1. Measurement accuracy is attained when...

Different people get the same result when measuring the same item or characteristic.

The same person taking multiple measurements on the same item or characteristic gets the same results every time.

The measured value has little deviation from the actual value.

When the resolution of the measurement instrument can give at least 5 distinct values in the range being measured. 

2. In a normal distribution 68% of the data will occur within...

+/- 2 standard deviations

+/- 1 standard deviation

+/- 3 standard deviations

Outside the bell-shaped curve

3. The Risk Priority Number (RPN) in an FMEA exercise is derived from...

severity x occurrence x risk

severity x risk x detection

occurrence x detection x control

severity x occurrence x detection

4. The Voice of the Customer

The number of errors in the process

A control chart with control limits

The department's output target

The customer's specification limits

5. A planning method designed to show the tasks associated with a project, the personnel responsible for completing the tasks and the timelines allowed

Pareto chart

Gantt chart

Microsoft Project

Check sheet

6. A bar chart that depicts the frequencies of numerical or measurement data

Sample

Histogram

Check Sheet

Process Map

7. SIPOC

Suppliers, Inputs, Procedure, Outputs, Customers

Simple, Inputs, Process, Outputs, Complex

Simple, Inputs, Procedure, Outputs, Complex

Suppliers, Inputs, Process, Outputs, Customers

8. An improvement process in which a company measures its performance against that of best-in-class companies, determines how those companies achieved their performance levels, and uses the information to improve its own performance

Control Chart

Six Sigma

Benchmarking

Cause and Effect Diagram

9. A control limit

Indicates the boundary of the bell curve in a normal distribution

Indicates that a process event or measurement is likely to fall within that limit

Indicates that a process event or measurement is likely to fall outside that limit

Indicates the customer's desired upper or lower performance limits

10. For a set of data, the average squared deviation from the mean, with a denominator of n-1

Sample Variance

Normal Distribution

Sample

Population11. Provides relationship between two variables, and provides a visual correlation coefficient

Scatter Diagram

Cause and effect chart

Box plot

Trend line12. The objective of Design of Experiments (DOE) is to

Map all process steps and determine their average duration

Establish optimal process performance by finding the right settings for key process input variables

Establish the best graphing method to illustrate process performance

Determine the mean and standard deviation of a population13. A six sigma capable process will have

Cp = 1.5, Cpk = 2.0 and DPMO = 3.4

Cp = 2.0, Cpk = 1.5 and DPMO = 6

Cp = 1.5 Cpk = 2.0 and DPMO = 6

Cp = 2.0, Cpk = 1.5 and DPMO = 3.414. A pictorial diagram showing possible causes (process inputs) for a given effect (process outputs) It is also referred to as the "Ishikawa diagram" or "fishbone diagram "

Standard Deviation

Cause and Effect Diagram

Random Experiment

Scatter Diagram

15. When the mean of the process is outside the customer specification limits the value of Cpk will be:

2.0

0.5

1.0

Negative16. Six sigma black belt responsibilities include all of the following, except:

Selecting projects for execution by green belts

Mentoring green belts

Training organisation staff in six sigma techniques and team work

Planning the sales and marketing strategy17. The middle value of a data set when the values are arranged in either ascending or descending order

Median

Mode

Mean

Discrete Data18. One of the most common measures of variability in a data set or population

Process capability

Specification limits

Mean

Standard Deviation 19. A sequence of 3 operations has first pass yield (right first time) rates as follows: 93%, 87% and 92%. The first pass yield rate is:

72%

74%

99%

87%20. The following are indicators of out of control conditions on a control chart, except

Six consecutive points, increasing or decreasing

Fourteen consecutive points that alternate up and down

Two points in zone c above the mean, followed by two points in zone b below the mean

One or more points outside the control limits

  

SIX SIGMA GREEN BELT EXAMINATION

1 . The men to r f o r t he Green Be l t shou ld a t l e a s t be a(A)Mas t e r  B l ack  be l t( B ) C h a m p i o n( C ) B l a c k B e l t( D ) G r e e n B e l tAns: C

2. The Black Belt is guiding projects carried out by green or yellow belts on a( A ) F u l l t i m e b a s i s( B ) P a r t i a l b a s i s(C)Beyond official working hours(D)Consu l t i ng  ba s i sAns: A

3 . The  da t a fo r p ro j ec t s   i s   co l l e c t ed  by   t he( A ) G r e e n   B e l t s( B ) B l a c k b e l t s( C ) B o t h   o f t h e m( D ) N o n e   o f   t h e mAns: A

4 . Me t r i c o f S IX S IGMA g ive s an i n s igh t i n to how many( A ) D e f e c t i v e s( B ) D e f e c t s(C)Defects per million opportunity

( D ) D e f e c t s p e r u n i tAns: C

5 . S IX  S IGMA  concep t s we re  bo rn i n(A)Al l i ed  S igna l  L td .(B)Gene ra l  E l ec t r i c  L td .( C ) C h r y s l e r L t d .( D ) M o t o r o l a L t d .Ans: D

6. The person who propagated SIX SIGMA concepts  in General Electric Ltd..was ( A ) J a c k W e l c h( B ) B o b   S m i t h( C ) P h i l i p   C r o s b y( D ) N o n e   o f   t h e mAns: A

7. Weaving of Cloth is being done in looms. It was seen that  defects like coagulation of thread, Knot, Breakage in continuity of thread, Grease marks are opportunities of defects. The number of such defects were found to be 20 in the 100 dhotis woven. Calculate the six sigma level at which the looms was operating.

Ans: No. of Defects = 20Total No. of Dhotis Woven = 100  No. of Opportunities = 4 (coagulation of threads, knot, breakage of continuity of threads & grease marks)Defects per unit (DPU) = D/U = 20/100 = 0.20Defects per opportunities (DPO) = 20/ (4*100) = 0.05Defects per million opportunities (DPMO) = 0.05*106= 50000 PPMZ = 0.5 – 0.05 = 0.45Z Value = 1.645 Sigma Value to Z = 1.645 + 1.5 = 3.145 

8 . Kano Mode l shows   t he  pa th t owards(A)Sa t i s fy ing a cus tomer  (B)De l igh t i ng a cus tomer  (C)Ensu re ba s i c needs o f a cus tomer  (D)None o f   t he   aboveAns: B

9 . Pa re to Cha r t   i s r e ad  by   t he  u se r t o   f i nd ou t(A)which 20% of the causes contribute towards 80% of the problem(B)which 20% of the people in a state posses 80% of the wealth( C ) B o t h o f t h e a b o v e(D)None o f   t he   above .Ans: C

10. Cause and Effect Diagram was first formulated by( A ) J u r a n( B ) D e m i n g( C ) T a g u c h i( D ) I s h i k a w aAns: D

11. In Measurement System Analysis the variance contribution allowed for GageR & R is to a maximum of ( A ) 2 0 %( B ) 1 0 %( C ) 3 0 %( D ) 5 %Ans: C

12. The following data on an experiment is given. Perform the measurementSystem Analysis on the data. P a r t s   O p e r a t o r  1 O p e r a t o r   2 T r i a l  1 T r i a l   2 T r i a l   1 Tr i a l   2 1 1 0 . 21 1 . 6 1 1 .0 1 1 . 2 1 1 .3 1 1 . 7 1 1 . 21 2 . 5 2 1 0 .9 1 1 . 8 1 1. 0 1 2 . 8 1 4. 0 1 1 . 5 1 1 .3 1 2 . 7 3 1 2. 0 1 0 . 2 11 . 2 1 3 . 01 1 . 6 1 0 . 6 10 . 3 1 3 . 4 4 12 . 6 1 0 . 51 1 . 4 1 0 .3 1 5 . 0 1 4 . 21 1 . 2 1 4 . 3 51 0 . 2 1 4 .6 1 1 . 3 1 3. 2 1 0 . 3 1 2. 3 1 1 . 6 1 0 .8 Ans:P a r t s   O p e r a t o r   1   Op e r a t o r   2 

T r i a l   1 T r i a l  2 a v g r a n g e T r i a l   1 T ri a l   2 a v g r a n g e 1 1 0. 2 1 1 . 6   1 1 1 1 .2 1 1 . 3 1 1 . 7  1 1 . 2 1 2 . 5 A v g 1 0 . 7 5 1 1 . 6 5 1 1 .2   1 1 . 1 1 1 . 8 5 1 1 . 4 75 r a n g e 1 . 1 0 .1   0 . 6 0 . 2 1 . 3  0 . 7 5 2 1 0 . 9 1 1. 8   1 1 1 2 . 8 1 4 1 1 . 5   1 1 . 3 1 2 . 7 A v g 1 2 . 4 5 1 1 . 6 5 1 2 . 05   1 1 . 1 5 1 2 . 7 5 1 1 . 9 5r a n g e 3 . 1 0 .3   1 . 7 0 . 3 1 .3   0 . 8 3 1 2 10 . 2   1 1 . 2 13 1 1 . 6 1 0 . 6  1 0 . 3 1 3 . 4 A v g 1 1 . 8 1 0 . 4 1 1 .1   1 0 . 7 5 1 3 . 2 1 1 .9 7 5 r a n g e 0 . 40 . 4   0 . 4 0 . 9 0. 4   0 . 6 5 4 1 2 .6 1 0 . 5   1 1 . 4 1 0 .3 1 5 1 4 . 2   1 1 . 2 1 4 . 3 A v g 1 3 . 8 1 2 . 3 5 1 3. 0 7 5   1 1 . 3 1 2 . 3 1 1. 8 r a n g e 2 . 4 3. 7 3 . 0 5 -0 . 2 4  1 . 9 5 1 0 . 2 1 4 . 6  1 1 . 3 1 3 . 2

 1 0 . 3 1 2 . 3  1 1 . 6 1 0 . 8 Avg1 0 . 2 5 1 3 . 4 511.851 1 . 4 5 1 211.725range0 . 1 2 . 31.20 . 3 2 . 41.35Mean of Xa=11.855;Mean of Xb=11.785;Range of A=1.39;Range of B=1.09X diff=0.07

13.The normality check on the data is done through normal probability paper where the Anderson Darling test is performed. For the data to be normalthe p-value should be( A ) 0 . 0 5( B ) > 0 . 0 5( C ) < 0 . 0 5( D ) 0 . 9 5Ans: B

14. In FMEA if the RPN number is high then we attack that mode of failure.first and then what do we first see in that mode of failure?(A)Occu r r ence i s   h igh(B)De tec t i on i s d i f f i cu l t( C ) S e v e r i t y i s f a t a l(D)None o f   t he   above .Ans: D

15. Quality function Deployment is a( A ) P l a n n i n g t o o l( B ) D i a g n o s t i c T o o l( C ) C h e c k S h e e t(D)None o f   t he   aboveAns: A

16.The transformation used to make a normal distribution with mean µ and standard deviation σ to a Standard Normal Distribution is given by( A ) ( X - µ) /σ2

( B ) ( X - µ)2/σ2

( C ) ( X - µ) /σ(D)None o f   t he   aboveAns: A

17.Green belts carry out project work during their (A)no rma l work ing hou r s(B)beyond  o f f i c e   hou r s( C ) t a k e s p e c i a l l e a v e( D ) A l l o f t h e a b o v eAns: A

18.If their arises a major doubt in the statistical analysis of the data then theGreen Belts and Black Belts seek help of 

( A ) C h a m p i o n

( B ) M a s t e r B l a c k B e l t

( C ) C E O

( D ) R e f e r a l i b r a r y

Ans: B

19.A project is spearheaded by a Black Belt after it has been approved by

( A ) C h a m p i o n

( B ) M a s t e r B l a c k B e l t

( C ) C E O

(D)Manag ing  D i r ec to r  

Ans: A

20.A process is following normal distribution with mean 10 and standarddeviation 2. What is the area under the curve if the sample collected have maxreading as 20 and min reading as 5?

Ans: 5<X<20

(5-10)/2<Z<(20-10)/2

-2.5<Z<5

P(Z<5)-P(Z<-2.5)

0.5-(-0.493790)

=0.993790

 21.If the DPO=0.025 then what is the percentage of acceptance of the product being produced ?Ans: DPO =0.025DPMO = DPO*1000000 = 0.025*1000000 = 25,000 ppmSigma Level corresponding to 25,000 ppm = 3.4Sigma percentage = 97.1283 % (from the table 2 for Conversion between PPM& Sigma) 

22.While selecting the projects the Black Belts should always choose projects.with(A)which have less impact but more saving(B)which have more impact and more saving(C)which are less time consuming and savings is more(D)which have more impact and less time consumingAns: B

23.The path from moving from a six sigma level of 4 to 5 is( A ) e a s y( B ) d i f f i c u l t(C ) looks   imposs ib l e(D)none o f   t he   aboveAns: B

24.The first journal on quality was published by( A ) U . S . A( B ) J a p a n( C ) G e r m a n y( D ) B r i t a i nAns: B

25.Rajiv Gandhi Award is a quality award given by(A)Rajiv Gandhi Foundation(B) Conferderation of Indian Industries(C)Bureau  o f   I nd i an  S t anda rd(D)Indian Statistical InstituteAns: C