. @@ �s.; Gr�GIJ"rr6fflu�u �roa;©a;· GP@ �a;(itJ"�Ql]"rr6fflu� Jl)�LGU!I)� a��6}JlLHT6lIT J51u_Ji>��6l5T$�� �@�$.Oi;i the b.clsi� qf wave theory �)<plain tqtal int�rn�l r�flection. Writ� th:e conditions, fortotal �ternal r�flection to take p��ce. · ·

67. 6f6U8'�1J"rr6ml6b-r uSlGm®JTLL ��!D� :5�� 8-,rr�LD J.J. �rrLD�Gm G5rrf£6l5>6lIT�UJ ��rfl.Describe J.J. Thomson's method for determining the specific charge of an electron:

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69 .. �® ffiLL CE Gu@8'cfilu51Gm GfµJGOurr��� �!b�0uL��LGm �GIT8>(§8>. ��rr�@-!� �601rrri"fElWGm ��rg��i;�-� � � Q"�-

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y:Vith � n�at circuit di�gram, ex:r.laitl the working ()i a s¢gle stage c� ~amplifier. Draw the frequency 1respon�e curve.

70. s;�LLl�L��6b-r g>_�@S)�L6?5T �6U8'c$1LJ t.5lrfla;@LD AM GJ!b.t.5l¢lajfr (SuperheterodyneAM receiver) G6UJ6QUrrLtq.�Gm 6lSlGIT8'(§8i.vVith t�e help of a block diagram, expla� the functio� C>f superheterody)1e AM receiver.

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