key questions ece 340 lecture 3 : semiconductors why is...
TRANSCRIPT
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ECE 340 Lecture 3 : Semiconductors
and Crystal Structure
Class Outline:
• Semiconductor Crystal Lattices • Miller Indices v Semiconductor Crystal Growth M.J. Gilbert ECE 340 – Lecture 3
Things you should know when you leave…
Key Questions
• Why is crystal order important? • How is a crystal defined? • What are the most common
types of crystal lattices used in semiconductor devices?
M.J. Gilbert ECE 340 – Lecture 3
Semiconductor Crystal Lattices
• Crystal structures come in three basic kinds – In the CRYSTALLINE state the atoms are ordered into a well-defined lattice that
extends over very long distances .
– POLYCRYSTALLINE materials consist of small crystallites that are embedded in AMORPHOUS regions of material.
– In the AMORPHOUS state there is little or no evidence for long-range crystalline order.
polycrystalline amorphous crystallinepolycrystalline amorphous crystallinepolycrystalline amorphous crystalline
What is the crystal structure?
Crystalline Polycrystalline Amorphous
M.J. Gilbert ECE 340 – Lecture 3
Semiconductor Crystal Lattices
• We can get a lot of information from the unit cell: – Density of atoms – Distance between nearest atoms
• Calculate forces between atoms – Perform simple calculations
• Fraction of atoms filled in volume • Density of atoms
What does it matter if it is crystalline or not?
Crystalline Amorphous
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M.J. Gilbert ECE 340 – Lecture 3
Semiconductor Crystal Lattices
• In the periodic lattice: – Symmetric array
of points is the lattice.
– We add the atoms to the lattice in an arrangement called a basis.
– We can define a set of primitive vectors which can be used to trace out the entire crystal structure.
Since we care about crystalline lattices, let’s examine the periodic lattice…
+
Basis 2D Crystal
=
2D lattice where the grey balls denote lattice points
M.J. Gilbert ECE 340 – Lecture 3
Semiconductor Crystal Lattices
• Examine the simple cubic structure: – All primitive vectors are equal in all three dimensions.
– Here again, the balls represent the lattice points, but no basis has been added.
In this section we consider some of the lattice types that will be important for our discussion of semiconductors…
y
x
z
a
)2.2(ˆ2 ya a=
)1.2(ˆ1 xa a=
)3.2(ˆ3 za a=
M.J. Gilbert ECE 340 – Lecture 3
Semiconductor Crystal Lattices
• Examine the body-centered cubic lattice (bcc): – Same as simple cubic but with an additional atom at
the center of the cell. – Primitive vectors are written in the more convenient
symmetric form but other representations exist.
[ ]
[ ]
[ ]zyxa
zyxa
zyxa
ˆˆˆ2
ˆˆˆ2
ˆˆˆ2
3
2
1
+−=
++−=
−+=
a
a
a
y
x
a
(2.4)
(2.6)
(2.5) z
A simple variant on the cubic lattice is the body-centered cubic lattice…
M.J. Gilbert ECE 340 – Lecture 3
Semiconductor Crystal Lattices
• Examine the face-centered cubic lattice (fcc): – This is formed by adding an additional atom in the center
of each face of the simple cubic configuration. – This is the most important configuration we will consider. – The primitive vectors have been written again by using
symmetry considerations.
A final variant is the face-centered cubic lattice…
y
x
z
a
[ ]
[ ]
[ ] )9.2(ˆˆ2
)8.2(ˆˆ2
)7.2(ˆˆ2
3
2
1
xza
zya
yxa
+=
+=
+=
a
a
a
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M.J. Gilbert ECE 340 – Lecture 3
Semiconductor Crystal Lattices
• There is a difference between unit cells and primitive cells. – The primitive cell is the volume associated with one
lattice point. – Often it is more convenient to use a unit cell that is
larger than the primitive cell since such a cell illustrates the crystal symmetry in a clearer way.
a
THE GRAY REGION DENOTES THE PRIMITIVE CELL FOR THIS LATTICE WHOSE VOLUME CAN BE DETERMINED FROM THE PRIMITIVE VECTORS INTRODUCED IN Eqns. 2.7 - 2.9
)10.2(3213 aVunit =⋅⋅= aaa
)11.2(4
)(3
213aVprimitive =×⋅= aaa
But be careful…
IN THIS FIGURE THE DOTTED LINES INDICATE THE UNIT CELL OF THE FACE-CENTERED CUBIC LATTICE
M.J. Gilbert ECE 340 – Lecture 3
Semiconductor Crystal Lattices
• To discuss the crystal structure of different semiconductors we will need to account for the basis unit that is added to each lattice point. – Elemental semiconductors such as silicon and germanium both exhibit
the diamond structure. – Named after one of the two crystalline forms of carbon.
Now let’s look at the silicon crystal…
• Here we display the silicon unit cell.
• The balls each represent one silicon atom.
• The solid lines represent chemical bonds.
• Note how the bonds form a tetrahedron.
• How many atoms per unit cell?
M.J. Gilbert ECE 340 – Lecture 3
Semiconductor Crystal Lattices
• It is really just two inter-penetrating fcc lattices with a diatomic basis. • It looks more complex because we do not show atoms extending beyond
the unit cell by convention. • In the figure below, each different color represents pairs of atoms
from the same basis. • The black balls represent atoms with one atom in their basis outside the
unit cell.
UNIT CELL LATTICE BASIS
)0,0,0(
)ˆ,ˆ,ˆ(4
zyxa
Looks confusing, but it’s not so bad…
M.J. Gilbert ECE 340 – Lecture 3
Semiconductor Crystal Lattices
• Many compound semiconductors such as Gallium Arsenide (GaAs) exhibit the zincblende crystal structure. – The atomic
configuration is the same as diamond.
– The difference lies in that each successive atom is from a different chemical element.
What about compound semiconductors? Gallium
Arsenide
Useful questions to ask: • How many atoms per unit cell? • Avogadro’s number: NA = # atoms / mole • Atomic mass: A = grams / mole • Atom counting in unit cell: atoms / cm3 • How do you calculate density?
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M.J. Gilbert ECE 340 – Lecture 3
Miller Indices
• The periodicity could possibly be used to define a series of planes.
• For any direction one could define many different equivalent planes.
• For instance, consider the different equivalent crystal planes in a cubic lattice.
How do we classify these periodic atomic arrangements?
M.J. Gilbert ECE 340 – Lecture 3
Miller Indices
1. Start with any arbitrary point in the crystal lattice. 2. Take the three primitive lattice vectors as axes. 3. Next we locate the intercepts of the desired plane with these
coordinate axes. 4. Finally, we take the reciprocal of the intercepts and multiply
each of these by the smallest factor required to convert them all to integers. – Indices which have no intercept have a Miller Index of zero.
We can classify crystal planes through the use of Miller Indices.
AXIS a1 a2 a3
INTERCEPT 3 2 2
RECIPROCAL
1/3
1/2
1/2
TO CONVERT THE RECIPROCALS TO INTEGERS WE NEED TO MULTIPLY BY A FACTOR OF SIX THIS YIELDS MILLER INDICES (233)
a1 a2
a3
LATTICE POINT
LATTICE POINT
LATTICE POINT
M.J. Gilbert ECE 340 – Lecture 3
Miller Indices
Applications of Miller Indices.
AXIS a1 a2 a3
INTERCEPT 2 4 3
RECIPROCAL
1/2
1/4
1/3
MILLER INDEX 6 3 4
AXIS a1 a2 a3
INTERCEPT 4 1 -2
RECIPROCAL
1/4
1/1
-1/2
MILLER INDEX 1 4 2
Notice how we denoted the miller index for a plane with a negative intercept
M.J. Gilbert ECE 340 – Lecture 3
Miller Indices
• Since we chose the origin arbitrarily when we began, Miller indices define a family of parallel planes.
• To denote crystal planes with the same symmetry, we use {hkl}.
• “h” is the x-axis intercept inverse, “k” is the y-axis intercept inverse, and “l” is the z-axis intercept inverse .
(100)
x
y
z
(010)
x
y
z
x
y
z
(001)
More Miller Indices:
All three planes shown here are related by simple rotations, thus they represent {100} family.
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M.J. Gilbert ECE 340 – Lecture 3
Miller Indices
• The direction [hkl] is used to denote the directions perpendicular to (hkl).
We can also use Miller Indices to denote directions:
[100]
[001]
[010]
[100]
[001]
[010]
( h k l )
[ h k l ]
Summary A crystal plane: (hkl)
Equivalent crystal planes: {hkl} Crystal direction: [hkl] (perpendicular to the plane (hkl) in a cubic lattice)
M.J. Gilbert ECE 340 – Lecture 3
Crystal Growth - Silicon
M.J. Gilbert ECE 340 – Lecture 3
Crystal Growth – Compound Semiconductors
• Heterojunctions are typically produced by a process known as MOLECULAR-BEAM EPITAXY – This is performed in an ultra-high vacuum (UHV)
evaporation chamber working at pressures of 10-11 Torr. – The materials to be grown are provided from heated
KNUDSEN CELLS in which the individual elements are individually vaporized
UHV PUMP
ELECTRON-‐ DIFFRACTION
SOURCE
ELECTRON-‐ DIFFRACTION DETECTOR
KNUDSEN CELLS CONTAINING Ga, Al, As & Si
CHAMBER WALLS COOLED
WITH LIQUID NITROGEN
600 °C
A SCHEMATIC DIAGRAM SHOWING THE KEY COMPONENTS OF A MOLECULAR-‐BEAM EPITAXY SYSTEM
M.J. Gilbert ECE 340 – Lecture 3
Crystal Growth – Compound Semiconductors
• Careful control of the deposition rates and the substrate temperature are required to realize heterojunctions with well-defined interfaces. – In order to achieve high uniformity the substrate is heated to
approximately 600 ºC and is slowly rotated in the vacuum chamber. – The growth rate of the epitaxial layer is of order several MICRONS
PER HOUR which allows for ATOMIC level resolution in the growth process.
– The growth is monitored in situ using electron diffraction and mass spectroscopy.
TEM IMAGES OF EPITAXIALLY GROWN GaAs/AlGaAs
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M.J. Gilbert ECE 340 – Lecture 3
Example Problem
Treating atoms as rigid spheres with radii equal to ½ the distance between the nearest neighbors, show that the ratio of the volume occupied by atoms to the total available volume in an FCC is 74%.