lab and assignment 2

14
REACTOR FOR PETROCHEMICAL CCB4433 ASSIGNMENT & LAB Mohamed Asyraf Bin Mohamed Lias 15564 Muhammad Farid BinShahman 15566 Khairil Amri Bin Romli 15387 Mohd Eshar Bin Abdul Halim 15638

Upload: kechikkrunch

Post on 05-Dec-2015

10 views

Category:

Documents


4 download

DESCRIPTION

Reactor design for petrochemical Lab and assignment using polymath

TRANSCRIPT

REACTOR FOR PETROCHEMICAL

CCB4433

ASSIGNMENT & LAB

Mohamed Asyraf Bin Mohamed Lias 15564

Muhammad Farid BinShahman 15566

Khairil Amri Bin Romli 15387

Mohd Eshar Bin Abdul Halim 15638

: ' ':

tl ko'n 'rdesl gqr lqu-,-

Pr=CrRT

tr= b o hoU

-

- U--C t+ Er)

Fr. ( 1 -x;\,- (t t Lr)

= CA. f t-x\Lffi)P,- (". f t-- L'- \#) B'"H) (#)

t* irottcrrnql .,,*i h'sn

1) dg _6j

{u rg

')g t' -0t dw

/U'*c , -o(\,z

ut'C-fir^ro

q* b,l , r^I-{)

lt' c - oc --l

St, l- qu i

l

$ =tt : ot u)

vz I , ( t-n-J'.,p.--*

2

OBJECTIVES

In this assignment, there are several objective to be achieved:

1. To solve using two method which are manually and using polymath software

2. To investigate the effect of varying the parameter chosen

3. To compare the weight of catalyst using different reactor Packed bed and fluidized

bed (CSTR).

RESULT AND DISSCUSSION.

1.0 Simulation on hydrogenation of ethylene to ethane (10.4).

The hydrogenation of ethelene to Ethane is carried out over a cobalt molybdenum catalyst.

The simulation is carried out based on the data given:

Run No. Reaction rate PE PEA PH

1 1.04 1 1 1

2 3.13 1 1 3

3 5.21 1 1 5

4 3.82 3 1 3

5 4.19 5 1 3

6 2.391 0.5 1 3

7 3.867 0.5 0.5 5

8 2.199 0.5 3 3

9 0.75 0.5 5 1

Table 1 : Diffrential Reactor Data

The simulation tested the data given through 4 different model equation which have

shown different result and values. The result of simulation will only cover the variance

value which indicate the best model of equation for the system.

3

Figure 1: Model 1 simulation result

Model 1 equation show the unrealistic result when the value of KEA can reach to

negative value since the value is 0.019 +-(0.03). This result shows that the model equation

cannot be used for the hydrogenation process. As Conclusion model 1 equation is not

suitable for the hydrogenation system.

Figure 2: Model 2 simulation result

Model 2 equation show good result because its shows very low value of variance

which is 0.0060534. Therefore Model 2 equation is suitable for the hydrogenation system

calculation.

4

Figure 3: Model 3 simulation result

Model 3 equation show good result because its shows very low value of variance which is

0.0623031. However the variance is higher than the model 2.

Figure 4: Model 4 simulation result

Model 4 equation show good result because its shows very low value of variance which is

0.0495372. However the variance is higher than the model 2.

5

2.0 Catalyst Decay in a Fluidized Bed Modeled as a CSTR(10.6).

The feed stream contains 80% crude and 20% inert. The crude oil contains sulphur

compounds, which poison the catalyst. The rate of catalyst is first order in the crude oil

concentration. The rate of catalyst decay is first order in the present of activity, and the

first order in the reactant concentration. The volumetric feed rate is 5000 m3/h. there are

50,000 kg of catalyst in the reactor and the bulk density is 500 kg/ m3.

Figure 5: Variation of C, a, and X with time in a CSTR.

The graph show the variation of concentration, activity and conversion of the

particular component with the function of time. The X- axis indicates the time of decay

which is 0.5. The concentration show the two direction which is decreasing and increasing.

The concentration decrease until time 0.05 and the increase until t=0.5. While the activity

show the decreasing order which ended at value of 0.2 at t=0.5. The conversion also show

two type of direction which are increasing and decreasing. The conversion increase until =

0.05 and the slightly decrease until t=0.5 with value of 0.35.

6

Figure 6: Catalyst Decay in a Fluidized Bed Modeled as a CSTR simulation result

7

3.0 Decay in Straight-Through Transport Reactor(10.8).

.Figure 7: Catalyst Decay in a Fluidized Bed Modeled as a CSTR simulation result

The graph show the variation of conversion of the particular component with the function

of height of reactor. The X- axis indicates the height of reactor which is 10m high. The

concentration show the two direction which is decreasing and increasing. The conversion

also increasing order which give value of 0.55 at height of 10 m.

0" q (Examplz W,e)

GuS o) el -4 Troducls 7n)

A --> 8+(

CPO '0'g wal ld,,t

C"o : t- 0 r,*l /)n1

K = 0u*' ''*5 l"-/

k4 : 1 ),ru3/_a\.1^

O -ov {,a'tlancl V Coo - V Cn + ro, \il .3}1atL

AI4 "coY , r^V= rjw

VaCau -jG rraV _, V dCo

N

@ r<,t-(n (.rw -rn , LqLn

@) ,rrca;) law *t ,kaqedt

G) rbictriorv'<1y, 'j = F , l{tx'-Vo F.ro

X = l- l-0. , [* Crjl-oo coo)o

i .l+t,t!1 lYo C.o'01

L . )oo6 -- (i*t-l) Jco ,)+o. !o"Cto

v - r{u - Cl '- , \ JaDVo Crd )o

ItY) : lo 'JRo

-

1t (n /Cto

G.p) rutubinq.I

\rCno - Va (l* )r.o ) 6.,

r+ CnlQokaCrY 'V

Volur,. e to"[ r" .riJ e r

" (no (r+;^")/(t t elc,") + a rk

Co

"lCaA+-

4iv',{c b3

vde

) w\evt (-- - vO

f-6T *\^€ U\lLfgtoh . X

x" jj:{Fno

= 1- 9Ce

Yo (no

. t-l r{Jno \ -(ar---__lC^oL t *(r/cro j

{:

;

h-\b

5 o oo o

;-' iuo

Go'o

- lO0 n'

5o oc>

-- 0-02h

rq*e lqwi -f ; . Y'?a

QaE d\ ql , froor.t-ct"r( ! I c,:Ve

A + B+<{tutr.

[ + Ka0,q t tu l, + fc]c

ui.ovt V,, , o-6ol( KwLa[ )y3.5 "atm

"lKn . O-Oe atvt'

-lKg, ' o-tg q{r"

".tKc . o-l o{t"

d€<ay laur : q"-1 tl>A :-7 bs'I + At'"

O v"n"\o $q\ar47s "' Foo { , - y6'td.z

@@ rct4L l,a* :

A dtc"y {aw I

io" - J, 4. Cqo

U ' -r'ad'2

Uj Cn,>

-I'o(t.,) : P'- fn

i t KB?n 1 Ks ps { K"?,

A65qm? Up = U9 " U

*rA = ?,8(*r'o)

-''* ' o[-rn Lt.ol

+--zU

4:\\12,+A(zi\))

whete U ' V /Ac , \rfu+Ll)f A"

41' f,r-D' /+

S-t6 \.V'i d t[etrY

o

O lvot\r.qts

J as t h'r,r { isotLPrrwq I

ho ?rrsr4re &V,P

\^y?po Ha"

?o', X

\{t1

-p. ,B

b\n:

?5

0l1

La.l

.)qo 6 ,0+r -l ) , )

,J =U^[t+tx)

:!:-RI"

o,otu letS)

O.2z !r'"t\ f r':

e

1(0"

f')"

_k-

tr rt{'-:: I axLCn. ,) . tt_x)'

5)

Fn"

^XJ rr _")o

-2clx

u

_qde

= clu,

i^ ' l*L '-"-le

!1=crUs

- - ljg'

o Fe"

L Cao" rls

f, -.wtr Cr" (

t\Fe. J"

ue clu

-q

let ;-

-(H) - '

-q\^J:dq j

dq

-q

t t"*l .

(t-".^")

(, .lrJ)I :(*x

F,*. taq

l. Cn.' {.Fao tt "\

-(ko lu' ) .^,

d \,"t

f *

- (Lu tus) r^r

\eJ"

cl ut

A {2 t L'+ LAue

tonce{lhv*Ir,oA qlt 9'\6 L+' Cw '\ C115 )f (g1 '+ Cr,s

-ot*s: zc>ocen.hq$,on A

Lgs i ta; :

cbs,k @

@ , vteLt ?tL,cvi v.?(anr €t\4

(g+f a? aJ:O"pt'96, i !',^/

=0a'C^5 frec+i6,n sf sqbce $;l€LL fr,prc) ur't\ A

{rd !c{, , ('a+ Ca; t kg? tsl + (c? c Ls;

?n In l*[?nYnl ?n uA 9n'rn

cos fn V Ca< [^ ?

rQle tqi,r-r I

*r ,6tr

(a

bl.-/c)

L,U

[nv a Ve Ye 8n v

+ Yc?c

KrP

(o ?

1+ r(A0A + Ye?a t V" Pe

,C

'=rA: qL-c'AL*,o)]

(7

0p

i+l(0

guVr'i; ir:{ e e2ued on 6, {9 on}