Pg 175 # lb.

Person I Person 2

m .

59kgIII.?na" a "

a)→ motion

ntwFs HasFg b) since m is a

Fs = FNET factor'

in both

Fs = maSides of equation

WE =m~Itdide,

Msnfg=m/aout

.

Pg no # ,.

Fenske.fm

m¥¥sok,Eaton¥10.us?HzsokDfr8 ;D

Ms = 0.55 ¥8 Fs . 1347.5N

Student m : 64kg Fs= 1300N .

Ms =;= .←.ly?jFsYdInH64kskaendFs=451NFs=4S0N

.

e) Not fair.

More Solving Friction Problems Unit 2: Dynamics April 2, 2015 sportspersons,r& 16

Pg. 177 #3

FBD → + FBD Mass hotOBJECT

INFN qFt

*←•¥nItC.d a

'- amass

Fnitbfgobject

Fg →th

Fatima

Fatima2dntEnpownsFh.ttFg-FtFnu-FFk@accekrationiFg.mgFk-MkFNmaiFtiMkm8ma.mg-FtFn.Mg0bsQm.3.Z

kg . mad m=tskg .

→ +

object .mass W

fs.2kDaiEfo.3oX3.2kDf8snDf5kgTailf5ksY9.8gD-Ft@2kDci-Ft.9.408Nf.SkgTat14.7NiFtfs.2kDai.Ft-9.41NIsolateFisfj2fpteat9i4dIg5at4.7N-k3.2kDat9.4iDtFt-32kDf.RmDt.9.4w4.5kgJa-I47N-3.2kDoi-9.41NEti3.6Nt9.41NY.SkgaJt3f2kDa-I4.7N-9.41NFt.13NfDH.7kgTai.5.29Nasa.s

.ge?pqgNIc)Vi=1.3M/sED

>a=1 .IM/s2*objut[ ] mass

a=1

.IM/5tDbd=viattIsaDthgt=1.2s=y.3H.Dttsuyd.2)2dd=2.4m

Questions y Pg. 177 #1,2,4 y Pg. 178 #2-5