chapter 7 : partial differentiation....determine the first partial derivative of z w.r.t y:.. treat...
TRANSCRIPT
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CHAPTER 7 : PARTIAL DIFFERENTIATION.
© John Wiley and Sons 2013 www.wiley.com/college/Bradley © John Wiley and Sons 2013
Essential Mathematics for Economics and Business, 4th Edition
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
• What is partial differentiation • How to get first order partial derivatives • How to get second order partial derivatives • Worked Example 7.2 • Worked Example 7.3 • Worked Example 7.4
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
Graphs and derivatives for function of one variable
Ordinary differentiation:
Example
26249)( 23 +−+−= xxxxf 26249 23 +−+−= xxxy
Graph: a curve in 2 dimensions
OR
24183 2 −+−= xxdxdy
18622
+−= xdx
yd
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
Functions of several variables
Copyright© 2013 Teresa Bradley and John Wiley & Sons Ltd
..treat y as a constant
Example
Graph: a surface in 3 dimensions
OR 42),( ++= yxyxf 42 ++= yxz
To differentiate z partially with respect to x
Partial differentiation
..then differentiate w.r.t. x:
xzxz or ∂∂
N.B. ∂ ..denotes partial differentiation d ..denotes ordinary differentiation
..denote the partial derivative of z wrt x
--see next slide
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
Determine the first partial derivative of z w.r.t x:
Worked Example 7.2(a) 42 ++= yxz
..treat y as a constant
..then differentiate z w.r.t. x:
4][2 ++= yxz
1001 =++=∂∂xz
..since derivatives of constant terms (2y and 4) are zero
xzxz or ∂∂
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
Determine the first partial derivative of z w.r.t y: or zy
Worked Example 7.2(b) 42 ++= yxz
..treat x as a constant
..then differentiate w.r.t. y:
yz∂∂
42][ ++= yxz
20)1(20 =++=∂∂yz
..since derivatives of constant terms (x and 4) are zero
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
Worked Example 7.3
Find the first-order partial derivatives for each of the following functions.
(a) (b) (c)
532 2 ++= yxxz
3.07.010 KLQ =
U x y= 2 5
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
Determine the first partial derivative of z w.r.t x:
..treat y as a constant
..then differentiate w.r.t. x: yxxz )1(3)2(2 +=∂∂
532 2 ++= yxxzWorked Example 7.3(a) 5][32 2 ++= yxxz
yxxz 34 +=∂∂
xzxz or ∂∂
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
Determine the first partial derivative of z w.r.t y:
..treat x as a constant
..then differentiate z w.r.t. y:
yzyz or ∂∂
0)1(30 ++=∂∂ xyz
532 2 ++= yxxzWorked Example 7.3(a) 5][3][2 2 ++= yxxz
xyz 3=∂∂
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Determine the first partial derivative of Q wrt L:
..treat K as a constant
..then differentiate Q w.r.t. L:
LQLQ or ∂∂
Worked Example 7.3(b) 3.07.010 KLQ =
][10 3.07.0 KLQ =
( ) 3.017.07.010 KLLQ −=∂∂
3.03.07 KLLQ −=∂∂
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
the first partial derivative of Q wrt K:
..treat L as a constant
..then differentiate Q w.r.t. K:
KQKQ or ∂∂
Worked Example 7.3(b) 3.07.010 KLQ =
3.07.0 ][10 KLQ =
( )13.07.0 3.010 −=∂∂ KLKQ
7.07.03 −=∂∂ KLKQ
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
the first partial derivative of U wrt x:
..treat y as a constant
..then differentiate U w.r.t. x:
xU∂∂
Worked Example 7.3(c)
( ) 52 yxxU
=∂∂
U x y= 2 5
][ 52 yxU =
52xyxU
=∂∂
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
the first partial derivative of U wrt y:
..treat x as a constant
..then differentiate U w.r.t. y:
yU∂∂
Worked Example 7.3(c)
)5( 42 yxyU
=∂∂
U x y= 2 5
52][ yxU =
425 yxyU
=∂∂
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
Worked Example 7.4
Find the second order partial derivatives for each of the following functions.
(a)
(b)
(c)
532 2 ++= yxxz
3.07.010 KLQ =
U x y= 2 5
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
or zxx : second partial derivative of z wrt x:
..treat y as a constant
..differentiate
2
2
xz
∂∂
532 2 ++= yxxzWorked Example 7.4(a)
yxxz 34 +=∂∂
..first partial derivative zx see Worked Example 7.3
][34 yxxz
+=∂∂
04)1(422
+==∂∂xz
xz∂∂ w.r.t x
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the second partial derivative of z wrt y:
..treat x as a constant
..differentiate w.r.t. y:
2
2
yz
∂∂
532 2 ++= yxxzWorked Example 7.4(a)
xyz 3=∂∂
..first partial derivative zy see Worked Example 7.3
][3 xyz=
∂∂
022
=∂∂yz
yz∂∂
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
the second partial derivative of z wrt x and y:
..treat x as a constant
..differentiate w.r.t. y:
xyz∂∂
∂2
532 2 ++= yxxzWorked Example 7.4(a)
yxxz 34 +=∂∂
..first partial derivative zx see Worked Example 7.3
xz∂∂
yxxz 3][4 +=∂∂
3)1(302
=+=∂∂
∂xy
z
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or QLL: second partial derivative of Q wrt L
..treat K as a constant
..then differentiate QL w.r.t. L:
2
2
LQ
∂∂
Worked Example 7.4(b) 3.07.010 KLQ =
( ) 3.013.022
3.07 KLLQ −−−=
∂
∂
3.03.07 KLLQ −=∂∂
..first partial derivative: QL
][7 3.03.0 KLLQ −=∂∂
3.03.12
21.2 KL
LQ −−=
∂
∂
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
: the second partial derivative of Q wrt K
Copyright© 2013 Teresa Bradley and John Wiley & Sons Ltd
..treat L as a constant
..differentiate QK w.r.t. K:
2
2
KQ
∂∂
Worked Example 7.4(b) 3.07.010 KLQ =
( )17.07.022
7.03 −−−=∂
∂ KLK
Q
7.07.03 −=∂∂ KLKQ
..first partial derivative QK
7.17.02
21.2 −−=
∂
∂ KLK
Q
7.07.0 ][3 −=∂∂ KLKQ
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
the second ‘mixed’ partial derivative of Q
Copyright© 2013 Teresa Bradley and John Wiley & Sons Ltd
..treat L as a constant
..differentiate QL w.r.t. K:
LKQ∂∂
∂2
Worked Example 7.4(b) 3.07.010 KLQ =
( )13.03.02 3.07 −−=∂∂
∂ KLLK
Q
3.03.07 KLLQ −=∂∂..first partial derivative: QL
3.03.0 ][7 KLLQ −=∂∂
7.03.12
1.2 −−=∂∂
∂ KLLK
Q
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the second partial derivative: Uxx
Copyright© 2013 Teresa Bradley and John Wiley & Sons Ltd
..treat y as a constant
..then differentiate Ux w.r.t. x:
2
2
xU
∂∂
Worked Example 7.4(c)
][2 5yxxU
=∂∂
U x y= 2 5
52xyxU
=∂∂
..first partial derivative: Ux
552
22)1(2 yy
xU
==∂
∂
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
the second partial derivative: Uyy
Copyright© 2013 Teresa Bradley and John Wiley & Sons Ltd
..treat x as a constant
..then differentiate Uy w.r.t. y:
2
2
yU
∂∂
Worked Example 7.4(c) U x y= 2 5
425 yxyU
=∂∂
..first partial derivative: Uy
32322
220)4(5 yxyx
yU
==∂
∂
42][5 yxyU
=∂∂
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www.wiley.com/college/Bradley © John Wiley and Sons 2013
the second mixed derivative: Uxy
..treat x as a constant
..then differentiate Ux w.r.t. y:
xyU∂∂
∂2
Worked Example 7.4(c)
5][2 yxxU
=∂∂
U x y= 2 5
52xyxU
=∂∂
..first partial derivative: Ux
442
10)5(2 xyyxxy
U==
∂∂∂
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Chapter 7 : partial differentiation.�Slide Number 2Graphs and derivatives for function of one variableFunctions of several variables Determine the first partial derivative of z w.r.t x: �Determine the first partial derivative of z w.r.t y: or zy �Worked Example 7.3Determine the first partial derivative of z w.r.t x:Determine the first partial derivative of z w.r.t y: �Determine the first partial derivative of Q wrt L: the first partial derivative of Q wrt K: the first partial derivative of U wrt x: the first partial derivative of U wrt y: Worked Example 7.4 or zxx : second partial derivative of z wrt x: the second partial derivative of z wrt y: the second partial derivative of z wrt x and y: or QLL: second partial derivative of Q wrt L : the second partial derivative of Q wrt K the second ‘mixed’ partial derivative of Q the second partial derivative: Uxx the second partial derivative: Uyy the second mixed derivative: Uxy