week. student will: laws of conservation of energy demonstrate and apply the laws of conservation...
TRANSCRIPT
Objective
Student will: Demonstrate and apply the laws
of conservation of energy in terms ofKinetic And Potential Energy
Cornell Notes (1/4)Energy: Ability to do work or cause change in a system Scalar Measured in Joules (J)
Gravitational Potential Energy (PE): Stored potential energy due to height
Potential Energy (J)= mass (kg) x gravity (9.81 m/s2) x
change in height (m)
Questions
1) Can an object that has zero height have PE?
g is positive because since energy is not a vector, no direction is
needed
No Trig needed!
Cornell Notes (2/4)Kinetic Energy: Energy due to an object’s motion.
KE = ½ mv2
Kinetic Energy (J) = ½ mass (kg) x (velocity)2 (m/s)
2) Can an object have both potential an kinetic energy?
Cornell Notes (4/4)
The law of conservation of energy: In a closed system, energy cannot be created or destroyed, it can only change forms.
PEi + KEi = PEf + KEf
mghi + ½ mvi2 = mghf +
½ mvf2
If friction is involve, that means energy is
lost somewhere
Cornell Notes (1/5)
Example: Conservation of Energy
Gwen Stacy is dropped from 84.3 meters (273.4 ft) from the top of the Brooklyn Bridge. Calculate her velocity right before she hits the water. Assume her mass is 70 kg.
Cornell Notes (2/5)Given:
vi = 0 m/s
hi = 84.3 m
hf = 0 mm = 70 kg
ay = g = 9.81 m/s2
Unknown: vf = ?
Steps1) Define
Gwen Stacy is dropped from 84.3 meters (273.4 ft) from the top of the Brooklyn Bridge. Calculate her velocity right before she hits the water. Assume her mass is 70 kg.
Cornell Notes (3/5)Choose an equation or situation:
Rearrange the equation to isolate the unknown:
2) Plan
𝑚𝑔 h𝑖+12𝑚𝑣 𝑖
2=𝑚𝑔 h𝑓 +12𝑚𝑣 𝑓
2
√2𝑔h 𝑖=𝑣
Gwen’s potential energy is all converted to kinetic
energy
𝑚𝑔 h𝑖+12𝑚𝑣 𝑖
2=𝑚𝑔 h𝑓 +12𝑚𝑣 𝑓
2
𝑚𝑔 h𝑖+0=0+12𝑚𝑣 𝑓
2
𝑚𝑔 h𝑖=12𝑚𝑣𝑓
2
𝑔 h𝑖=12𝑣 𝑓2
Cornell Notes (4/5)Substitute the values into the equation and solve
3) Calculate
40.669=𝑣
√2𝑔h 𝑖=𝑣
√2 ∙9.8 ∙84.3=𝑣
40.669𝑚 /𝑠=𝑣