what would justin do? algebra outside of “the box”

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What would Justin do? Algebra outside of “the box” WATERTOWN MIDDLE SCHOOL Lesson Study Open House April 11, 2006

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What would Justin do? Algebra outside of “the box”. WATERTOWN MIDDLE SCHOOL Lesson Study Open House April 11, 2006. Let’s go back to Justin…. Calculating surface area (of a cube). Justin’s way (cube). Calculating surface area of a rectangular prism. S = 2 lw + 2 lh + 2 wh. - PowerPoint PPT Presentation

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Page 1: What would Justin do?  Algebra outside of “the box”

What would Justin do? Algebra outside of

“the box”

WATERTOWN MIDDLE SCHOOLLesson Study Open House

April 11, 2006

Page 2: What would Justin do?  Algebra outside of “the box”

Let’s go back to Justin…

Page 3: What would Justin do?  Algebra outside of “the box”

Calculating surface area (of a cube)

S = 6x 2

Page 4: What would Justin do?  Algebra outside of “the box”

Justin’s way (cube)

S = ( 4 x ) x + x2

+ x2

S = 6 x2

Page 5: What would Justin do?  Algebra outside of “the box”

Calculating surface area of a rectangular prism

• S = 2lw + 2lh + 2wh

QuickTime™ and aTIFF (Uncompressed) decompressorare needed to see this picture.

Page 6: What would Justin do?  Algebra outside of “the box”

Justin’s way:

• S = 2lw + 2lh + 2wh• S = l(2w + 2h) + 2wh

QuickTime™ and aTIFF (Uncompressed) decompressorare needed to see this picture.

Page 7: What would Justin do?  Algebra outside of “the box”

If you picked up this prism, how many exposed faces

could you count?

Page 8: What would Justin do?  Algebra outside of “the box”

Fill in the chart below1.Number of cubes in

the prismNumber of exposed

faces

1

2

3

100

500

N

Page 9: What would Justin do?  Algebra outside of “the box”

Fill in the chart below1.Number of cubes in

the prismNumber of exposed

faces

1 6

2 10

3 14

100 402

500 2002

N 4N + 2

Page 10: What would Justin do?  Algebra outside of “the box”

How did you get your answer?

Page 11: What would Justin do?  Algebra outside of “the box”

Try to find two other correct algebraic expressions for the number of exposed faces in a

prism formed by N cubes - by thinking about the problem

differently.(i.e.: what would Justin do?)

Page 12: What would Justin do?  Algebra outside of “the box”

How might you get…?

• 6N – 2(N – 2) – 2

Page 13: What would Justin do?  Algebra outside of “the box”

How might you get…?

• 6N – 2(N – 2) – 2

• N+N+N+N+2

Page 14: What would Justin do?  Algebra outside of “the box”

How might you get…?

• 6N – 2(N – 2) – 2

• N+N+N+N+2

• 5N – 2(N – 2)

Page 15: What would Justin do?  Algebra outside of “the box”

What happens if, instead of a prism that is one cube wide, we create prisms that are two cubes

or three cubes wide?

3 cubes wide2 cubes wide

Page 16: What would Justin do?  Algebra outside of “the box”

• :

1 cube wide

2 cubes wide

3 cubes wide

1 cube long2 cubes long3410100500N

Page 17: What would Justin do?  Algebra outside of “the box”

• :

1 cube wide

2 cubes wide

3 cubes wide

1 cube long 6 10 142 cubes long

10 16 22

3 144 1810 42100 402500 2002N 4N + 2 6N + 4 8N + 6

Page 18: What would Justin do?  Algebra outside of “the box”

How can you describe the exposed faces of a prism in terms of the width (W) AND

the length (N)?

Page 19: What would Justin do?  Algebra outside of “the box”

How can you describe the exposed faces of a prism in terms of the width (W) AND

the length (N)? • 2WN + 2W + 2N

Page 20: What would Justin do?  Algebra outside of “the box”

How can you describe the exposed faces of a prism in terms of the width (W) AND

the length (N)? • F(W,N) = 2WN + 2W + 2N

(A function of two variables?!)

Page 21: What would Justin do?  Algebra outside of “the box”

Determine the number of exposed faces of a prism that is N cubes long, W cubes wide, and H

cubes high.

4 cubes long4 cubes wide3 cubes high4 cubes long3 cubes wide2 cubes high