when should you find the confidence interval, and when should you use a hypothesis test? page 174
TRANSCRIPT
A May 2000 Gallup Poll found that 38% of a random sample of 1012 adults said that they believe in ghosts. Find a 95% confidence interval for the true proportion of adults who believe in ghost.
A May 2000 Gallup Poll found that 38% of a random sample of 1012 adults said that they believe in ghosts. Find a 95% confidence interval for the true proportion of adults who believe in ghost.
Find the confidence interval only.
No hypothesis test is required.
Assumptions:
•Have an SRS of adults
•np =1012(.38) = 384.56 & n(1-p) = 1012(.62) = 627.44 Since both greater than 10, can approximate to normal.
•Population of adults is at least 10,120.
Conclusion: We are 95% confident that the true proportion of adults who believe in ghosts is between 35% and 41%.
AP Format Given: n = 1012p = .38q = .62Phat=.38x = (1012)(.38) = 385
Calculations:
A new flu vaccine claims to prevent a certain type of flu in 70% of the people who are vaccinated. In a test, vaccinated people were exposed to the flu. The test statistic for the results is z = -1.38. Is this claim too high?
A new flu vaccine claims to prevent a certain type of flu in 70% of the people who are vaccinated. In a test, vaccinated people were exposed to the flu. The test statistic for the results is z = -1.38. Is this claim too high?
Use a hypothesis test.
A new flu vaccine claims to prevent a certain type of flu in 70% of the people who are vaccinated. In a test, vaccinated people were exposed to the flu. The test statistic for the results is z = -1.38. Is this claim too high? Write the hypotheses, calculate the p-value & write the appropriate conclusion for = 0.05.
H0: p = .7Ha: p < .7Where p is the true proportion of vaccinated people who get the flu
P-value = normalcdf(-10^99,-1.38) =.0838
Since the p-value > , I fail to reject H0. There is not sufficient evidence to suggest that the proportion of vaccinated people who do not get the flu is less than 70%.
Formula for hypothesis test:Formula for hypothesis test:
statistic of SD
parameter - statisticstatisticTest
z pp ˆ
npp
pp
1
ˆ
P. 174 #2 A magazine is considering the launch of an online edition. The magazine plans to go ahead only if it’s convinced that more than 25% of current readers would subscribe. The magazine contacts a random sample of 500 current subscribers and 137 of those surveyed expressed an interest. Is this sufficient evidence for the magazine to start the online edition?
P. 174 #2 A magazine is considering the launch of an online edition. The magazine plans to go ahead only if it’s convinced that more than 25% of current readers would subscribe. The magazine contacts a random sample of 500 current subscribers and 137 of those surveyed expressed an interest. Is this sufficient evidence for the magazine to start the online edition?
Use a hypothesis test.
Assumptions:
•Have an SRS of current subscribers
•np = 500(.25) = 125 & n(q) = 500(.75) = 375 Since both greater than 10, can approximate to normal.
•Population of subscribers is at least 5000.
Conclusion: Since the p-value is greater than α, I fail to reject the null hypothesis. There is not sufficient evidence for the magazine to start the online edition.
P. 174 #2 AP Format Given: n = 500, x = 137p = .25q = .75phat=137/500 = .274
Calculations:
P-value = normalcdf(1.239,10^99) =.108
Hypotheses: H0: p = .25 α = .05Ha: p > .25Where p is the true proportion of current readers who would subscribe.
REVIEW: Facts about p-values:
• ALWAYS make decision about the null hypothesis!
• Large p-values show support for the null hypothesis, but never that it is true! “Fail to reject”
• Small p-values show support that the null is not true. “Reject”
• Double the p-value for two-tail (=) tests
• Never acceptNever accept the null hypothesis!
At an level of .05, would you reject or fail to reject H0 for the given p-values?
a) .03
b) .15
c) .45
d) .023
Reject
Fail to reject
Fail to reject
Reject