int math 2 section 2-5 1011
TRANSCRIPT
Essential Questions
How are variable expressions simplified?
How are variable expressions evaluated?
Where you’ll see this:
Part-time job, weather, engineering, spreadsheets
Vocabulary1. Property of the Opposite of a Sum: The negative
outside the parentheses makes everything inside it opposite
2. Distributive Property:
Vocabulary1. Property of the Opposite of a Sum: The negative
outside the parentheses makes everything inside it opposite
2. Distributive Property: Multiply each term inside the parentheses by the term outside
Example 1Simplify.
a. − 2(n − 5) b. .3(x + .7)
−2n +10 .3x +.21
c. -(2ab + 9ac) d. 2x(4x + 7y )
−2ab
Example 1Simplify.
a. − 2(n − 5) b. .3(x + .7)
−2n +10 .3x +.21
c. -(2ab + 9ac) d. 2x(4x + 7y )
−2ab
Example 1Simplify.
a. − 2(n − 5) b. .3(x + .7)
−2n +10 .3x +.21
c. -(2ab + 9ac) d. 2x(4x + 7y )
−2ab −9ac
Example 1Simplify.
a. − 2(n − 5) b. .3(x + .7)
−2n +10 .3x +.21
c. -(2ab + 9ac) d. 2x(4x + 7y )
−2ab −9ac
Example 1Simplify.
a. − 2(n − 5) b. .3(x + .7)
−2n +10 .3x +.21
c. -(2ab + 9ac) d. 2x(4x + 7y )
−2ab −9ac 8x2
Example 1Simplify.
a. − 2(n − 5) b. .3(x + .7)
−2n +10 .3x +.21
c. -(2ab + 9ac) d. 2x(4x + 7y )
−2ab −9ac 8x2
Example 1Simplify.
a. − 2(n − 5) b. .3(x + .7)
−2n +10 .3x +.21
c. -(2ab + 9ac) d. 2x(4x + 7y )
−2ab −9ac 8x2
+14xy
Dividing Variable Expressions
Divide each term in numerator by denominator
Rewrite as distribution
3 − x
2
Dividing Variable Expressions
Divide each term in numerator by denominator
Rewrite as distribution
3 − x
2
12i3 − x
1
Dividing Variable Expressions
Divide each term in numerator by denominator
Rewrite as distribution
3 − x
2
12i3 − x
1 12(3 − x )
Dividing Variable Expressions
Divide each term in numerator by denominator
Rewrite as distribution
3 − x
2
12i3 − x
1 12(3 − x )
32− 1
2x
Dividing Variable Expressions
Divide each term in numerator by denominator
Rewrite as distribution
3 − x
2
12i3 − x
1 12(3 − x )
32− 1
2x −
12
x + 32
Example 2Simplify. Practice both methods of division to see
which one you prefer.
a.
6x + 33
b. 10y − 5
2
Example 2Simplify. Practice both methods of division to see
which one you prefer.
a.
6x + 33
b. 10y − 5
2
6x
3+
33
Example 2Simplify. Practice both methods of division to see
which one you prefer.
a.
6x + 33
b. 10y − 5
2
6x
3+
33
2x +1
Example 2Simplify. Practice both methods of division to see
which one you prefer.
a.
6x + 33
b. 10y − 5
2
6x
3+
33
2x +1
12(10y − 5)
Example 2Simplify. Practice both methods of division to see
which one you prefer.
a.
6x + 33
b. 10y − 5
2
6x
3+
33
2x +1
12(10y − 5)
5y − 52
Example 2Simplify. Practice both methods of division to see
which one you prefer.
c.
1.6 − .8z
−8 d.
9x + 5y
7
Example 2Simplify. Practice both methods of division to see
which one you prefer.
c.
1.6 − .8z
−8 d.
9x + 5y
7
1.6−8
−.8z
−8
Example 2Simplify. Practice both methods of division to see
which one you prefer.
c.
1.6 − .8z
−8 d.
9x + 5y
7
1.6−8
−.8z
−8
−.2 + .1z
Example 2Simplify. Practice both methods of division to see
which one you prefer.
c.
1.6 − .8z
−8 d.
9x + 5y
7
1.6−8
−.8z
−8
−.2 + .1z
.1z − .2
Example 2Simplify. Practice both methods of division to see
which one you prefer.
c.
1.6 − .8z
−8 d.
9x + 5y
7
1.6−8
−.8z
−8
−.2 + .1z
.1z − .2
17(9x + 5y )
Example 2Simplify. Practice both methods of division to see
which one you prefer.
c.
1.6 − .8z
−8 d.
9x + 5y
7
1.6−8
−.8z
−8
−.2 + .1z
.1z − .2
17(9x + 5y )
97
x + 57
y
Example 3Evaluate when x = 2 and y = -4.
a. − 3(x2 +1) b. − 4 6 − y
−3x2 − 3
−3(2)2 − 3
−3(4) − 3
−12 − 3
Example 3Evaluate when x = 2 and y = -4.
a. − 3(x2 +1) b. − 4 6 − y
−3x2 − 3
−3(2)2 − 3
−3(4) − 3
−12 − 3
−15
Example 3Evaluate when x = 2 and y = -4.
a. − 3(x2 +1) b. − 4 6 − y
−3x2 − 3
−3(2)2 − 3
−3(4) − 3
−12 − 3
−15
−4 6 − (−4)
Example 3Evaluate when x = 2 and y = -4.
a. − 3(x2 +1) b. − 4 6 − y
−3x2 − 3
−3(2)2 − 3
−3(4) − 3
−12 − 3
−15
−4 6 − (−4)
−4 6 + 4
Example 3Evaluate when x = 2 and y = -4.
a. − 3(x2 +1) b. − 4 6 − y
−3x2 − 3
−3(2)2 − 3
−3(4) − 3
−12 − 3
−15
−4 6 − (−4)
−4 6 + 4
−4 10
Example 3Evaluate when x = 2 and y = -4.
a. − 3(x2 +1) b. − 4 6 − y
−3x2 − 3
−3(2)2 − 3
−3(4) − 3
−12 − 3
−15
−4 6 − (−4)
−4 6 + 4
−4 10
−4(10)
Example 3Evaluate when x = 2 and y = -4.
a. − 3(x2 +1) b. − 4 6 − y
−3x2 − 3
−3(2)2 − 3
−3(4) − 3
−12 − 3
−15
−4 6 − (−4)
−4 6 + 4
−4 10
−4(10)
−40