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  • 8/17/2019 Differentiation Of

    1/18

    DIFFERENTIATIONOF

    EXPONENTIALFUNCTIONS

  • 8/17/2019 Differentiation Of

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    OBJECTIV

    ES:•

    apply the properties of exponentialfunctions to simplify dierentiation;

    • dierentiate functions involvingexponential functions; and

    • solve problems involvingdierentiation of exponentialfunctions.

     

  • 8/17/2019 Differentiation Of

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    The EXPONENTIAL FUNCTION

    . ylog  x

     as writtenbealso maya y  function,clogarithmi of  inverse the is  functionl exponentia the Since

    number.real a is  x wherea ybydefined  is1,a

     and  0a a, base with functionl exponentia The 

    a

     x

     x

    =

    =

    =≠

    >

    .

  • 8/17/2019 Differentiation Of

    4/18

    .

    nmanama .1   +=⋅

    <

    =>−

    =

    nm if  ,m-na

    1

    nm if  , 1

    nm if  ,nma

    na

    ma .2

    ( ) mnanma .   =

    ( ) nbnanab .!   =

    nb

    nan

    ba

     ."   =   

      

     0a provided  ,10

    a .#    ≠= n1mam

    n1anma .$     

      

      

       

      

      ==

    Laws of Exponents

     xa .% xlog a=

     y x then aaif  .& y x

    ==

  • 8/17/2019 Differentiation Of

    5/18

    DIFFERENTIATION FORMULA

    Der!at!e of Exponenta"F#n$ton  The derivative of the exponentialfunction for

    any given base and any dierentiablefunction of u.( )

      f'x(u where)dx

    due  (e' 

    dx

      f'x(u where)dx

    dualna  (a' 

    dx

    uu

    uu

    ===

    ==

    :ebaseFor 

    :abasegivenany For 

  • 8/17/2019 Differentiation Of

    6/18

    A. Find the derivative of each of thefollowing natural logarithm and

    simplify the result:( )

    2 xe x f  .1   =

    ( )  x21e x g  .2   −=

    ( )  x * 12e x! xh .   =

    ( ) ( )

    ( )2

    2

     x

     x

     xe#  x+  f 

     x# e x+  f 

    =

    =

    ( ) x212

    2e x+  g   x21

    −−

    ⋅=   −

    ( )   ( )   ( )

     

      

      −=  x2e x

    1e x! x+ h

     x * 1

    2

     x * 12

    EXA%PLE:

    ( ) x21

     x21

     x21

    e x+  g 

     x21

    −−

    •−

    −=−

    ( ) ( ) x21e! x+ h  x * 1 +−=

    ( ) ( )1 x2e! x+ h  x * 1 −=

    ( ) x21

     x21e x+  g 

     x21

    −−=

  • 8/17/2019 Differentiation Of

    7/18

    2 y x2 x

     xye .!   +=+

    [ ]   [ ] [ ] 02 y

    +  y x1 y x21 y+  xy xye   +−=+⋅+

    2 y

    +  xy y x2 y

     xye+  y

     xy xe

      −=++

    +  xy y2

     xy2 xye

     y+  y

     xye

    2 xy   −=++

    2 xy2 xye y y x

     xye2 xy+  y   −−=+    

      

      

       

      

       

      

    +

    −−

    =  xye2 y1 x

     xye2 y xy21 y

    +  y

  • 8/17/2019 Differentiation Of

    8/18

    " x!2 x$  y ."   +−=

    ( )      

       +−+−= " x!2 x

    dx

    d $ ln" x!

    2 x$ +  y

    ( )[ ]! x# $ ln" x!2

     x$ +  y   −+−=

    ( )( ) " x!2 x$ $ ln2 x2+  y   +−−=

    ( )2

     x!ln xh .#    =

    2 x!

    2 x!dxd 

     ( x' + h   

      

     

    =

    ( ) ( )2 x!

    2 xdx

    d !ln

    2 x!

     x+ h     =

    ( )   ( )[ ] x# !ln x+ h   =

    ( ) !ln x#  x+ h   =

    ( )2 x!ln xh   =

    ( ) !ln2 x xh   =

    ( )   ( )      

      = 2 x

    dxd !ln x+ h

    ( )   ( )[ ] x2!ln x+ h   =

    ( ) !ln x#  x+ h   =

  • 8/17/2019 Differentiation Of

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    ( )   ( )      

       ++=  x2e1 xelog  x .# 

    ( )   ( ) ( )elog 1elog  x.  x2 x +++=

    ( ) elog e

    2eelog 

    1e

    e x+ .

     x2

     x2

     x

     x

    +⋅

    ++

    =

    ( )   ( ) ( )( )( )elog 

    e1e1ee2ee x+ .

     x2 x

     x x2 x2 x

    +++++=

    ( ) ( )( ) elog ee1ee2e2e

     x+ .

     x

     x2 x

     x x2 x2

    ++

    +++

    =

    ( )( )( )

    elog ee1e

    e2e x+ .  x

     x2 x

     x x2

    ++++

    =

  • 8/17/2019 Differentiation Of

    10/18

    ( )2!

     x x"2 x f  .$    ⋅=

    ( )   ( ) ( )!22!  x x x x 2dx

    d ""

    dx

    d 2 x+  f    +=

    ( ) ( )[ ]   ( )[ ] x x x x  x122ln2" x2"ln"2 x+  f  !22! +=

    ( )   [ ]2ln x# "ln"2 x2 x+  f  2 x x2!

    +=

    ( )   ( ) x2ln x# "ln"2 x+  f  2 x1 x2!

    +=  +

    ( )2!

     x x"2 x f    ⋅=

    ( )   ( )2!  x x "2ln x f ln   =

    ( )2!

     x x "ln2ln x f ln   +=

    ( ) "ln x2ln x x f ln 2! +=

    ( )

    ( )  ( )[ ]   ( )[ ] x2"ln x!2ln

     x f 

     x+  f  +=

    ( )

    ( )  [ ]"ln2ln x#  x2

     x f 

     x+  f  2 +=

    [ ]"ln2ln x#  x2"2 ( x' +  f  2 x x2!

    +⋅⋅=

    ( )   ( ) x"ln2ln x# "2 x+  f 2 x1 x 2!

    +=

      +

  • 8/17/2019 Differentiation Of

    11/18

     y x" .%! y x +=+

    ( ) ( ) +  y x!+  y"ln"ln  y x

    +=+( )[ ]   ( )ln x!1"ln"+  y  x y −=−

    ( )

    ( )[ ]1"ln"

    ln x!+  y

     y

     x

    −=

  • 8/17/2019 Differentiation Of

    12/18

    A. Find the derivative and simplify the res

    ( ) 1 x x2

     x g  .1   +−=

    ( )22

     xln xe x f  .2

      +=

    2ee y . x

     x!

    +=

    ( )

     x22

    2 xlog  xh .!   ⋅=

    ( )2 x" x.1   =

    2ln y x xe ye.222 y x ++=+

    ( ) ( )2

     / 1 x x  .   +=

    1 x2

    e y.!

    1 x2

    +=

    +

    ( )   ( ) x2 x2 eeln x f ."   −+=

    . Apply the appropriate formulas to obtai  derivative of the given function and si 

    EXERCISES:

  • 8/17/2019 Differentiation Of

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    Logarithmic Differentiation

    !ftentimes" the derivatives of algebraicfunctionswhich appear complicated in form#involving products" $uotients and

    powers% can be found $uic&ly by ta&ingthe natural logarithms of both sides andapplying the properties of logarithms

    before dierentiation. This method iscalled "o&art'($ )*erentaton.

  • 8/17/2019 Differentiation Of

    14/18

    '. Ta&e the natural logarithm of bothsides and apply the properties oflogarithms.

    (. )ierentiate both sides and reducethe right side to a single fraction.

    *. +olve for y, by multiplying the rightside by y.

    -. +ubstitute and simplify the result.

    Steps n app"+n& "o&art'($ )*ere

    ogarithmic dierentiation is also applicablewheneverthe base and its power are both functions.

  • 8/17/2019 Differentiation Of

    15/18

     x x yif  

    dx

    dy  ind  .1   =

     xln x yln

     xln yln  x

    =

    =

    ogarithmic dierentiation is also applicablewhenever the base and its power are bothfunctions. #/ariable to variable power.%

    0xample:

    ( ) ( )1 xln1 x

    1 x+  y

     y

    1+=

    ( )  x x y but  y xln1+  y   =→+=

    ( ) ( ) x x xln1+  y   +=∴

  • 8/17/2019 Differentiation Of

    16/18

    ( )

    ( ) ( )1 x2ln1 x yln

    1 x2ln yln1 x

    +−=

    +=   −

    ( ) 1 x1 x2 yif  dx

    dy  ind  .2

      −+=

    ( ) ( ) ( )( )11 x2ln21 x2

    11 x+  y

     y

    1++

    +

    −=

    ( )( )1 x2ln1 x2

    1 x2+  y y

    1++

    +

    =

    ( )( ) ( ) 1- x12x y but  y1 x2ln

    1 x2

    1 x2+  y   +=→

    ++

    +−

    =

    ( ) ( ) ( ) ( ) 1- x12x1 x21 x2ln1 x21 x2+  y   + + +++−=

    ( ) ( ) ( )[ ] ( ) 1-1- x12x1 x2ln1 x21 x2+  y   ++++−=

    ( ) ( ) ( )[ ] ( ) 2- x12x1 x2ln1 x21 x2+  y   ++++−=∴

    ( )

  • 8/17/2019 Differentiation Of

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    ( )  x" x#  y .   +=

    ( )" x# ln x yln

    " x# ln yln x

    +=

    +=

      

      

     ++ 

     

      

     

    +  

      

     

    +=

     x2

    1" x# ln

    " x# 2

    " x# 

    1 x y+ 

     y

    1

    ( )( ) 12

     x

    " x#  x2

    " x# ln" x#  x#  y+ 

      −+

      +++=∴

     x2

    " x# ln

    " x# 

     x y+ 

     y

    1   ++

    +=

    ( )

    ( )" x#  x2

    " x# ln" x#  x#  y+ 

     y

    1

    +

    +++=

    ( )

    ( )  ( )   ( )  x" x#  y but  y

    " x#  x2

    " x# ln" x#  x#  y+    +=⇒

    +

    +++=

    ( )

    ( )  ( )  x" x# 

    " x#  x2

    " x# ln" x#  x#  y+    +

    +

    +++=

  • 8/17/2019 Differentiation Of

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    ( ) 1 x x! y .!   −−=

    ( )

    ( ) x!ln1 x yln

     x!ln yln1 x

    −−=

    −=   −

    ( ) ( )     

      

     

    −−+ 

     

      

      −−

    −=1 x2

    1 x!ln

     x!

    11 x+  y

     y

    1

    ( )

    1 x2

     x!ln

     x!

    1 x+  y

     y

    1

    −+

    −−=

    ( ) ( ) ( )

    ( ) 1 x x!2

     x!ln x!1 x# +  y

     y

    1

    −−

    −−+−−=

    ( ) ( ) ( )

    ( )  ( ) ( ) 1 x x! y but   y

    1 x x!2

     x!ln x!1 x#  y+ 

      −−=⇒

    −−

    −−+−−=

    ( ) ( ) ( )

    ( )  ( ) 1 x x!

    1 x x!2

     x!ln x!1 x# +  y

      −−

    −−

    −−+−−=

    ( ) ( ) ( )( )

    11 x

     x!1x2

     x!ln x!1 x#  y+ 

      −−

    −−+−−=∴