complement filtres premier second ordre
DESCRIPTION
filtre électrTRANSCRIPT
PRINCIPAUX FILTRES DU PREMIER ET SECOND ORDRE
Passe-bas du premier ordre
Passe-haut du premier ordre
jx
HjxH
+=
1)( 0
jx
jxHjxH
+⋅
=1
)( 0
GdB
logx
-20dB/décade
-60
-50
-40
-30
-20
-10
0-3 -2 -1 1 2 3
GdB
logx
+20dB/décade
-60
-50
-40
-30
-20
-10
0-3 -2 -1 1 2 3
logx
−π2
−π4
-3 -2 -1 10 2 3
logx
+ π2
+ π4
-3 -2 -1 10 2 3
−+
⋅=
xxjQ
jxQH
jxH1
1)(
0
−+
⋅=
xxjQ
xQjHjxH
11
)( 0
Passe-bas du second ordre
Passe-haut du second ordre
Q = 5
Q = 5
Q =1
2
Q =1
2
Q = 0 2,
Q = 0 2,
GdB
logx
-40dB/décade
-120
-100
-80
-60
-40
-20
0-3 -2 -1 1 2 3
GdB
logx
-40dB/décade
-120
-100
-80
-60
-40
-20
0
-3 -2 -1 10 2 3
GdB
logx
-40dB/décade
-120
-100
-80
-60
-40
-20
0-3 -2 -1 1 2 3
GdB
logx
+40dB/décade
-120-100-80-60-40-20
-3 -2 -1 10 2 3
GdB
logx
+40dB/décade
-120
-100
-80
-60
-40
-20
-3 -2 -1 10 2 3
+40dB/décade
GdB
logx
-120
-100
-80
-60
-40
-20
-3 -2 -1 10 2 3
logx
− π2
-3 -2 -1 10 2 3 logx
−π2
-3 -2 -1 10 2 3 logx
− π2
-3 -2 -1 10 2 3
logx
+π2
-3 -2 -1 10 2 3logx
+ π2
-3 -2 -1 10 2 3logx
+ π2
-3 -2 -1 10 2 3
Passe-bande du second ordre
Coupe-bande du second ordre
−+=
xxjQ
HjxH
11
)( 0
−+
=
xxjQ
HjxH
11
1)( 0
Q = 1
2Q = 0 2,
logx
+ π2
− π2
-3 -2 -1 0 1 2 3 logx
+π2
− π2
-3 -2 -1 10 2 3 logx
+ π2
− π2
0
-3 -2 -1 0 1 2 3
Q = 5 Q = 1
2Q = 0 2,
-3 -2 -1 0 1 2 3GdB
logx -3 -2 -1 0 1 2 3GdB
logx
-40
-30
-20
-10
-3 -2 -1 0 1 2 3GdB
logx
-60
-50
-40
-30
-20
-10
logx
− π2
+ π2
-3 -2 -1 0 1 2 3 logx
− π2
+ π2
-3 -2 -1 0 1 2 3 logx
− π2
+ π2
-3 -2 -1 0 1 2 3
Q = 5
GdB
logx
+20dB/décade-20dB/décade
-70
-60
-50
-40
-30
-20
-10
0-3 -2 -1 1 2 3
GdB
logx
+20dB/décade
-20dB/décade
-50
-40
-30
-20
-10
0-3 -2 -1 1 2 3
GdB
logx
+20dB/décade
-20dB/décade
-40
-30
-20
-10
-3 -2 -1 10 2 3
+ π2
+ π4
− π2
− π4
GdB
logx
Passe-bande du second ordre
+20dB/décade -20dB/décade
H jxH
jQ xx
( ) =+ −
0
11
GdBmax
GdB dBmax − 3
G QdBmax log− 20
logxb logxh
-25
-20
-15
-10
-5
0-0.6 -0.4 -0.2 0.2 0.4 0.6
logx0-0.6 -0.4 -0.2 0.2 0.4 0.6