microprocessor lab - einstein

8/21/2019 Microprocessor Lab - Einstein

1/76

EINSTEINCOLLEGE OF ENGINEERINGSir.C.V.Raman Nagar, Tirunelveli-12

Department of Electronics and Communication

EngineeringSubject Code :EC 58

Microprocessors and Microcontrollers Lab

Name :

Reg No :

Branch :

Year & Semester :

www.Vidyarthiplus.com



2/76

Sub Code: EC 58 Microprocessors and Microcontrollers Lab

Einstein College of EngineeringPage 2 of 76

INDEX

SLNO DATE Name of the Experiment MARKS STAFF

SIGNATURE

1

2

3

4

5

6

7

8

9

10

11

12

13

1415

16

17




3/76



EX.NO. :1

DATE :

8-BIT ARITHMETIC OPERATIONS

8-BIT ADDITION:

AIMTo write an ALP to perform 8-bit addition using 8085 microprocessor trainer

kit.

APPARATUS REQUIRED1. 8085 microprocessor trainer kit.2. Power supply

ALGORITHM1. Start the program2. Get the first data to the accumulator.3. The second data is given to B register.4. The content of B register is then added with accumulator

contents.5. The addition for carry is checked and the result is stored in the

specified memory location

6. The program is terminated.

PROGRAM

ADDRESS LABEL MNEMONICS OPCODE

41004102410441054108

410A410D410E410F4112

START

L1

MVI A, 35MVI B, 12ADD BSTA 4200MVI C, 00

JNC L1INR CMOV A, CSTA 4201HLT

3E,3506,128032,00,420E,00

D2,0E,410C7932,01,4276




4/76



INPUT:4101-354103-12

OUTPUT:

4200-474201-00

MANUAL CALCULATION:




5/76



8-BIT SUBTRACTION

AIMTo write an ALP to perform 8-bit subtraction using 8085 microprocessor

trainer kit.

APPARATUS REQUIRED1. 8085 microprocessor trainer kit.2. Power supply

ALGORITHM1. Start the program2. Get the first data to the accumulator.3. The second data is given to B register.

4. The content of B register is then subtracted with accumulator contents.5. The addition for carry is checked and the result is stored in the specifiedmemory location.6. The program is terminated.

PROGRAM


41004102410441054108410A410D410E410F

4112

START

L1

MVI A, 35MVI B, 12SUB BSTA 4200MVI C, 00JNC L1INR CMOV A, CSTA 4201

HLT

INPUT:




6/76



4101-354103-12

OUTPUT:4200-23

4201-00

MANUAL CALCULATION:




7/76



8-BIT MULTIPLICATION

AIM

To write an ALP to perform 8-bit multiplication using 8085 microprocessortrainer kit.

APPARATUS REQUIRED

1. 8085 microprocessor trainer kit.2. Power supply

ALGORITHM

1. Start the program

2. Clear the accumulator3. Get the first data to the register B.4. Get the second data to the register C.5. Add the contents of register B is added with the accumulator and stored inaccumulator.6. After performing the addition operation the register C would decremented

by 17. When the zero flag is set, the result was stored in the specified memorylocation.8. Otherwise the loop of addition operation was continued.

PROGRAM


410041024104

410641074108410B410E

START

L1

MVI A, 00MVI B, 12MVI C, 45

ADD BDCR CJNZ L1

STA 4200HLT




8/76



INPUT:4103-124105-45

OUTPUT:4200-

MANUAL CALCULATION




9/76



8-BIT DIVISION

AIMTo write an ALP to perform 8-bit division using 8085 microprocessor trainer

kit.

APPARATUS REQUIRED

1. 8085 microprocessor trainer kit.2. Power supply

ALGORITHM

1. Start the program2. Clear the accumulator and load the accumulator by divisor value to the

specified memory location.3. Move the content of A to B register.4. Load accumulator with dividend value.5. Initialize 00 to C register.6. Compare B register with accumulator.7. If carry is generated move to the 11thstep.8. Subtract the B register content from the accumulator.9. Increment the content of C register.10. Jump control to step 6.11. Store the remainder in accumulator in specified memory location.12. Move the C register content to accumulator.13. Store the quotient value in accumulator.14. End the program.

PROGRAM


START

L1

L2

SUB ALDA 4200MOV B,ALDA 4201

MVI C,00CMP BJC L2SUB BINR CJMP L1STA 4250

MOV A,CSTA 4251HLT




10/76



INPUT:

OUTPUT:

MANUAL CALCULATION:

RESULT:Thus the ALP was written and the 8 bit arithmetic operations were performed

successfully using 8085 microprocessor trainer kit.

EX.NO. :2




11/76



DATE :

16-BIT ARITHMETIC OPERATIONS

16-BIT ADDITION

AIMTo write an ALP to perform 16-bit addition using 8086 microprocessor trainerkit.

APPARATUS REQUIRED1. 8085 microprocessor trainer kit.2.Power supply

ALGORITHM

.

PROGRAM




12/76



INPUT:

OUTPUT:

MANUAL CALCULATION:




13/76






14/76






15/76



RESULT:Thus the ALP was written and the 16-bit arithmetic operations was performed

successfully by using the 8086 microprocessor trainer




16/76



EX.NO. :3

DATE :

INTERFACING AND PROGRAMMING OF STEPPER MOTOR

AIM: To run a stepper motor at different speed in two directions.

APPARATUS REQUIRED:8086 p kit, stepper motor, Interface board and Interface chord.

THEORY:A motor in which the rotor is able to assume only discrete stationary angular

position is a stepper motor. They are widely used in a variety of applications such ascomputer peripherals and in the area of process control machine tools, roboticsetc..

2 phase scheme:In this scheme any two adjacent stator windings are energised. There are two

magnetic fields active in quadrature and none of the rotor pole faces can be in directalignment with the stator poles. A partial but symmetric alignment of the rotor polesis of course possible.

Typical equilibrium conditions of the rotor when the windings on 2successive stator poles are excited. In step(a) A1 and B1 are energised .The pole faceS1 tries to align itself with the axis of A1(N) and the pole face S2 with B1(N) .Thenorth pole N3 of the rotor finds itself in the neutral zone between A1(N) and B1(N) .S1 and S2 of the rotor position themselves symmetrically with respect to the two

stator north pole.Next. When B1 and A2 are energised . S2 tends to align with B1(N) and S3

with A2(N), of course again under equilibrium conditions.Only partial alignment ispossible and N1 finds itself in the neutral region , midway between B1(N) and A2(N)(in step (b)). In step(c), A2 and B2 are on. S3 and S1 tend to algin with A2(N) andB2(N), respectively, with N2 in neutral zone. Step(d) illustrates the case when A1 andB2 are on.

ALGORITHM:

1.

Load the input data.

2.

Move the count value to B register.3. Send data to the output device through port.4. Call the delay program5. After the delay time load the next data and repeat the same.6. By changing the delay time we can change the speed.




17/76






18/76






19/76



CLOCKWISE ANTICLOCKWISE

STEP

A1 A2 B1 B2 HEXA STEP A1 A2 B1 B2 HEXA

1 1 0 01

091 1 0 1 0 A

2 0 1 0 1 05 2 0 1 1 0 06

3 0 1 1 0 06 3 0 1 0 1 05

4 1 0 1 0 0A 4 1 0 0 1 09

PROGRAM:FORWARD DIRECTION


1018 LOOKUP




20/76



REVERSE DIRECTION


RESULT:Thus a program to run a stepper motor at different speeds in two directions

was written and executed using 8086 p




21/76



EX.NO. :4

DATE :

ANALOG TO DIGITAL CONVERTER

AIM:To write an assembly language program to convert analog to digital output

APPARATUS REQUIRED:

8085 p kit, ADC board, Interface chord, Power chord.

ALGORITHM:

1. Load the data 10 H to make the ALE signal low.2. Load the data 18 H to make the ALE signal low.3. Place jumper J2 in B position.4. Place jumper J5 in A position.5. Enter & execute the program.6. Vary the analog input (using prompt) and give the SOC (by pressing the SOCswitch).7. Set the corresponding digital value in the LED display.

THEORY:

The device contains an 8 channel single ended analog signal multiplexer. Aparticular input channel is selected by using the address decoding.

I/O decoding

A 3:8 decoder 74LS138 is employed to generate I/O decoding logic. The addresslines A3, A4, and A5 are tied to pin 1, 2, 3 of 74LS138 respectively. The address linesA6 and A7 are NANDed together and the NAND gate o/p is connected to pin 5 of74LS 138.similarly IOW and IOR signals NANDed together and the NAND gate o/p

is connected to pin 6 of 74LS 138. Pin 4 is grounded. The buffer 74LS244 whichtransfers the converted data output to data bus is selected when

A7 A6 A5 A4 A3 A2 A1 A0

1 1 0 0 0 X X X

=C0 H




22/76






23/76






24/76



The I/O address for the latch 74LS174 which latches the data bus to address A,B,Cand ALE1 and ALE 2.

A7 A6 A5 A4 A3 A2 A1 A0

1 1 0 0 1 X X X=C8

Data to be outputted to port address C8 for channels 0 to 7

PROGRAM:


MVI A,10

OUT 0C8 H

MVI A,18

OUT 0C8 H

HLT

S.No Channel No EOC address in Hexa Data in Hex

Channel NoALE HighOE Low

Channel NoALE LowOE High

12

345678

CHOCH1

CH2CH3CH4CH5CH6CH7

D8D8

D8D8D8D8D8D8

1819

1A1B1C1D1E1F

1011

121314151617




25/76



MANUAL CALCULATION

RESULT:

Thus the assembly language program to convert analog to digital output digitaloutput was executed successfully.




26/76



EX.NO. :5

DATE :

GENRATION OF SIMPLE WAVEFORMS USING DAC

AIMTo generate square, sawtooth, triangular and sine waveforms using DAC.

APPARATUS REQUIRED:8085 p kit, CRO, DAC and interfacing chords.

CIRCUIT IMPLEMENTATION:The basic DAC interface board incorporates two 8 bit digital to analog

converters, DAC0800.The DAC interface section comprises of I/O decoding and D/Aconversion circuit.

I/O decoding

A 3:8 decoder 74LS138 is employed to generate I/O decoding logic. The addresslines A3, A4, and A5 are tied to pin 1, 2, 3 of 74LS138 respectively. The address linesA6 and A7 are NANDed together and the NAND gate o/p is connected to pin 5 of74LS 138.similarly IOW and IOR signals NANDed together and the NAND gate o/p

is connected to pin 6 of 74LS 138. Pin 4 is grounded.

Thus with

A7 A6 A5 A4 A3 A2 A1 A0

1 1 0 0 0 X X X

=C0 H DAC1 is selected, and with

A7 A6 A5 A4 A3 A2 A1 A0

1 1 0 0 1 X X X

=C8DAC2 is selected




27/76



The o/p voltage between -5V and 5V.the o/p voltage varies in steps of 10/256=.04

i/p data in hexa o/p voltage

000102......7F..FDFEFF

-5.00-4.96-4.92......0.00..4.924.965.00

SQUARE WAVEFORM AT DAC 2 OUTPUT:

ALGORITHM:1. Clear the accumulator to Display low level of square wave2. Send the data to o/p device through port3. Call the delay program.4. Load the accumulator with FF to Display high level of square wave5. Send the data to o/p device through port6. Call the delay program7.

Continue from step1

PROGRAM:





28/76



OUTPUT:

SAWTOOTH WAVEFORM AT DAC 1 OUTPUT:

ALGORITHM :1. Clear the accumulator

2.

Send the data to o/p device through port3. Incrment the accumulator to display next o/p voltage.4. Do the above process until zero flag is set5. Continue from step1

PROGRAM:


OUTPUT:

TRIANGULAR WAVEFORM AT DAC2OUTPUT:

ALGORITHM:1. Clear the accumulator through L register.2. Send the data to o/p device through port3. Incrment the L register

4.

Do the above process until zero flag is set5. Load the accumulator with FF through L register.




29/76



6. Send the data to o/p device through port7. Incrment the L register8. Do the above process until zero flag is set9. Continue from step1

PROGRAM:

OPCODE

MOV BL,00MOV AL,BLOUT C8,AL

INC BLJNZ 1003MOV BL,FFMOV AL,BLOUT C8,ALDEC BLJNZ 100EJMP 1000

OUTPUT:

SINE WAVEFORM GENERATION AT DAC1 OUTPUT:

ALGORITHM:1.

Load 49 input datas to generate sine wave in lookup table2. Load the count as 49 in C register3. Send the data to o/p device through port4. Load the next data5. Decrement the count and check if it is zero6. If zero go to the loop or else go to step 1




30/76



FORMULA USED:

128+128 SINX WHERE X=0 to 360 with step 5

EXAMPLE:

DEGREES DECIMAL HEXA

0 128 80

PROGRAM:


1100 LOOKUP

MOV BX,1100MOV CL,49MOV AL,[BX]OUT C0,ALINC BX

LOOP 1007

JMP 100080,8B,96,A1,AB,B6,C0,C9,D2,DA,E2,E8,EF,F4,F8,FB,FE,FF,FF,FF,FF,FE,FB,F8,F4,EF,E8,E2,DA,D2,C9,C0,B6,AB,A1,96,8B,80,74,6A,5F,54,4A,40,36,2E,25,1E,17,11,0C,08,04,02,00,00,00,02,04,08,0C,11,

17,1E,25,2E,36,40,4A,54,5F,6A,74,80




31/76



RESULT: Thus the square, saw tooth, triangular and sine waveforms were generatedusing 8086 p.




32/76



EX.NO. :6

DATE :

INTERFACING & PROGRAMMING OF 8253 WITH 8086

MICROPROCESSOR

AIM:

To write the program for interfacing 8253 with 8085 microprocessor in mode0and mode 3.6APPARATUS REQUIRED:

8085 p kit,8253 interfacing board, interfacing chord, power chord,CRO, probe.

CIRCUIT IMPLEMENTATION:

I/O decoding

A 3:8 decoder 74LS138 is employed to generate I/O decoding logic. The addresslines A3, A4, and A5 are tied to pin 1, 2, 3 of 74LS138 respectively. The address linesA6 and A7 are NANDed together and the NAND gate o/p is connected to pin 5 of74LS 138.similarly IOW and IOR signals NANDed together and the NAND gate o/pis connected to pin 6 of 74LS 138. Pin 4 is grounded.

THEORY:

The I/O address of control register, channel 0, channel 1 and channel 2.

A7 A6 A5 A4 A3 A2 A1 A0 HexaControl register 1 1 0 0 1 1 1 0 CEChannal 0 1 1 0 0 1 0 0 0 C8Channal 1 1 1 0 0 1 0 1 0 CAChannal 2 1 1 0 0 1 1 0 0 CC

The chip 8253 has a control register which stores the operational modeof each counter. This register can only be within into, no read operation of its contentsare possible .Each counter of 8253 can be individually programmed by writingcorresponding control words by simple I/O operation.

CONTROL WORD FORMAT:

D7 D6 D5 D4 D3 D2 D1 D0

D7 D6 ---- Select counter(SC1,SC0)D5 D4 ---- Read/Write(RL1,RL0)D3 D2 D1 ---- Mode(M2,M1,M0)D0 ---- BCD




33/76



SELEST COUNTER RD/WRD7 D6 D5 D40 0 CH0 0 0 Latch0 1 CH1 0 1 LSB

1 0 CH2 1 0 MSB1 0 X 1 1 LSB/MSB

D3 D2 D1 MODE0 0 0 00 0 1 10 1 0 20 1 1 31 0 0 41 0 1 5

CONTROL WORD

D7 D6 D5 D4 D3 D2 D1 D00 0 1 1 0 0 0 0 -------- 30-------------- -------------- ---------------------- ----Channel 0 LSB/MSB Mode 0 binary

D7 D6 D5 D4 D3 D2 D1 D00 0 1 1 0 1 1 0 -------- 36-------------- -------------- ---------------------- ----Channel 0 LSB/MSB Mode 3 binary

ALGORITHM:1. Load the accumulator with control word for channel 0and mode 0

selection.2. Move the data to control register.3. Load the MSB and LSB of count4. Move the data to data register




34/76



OUTPUT:

EXAMPLE:

CLOCK FREQUENCY=1.5MHZREQUIRED FREQUENCY=150KHZCOUNT=1.5M/150K=10 (decimal)=0A(hexa)

MANUAL CALCULATION:

OUTPUT:




35/76



PROGRAM:MODE 0- INTERRUPT ON TERMINAL COUNT


START MOV AL,300UT CE,ALMOV AL,05OUT C8,ALMOV AL,00OUT C8,ALHLT

ALGORITHM:MODE 3- SQUARE WAVE GENERATOR

1 Load the accumulator with control word for channel 0and mode 3selection.

2 Move the data to control register.3 Load the MSB and LSB of count4 Move the data to data register

PROGRAM:MODE 3- SQUARE WAVE GENERATOR


START MOV AL,360UT CE,ALMOV AL,OUT C8,ALMOV AL.OUT C8,AL

HLT




36/76



RESULT: Thus the program for 8253 interfacing with 8086 microprocessor waswritten successfully.




37/76



EX.NO. :7

DATE :

PROGRAMMING & INTERFACING OF 8279 WITH 8085

MICROPROCESSOR

AIM:

To write the program for keyboard & Display interfacing using 8279.

APPARATUS REQUIRED:

8086 p kit, 8279 interface board, Interface chord, Power chord.

CIRCUIT IMPLEMENTATION:

I/O decoding

A 3:8 decoder 74LS138 is employed to generate I/O decoding logic. The addresslines A3, A4, and A5 are tied to pin 1, 2, 3 of 74LS138 respectively. The address linesA6 and A7 are NANDed together and the NAND gate o/p is connected to pin 5 of74LS 138.similarly IOW and IOR signals NANDed together and the NAND gate o/pis connected to pin 6 of 74LS 138. Pin 4 is grounded.

I/O DecodingAddress

Control /Status Register C2

Data Register C0

Segment Definition

ab

c

d

Databus

D7 D6 D5 D4 D3 D2 D1 D0

Segment D C b a dp g f e




38/76



COMMAND WORD FORMAT :Display Mode set up

0 0 0 D D K K K

DD (Display Mode)

00- 8 bit character display left entry01-

16 bit character display left entry10- 8 bit character display right entry11- 16 bit character display right entry

KKK (Keyboard Mode)

000-2 Key lockout

0 0 0 0 0 0 0 0

=00

Clear Display(110)

1 1 0 CD CD CD CF CA

1 1 0 0 1 1 0 0

=CC H

Write display RAM(100)

1 0 0 AI A A A A

1 0 0 1 0 0 0 0

=90 H

Read FIFO RAM(010):

0 1 0 AI X A A A

0 1 0 0 0 0 0 0

=40




39/76



Read FIFO Status

DU S/E O U F N N N

0 0 0 0 0 1 1 1=07

CLEAR DISPLAY RAM

1 1 1 1 1 1 1 1

=FF

(A) KEYBOARD INTERFACE

ALGORITHM:

1.

Load the data count in B register2.

Set display mode3. Move the data to control register.4. Clear display.5. Move the data to control register.6. Write display RAM7. Move the data to control register8. Clear the display RAM9. Move the data to data register.10.Decrement the count11.

Repeat the step5 for all the data display

12.

Check whether the key is pressed or not13.If the key is pressed go to next step otherwise repeat step 12.14.Set to read FIFO RAM.15.Move the data to control register16.Get the data from the pressed key & display it




40/76



PROGRAM:ACCEPT A KEY AND DISPLAY IT

ADDRESS LABEL MNEMONICSOPCODE

LOOKUP TABLE

4200 0C 9F 4A 0B

4204 99 29 28 8F

4208 08 09 88 38

420C 6C 1A 68 E8




41/76



(B) (ROLLING DISPLAY)

ALGORITHM:

1.

Initialise the counter2. Set Display mode.3. Move the data to control register4.

Clear display5. Move the data to control register6. set the write display RAM7. Move the data to control register8. Get the first data to be displayed9. Display the data10.Call the delay subroutine11.Get the next data & repeat the steps 9,10until the count is zero




42/76



PROGRAM


LOOK UP

1200 FF FF FF FF

1204 FF FF FF FF

1208 98 68 7C C8120C 1C 29 FF FF




43/76



RESULT:

Thus keyboard & Display were interfaced with 8279 by using8086microprocessor.




44/76



EX.NO. :8

DATE :

MAXIMUM AND MINIMUM OF NUMBERS

AIM:To write a program for searching largest and smallest numbers in an array using

8086p.

APPARATUS REQUIRED:8086 p kit, keyboard, power chord.

MINIMUM NUMBER:

ALGORITHM:

1.

Get the COUNT in CX register and inputs in specified memory location.2.

Compare the 1sttwo datas and load the small data in accumulator.3. Compare the accumulator with the remaining datas and store the smallest

data in accumulator.4. Stop the program.

PROGRAM:


START

L2

L1

MOV DX,05DEC DXMOV CX,DXMOV BX,1100MOVAX,[BX]ADD BX,2CMP AX,[BX]JB L1MOV AX,[BX]LOOP L2MOV [1500],AXHLT




45/76



MAXIMUM NUMBER:

ALGORITHM:1. Get the COUNT in CX register and inputs in specified memory location.

2 .Compare the 1st

two datas and load the small data in accumulator.3. Compare the accumulator with the remaining datas and store the largestdata in accumulator.5.

Stop the program.

INPUT:

OUTPUT:

MANUAL CALCULATION:

INPUT:

OUTPUT:




46/76



PROGRAM:


START

L2

L1

MOV DX,05DEC DXMOV CX,DXMOV BX,1100MOVAX,[BX]ADD BX,2CMP AX,[BX]JNB L1

MOV AX,[BX]LOOP L2MOV [1500],AXHLT

RESULT:Thus the ALP for searching largest and smallest numbers from an array of

datas was executed using 8086p.




47/76



EX.NO.:9

DATE :

SORTING AN ARRAY

AIM:To write a program to sort an array in ascending and descending order by using

8086 p.


ASCENDING ORDER:

ALGORITHM:1. Get the number of inputs.

2.

Load the inputs in memory location 1100.3. Compare the 1stand 2nddata.4. If there is carry go to step 6.5. If no carry exchange two datas.6. Compare 2ndand 3rd data and repeat the same up to last data.7.

Now, we get the largest number in the last place.8. Repeat the steps from 3.9. Stop the program.

PROGRAM:


STARTL1

L2

L3

MOV CX,05MOV DX,CXMOV BX,1100MOV AX,[BX]CMP AX,[BX+2]JB L3

XCHG [BX+2],AX

MOV [BX],AXADD BX,2LOOP L2MOV CX,DXLOOP L1HLT




48/76



INPUT:

OUTPUT:

MANUAL CALCULATION:




49/76



DESCENDING ORDER :

ALGORITHM:1. Get the number of inputs.2. Load the inputs in memory location 1100.3.

Compare the 1stand 2nddata.4. If there is no carry go to step 6.5. If there is carry exchange two datas.6. Compare 2ndand 3rd data and repeat the same up to last data.7. Now, we get the smallest number in the last place.8. Repeat the steps from 3.9. Stop the program.

PROGRAM:


STARTL1

L2

L3

MOV CX,05MOV DX,CXMOV BX,1100MOV AX,[BX]CMP AX,[BX+2]JNB L3

XCHG [BX+2],AXMOV [BX],AXADD BX,2LOOP L2MOV CX,DXLOOP L1HLT




50/76



INPUT:

OUTPUT:

MANUAL CALCULATION:

RESULT:Thus an ALP for sorting an array in ascending and descending order were

executed using 8086 p.




51/76



EX.NO. :10

DATE :

STRING MANIPULATIONS

AIM:To write an ALP for performing string manipulation using 8086.


a) MOVING AN ARRAY OF DATA FROM SOURCE TODESTINATION

ALGORITHM:1. Load the source and destination address.2. Load the no of datas.3. Facilitate auto increasing of the index register.4. Move the string byte up to the last data.5. Stop the program.

PROGRAM:


L1

MOV SI, 2000MOV DI, 2100MOV CX, 05CLDMOV SBLOOP L1HLT




52/76



b) STORING A DATA IN SET OF LOCATIONS:

OBJECTIVE:

To fill the locations in memory with the byteINPUT:

OUTPUT:

MANUAL CALCULATION:

ALGORITHM:1. Load the number of inputs.2. Load the destination address.3. Load the data byte.

4.

Facilitate auto incrementing of index register.5. Store the data in the locations up to the last location.6. Stop the program.




53/76



PROGRAM:


L1

MOV CX, 0006MOV DI, 1100MOV AX, 0034CLDSTO SBLOOP L1

HLT

c) CALCULATING THE LENGTH OF A STRING:

OBJECTIVE:To find the number of character in a string

ALGORITHM1.

Load the source address.2. Clear the count register.3. Load the assumed last data.4. Increment the count.5. Compare the data in source register with last data.6. If both the datas are same, store the count in location 1100.7. If both the datas are not same, increment the source address and load

the second data.8. Repeat the steps from 4.

INPUT:

OUTPUT:




54/76



MANUAL CALCULATION:

PROGRAM:


L1

MOV SI, 1200MOV DX, FFFFMOV AH, FFINC DXMOV AL,[SI]INC SICMP AH, ALJNZ L1MOV [1100], DXHLT




55/76



RESULT:Thus the programs for string manipulation operations were performed by using

8086 p.




56/76



EX.NO. :11

DATE :

ARITHMETIC OPERATIONS USING 8051

MICROCONTROLLER

AIM:To write the microcontroller programs to perform 8 bit arithmetic operations.

APPARATUS REQUIRED :8051 microcontroller kit, power chord.

8-BIT ADDITION:

ALGORITHM:

1.

Clear C register for carry2. Load the addend3. Add the augend and addend4. If there is no carry,store the result5. If there is carry, increment the C register and store results6. Stop the program

PROGRAM:


STOP

ORG 4100CLR CMOV A,#09ADD A,#05MOV DPTR,#4150MOVX @DPTR,AINC DPTR

MOVX @DPTR,ASJMP STOP




57/76



INPUT:

OUTPUT:

MANUAL CALCULATION:




58/76



8-BIT SUBRACTION:

ALGORITHM:

1.

Clear C register for carry2. Load the minuend3. Subtact the subtrahend from minuend4.

If there is no carry,store the result5. If there is carry, increment the C register and store results6. Stop the program

PROGRAM:

ADDRESS LABEL MNEMONICS

OPCODE

STOP

ORG 4100CLR CMOV A,#32SUBB A,#30

MOV DPTR,#4150MOVX @DPTR,A

SJMP STOP

8-BIT MULTIPLICATION:

ALGORITHM:

1.

Load the two datas in A and B registers2. Multiply the two datas3. Store the result4.

Stop the program




59/76



INPUT:

OUTPUT:

MANUAL CALCULATION:

INPUT:

OUTPUT:

MANUAL CALCULATION:




60/76



PROGRAM:

ADDRESS LABEL MNEMONICS

OPCODE

STOP

ORG 4100MOV A,#12MOV B,#12MUL ABMOV DPTR,#4500MOVX @DPTR,AINC DPTRMOV A,BMOVX @DPTR,ASJMP STOP

8-BIT DIVISION:

ALGORITHM:1. Load the dividend and divisor2. Divide the dividend by divisor3. Store the quotient and reminder4. Store the program

PROGRAM:


STOP

ORG 4100MOV A,#12MOV B,#12DIV ABMOV DPTR,#4500

MOVX @DPTR,AINC DPTRMOV A,BMOVX @DPTR,ASJMP STOP




61/76



RESULT:Thus the 8-bit arithmetic operations like addition, subtraction, multiplicationand division by using 8051 microcontroller and cross assembler were performed andexecuted




62/76



EX.NO. :12

DATE :

BIT MANIPULATIONS USING 8051 MICROCONTROLLER

AIM:To write a program for setting and masking the bits in a b-bit data using 8051.

APPARATUS REQUIRED:8051 microcontroller kit, power chord

SETTING THE HIGHER ORDER BITS:

ALGORITHM:

1.

Load the given data2.

Set the bit by ORing that particular bit by 13. Store the result and stop the program.

PROGRAM:


STOP

ORG 4100MOV A,#32ORL A,#F0

MOV DPTR,#4500MOVX@DPTR,ASJMP STOP

MASKING THE HIGHER ORDER BYTES:

ALGORITHM:1.Load the given data2.Set the bit by ANDing that particular bit by 13.Store the result and stop the program.

PROGRAM:


STOP

ORG 4100MOV A,#32ANL A,#0FMOV DPTR,#4500MOVX@DPTR,A

SJMP STOP




63/76



RESULT:

Thus the program for masking and setting the higher order bits by using 8051microcontroller and cross assembler were performed and executed .




64/76



EX.NO. :13

DATE :

LOGICAL OPERATIONS USING 8051 MICROCONTROLLER

AIM:To write a program for finding 1`s and 2`s complement of the given number and

for the conversion of binary to gray using logical list.

APPARATUS REQUIRED:8051 microcontroller kit,power chord.

1`S AND 2`S COMPLEMENT:

ALGORITHM:1.

Load the given data in accumulator2. Complement the accumulator3. Store the complement result4. Increment the result by 1 and store5. Stop the program

PROGRAM:


STOP

ORG 4100MOV A,#12CPL AMOV DPTR,#4200MOVX@DPTR,AINC AINC DPTRMOVX@DPTR,ASJMP STOP

RESULT:Thus a program for performing logical operations using 8051 and cross

assemler were executed




65/76






66/76






67/76






68/76






69/76



FAQ

1. Define opcode and operand?

2.

What is Instruction cycle?

3. What is processor cycle (Machine cycle)?

4. Types of addressing modes?

5. What is immediate addressing mode?

6. What is direct addressing mode?

7. What is register addressing mode?

8. What is indirect addressing mode?

9. What is implied addressing mode?




70/76



10. What is the function of LXI H, 4000 instruction?

11. What is the function of INX H instruction?

12. What is the function of DCX H instruction?

13.

What is the function of LHLD, 4200 instruction?

14.What is the function of XCHG instruction?

15.. What is the function of DAD instruction?

16.What is the function of SHLD instruction?

17.What is the function of SBB,B instruction?

18.What is the function of SPHL instruction?




71/76



19. What is the function of ORA D instruction?

20.What is the function of OUT & IN instruction?

21.What is the function of control& data register?

22.What is the difference between CALL &RET instruction?

23. Define interrupts?

24. What is the function of subroutine?

25.What is the function of RST instruction?

26. What is the function of JNC instruction?

27.What is the function of MVI instruction?

28.What is the function of STA instruction?




72/76



29.What is the function of MOV A, C instruction?

30.What is the function of INR instruction?

31. What is the function of DCR instruction?

32.What is the function of JNZ instruction?

33. Why interfacing is needed for I/0 devices?

34.

List some of the features of INTEL 8259(Programmable Interrupt Controller)

35.

What is the function of DEC DX instruction?

36. What is the function of LOOP instruction?




73/76



37. What is the function of JNB instruction?

38. What is the function of MOV instruction in 8086 processor?

39. What is the function of CLD instruction?

40. What is the function of STOSB instruction?

41. What is the function of INC DX, INC SI instruction?

42. What is the function of MOV DPTR, # 4150 instructions?

43. What is the function of MOVX @ DPTR, A instruction?

44. What is the function of SJMP instruction?

45. What is the function of ORL, ANL, and CPLA instruction?




74/76



46. What is the function of MUL AB instruction?

47. What is the function of INC DPTR instruction?

48. What is the function of LDA instruction?

49. What is the function of JMP instruction?

50. Give some examples of input devices to microprocessor-based system.

51. What is mean by microcontroller?

52. List the features of 8051 microcontroller?

53. What is the function of CMP M instruction?

54. What is the function of JNC instruction?




75/76






76/76



microprocessor lab - einstein

Documents