7 qc tools
DESCRIPTION
For quality engineerTRANSCRIPT
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7 QC ToolsCheck-sheetCause and EffectParetoHistogramControl ChartScatter PlotStratification
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Check-sheetFor problem solving data is to be captured.Check-sheet is a tool to capture data as per check listCheck list is a tool to capture the parameter
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4. Additional causes can be branched off the tertiary causes.
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Pareto ChartFind the few important reasons !the vital few and the trivial many80 20 ruleClass dataCollect data in a tableCalculate the cumulative valuesPlot pareto diagram
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Example
Chart1
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.010.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.010.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
0.0050.0204-0.0099
00.0204-0.0099
U.C.L. =0.0204
L.C.L. = -0.0099
DATE
FRACTION DEFECTIVE
FRACTION DEFECTIVE CHART(PRESS SHOP)JAN-05
Chart2
44.144.1
38.282.3
11.894.1
5.9100
DEFECTS
% AGE
CUMULATIVE % AGE
PARETO CHART FOR PRESS SHOP(JAN-05)
Sheet1
Type of DefectNo. of defective pc.%Cum. %
3-Jan0.0050.0204-0.0099Sheet Hard5644.144.1
4-Jan0.0050.0204-0.0099Draw & Die Setting4938.282.3
5-Jan0.0050.0204-0.0099Sheet Line1511.894.1
6-Jan0.0050.0204-0.0099Operator Defect75.9100
7-Jan0.0050.0204-0.0099Total127
9-Jan0.0050.0204-0.0099
10-Jan0.0050.0204-0.0099
11-Jan0.010.0204-0.0099
12-Jan0.0050.0204-0.0099
13-Jan0.0050.0204-0.0099
15-Jan0.0050.0204-0.0099
17-Jan0.0050.0204-0.0099
18-Jan0.0050.0204-0.0099
19-Jan0.0050.0204-0.0099
20-Jan0.0050.0204-0.0099
21-Jan0.0050.0204-0.0099
22-Jan0.0050.0204-0.0099
24-Jan0.010.0204-0.0099
25-Jan0.0050.0204-0.0099
27-Jan0.0050.0204-0.0099
28-Jan0.0050.0204-0.0099
29-Jan0.0050.0204-0.0099
31-Jan00.0204-0.0099
Sheet2
Sheet3
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Chart1
Chart3
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.010.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.010.0224-0.0104
0.0050.0224-0.0104
0.010.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.010.0224-0.0104
0.010.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
U.C.L. = 0.0224
L.C.L. = -0.0104
DATE
FRACTION DEFECTIVE
FRACTION DEFECTIVE CHART(PRESS SHOP)DEC-04
Sheet1
3-Dec0.0050.0224-0.0104
4-Dec0.0050.0224-0.0104
6-Dec0.0050.0224-0.0104
7-Dec0.0050.0224-0.0104
8-Dec0.010.0224-0.0104
9-Dec0.0050.0224-0.0104
10-Dec0.0050.0224-0.0104
11-Dec0.0050.0224-0.0104
13-Dec0.0050.0224-0.0104
14-Dec0.0050.0224-0.0104
15-Dec0.0050.0224-0.0104
16-Dec0.0050.0224-0.0104
17-Dec0.0050.0224-0.0104
18-Dec0.0050.0224-0.0104
20-Dec0.010.0224-0.0104
21-Dec0.0050.0224-0.0104
22-Dec0.010.0224-0.0104
23-Dec0.0050.0224-0.0104
24-Dec0.0050.0224-0.0104
25-Dec0.0050.0224-0.0104
27-Dec0.010.0224-0.0104
28-Dec0.010.0224-0.0104
29-Dec0.0050.0224-0.0104
30-Dec0.0050.0224-0.0104
31-Dec0.0050.0224-0.0104
Sheet1
46.146.1
38.584.6
10.394.9
5.1100
&A
Page &P
DEFECTS
% AGE
CUMULATIVE %AGE
PARETO CHART FOR PRESS SHOP (DEC-04)
Sheet2
Sheet3
Chart5
46.146.1
38.584.6
10.394.9
5.1100
DEFECTS
% AGE
CUMULATIVE %AGE
PARETO CHART FOR PRESS SHOP (DEC-04)
Chart3
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.010.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.010.0224-0.0104
0.0050.0224-0.0104
0.010.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.010.0224-0.0104
0.010.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
0.0050.0224-0.0104
U.C.L. = 0.0224
L.C.L. = -0.0104
DATE
FRACTION DEFECTIVE
FRACTION DEFECTIVE CHART(PRESS SHOP)DEC-04
Sheet1
3-Dec0.0050.0224-0.0104
4-Dec0.0050.0224-0.0104
6-Dec0.0050.0224-0.0104
7-Dec0.0050.0224-0.0104
8-Dec0.010.0224-0.0104
9-Dec0.0050.0224-0.0104
10-Dec0.0050.0224-0.0104
11-Dec0.0050.0224-0.0104
13-Dec0.0050.0224-0.0104
14-Dec0.0050.0224-0.0104
15-Dec0.0050.0224-0.0104
16-Dec0.0050.0224-0.0104
17-Dec0.0050.0224-0.0104
18-Dec0.0050.0224-0.0104
20-Dec0.010.0224-0.0104
21-Dec0.0050.0224-0.0104
22-Dec0.010.0224-0.0104
23-Dec0.0050.0224-0.0104
24-Dec0.0050.0224-0.0104
25-Dec0.0050.0224-0.0104
27-Dec0.010.0224-0.0104
28-Dec0.010.0224-0.0104
29-Dec0.0050.0224-0.0104
30-Dec0.0050.0224-0.0104
31-Dec0.0050.0224-0.0104
Sheet1
46.146.1
38.584.6
10.394.9
5.1100
&A
Page &P
DEFECTS
% AGE
CUMULATIVE %AGE
PARETO CHART FOR PRESS SHOP (DEC-04)
Sheet2
Sheet3
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What is a Histogram?Histogram is a visual tool for presenting variable data. It organises data to describe the process performance.
Additionally histogram shows the amount and pattern of the variation from the process.
Histogram offers a snapshot in time of the process performance.
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Definition of HistogramA histogram is a graphical summary of variation in a set of data.
The pictorial nature of the histogram enables us to see patterns that are difficult to see in a table of numbers.
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Key Concept of HistogramData always have variationVariation have patternPatterns can be seen easily when summarized pictorially
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Location of mean of the process Spread of the process Shape of the process
While studying histogram look for its
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Calculations for Histogram
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Calculations for HistogramSmallest Value, S= 47Largest Value, L = 55Range= L-S= R= 8No. of cells= 1+3.22log10(50)= 7Calculated cell width (CW)= R/no. of cell=1.14Rounded off Cell width= 1 (multiple of 1,2,5 of least count
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Calculations for HistogramStarting value, A= 47LCB(1)= A-cw/2= 47-1/2= 46.5UCB (1)= LCB(1)+CW= 46.5+1= 47.5
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Plotting Histogram
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Histogram
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Skewness Is the histogram symmetrical? If so, Skewness is zero. If the left hand tail is longer, skewness will be negative. If the right hand tail is longer, skewness will be positive. Where skewness exists, process capability indices are suspect. For process improvement, a good rule of thumb is to look at the long tail of your distribution; that is usually where quality problems lie
Kurtosis Kurtosis is a measure of the pointiness of a distribution. The standard normal curve has a kurtosis of zero. The Matter horn, has negative kurtosis, while a flatter curve would have positive kurtosis. Positive kurtosis is usually more of a problem for quality control, since, with "big" tails, the process may well be wider than the spec limits.
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Distributions you may encounter
The standard normal distribution, with its zero skewness and zero kurtosisA skewed distribution, with one tail longer than the other.
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A double-peaked curve often means that the data actually reflects two distinct processes with different centers. You will need to distinguish between the two processes to get a clear view of what is really happening in either individual process
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Why Control Chart ?To findIs there any change in location of process average ?Is there any change in the spread of the process ?Is there any change in shape?
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Control ChartsVariablesAttributesp Chartnp ChartC Chartu Chart
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defect prevention and process improvementmore expensive to construct and maintaincan tell reason for process behaviorsmaller n (1-10) neededdefect detection a screening device to initiate variables control chartingcheaper to construct and maintaincannot tell cause of defectneed large n (>100)Variable Control ChartsAttribute Control Charts
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Attribute Control Chartsp ChartMeasures % defectiveCharts number of defects in varying sized samplesnp ChartMeasures number of defective piecesCharts the numbers of defective pieces in fixed size samplesC ChartMeasures number of defectsLooks at a single product or pieceu ChartMeasures number of defects per unit area, time, length, etc.Charts number of defects in a product of varying size
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StartSelecting a Control Chart
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Control Limits1234567Sample NumberUpper Control LimitLower Control LimitTarget3 x sd of means
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Control Chart Technique - 1 Select a quality characteristicsWeightLengthViscosityTensile StrengthCapacitance
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Control Chart Technique - 2 Choose sub group size Sensitivity increases with the sub group size Cost of sampling increases with size In case of destructive testing - 2 or 3 Normally sub group size can be 4 or 5Choose Interval of data collection (frequency) of sample sizeCollect the data
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If mean of the process shifts by 1 times sd ( Impact of sample size)
Sample Size
Chances of Detecting a shift (%)
2
5
4
10
10
55
15
82
20
95
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Typical Data Table
Part
Operation
Other Details
SN
Date
Time
Measurement
Mean
Range
X1
X2
X3
X4
1
12/12
10.25
35
40
32
33
35.0
8
2
12/12
13.45
46
42
40
38
41.5
8
3
12/12
15.34
34
40
34
36
36.0
6
..
25
15/12
10.30
38
34
44
40
39
10
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Determine trial control limits
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Constants for Trial Control Limits
group Size
A2
D4
D3
2
1.880
3.267
0
3
1.023
2.527
0
4
0.729
2.282
0
5
0.577
2.115
0
6
0.483
2.004
0
7
0.419
1.924
0.076
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Formula for Control LimitsFor mean control chartUpper Control Limit, UCLx = T + A2 x R Lower Control Limit, LCLx = T - A2 x RFor range control chartUpper Control Limit, UCLr = D4 x RLower Control Limit, LCLr = D3 x R
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Sample CalculationIn our caseTarget, T = 50Mean range, R = 9Sub Group size, n = 4Values obtained from the table of constantsA2 = 0.729D4 = 2.282D3 = 0
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Sample CalculationsUCLX = 50 + 0.729 X 9 = 56.56LCLX = 50 - 1.079 X 9 = 43.44UCLr = 2.282 X 9 = 20.54LCLr = 0 X 9 = 0
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OutliersOutliers are those observations which do not belong to normal population.If Outliers are included in the calculation, then the information is distorted. Not more than 20% subgroups are omitted
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OutliersScan column for meansIf any mean is more than UCLx or mean is less than LCLx then drop that sub-group
Checking for range outliersScan column for ranges, if any range is more than UCLr then drop that sub-group
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If any sub-group(s) is dropped then recalculate the trial control limits using remaining sub-group(s)Continue this exercise till there is no further droppings ( max 20%)
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Control Chart12345678Sample Number MeanUCLx LCLxUCLrT=50Range555040456020100
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Control Chart with Action Limit12345678Sample Number MeanUCLx LCLxT=5050404030603010020UWLx LWLx 2/3 A2 x R2/3 A2 x R
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One Point Falling Out side Control Limit12345678Sample NumberSample MeanUCLxLCLx
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12345678Sample NumberSample MeanTwo out of 3 points falling between Control Limit and Warning LimitsUCLxLCLx
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12345678Sample NumberSample Mean7 Consecutive points falling on one side of the center line ( A run of seven )UCLxLCLx
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Over Adjustment Over adjustment is fiddling with the controls of stable process.
It is often a well intention move of the process owner, but bad attempt to improve the process.
It actually adds a further source of variation to the process, and hence will increase total variation.
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Problem of Over Adjustment3848505254565840424446Resultant distributionwith flat top
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Scatter Plot
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Scatter diagram Exhibits RelationshipA scatter diagram shows the relationship between independent variable (cause) and dependent variable (effect).
The independent variable is plotted on x-axis and dependent variable on y-axis.
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Characteristics of Independent VariableIt should be measurable on a continuous scale.
It should have a logical relationship with the dependent variable.
Changes in level of independent variable should cause changes in level of dependent variable.
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Typical Relationship We Normally Like to StudyIndependent VariableDependent VariableMoisture contents Elongation of threadWax purity Hardness of lipstickRoller PressurePaper thicknessCharge weight Range of bulletNumber of users Response time
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Pull SpeedLength of barTypical RelationshipYX
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Shelf LifePotencyTypical RelationshipYX
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Table - Humidity Vs Voltage
Humidity %
Voltage
V1
V2
V3
V4
V5
10
20
30
40
50
60
70
80
90
100
40
46
45
49
51
54
54
57
59
60
43
43
43
45
47
51
52
55
57
58
41
46
43
48
50
51
51
54
56
57
42
46
44
49
51
52
55
58
59
58
40
44
43
46
49
53
53
58
57
58
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Scatter Plot1050204060307080901004045505560HumidityVoltage35
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StratificationStratification is simply the creation of a set of pareto charts for the same data, using different possible causative factors
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Following figures plot defects against three possible sets of potential causes. The figure shows that there is no significant difference in defects between production lines or shifts. But product type three has significantly more defects than do the others. Finding the reason for this difference in number of defects could be worthwhile
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A problem is solved according to the following SEVEN STEPS of Q.I.Story.
SEVEN STEPS OF Q.I.STORY :
1. Reason For Improvement
2. Current Situation
3. Analysis
4. Counter Measure
5. Result
6. Standardization
7. Future Plan
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