r.c. shear wall design spreadsheet to · pdf filedesign shear walls for a ... r.c. shear wall...

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Page 1: R.C. SHEAR WALL DESIGN SPREADSHEET TO · PDF fileDesign shear walls for a ... R.C. SHEAR WALL DESIGN SPREADSHEET TO BS8110 ... The ‘length of wall ends’ column is used to determine

Design shear walls for a

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-

-

-

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-

-

It is important to note that:

1. You have to enter at least

push/pull forces. This is because

2. The spreadsheet was developed to design walls under dead and wind load combination.

However it can be used to design for other load combinations but then

Safety should be

place of

3. The spreadsheet applies wind load in

give the worst case results.

See the below diagrams:

NOTE: When

system is in the bottom left hand corner of building being designed. This makes entering wall

co-ordinates a lot simpler. However, in this case a 7.5m x 3.0m offset was assume

more complex case.

R.C. SHEAR WALL DESIGN SPREADSHEET TO BS8110

Design shear walls for a

the building is rectangular in

it has one stair core and one extra wall at far right

walls are 300mm thick;

it consists of a two storey basement (substructure)

each storey is 2.85m high

unfactored vertical dead load is

unfactored vertical imposed load is

unfactored wind pressure is

It is important to note that:

ou have to enter at least

push/pull forces. This is because

The spreadsheet was developed to design walls under dead and wind load combination.

However it can be used to design for other load combinations but then

afety should be calculated

place of dead load safety factor.

3. The spreadsheet applies wind load in

give the worst case results.

See the below diagrams:

NOTE: When using the spreadsheet it is advised to assume that beginning of the co

system is in the bottom left hand corner of building being designed. This makes entering wall

ordinates a lot simpler. However, in this case a 7.5m x 3.0m offset was assume

more complex case.

R.C. SHEAR WALL DESIGN SPREADSHEET TO BS8110

Provided by:

Design shear walls for an R.C. frame building.

he building is rectangular in

one stair core and one extra wall at far right

walls are 300mm thick;

consists of a two storey basement (substructure)

each storey is 2.85m high

unfactored vertical dead load is

unfactored vertical imposed load is

unfactored wind pressure is

It is important to note that:

ou have to enter at least two walls in each direction

push/pull forces. This is because

The spreadsheet was developed to design walls under dead and wind load combination.

However it can be used to design for other load combinations but then

calculated based on percentage of dead load to live load,

oad safety factor.

3. The spreadsheet applies wind load in

give the worst case results.

See the below diagrams:

using the spreadsheet it is advised to assume that beginning of the co

system is in the bottom left hand corner of building being designed. This makes entering wall

ordinates a lot simpler. However, in this case a 7.5m x 3.0m offset was assume

more complex case.

R.C. SHEAR WALL DESIGN SPREADSHEET TO BS8110

WORK

Provided by: www.YourSpreadsheets.co.uk

R.C. frame building.

he building is rectangular in plan: 33m x 12.5m

one stair core and one extra wall at far right

walls are 300mm thick;

consists of a two storey basement (substructure)

each storey is 2.85m high;

unfactored vertical dead load is 4

unfactored vertical imposed load is

unfactored wind pressure is 1.3kN/m2.

two walls in each direction

push/pull forces. This is because the spreadsheet designs

The spreadsheet was developed to design walls under dead and wind load combination.

However it can be used to design for other load combinations but then

based on percentage of dead load to live load,

oad safety factor.

3. The spreadsheet applies wind load in each direction at any one time i.e. +X,

using the spreadsheet it is advised to assume that beginning of the co

system is in the bottom left hand corner of building being designed. This makes entering wall

ordinates a lot simpler. However, in this case a 7.5m x 3.0m offset was assume

R.C. SHEAR WALL DESIGN SPREADSHEET TO BS8110

WORKED EXAMPLE

www.YourSpreadsheets.co.uk

R.C. frame building. Use the following data:

plan: 33m x 12.5m

one stair core and one extra wall at far right

consists of a two storey basement (substructure)

400kN/m per

unfactored vertical imposed load is 250kN/m per wall;

kN/m2.

two walls in each direction

the spreadsheet designs

The spreadsheet was developed to design walls under dead and wind load combination.

However it can be used to design for other load combinations but then

based on percentage of dead load to live load,

each direction at any one time i.e. +X,

using the spreadsheet it is advised to assume that beginning of the co

system is in the bottom left hand corner of building being designed. This makes entering wall

ordinates a lot simpler. However, in this case a 7.5m x 3.0m offset was assume

R.C. SHEAR WALL DESIGN SPREADSHEET TO BS8110

EXAMPLE

www.YourSpreadsheets.co.uk

Use the following data:

plan: 33m x 12.5m;

one stair core and one extra wall at far right;

consists of a two storey basement (substructure) and four storey superstructure

00kN/m per wall;

0kN/m per wall;

two walls in each direction for the spreadsheet to calculate

the spreadsheet designs walls

The spreadsheet was developed to design walls under dead and wind load combination.

However it can be used to design for other load combinations but then

based on percentage of dead load to live load,

each direction at any one time i.e. +X,

using the spreadsheet it is advised to assume that beginning of the co

system is in the bottom left hand corner of building being designed. This makes entering wall

ordinates a lot simpler. However, in this case a 7.5m x 3.0m offset was assume

R.C. SHEAR WALL DESIGN SPREADSHEET TO BS8110

www.YourSpreadsheets.co.uk

Use the following data:

and four storey superstructure

for the spreadsheet to calculate

walls for in-plane loads only.

The spreadsheet was developed to design walls under dead and wind load combination.

However it can be used to design for other load combinations but then Global

based on percentage of dead load to live load,

each direction at any one time i.e. +X,

using the spreadsheet it is advised to assume that beginning of the co

system is in the bottom left hand corner of building being designed. This makes entering wall

ordinates a lot simpler. However, in this case a 7.5m x 3.0m offset was assume

R.C. SHEAR WALL DESIGN SPREADSHEET TO BS8110

and four storey superstructure

for the spreadsheet to calculate

plane loads only.

The spreadsheet was developed to design walls under dead and wind load combination.

lobal Factor of

based on percentage of dead load to live load, and entered

each direction at any one time i.e. +X, -X, +Y,

using the spreadsheet it is advised to assume that beginning of the co-ordinate

system is in the bottom left hand corner of building being designed. This makes entering wall

ordinates a lot simpler. However, in this case a 7.5m x 3.0m offset was assumed to cover

and four storey superstructure;

for the spreadsheet to calculate

plane loads only.

The spreadsheet was developed to design walls under dead and wind load combination.

Factor of

and entered in

X, +Y, -Y to

ordinate

system is in the bottom left hand corner of building being designed. This makes entering wall

d to cover

Page 2: R.C. SHEAR WALL DESIGN SPREADSHEET TO · PDF fileDesign shear walls for a ... R.C. SHEAR WALL DESIGN SPREADSHEET TO BS8110 ... The ‘length of wall ends’ column is used to determine

NOTE: the spreadsheet assumes that

Start with entering the basic geometry and

The ‘maximum vertical bar spacing’ limits the ve

spacing is calculated based on wall thickness as given in BS8110.

Now enter wind loads. Spreadsheet treats the structure as a cantilever with a partial line

load (partial because wind is not applied to the substruct

total wind load

Wind load WL1:

WL1 is applied to

height is 1.3kN/m2 x 33m = 42.9kN/m. The load is applied at

therefore the distance from the beginning of the co

offset) + 16.5m = 24.0m. Note that the value entered

NOTE: the spreadsheet assumes that

Start with entering the basic geometry and

The ‘maximum vertical bar spacing’ limits the ve

spacing is calculated based on wall thickness as given in BS8110.

Now enter wind loads. Spreadsheet treats the structure as a cantilever with a partial line

load (partial because wind is not applied to the substruct

total wind load per meter height

Wind load WL1:

WL1 is applied to north/south

height is 1.3kN/m2 x 33m = 42.9kN/m. The load is applied at

therefore the distance from the beginning of the co

+ 16.5m = 24.0m. Note that the value entered

NOTE: the spreadsheet assumes that

Start with entering the basic geometry and

The ‘maximum vertical bar spacing’ limits the ve

spacing is calculated based on wall thickness as given in BS8110.

Now enter wind loads. Spreadsheet treats the structure as a cantilever with a partial line

load (partial because wind is not applied to the substruct

per meter height

north/south

height is 1.3kN/m2 x 33m = 42.9kN/m. The load is applied at

therefore the distance from the beginning of the co

+ 16.5m = 24.0m. Note that the value entered

NOTE: the spreadsheet assumes that wind pressure can only be applied to superstructure

Start with entering the basic geometry and

The ‘maximum vertical bar spacing’ limits the ve

spacing is calculated based on wall thickness as given in BS8110.

Now enter wind loads. Spreadsheet treats the structure as a cantilever with a partial line

load (partial because wind is not applied to the substruct

per meter height. And so, in this example:

north/south elevation which is

height is 1.3kN/m2 x 33m = 42.9kN/m. The load is applied at

therefore the distance from the beginning of the co

+ 16.5m = 24.0m. Note that the value entered

wind pressure can only be applied to superstructure

Start with entering the basic geometry and material properties

The ‘maximum vertical bar spacing’ limits the vertical spacing to the given figure. The

spacing is calculated based on wall thickness as given in BS8110.

Now enter wind loads. Spreadsheet treats the structure as a cantilever with a partial line

load (partial because wind is not applied to the substruct

. And so, in this example:

elevation which is 33m long.

height is 1.3kN/m2 x 33m = 42.9kN/m. The load is applied at

therefore the distance from the beginning of the co

+ 16.5m = 24.0m. Note that the value entered

wind pressure can only be applied to superstructure

material properties

rtical spacing to the given figure. The

spacing is calculated based on wall thickness as given in BS8110.

Now enter wind loads. Spreadsheet treats the structure as a cantilever with a partial line

load (partial because wind is not applied to the substructure). Therefore you have to enter

. And so, in this example:

33m long. Therefore wind load per meter

height is 1.3kN/m2 x 33m = 42.9kN/m. The load is applied at the

therefore the distance from the beginning of the co-ordinate system is

+ 16.5m = 24.0m. Note that the value entered is to be in mm, hence 24000mm.

wind pressure can only be applied to superstructure

material properties into the spreadsheet:

rtical spacing to the given figure. The

spacing is calculated based on wall thickness as given in BS8110.

Now enter wind loads. Spreadsheet treats the structure as a cantilever with a partial line

ure). Therefore you have to enter

Therefore wind load per meter

the centre of the elevation

ordinate system is 7.5m

is to be in mm, hence 24000mm.

wind pressure can only be applied to superstructure

into the spreadsheet:

rtical spacing to the given figure. The

Now enter wind loads. Spreadsheet treats the structure as a cantilever with a partial line

ure). Therefore you have to enter

Therefore wind load per meter

centre of the elevation

7.5m (building

is to be in mm, hence 24000mm.

wind pressure can only be applied to superstructure.

into the spreadsheet:

rtical spacing to the given figure. The

Now enter wind loads. Spreadsheet treats the structure as a cantilever with a partial line

ure). Therefore you have to enter

Therefore wind load per meter

centre of the elevation

(building

is to be in mm, hence 24000mm.

Page 3: R.C. SHEAR WALL DESIGN SPREADSHEET TO · PDF fileDesign shear walls for a ... R.C. SHEAR WALL DESIGN SPREADSHEET TO BS8110 ... The ‘length of wall ends’ column is used to determine

Wind load WL2:

WL2 is applied to east/west elevation which is 12.5m long. Therefore wind load per meter

height is 1.3kN/m2 x 12.5m = 16.25kN/m.

therefore the distance from t

offset) + 6.

See below:

Now calculate wall co

Below is a

the spreadsheet:

Below is a

Wind load WL2:

WL2 is applied to east/west elevation which is 12.5m long. Therefore wind load per meter

height is 1.3kN/m2 x 12.5m = 16.25kN/m.

therefore the distance from t

+ 6.25m = 9.25

See below:

Now calculate wall co

Below is a diagram from AutoCAD which gives all wall co

the spreadsheet:

Below is a close-up of the stair

WL2 is applied to east/west elevation which is 12.5m long. Therefore wind load per meter

height is 1.3kN/m2 x 12.5m = 16.25kN/m.

therefore the distance from the beginning of the co

9.25m. Note that the value entered is to be in mm, hence

Now calculate wall co-ordinates by hand or use CAD if there are more than a few walls.

diagram from AutoCAD which gives all wall co

up of the stair

WL2 is applied to east/west elevation which is 12.5m long. Therefore wind load per meter

height is 1.3kN/m2 x 12.5m = 16.25kN/m.

he beginning of the co

m. Note that the value entered is to be in mm, hence

ordinates by hand or use CAD if there are more than a few walls.

diagram from AutoCAD which gives all wall co

up of the stair core:

WL2 is applied to east/west elevation which is 12.5m long. Therefore wind load per meter

height is 1.3kN/m2 x 12.5m = 16.25kN/m. The load is applied at the centre of the elevation

he beginning of the co

m. Note that the value entered is to be in mm, hence

ordinates by hand or use CAD if there are more than a few walls.

diagram from AutoCAD which gives all wall co

WL2 is applied to east/west elevation which is 12.5m long. Therefore wind load per meter

The load is applied at the centre of the elevation

he beginning of the co-ordinate system is 3.0

m. Note that the value entered is to be in mm, hence

ordinates by hand or use CAD if there are more than a few walls.

diagram from AutoCAD which gives all wall co-ordinates that will be entered into

WL2 is applied to east/west elevation which is 12.5m long. Therefore wind load per meter

The load is applied at the centre of the elevation

ordinate system is 3.0

m. Note that the value entered is to be in mm, hence

ordinates by hand or use CAD if there are more than a few walls.

ordinates that will be entered into

WL2 is applied to east/west elevation which is 12.5m long. Therefore wind load per meter

The load is applied at the centre of the elevation

ordinate system is 3.0m (building

m. Note that the value entered is to be in mm, hence 9250mm.

ordinates by hand or use CAD if there are more than a few walls.

ordinates that will be entered into

WL2 is applied to east/west elevation which is 12.5m long. Therefore wind load per meter

The load is applied at the centre of the elevation

(building

mm.

ordinates by hand or use CAD if there are more than a few walls.

ordinates that will be entered into

Page 4: R.C. SHEAR WALL DESIGN SPREADSHEET TO · PDF fileDesign shear walls for a ... R.C. SHEAR WALL DESIGN SPREADSHEET TO BS8110 ... The ‘length of wall ends’ column is used to determine

Now enter these co

the right hand size to allo

when using co

The spreadsheet plots walls automatically as you type:

The spreadsheet calculates stiffness per wall and combined with

centre of rotation

Now enter these co

the right hand size to allo

when using co-ordinates.

The spreadsheet plots walls automatically as you type:

The spreadsheet calculates stiffness per wall and combined with

centre of rotation

Now enter these co-ordinates

the right hand size to allow quick checks. Make sure you use this facility to eliminate errors

ordinates.

The spreadsheet plots walls automatically as you type:

The spreadsheet calculates stiffness per wall and combined with

centre of rotation and torsional

ordinates into the spreadsheet. The spreadsheet gives you wall size on

w quick checks. Make sure you use this facility to eliminate errors

The spreadsheet plots walls automatically as you type:

The spreadsheet calculates stiffness per wall and combined with

torsional moments:

into the spreadsheet. The spreadsheet gives you wall size on

w quick checks. Make sure you use this facility to eliminate errors

The spreadsheet plots walls automatically as you type:

The spreadsheet calculates stiffness per wall and combined with

moments:

into the spreadsheet. The spreadsheet gives you wall size on

w quick checks. Make sure you use this facility to eliminate errors

The spreadsheet plots walls automatically as you type:

The spreadsheet calculates stiffness per wall and combined with

into the spreadsheet. The spreadsheet gives you wall size on

w quick checks. Make sure you use this facility to eliminate errors

The spreadsheet calculates stiffness per wall and combined with wall location it calculates

into the spreadsheet. The spreadsheet gives you wall size on

w quick checks. Make sure you use this facility to eliminate errors

wall location it calculates

into the spreadsheet. The spreadsheet gives you wall size on

w quick checks. Make sure you use this facility to eliminate errors

wall location it calculates

Page 5: R.C. SHEAR WALL DESIGN SPREADSHEET TO · PDF fileDesign shear walls for a ... R.C. SHEAR WALL DESIGN SPREADSHEET TO BS8110 ... The ‘length of wall ends’ column is used to determine

� � � 矃骢 骢 �玢玢 玢珕�+� The spreadsheet calculates

manner. Note that the spreadsheet also gives you factored tension and compression

stresses per wall for easy hand

Enter bar diameter per wall to achieve

The ‘length of wall ends’ column is used to determine where lower area rei

be calculated, see below stress diagram.

THE END.

Worked

Download a free lite version of the spreadsheet to see its full capacity before purchasing.

Document version 1.0

The spreadsheet calculates

manner. Note that the spreadsheet also gives you factored tension and compression

stresses per wall for easy hand

Enter bar diameter per wall to achieve

The ‘length of wall ends’ column is used to determine where lower area rei

be calculated, see below stress diagram.

THE END.

Worked example pr

Download a free lite version of the spreadsheet to see its full capacity before purchasing.

Document version 1.0

The spreadsheet calculates required reinforcement per wall and gives results in a tabulated

manner. Note that the spreadsheet also gives you factored tension and compression

stresses per wall for easy hand

Enter bar diameter per wall to achieve

The ‘length of wall ends’ column is used to determine where lower area rei

be calculated, see below stress diagram.

example provided by

Download a free lite version of the spreadsheet to see its full capacity before purchasing.

Document version 1.0 – released on

required reinforcement per wall and gives results in a tabulated

manner. Note that the spreadsheet also gives you factored tension and compression

stresses per wall for easy hand checks.

Enter bar diameter per wall to achieve acceptable

The ‘length of wall ends’ column is used to determine where lower area rei

be calculated, see below stress diagram.

by www.YourSpreadsheets.co.uk

Download a free lite version of the spreadsheet to see its full capacity before purchasing.

released on 15/01/2014

required reinforcement per wall and gives results in a tabulated

manner. Note that the spreadsheet also gives you factored tension and compression

acceptable bar spacing.

The ‘length of wall ends’ column is used to determine where lower area rei

www.YourSpreadsheets.co.uk

Download a free lite version of the spreadsheet to see its full capacity before purchasing.

15/01/2014

required reinforcement per wall and gives results in a tabulated

manner. Note that the spreadsheet also gives you factored tension and compression

bar spacing.

The ‘length of wall ends’ column is used to determine where lower area rei

www.YourSpreadsheets.co.uk

Download a free lite version of the spreadsheet to see its full capacity before purchasing.

required reinforcement per wall and gives results in a tabulated

manner. Note that the spreadsheet also gives you factored tension and compression

bar spacing.

The ‘length of wall ends’ column is used to determine where lower area rei

Download a free lite version of the spreadsheet to see its full capacity before purchasing.

required reinforcement per wall and gives results in a tabulated

manner. Note that the spreadsheet also gives you factored tension and compression

The ‘length of wall ends’ column is used to determine where lower area reinforcement is to

Download a free lite version of the spreadsheet to see its full capacity before purchasing.

required reinforcement per wall and gives results in a tabulated

manner. Note that the spreadsheet also gives you factored tension and compression

nforcement is to

Download a free lite version of the spreadsheet to see its full capacity before purchasing.