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Page 1: vd calculation

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SECTION-9

ELECTRICAL DESIGN CALCULATION

507

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1.0 Formula Used:

1.1 Working Load in kVA = L. F.

1.2 System P. F. = P. F.

D. F.

Effi.2.0

UnitTotal

(kW)Unit

Total

(kW)

2.1 280 0.946 0.85 0.9 1 3 840 2 504

Total Load 840 504

3.0 = 752.15 kVA

4.0 = 0.8041

5.0

5.1 = 1250 kVA5.2 = 5 %

5.3 = 280 KW

5.4 = 3.3 kV

5.5 = 0.85

5.6 = 0.946

5.9 = 348.2153961 kVA

5.10 = 2089.292377 kVA

5.11 = 696.4307922 kVA

5.14 = 25000 kVA

(within 10%)S.C capacity of transformer

The selected rating of transformer is 1250 kVA

5.16Voltage drop at transformer terminal when largest

motor start with Star Delta starting= 4.2 %

[Motor Starting kVA (S/D) + Base Load kVA] x 100

S.C capacity of transformer 1.7321 x kV x I SC

5.15Voltage drop at transformer terminal when largest

motor start with DOL starting= 9.750031091 %

[Motor Starting kVA (DOL) + Base Load kVA] x 100(within 10%)

S.C capacity of transformer

5.13 Fault current of transformer secondary side (ISC) = 4.373741456 kAFault Level in MVA

1.7321 x kV

5.12 Fault Level at transformer secondary side = 25 MVARating of transformer in MVA x 100

Impedance of transformer in %

Base load on transformer before starting Second

largest motor(Considering only one motor is working and the Second motor is starte

Motor starting Kva with DOL start = 6 x 1.7321 x kV x I FLC

Motor starting Kva with Star Delta start = 3 x 1.7321 x kV x I FLC

5.8 Rating of largest size motor in kVA = 348.2153961 kVAkW

P.F x Efficiency

5.7 FLC of motor = 60.92016454 AkW x 1000

1.7321 x V x p.f x efficiency

Supply voltage System voltage

P.F of largest size motor From the above table

Efficiency of largest size motor From the above table

Calculation to check the starting of largest size motor

Rating of transformer assumed Nearest standard size (Confg. 33/3.3KV,Dyn11,Delta-star)

% impedance of transformer assumed From IS 2026

Rating of the largest size motor From the above table

626.79

Considering 20% contingency

System P. F.

D. F.

Connected Load Working LoadWorking Load

(kVA)

Pump 626.79

Sr.

No.Item Description

Rating in

kWEffi. P. F. L. F.

= Motor EfficiencyInput Data and Calculations:

TRANSFORMER SIZING FOR CWPS PLANT

[ Working Load (kW) x L. F. ] / [ D. F. x P. F. x Effi. ] = Load Factor

Total Working Load (kW) / Total Working Load (kVA) = Motor Power Factor

= Diversity Factor

508

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CAPACITOR BANK SIZING ACROSS MOTOR TERMINAL

1 Motor rating (kW) 280

2 Motor rating after 90% load factor (kW) 252 To be considered for further calculations

3 Supply Voltage (V) 3300

4 Motor Power Factor (p.f 1) 0.85 Based on actual Values given by jyoti

5 Motor efficiency (Effi.) 0.946 Based on actual Values given by jyoti

6 Power Factor to be improved (p.f 2) 0.98

7 No load p.f. (p.f NL) 0.1 Assumption

8 Motor Full Load Current in amp.(FLC) 54.828 = (kW x 1000) / (1.7321 x V x cos(p.f 1) x Effi.)

9 No load current in amp. (INLC) 19.190 35% of FLC

10 Motor magnetising current in amp. 19.094 = [ INLC x sin(cos-1

p.f NL) ]

11 Capacitor current (Ic) 17.184 Shall be 90% of motor magnetising current

12Max. kVAR that can be connected across motor

terminal98.22 = (1.7321 x V x Ic) / 1000

13Total kVAR to be connected across the motor

terminal105.00 = kW[ tan(cos

-1p.f 1) - tan(cos

-1p.f 2) ]

14Excess kVAR to be connected across the

switchgear bus bars (13 - 12)6.79

Negative value indicates capacitor bank is not

required across the bus.

Main Pumps For Clear water pumping station

509

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1.0 Formula Used:

1.1 Working Load in kVA = L. F.

1.2 System P. F. = P. F.

D. F.

Effi.2.0

UnitTotal

(kW)Unit

Total

(kW)

a EOT crane 15 0.87 0.82 1 2 1 15 1 7.5

b Exhaust fan 0.5 0.67 0.82 1 1 8 4 8 4

c 15 0.8 0.8 1 1.5 Lumpsum 15 Lumpsum 10

d 1.5 0.79 0.81 0.9 1 2 3 2 2.7

e 7.5 0.87 0.82 0.9 1 2 15 2 13.5

f 160 0.962 0.86 0.9 2 2 320 1 72

g 37 0.935 0.86 0.9 2 2 74 1 16.65

h 1.1 0.79 0.81 0.9 2 2 2.2 1 0.495

i 1.1 0.77 0.81 0.9 1 2 2.2 1 0.99

 j 3.7 0.77 0.82 0.9 1 2 7.4 1 3.33

k 1.5 0.79 0.81 1 2 3 4.5 3 2.25

l 1.5 0.79 0.81 1 2 3 4.5 3 2.25

m 1.5 0.79 0.81 1 2 3 4.5 3 2.25

n 1.5 0.79 0.81 1 1 2 3 1 1.5

o 1.5 0.79 0.81 1 1 2 3 1 1.5

p 1.5 0.79 0.81 1 1 2 3 1 1.5

q 0.5 0.67 0.82 0.9 2 30 15 30 6.75

r 7.5 0.87 0.82 0.9 1 1 7.5 1 6.75

s 40 0.902 0.81 1 1.5 Lumpsum 40 Lumpsum 26.666667

Total Load 542.8 182.58167

3.0 = 297.31 kVA

4.0 = 0.7369

5.0

5.1 = 315 kVA

5.2 = 4.5 %

5.3 = 160 KW

5.4 = 0.415 kV

5.5 = 0.86

5.6 = 0.962

5.9 = 121.6044578 kVA

5.10 = 1160.373253 kVA

5.11 = 386.7910845 kVA

5.14 = 7000 kVA

= Motor EfficiencyInput Data and Calculations:

D. F.

Connected Load Working LoadWorking Load

(kVA)

TRANSFORMER SIZING FOR CWPS PLANT

[ Working Load (kW) x L. F. ] / [ D. F. x P. F. x Effi. ] = Load Factor

Total Working Load (kW) / Total Working Load (kVA) = Motor Power Factor

= Diversity Factor

Sr.

No.Item Description

Rating in

kWEffi. P. F. L. F.

247.76

Considering 20% contingency

10.51

7.28

Flash mixture 4.22

Lighting (CWPS) 15.63

System P. F.

Calculation to check the starting of largest size motor

Rating of transformer assumed Nearest staanddard size (Confg. 33/0.433KV,Dyn11,Delta-star)

% impedance of transformer assumed From IS 2026

Rating of the largest size motor From the above table

Supply voltage System voltage

P.F of largest size motor From the above table

Efficiency of largest size motor From the above table

5.7 FLC of motor = 269.0452946 AkW x 1000

1.7321 x V x p.f x efficiency

5.8 Rating of largest size motor in kVA = 193.3955422 kVAkW

P.F x Efficiency

Base load on transformer before starting fourth

largest motor(Rating in kVA of transformer assumed - Largest motor KVA)

Motor starting Kva with DOL start = 6 x 1.7321 x kV x I FLC

Motor starting Kva with Star Delta start = 3 x 1.7321 x kV x I FLC

5.12 Fault Level at transformer secondary side = 7 MVARating of transformer in MVA x 100

Impedance of transformer in %

5.13 Fault current of transformer secondary side (ISC) = 9.738161699 kAFault Level in MVA

1.7321 x kV

S.C capacity of transformer 1.7321 x kV x I SC

5.15Voltage drop at transformer terminal when largest

motor start with DOL starting= 18.3139673 %

[Motor Starting kVA (DOL) + Base Load kVA] x 100(within 10%)

S.C capacity of transformer

(within 10%)S.C capacity of transformer

The selected rating of transformer is 400 kVA

5.16Voltage drop at transformer terminal when largest

motor start with Star Delta starting= 7.3 %

[Motor Starting kVA (S/D) + Base Load kVA] x 100

Clarifloculator mechanism phase-1 18.92

backwash pumps 87.03

Air blower 20.71

Chlorine booster pumps for prechlorination 0.77

Chlorine booster pumps for postchlorination 1.59

Service water pumps 5.27

Agitator for Alum dosing pump 3.52

Agitaotor for Lime dosing pump 3.52

Agitator for polyelectrolyte dosing tank 3.52

Dosing pump for alum 2.34

Dosing pump for lime 2.34

Dosing pump for polyelectrolyte 2.34

EOT crane 9.46

Lighting (chemical,Filter,pump,outdoor) 36.50

Valves 12.29

510

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CAPACITOR BANK SIZING ACROSS BUS

Intermediate Pumping Station

1 Average Power factor (pf1) 0.737

2 Total Working load in IPS 210 kW

3 Power factor To be improved (pf2) 0.98

Total kVAR to be connected across Bus

4 Total kVAR to be connected across Bus 150 KVAR

Working load ( Tan ( Cos-1

pf1) - Tan (Cos-1

pf2))

511

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Short circuit calculation CWPS main Pump

Assumptions

1 Fault level at 220kV bus 20000 MVA (as per IS :2026)

2 Base MVA 2000

Ratio = 220kV / 132kV

Capacity = 100.00 MVA

Z= 9.27%

Qty 1 Nos

Considering negative tolerance Z = 8.34%

Net Z for transformers single transformer= 8.34%

3

Ratio = 132kV / 33kV

Capacity = 40.00 MVA

Z= 10.18%

Qty 1 Nos

Considering negative tolerance Z = 9.16%

Net Z for transformers single transformer= 9.16%

4

Line length = 15 kM

Conductor Type = DOG Assumed

Conductor Resiatance = 0.2733 ohm/kM

Z,Considering Reactance Negligible = 4.0995 ohm

5

Ratio = 33kV / 3.3kV

Capacity = 1.25 MVA

Z= 5.0%

Qty 1 Nos

Considering negative tolerance Z = 4.5%

Net Z for transformers single transformer= 4.5%

6 K' Constant for XLPE AL cable= 94

K' Constant for PVC AL cable= 75

K' Constant for PVC CU cable= 112

7 Fault clearing time for 33kV Breaker (t) = 1 Sec

Fault clearing time for 3.3kV Breaker (t) = 1 Sec

10 Starting Voltage dip = 15%

11 Starting current for DOL= 6 times

12 Starting current for Y-D= 2 times

13 Starting current for FCMA softstarter= 2.5 times

Transformer Details at Chandaka220KV/132KV

Transformer Details at Chandaka 132KV/33KV

33kV Over head line from Chandaka to CWPS

Transformer at CWPS

512

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Calculation

a chandaka Grid Substation

220KV Bus 0.1 20000 52

220KV/132KV,100MVA transformer 1.7

1 132kV Bus 1.8 1130.8 5

2 132kV/33kV,40MVA transformer 4.6

3 33kV Bus 6.3 315.0 5.51 58.6

b CWPS

1 15 kM 33kV O/H line from Chandaka Substation to CWPS 7.53

2 33kV Bus 13.88 144.1 2.52 26.8

3

33kV , XLPE, cable 3core x 95sqmm cable from 6 Pole

structure to 33KV panel 0.03950

4 33kV panel 13.92 143.7 2.51 26.7

5

33kV , XLPE, cable 3core x 95sqmm cable from 33KV panel

to transformer 0.000987

6 33kV/3.3kV, 1.25MVA transformer 72.00

7 3.3kV side of 1.25MVA transformer 86.02 23.3 4.07 43.3

(XLPE,AL,3.3 kV)

8

3.3kV , XLPE, cable 3core x 300sqmm cable from

transformer secondary to CWPS PMCC 1.91

9 3.3kV CWPS PMCC Bus 87.83 22.8 3.98 42.4

(,AL,3.3 kV)

Sr No Description

Impedance "

Z"

Fault level

"MVA"

Fault Current

"kA"

Minimum Cable

size "SQMM"

513

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 349

2 VOLTAGE (V) = 3.3

3 PF = 0.84 FAULT CURRENT Ish = 3.98

5 FAULT CLEARING TIME t = 1

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 42.34042553

2 CABLE SIZE CHOSEN = 50 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.76

3 OVERALL DERATING FACTOR = 0.722

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE x 1.732

= 35.25

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

48.83

3 Current carring capacity of 3.5C x50 Sqmm AL XLPE cable is = 120

4 No of cable required = 0.41

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x50 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 50 SQmm AL XLPE Cable) = 0.82

3 X AT CONDUCTOR TEMP. (3C x 50 Qmm AL XLPE Cable) = 0.086

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.052371797

CABLE SIZE CHOSEN = 3.5CX50 sq.mm Al XLPE Cable

#$#%&"'(")*+"

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

515

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Short circuit calculation CWPS Auxilary WTP load

Assumptions

1 Fault level at 220kV bus 20000 MVA (as per IS :2026)

2 Base MVA 2000

Ratio = 220kV / 132kV

Capacity = 100.00 MVA

Z= 9.27%

Qty 1 Nos

Considering negative tolerance Z = 8.34%

Net Z for transformers single transformer= 8.34%

3

Ratio = 132kV / 33kV

Capacity = 40.00 MVA

Z= 10.18%

Qty 1 Nos

Considering negative tolerance Z = 9.16%

Net Z for transformers single transformer= 9.16%

4

Line length = 15 kM

Conductor Type = DOG Assumed

Conductor Resiatance = 0.2733 ohm/kM

Z,Considering Reactance Negligible = 4.0995 ohm

5

Ratio = 33kV / 0.415kV

Capacity = 0.32 MVA

Z= 4.5%

Qty 1 Nos

Considering negative tolerance Z = 4.1%

Net Z for transformers single transformer= 4.1%

6 K' Constant for XLPE AL cable= 94

K' Constant for PVC AL cable= 75

K' Constant for PVC CU cable= 112

7 Fault clearing time for 33kV Breaker (t) = 1 Sec

Fault clearing time for 0.415kV ACB Breaker (t) = 0.08 Sec

Fault clearing t ime for 0.415kV MCCB Breaker (t) = 0.04 Sec

10 Starting Voltage dip = 15%

11 Starting current for DOL= 6 times

12 Starting current for Y-D= 3.5 times

13 Starting current for FCMA softstarter= 2.5 times

Formula used

1

2

3 Zline =

4 Zcable =

Transformer Details at Chandaka220KV/132KV

Transformer Details at Chandaka 132KV/33KV

33kV Over head line from Chandaka to CWPS

Transformer at CWPS

Zsource =Base MVA

Fault level at 132kV bus

Ztransformer =Base MVA

X tranformer Z%Transformer capacity in MVA

Base MVAX Line Z

kV2

Base MVAX Cable Z

kV2

516

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Calculation

a chandaka Grid Substation

1 220KV Bus 0.1 20000 52

2 220KV/132KV,100MVA transformer 1.7

3 132kV Bus 1.8 1130.8 5

4 132kV/33kV,40MVA transformer 4.6

5 33kV Bus 6.3 315.0 5.51

b CWPS

1 15 kM 33kV O/H line from Chandaka Substation to CWPS 7.53

2 33kV Bus 13.88 144.1 2.52 26.8

4 33kV/0.415kV, 315KVA transformer 257.14

5 0.415kV side of 315KVA transformer 271.02 7.4 10.27 30.9

(XLPE,AL,0.415kV)

6

0.415kV , XLPE, cable 2 X 3.5c x 240.sqmm cable from

transformer secondary to CWPS PMCC 40.66

7 0.415kV CWPS AUXILARY MCC 311.68 6.4 8.93 26.9

(,AL,0.415 kV)

8

0.415kV , XLPE, cable 2 x 3.5core x 120sqmm cable from

CWPS PMCC to Motor (160KW) 81.31

9 0.415kV 160KW motor (194) 392.99 5.1 7.08 15.1

(,AL,0.415 kV)

10

0.415kV , XLPE, cable 3.5C x 240sqmm cable from CWPS

PMCC to WTP & Chemical 508.19

11 0.415kV WTP & Chemical 819.87 2.4 3.39 7.2

(,AL,0.415 kV)

Sr No Description

Impedance "

Z"

Fault level

"MVA"

Fault Current

"kA"

Minimum Cable

size "SQMM"

517

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 315

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 10.275 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 30.90207082

2 CABLE SIZE CHOSEN = 35 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable directly burried (3 cables touching)

RATING FACTOR = 0.69

3 OVERALL DERATING FACTOR = 0.6555

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 438.24

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

668.56

3 Current carring capacity of 3.5C x240 Sqmm AL XLPE cable is = 326

4 No of cable required = 2.05

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x240 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 240 SQmm AL XLPE Cable) = 0.16

3 X AT CONDUCTOR TEMP. (3.5C x 240 Qmm AL XLPE Cable) = 0.071

4 COSø = 0.8

5 SINø = 0.66 No of runs: = 2

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.624055741

CABLE SIZE CHOSEN = 2X3.5CX240 sq.mm Al XLPE Cable

""*,-+

(FULL LOAD CURRENT X LENGTH X IMPEDENCE)/NO

OF RUNS X VOLTAGE

518

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 194

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 8.935 FAULT CLEARING TIME t = 0.04

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 19

2 CABLE SIZE CHOSEN = 25 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE x 1.732

= 155.83

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

248.54

3 Current carring capacity of 3C x120 Sqmm AL XLPE cable is = 257

4 No of cable required = 0.97

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x120 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 120SQmm AL XLPE Cable = 0.324

3 X AT CONDUCTOR TEMP. (3C x 120 Qmm AL XLPE Cable) = 0.0712

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.785433685

CABLE SIZE CHOSEN = 2X3CX120 sq.mm Al XLPE Cable

*,-+".*"

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

519

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 46

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 8.935 FAULT CLEARING TIME t = 0.04

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 19

2 CABLE SIZE CHOSEN = 25 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE x 1.732

= 36.95

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

58.93

3 Current carring capacity of 3C x25 Sqmm AL XLPE cable is = 96

4 No of cable required = 0.61

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x25 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 25SQmm AL XLPE Cable) = 1.54

3 X AT CONDUCTOR TEMP. (3C x 25 Qmm AL XLPE Cable) = 0.0805

4 COSø = 0.8

5 SINø = 0.66 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.789742459

CABLE SIZE CHOSEN = 2X3CX25 sq.mm Al XLPE Cable

*,-+"#/*"

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

520

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 91

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 8.935 FAULT CLEARING TIME t = 0.04

6 CONSTANT K = 94

7 LENGTH = 250

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 19

2 CABLE SIZE CHOSEN = 25 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable directly burried (3 cables touching)

RATING FACTOR = 0.69

3 OVERALL DERATING FACTOR = 0.6555

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 126.60

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

193.14

3 Current carring capacity of 3.5C x240 Sqmm AL XLPE cable is = 367

4 No of cable required = 0.53

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x240 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 300 SQmm AL XLPE Cable) = 0.128

3 X AT CONDUCTOR TEMP. (3.5C x 300Qmm AL XLPE Cable) = 0.0705

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.911409493

CABLE SIZE CHOSEN = 3.5CX300 sq.mm Al XLPE Cable

+*,-+"*,+

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

521

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 20

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 3.395 FAULT CLEARING TIME t = 0.04

6 CONSTANT K = 94

7 LENGTH = 120

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 7.212765957

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable directly burried (6 cables touching)

RATING FACTOR = 0.54

3 OVERALL DERATING FACTOR = 0.513

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 27.82

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

54.24

3 Current carring capacity of 3.5C x35 Sqmm AL XLPE cable is = 113

4 No of cable required = 0.48

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x35 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 35 SQmm AL XLPE Cable) = 1.11

3 X AT CONDUCTOR TEMP. (3.5C x 35 Qmm AL XLPE Cable) = 0.0783

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.302918856

CABLE SIZE CHOSEN = 3.5CX35 sq.mm Al XLPE Cable

*,'&0+",1

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

522

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A) FEEDER DATA

1 WORKING LOAD (KW) 5.6

2 WORKING LOAD (KVA) = 7

2 VOLTAGE (V) = 0.4153 PF = 0.8

4 FAULT CURRENT Ish = 3.39

5 FAULT CLEARING TIME t = 0.04

6 CONSTANT K = 94

7 LENGTH = 120

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 7.212765957

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable directly burried (6 cables touching)

RATING FACTOR = 0.54

3 OVERALL DERATING FACTOR = 0.513

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 9.74

2 CURRENT RATING REQ.AFTER CONSIDERING DERA = FULL LOAD CURRENT/DERATING FACTOR

18.98

3 Current carring capacity of 4C x16 Sqmm AL XLPE cable = 67

4 No of cable required = 0.28

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 4C x16 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (4C x16 SQmm AL XLPE C = 2.44

3 X AT CONDUCTOR TEMP. (4C x16 Qmm AL XLPE Cab = 0.0837

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.976550907

CABLE SIZE CHOSEN = 4CX16 sq.mm Al XLPE Cable

*,'&0+",1

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

523

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A) FEEDER DATA

1 WORKING LOAD (KW) 12

2 WORKING LOAD (KVA) = 15

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 3.39

5 FAULT CLEARING TIME t = 0.04

6 CONSTANT K = 94

7 LENGTH = 105

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 7.212765957

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable directly burried (6 cables touching)

RATING FACTOR = 0.54

3 OVERALL DERATING FACTOR = 0.513

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 20.87

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

40.68

3 Current carring capacity of 4C x16 Sqmm AL XLPE cable is = 67

4 No of cable required = 0.61

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 4C x16 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (4C x16 SQmm AL XLPE Cable) = 2.443 X AT CONDUCTOR TEMP. (4C x16 Qmm AL XLPE Cable) = 0.0837

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.831032951

CABLE SIZE CHOSEN = 4CX16 sq.mm Al XLPE Cable

*,'&0+",1#

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

524

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 75

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 8.935 FAULT CLEARING TIME t = 0.04

6 CONSTANT K = 94

7 LENGTH = 25

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 19

2 CABLE SIZE CHOSEN = 25 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 104.34

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

166.42

Considering 35% extra current 224.66

3 Current carring capacity of 3.5C x120 Sqmm AL XLPE cable is = 257

4 No of cable required = 0.87

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x120 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 120 SQmm AL XLPE Cable) = 0.264

3 X AT CONDUCTOR TEMP. (3.5C x 120 Qmm AL XLPE Cable) = 0.0716

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.276701989

CABLE SIZE CHOSEN = 3.5CX120 sq.mm Al XLPE Cable

*,23&0!+"/4&"

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

525

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 100

2VOLTAGE (V) = 0.4153 PF = 0.8

4 FAULT CURRENT Ish = 3.09

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 25

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 9.297701931

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABL = Cable laid in ground (3 cables touching)

RATING FACTOR = 0.69

3 OVERALL DERATING FACTOR = 0.6555

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 139.12

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

212.24

3 Current carring capacity of 3.5C x120 Sqmm = 223

4 No of cable required = 0.95

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x120 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 120 SQ = 0.324

3 X AT CONDUCTOR TEMP. (3.5C x 120 Qm = 0.0712

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.438263899

CABLE SIZE CHOSEN = 3.5CX120 sq.mm Al XLPE Cable

!"#

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

526

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 29

2 VOLTAGE (V) = 0.415

3 PF = 0.84 FAULT CURRENT Ish = 2.64

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 45

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 7.943667669

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.952 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 40.35

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

64.35

3 Current carring capacity of 3C x16 Sqmm AL = 70

4 No of cable required = 0.92

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x16Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 16 SQmm = 2.44

3 X AT CONDUCTOR TEMP. (3C x 16 Qmm = 0.0808

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.515823138

CABLE SIZE CHOSEN = 2X3CX16 sq.mm Al XLPE Cable

$!"#%%&

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

527

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 16

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 2.64

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 55

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 7.943667669

2 CABLE SIZE CHOSEN = 10 SQ.MM AL(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 22.26

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

35.50

3 Current carring capacity of 3C x10 Sqmm AL = 67

4 No of cable required = 0.53

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x10 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 10 SQm = 3.94

3 X AT CONDUCTOR TEMP. (3C x 10 Qmm = 0.0837

4 COSø = 0.8

5 SINø = 0.66 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.636204732

CABLE SIZE CHOSEN = 2X3CX10 sq.mm Al XLPE Cable

$!"#&

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

528

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 20

2VOLTAGE (V) = 0.4153 PF = 0.8

4 FAULT CURRENT Ish = 2.64

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 35

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 7.943667669

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 27.82

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

44.38

Considering 35% extra current 59.91

3 Current carring capacity of 4C x10 Sqmm AL = 67

4 No of cable required = 0.89

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 4C x10 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (4C x 10 SQm = 3.94

3 X AT CONDUCTOR TEMP. (4C x 10 Qmm = 0.0837

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.301526492

CABLE SIZE CHOSEN = 4CX10 sq.mm Al XLPE Cable

$!"#%'

(FULL LOAD CURRENT X LENGTH XIMPEDENCE)/NO OF RUNS X VOLTAGE

529

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A) FEEDER DATA

1 WORKING LOAD (KW) 10

2 WORKING LOAD (KVA) = 12.5

2VOLTAGE (V) = 0.4153 PF = 0.8

4 FAULT CURRENT Ish = 2.64

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 30

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 7.943667669

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 17.39

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

27.74

3 Current carring capacity of 4C x10 Sqmm AL = 67

4 No of cable required = 0.41

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 4C x10 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (4C x 10 SQm = 3.94

3 X AT CONDUCTOR TEMP. (4C x 10 Qmm = 0.0837

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.697246335

CABLE SIZE CHOSEN = 4CX10 sq.mm Al XLPE Cable

$!"#

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

530

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1.0 Formula Used:

1.1 Working Load in kVA = L. F.

1.2 System P. F. = P. F.

D. F.

Effi.

2.0

UnitTotal

(kW)Unit

Total

(kW)

2.1 22 0.917 0.83 0.9 1 2 44 1 19.8

2.2 11 0.892 0.81 0.9 1 2 22 2 19.8

2.3 2 0.83 0.82 1 2 1 2 1 1

2.4 0.5 0.67 0.82 1 1 6 3 6 3

2.5 10 0.8 0.8 1 1.5 Lumpsum 10 Lumpsum 6.6666667

81 50.266667

3.0 = 84.92 kVA

4.0 = 0.71

5.0

5.1 = 100 kVA

5.2 = 4.5 %

5.3 = 22 KW5.4 = 0.415 kV

5.5 = 0.83

5.6 = 0.917

5.9 = 71.095 kVA

5.10 = 173.43 kVA

5.11 = 101.17 kVA

5.14 = 2222.2 kVA

TRANSFORMER SIZING FOR JATNI (KAJU PLANTATION) PUMPING STATION

[ Working Load (kW) x L. F. ] / [ D. F. x P. F. x Effi. ] = Load Factor

Lighting 10.42

5.46

1.47

Sr.

No.L. F. D. F.

Total Working Load (kW) / Total Working Load (kVA) = Motor Power Factor

Rating of the largest size motor From the above table

Considering 20% contingency

System P. F.

= Diversity Factor

= Motor Efficiency

Item DescriptionRating in

kWEffi.

Working Load

(kVA)

Connected Load Working Load

Input Data and Calculations:

P. F.

Total Load

Chain pully

Exhaust Fan

70.77

Pump-1 26.01

Pump-2 27.40

Supply voltage System voltage

Calculation to check the starting of largest size motor

Rating of transformer assumed Nearest staanddard size (Confg. 11/0.433KV,Dyn11,Delta-star)

% impedance of transformer assumed From IS 2026

P.F of largest size motor From the above table

Efficiency of largest size motor From the above table

5.7 FLC of motor = 40.212 AkW x 1000

1.7321 x V x p.f x efficiency

Motor starting Kva with Star-Delta start = 3 x 1.7321 x kV x I FLC

5.8 Rating of largest size motor in kVA = 28.905 kVAkW

P.F x Efficiency

Base load on transformer before starting fourth

largest motor(Rating in kVA of transformer assumed - Largest motor KVA)

Motor starting Kva with DOL start = 6 x 1.7321 x kV x I FLC

5.13 Fault current of transformer secondary side (ISC) = 3.0915

5.12 Fault Level at transformer secondary side = 2.2222

S.C capacity of transformer

MVARating of transformer in MVA x 100

Impedance of transformer in %

kAFault Level in MVA

1.7321 x kV

S.C capacity of transformer 1.7321 x kV x I SC

5.15Voltage drop at transformer terminal when largest

motor start with DOL starting= 11.004 %

[Motor Starting kVA (DOL) + Base Load kVA] x 100(within 10%)

The selected rating of transformer is 100 kVA

%[Motor Starting kVA (S/D) + Base Load kVA] x 100

(within 10%)S.C capacity of transformer

5.16Voltage drop at transformer terminal when largest

motor start with Star-Delta starting= 7.8

531

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CAPACITOR BANK SIZING ACROSS BUS

1 Average Power factor (pf1) 0.710

2 Total Working load 50 kW

3 Power factor To be improved (pf2) 0.98

Total kVAR to be connected across Bus

4 Total kVAR to be connected across Bus 40 KVAR

Working load ( Tan ( Cos-1

pf1) - Tan (Cos-1

pf2))

532

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1.0 Formula Used:

1.1 Working Load in kVA = L. F.

1.2 System P. F. = P. F.

D. F.

Effi.

2.0

UnitTotal

(kW)Unit

Total

(kW)

2.1 22 0.917 0.83 0.9 1 2 44 1 19.8

2.2 11 0.892 0.81 0.9 1 2 22 2 19.8

2.3 2 0.83 0.82 1 2 1 2 1 1

2.4 0.5 0.67 0.82 1 1 6 3 6 3

2.5 10 0.8 0.8 1 1.5 Lumpsum 10 Lumpsum 6.6666667

81 50.266667

3.0 = 84.92 kVA

4.0 = 0.71

5.0

5.1 = 100 kVA

5.2 = 4.5 %

5.3 = 22 KW5.4 = 0.415 kV

5.5 = 0.83

5.6 = 0.917

5.9 = 71.095 kVA

5.10 = 173.43 kVA

5.11 = 101.17 kVA

5.14 = 2222.2 kVA

TRANSFORMER SIZING FOR JATNI (KAJU PLANTATION) PUMPING STATION

[ Working Load (kW) x L. F. ] / [ D. F. x P. F. x Effi. ] = Load Factor

Lighting 10.42

5.46

1.47

Sr.

No.L. F. D. F.

Total Working Load (kW) / Total Working Load (kVA) = Motor Power Factor

Rating of the largest size motor From the above table

Considering 20% contingency

System P. F.

= Diversity Factor

= Motor Efficiency

Item DescriptionRating in

kWEffi.

Working Load

(kVA)

Connected Load Working Load

Input Data and Calculations:

P. F.

Total Load

Chain pully

Exhaust Fan

70.77

Pump-1 26.01

Pump-2 27.40

Supply voltage System voltage

Calculation to check the starting of largest size motor

Rating of transformer assumed Nearest staanddard size (Confg. 11/0.433KV,Dyn11,Delta-star)

% impedance of transformer assumed From IS 2026

P.F of largest size motor From the above table

Efficiency of largest size motor From the above table

5.7 FLC of motor = 40.212 AkW x 1000

1.7321 x V x p.f x efficiency

Motor starting Kva with Star-Delta start = 3 x 1.7321 x kV x I FLC

5.8 Rating of largest size motor in kVA = 28.905 kVAkW

P.F x Efficiency

Base load on transformer before starting fourth

largest motor(Rating in kVA of transformer assumed - Largest motor KVA)

Motor starting Kva with DOL start = 6 x 1.7321 x kV x I FLC

5.13 Fault current of transformer secondary side (ISC) = 3.0915

5.12 Fault Level at transformer secondary side = 2.2222

S.C capacity of transformer

MVARating of transformer in MVA x 100

Impedance of transformer in %

kAFault Level in MVA

1.7321 x kV

S.C capacity of transformer 1.7321 x kV x I SC

5.15Voltage drop at transformer terminal when largest

motor start with DOL starting= 11.004 %

[Motor Starting kVA (DOL) + Base Load kVA] x 100(within 10%)

The selected rating of transformer is 100 kVA

%[Motor Starting kVA (S/D) + Base Load kVA] x 100

(within 10%)S.C capacity of transformer

5.16Voltage drop at transformer terminal when largest

motor start with Star-Delta starting= 7.8

533

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CAPACITOR BANK SIZING ACROSS BUS

1 Average Power factor (pf1) 0.710

2 Total Working load 50 kW

3 Power factor To be improved (pf2) 0.98

Total kVAR to be connected across Bus

4 Total kVAR to be connected across Bus 40 KVAR

Working load ( Tan ( Cos-1

pf1) - Tan (Cos-1

pf2))

534

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 100

2VOLTAGE (V) = 0.4153 PF = 0.8

4 FAULT CURRENT Ish = 3.09

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 25

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 9.297701931

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABL = Cable laid in ground (3 cables touching)

RATING FACTOR = 0.69

3 OVERALL DERATING FACTOR = 0.6555

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 139.12

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

212.24

3 Current carring capacity of 3.5C x120 Sqmm = 223

4 No of cable required = 0.95

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x120 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 120 SQ = 0.324

3 X AT CONDUCTOR TEMP. (3.5C x 120 Qm = 0.0712

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.438263899

CABLE SIZE CHOSEN = 3.5CX120 sq.mm Al XLPE Cable

!"#

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

535

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 29

2 VOLTAGE (V) = 0.415

3 PF = 0.84 FAULT CURRENT Ish = 2.64

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 45

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 7.943667669

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.952 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 40.35

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

64.35

3 Current carring capacity of 3C x16 Sqmm AL = 70

4 No of cable required = 0.92

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x16Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 16 SQmm = 2.44

3 X AT CONDUCTOR TEMP. (3C x 16 Qmm = 0.0808

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.515823138

CABLE SIZE CHOSEN = 2X3CX16 sq.mm Al XLPE Cable

$!"#%%&

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

536

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 16

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 2.64

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 55

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 7.943667669

2 CABLE SIZE CHOSEN = 10 SQ.MM AL(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 22.26

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

35.50

3 Current carring capacity of 3C x10 Sqmm AL = 67

4 No of cable required = 0.53

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x10 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 10 SQm = 3.94

3 X AT CONDUCTOR TEMP. (3C x 10 Qmm = 0.0837

4 COSø = 0.8

5 SINø = 0.66 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.636204732

CABLE SIZE CHOSEN = 2X3CX10 sq.mm Al XLPE Cable

$!"#&

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

537

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 20

2VOLTAGE (V) = 0.4153 PF = 0.8

4 FAULT CURRENT Ish = 2.64

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 35

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 7.943667669

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 27.82

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

44.38

Considering 35% extra current 59.91

3 Current carring capacity of 4C x10 Sqmm AL = 67

4 No of cable required = 0.89

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 4C x10 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (4C x 10 SQm = 3.94

3 X AT CONDUCTOR TEMP. (4C x 10 Qmm = 0.0837

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.301526492

CABLE SIZE CHOSEN = 4CX10 sq.mm Al XLPE Cable

$!"#%'

(FULL LOAD CURRENT X LENGTH XIMPEDENCE)/NO OF RUNS X VOLTAGE

538

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A) FEEDER DATA

1 WORKING LOAD (KW) 10

2 WORKING LOAD (KVA) = 12.5

2VOLTAGE (V) = 0.4153 PF = 0.8

4 FAULT CURRENT Ish = 2.64

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 30

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 7.943667669

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 17.39

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

27.74

3 Current carring capacity of 4C x10 Sqmm AL = 67

4 No of cable required = 0.41

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 4C x10 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (4C x 10 SQm = 3.94

3 X AT CONDUCTOR TEMP. (4C x 10 Qmm = 0.0837

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.697246335

CABLE SIZE CHOSEN = 4CX10 sq.mm Al XLPE Cable

$!"#

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

539

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1.0 Formula Used:

1.1 Working Load in kVA = L. F.

1.2 System P. F. = P. F.

D. F.

Effi.

2.0

UnitTotal

(kW)Unit

Total

(kW)

2.1 45 0.936 0.86 0.9 1 2 90 1 40.5

2.2 2.5 0.83 0.82 1 1 1 2.5 1 2.5

2.3 8 0.8 0.8 1 1.3 Lumpsum 8 Lumpsum 6.1538462

2.4 0.5 0.67 0.82 1 1 6 3 6 3

103.5 52.153846

3.0 = 82.87 kVA

4.0 = 0.76

5.0

5.1 = 100 kVA

5.2 = 4.5 %

5.3 = 45 KW

5.4 = 0.415 kV

5.5 = 0.86

5.6 = 0.936

5.9 = 44.097 kVA

5.10 = 335.42 kVA

5.11 = 111.81 kVA

5.14 = 2222.2 kVA

The selected rating of transformer is 100 kVA

%[Motor Starting kVA (S/D) + Base Load kVA] x 100

(within 10%)S.C capacity of transformer

5.16Voltage drop at transformer terminal when largest

motor start with Star-Delta starting= 7.0

S.C capacity of transformer 1.7321 x kV x I SC

5.15Voltage drop at transformer terminal when largest

motor start with DOL starting=

17.078%

[Motor Starting kVA (DOL) + Base Load kVA] x 100

(within 10%)

2.2222

S.C capacity of transformer

MVARating of transformer in MVA x 100

Impedance of transformer in %

kAFault Level in MVA

1.7321 x kV

(Rating in kVA of transformer assumed - Largest motor KVA)

Motor starting Kva with DOL start = 6 x 1.7321 x kV x I FLC

5.13 Fault current of transformer secondary side (ISC) = 3.0915

5.12 Fault Level at transformer secondary side =

Motor starting Kva with Star-Delta start = 3 x 1.7321 x kV x I FLC

5.8 Rating of largest size motor in kVA = 55.903 kVAkW

P.F x Efficiency

Base load on transformer before starting fourth

largest motor

5.7 FLC of motor = 77.771 AkW x 1000

1.7321 x V x p.f x efficiency

Rating of the largest size motor From the above table

P.F of largest size motor From the above table

Efficiency of largest size motor From the above table

9.62

Pump (existing)

Supply voltage System voltage

Calculation to check the starting of largest size motor

Rating of transformer assumed Nearest staanddard size (Confg. 11/0.433KV,Dyn11,Delta-star)

% impedance of transformer assumed From IS 2026

System P. F.

= Diversity Factor

= Motor Efficiency

Item Description Rating inkW

Effi. Working Load(kVA)

Connected Load Working Load

Input Data and Calculations:

D. F.

Total Working Load (kW) / Total Working Load (kVA) = Motor Power Factor

P. F.

Considering 20% contingency

Total Load 69.06

Lighting

TRANSFORMER SIZING FOR JATNI (PHED Transmission) PUMPING STATION

[ Working Load (kW) x L. F. ] / [ D. F. x P. F. x Effi. ] = Load Factor

5.46Exhaust Fan (existing)

3.67Chain pully (existing)

50.31

Sr.No.

L. F.

540

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CAPACITOR BANK SIZING ACROSS BUS

1 Average Power factor (pf1) 0.755

2 Total Working load 52 kW

3 Power factor To be improved (pf2) 0.98

Total kVAR to be connected across Bus

4 Total kVAR to be connected across Bus 35 KVAR

Working load ( Tan ( Cos-1

pf1) - Tan (Cos-1

pf2))

541

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 100

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 3.09

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 60

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 9.297701931

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in ground (3 cables touching)

RATING FACTOR = 0.69

3 OVERALL DERATING FACTOR = 0.6555

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 139.12

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

212.24

3 Current carring capacity of 3.5C x120 Sqmm AL XLPE cable is = 223

4 No of cable required = 0.95

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x120 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 120 SQmm AL XLPE Cable) = 0.324

3 X AT CONDUCTOR TEMP. (3.5C x 120 Qmm AL XLPE Cable) = 0.0712

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.051833358

CABLE SIZE CHOSEN = 3.5CX120 sq.mm Al XLPE Cable

!"#$

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

542

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 56

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 3.095 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 9.297701931

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 77.91

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

124.26

3 Current carring capacity of 3C x50 Sqmm AL XLPE cable is = 142

4 No of cable required = 0.88

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x50 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 50 SQmm AL XLPE Cable) = 0.82

3 X AT CONDUCTOR TEMP. (3C x 50 Qmm AL XLPE Cable) = 0.075

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.911737553

CABLE SIZE CHOSEN = 2X3CX50 sq.mm Al XLPE Cable

!"#$%&'

(FULL LOAD CURRENT X LENGTH XIMPEDENCE)/NO OF RUNS X VOLTAGE

543

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 20

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 3.095 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 9.297701931

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 27.82

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

44.38

Considering 35% extra current 59.91

3 Current carring capacity of 4C x10 Sqmm AL XLPE cable is = 67

4 No of cable required = 0.89

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 4C x10 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (4C x 10 SQmm AL XLPE Cable) = 3.94

3 X AT CONDUCTOR TEMP. (4C x 10 Qmm AL XLPE Cable) = 0.0837

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.487458847

CABLE SIZE CHOSEN = 4CX10 sq.mm Al XLPE Cable

!"#$(!)!

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

544

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A) FEEDER DATA

1 WORKING LOAD (KW) 15

2 WORKING LOAD (KVA) = 18.75

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 3.095 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 9.297701931

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 26.09

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

41.60

3 Current carring capacity of 4C x10 Sqmm AL XLPE cable is = 67

4 No of cable required = 0.62

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 4C x10 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (4C x 10 SQmm AL XLPE Cable) = 3.94

3 X AT CONDUCTOR TEMP. (4C x 10 Qmm AL XLPE Cable) = 0.0837

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.394492669

CABLE SIZE CHOSEN = 4CX10 sq.mm Al XLPE Cable

!"#$

(FULL LOAD CURRENT X LENGTH XIMPEDENCE)/NO OF RUNS X VOLTAGE

545

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CAPACITOR BANK SIZING ACROSS BUS

1 Average Power factor (pf1) 0.749

2 Total Working load 81 kW

3 Power factor To be improved (pf2) 0.98

Total kVAR to be connected across Bus

4 Total kVAR to be connected across Bus 55 KVAR

Working load ( Tan ( Cos-1

pf1) - Tan (Cos-1

pf2))

546

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1.0 Formula Used:

1.1 Working Load in kVA = L. F.

1.2 System P. F. = P. F.

D. F.

Effi.

2.0

UnitTotal

(kW)Unit

Total

(kW)

2.1 37 0.935 0.86 0.9 1 2 74 1 33.3

2.2 18.5 0.913 0.83 0.9 1 2 37 2 33.3

2.3 2.5 0.87 0.82 1 1 1 2.5 1 2.5

2.4 0.5 0.67 0.82 1 1 6 3 6 3

2.5 10.124 0.8 0.8 1 1.2 Lumpsum 10.124 Lumpsum 8.4366667

126.624 80.536667

3.0 = 129.00 kVA

4.0 = 0.75

5.0

5.1 = 160 kVA

5.2 = 4.5 %

5.3 = 37 KW

5.4 = 0.415 kV

5.5 = 0.86

5.6 = 0.935

5.9 = 113.99 kVA

5.10 = 276.09 kVA

5.11 = 161.05 kVA

5.14 = 3555.6 kVA

Total Working Load (kW) / Total Working Load (kVA) = Motor Power Factor

P. F.

= Diversity Factor

= Motor Efficiency

TRANSFORMER SIZING FOR JATNI (PHED) PUMPING STATION

[ Working Load (kW) x L. F. ] / [ D. F. x P. F. x Effi. ] = Load Factor

Working Load(kVA)

Connected Load

System P. F.

5.46

3.50

Pump-1 41.41

Sr.No.

L. F. D. F.

Lighting 13.18

Working Load

Considering 20% contingency

Input Data and Calculations:

Total Load

Crane

Exhaust Fan

107.50

Pump-2 43.94

Item Description Rating inkW

Effi.

Supply voltage System voltage

Calculation to check the starting of largest size motor

Rating of transformer assumed Nearest staanddard size (Confg. 11/0.433KV,Dyn11,Delta-star)

% impedance of transformer assumed From IS 2026

Rating of the largest size motor From the above table

P.F of largest size motor From the above table

Efficiency of largest size motor From the above table

5.7 FLC of motor = 64.013 AkW x 1000

1.7321 x V x p.f x efficiency

Motor starting Kva with Star-Delta start = 3 x 1.7321 x kV x I FLC

5.8 Rating of largest size motor in kVA = 46.014 kVAkW

P.F x Efficiency

Base load on transformer before starting fourth

largest motor(Rating in kVA of transformer assumed - Largest motor KVA)

Motor starting Kva with DOL start = 6 x 1.7321 x kV x I FLC

5.13 Fault current of transformer secondary side (ISC) = 4.9464

5.12 Fault Level at transformer secondary side = 3.5556

S.C capacity of transformer

MVARating of transformer in MVA x 100

Impedance of transformer in %

kAFault Level in MVA

1.7321 x kV

S.C capacity of transformer 1.7321 x kV x I SC

5.15Voltage drop at transformer terminal when largestmotor start with DOL starting

= 10.971 %[Motor Starting kVA (DOL) + Base Load kVA] x 100

(within 10%)

The selected rating of transformer is 160 kVA

%[Motor Starting kVA (S/D) + Base Load kVA] x 100

(within 10%)S.C capacity of transformer

5.16Voltage drop at transformer terminal when largest

motor start with Star-Delta starting= 7.7

547

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 160

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 4.955 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 30

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 14.89437688

2 CABLE SIZE CHOSEN = 16 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in ground (3 cables touching)

RATING FACTOR = 0.69

3 OVERALL DERATING FACTOR = 0.6555

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 222.60

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

339.59

3 Current carring capacity of 3.5C x120 Sqmm AL XLPE cable is = 223

4 No of cable required = 1.52

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x120 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 120 SQmm AL XLPE Cable) = 0.324

3 X AT CONDUCTOR TEMP. (3.5C x 120 Qmm AL XLPE Cable) = 0.0712

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 2

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.420733343

CABLE SIZE CHOSEN = 2X3.5CX120 sq.mm Al XLPE Cable

!"#$%

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

548

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 46

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 4.95

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 55

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 14.89437688

2 CABLE SIZE CHOSEN = 16 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 64.00

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

102.07

3 Current carring capacity of 3C x35 Sqmm AL XLPE cable is = 117

4 No of cable required = 0.87

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x35 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 35 SQmm AL XLPE Cable) = 1.113 X AT CONDUCTOR TEMP. (3C x 35 Qmm AL XLPE Cable) = 0.0783

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.373493628

CABLE SIZE CHOSEN = 2X3CX35 sq.mm Al XLPE Cable

!"#$%&'(

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

549

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 25

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 4.95

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 65

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 14.89437688

2 CABLE SIZE CHOSEN = 16 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 34.78

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

55.47

3 Current carring capacity of 3C x16 Sqmm AL XLPE cable is = 70

4 No of cable required = 0.79

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x16 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 16 SQmm AL XLPE Cable) = 2.443 X AT CONDUCTOR TEMP. (3C x 16 Qmm AL XLPE Cable) = 0.0783

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.886103934

CABLE SIZE CHOSEN = 2X3CX16 sq.mm Al XLPE Cable

!"#$%)*+(

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

550

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 30

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 4.955 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 14.89437688

2 CABLE SIZE CHOSEN = 16 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 41.74

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

66.57

Considering 35% extra current 89.87

3 Current carring capacity of 3.5C x25 Sqmm AL XLPE cable is = 96

4 No of cable required = 0.94

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x25 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 25 SQmm AL XLPE Cable) = 1.54

3 X AT CONDUCTOR TEMP. (3.5C x 25 Qmm AL XLPE Cable) = 0.0805

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.892065612

CABLE SIZE CHOSEN = 3.5CX25 sq.mm Al XLPE Cable

!"#$%,'"-"

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

551

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A) FEEDER DATA

1 WORKING LOAD (KW) 10

2 WORKING LOAD (KVA) = 12.5

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 4.955 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 14.89437688

2 CABLE SIZE CHOSEN = 16 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 17.39

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

27.74

3 Current carring capacity of 4C x16 Sqmm AL XLPE cable is = 67

4 No of cable required = 0.41

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 4C x16 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (4C x 16 SQmm AL XLPE Cable) = 2.44

3 X AT CONDUCTOR TEMP. (4C x 16 Qmm AL XLPE Cable) = 0.0808

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.580775149

CABLE SIZE CHOSEN = 4CX16 sq.mm Al XLPE Cable

!"#$%

(FULL LOAD CURRENT X LENGTH XIMPEDENCE)/NO OF RUNS X VOLTAGE

552

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 160

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 4.945 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 35

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 14.86428723

2 CABLE SIZE CHOSEN = 16 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in ground (3 cables touching)

RATING FACTOR = 0.69

3 OVERALL DERATING FACTOR = 0.6555

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 222.60

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

339.59

3 Current carring capacity of 3.5C x120 Sqmm AL XLPE cable is = 223

4 No of cable required = 1.52

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x120 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 120 SQmm AL XLPE Cable) = 0.324

3 X AT CONDUCTOR TEMP. (3.5C x 120 Qmm AL XLPE Cable) = 0.0712

4 COSø = 0.8

5 SINø = 0.66 No of runs: = 2

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.490855567

CABLE SIZE CHOSEN = 2 X 3.5CX120 sq.mm Al XLPE Cable

!"#$%

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

553

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 37

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 4.955 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 60

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 14.89437688

2 CABLE SIZE CHOSEN = 16 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE x 1.732

= 29.72

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

47.40

3 Current carring capacity of 3C x16 Sqmm AL XLPE cable is = 70

4 No of cable required = 0.68

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x16 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 16 SQmm AL XLPE Cable) = 2.44

3 X AT CONDUCTOR TEMP. (3C x 16 Qmm AL XLPE Cable) = 0.0808

4 COSø = 0.8

5 SINø = 0.66 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.48882313

CABLE SIZE CHOSEN = 2X3CX16 sq.mm Al XLPE Cable

!"#$%&'

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

554

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 24

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 4.95

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 70

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 14.89437688

2 CABLE SIZE CHOSEN = 16 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 33.39

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

53.25

3 Current carring capacity of 3C x16 Sqmm AL XLPE cable is = 70

4 No of cable required = 0.76

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x16 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 16 SQmm AL XLPE Cable) = 2.443 X AT CONDUCTOR TEMP. (3C x 16 Qmm AL XLPE Cable) = 0.0783

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.949941298

CABLE SIZE CHOSEN = 2X3CX16 sq.mm Al XLPE Cable

!"#$%()*'

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

555

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 13

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 4.95

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 85

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 14.89437688

2 CABLE SIZE CHOSEN = 16 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 18.09

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

28.85

3 Current carring capacity of 3C x16 Sqmm AL XLPE cable is = 70

4 No of cable required = 0.41

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x16 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 16 SQmm AL XLPE Cable) = 2.443 X AT CONDUCTOR TEMP. (3C x 16 Qmm AL XLPE Cable) = 0.0783

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.282550675

CABLE SIZE CHOSEN = 2X3CX16 sq.mm Al XLPE Cable

!"#$%+)&'

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

556

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A) FEEDER DATA

1 WORKING LOAD (KW) 15

2 WORKING LOAD (KVA) = 18.75

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 4.955 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 30

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 14.89437688

2 CABLE SIZE CHOSEN = 16 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 26.09

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

41.60

3 Current carring capacity of 4C x16 Sqmm AL XLPE cable is = 70

4 No of cable required = 0.59

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 4C x16 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (4C x 16 SQmm AL XLPE Cable) = 2.44

3 X AT CONDUCTOR TEMP. (4C x 16 Qmm AL XLPE Cable) = 0.0808

4 COSø = 0.8

5 SINø = 0.66 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.653372042

CABLE SIZE CHOSEN = 4CX16 sq.mm Al XLPE Cable

!"#$%,#,

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

557

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 31

2 VOLTAGE (V) = 0.415

3PF = 0.84 FAULT CURRENT Ish = 4.95

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 14.89437688

2 CABLE SIZE CHOSEN = 16 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 43.13

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

68.79

Considering 35% extra current 92.86

3 Current carring capacity of 3.5C x25 Sqmm AL XLPE cable is = 96

4 No of cable required = 0.97

E) CHECK FOR VOLTAGE DROP1 CABLE SIZE = 3.5C x25 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 25 SQmm AL XLPE Cable) = 3.94

3 X AT CONDUCTOR TEMP. (3.5C x 25 Qmm AL XLPE Cable) = 0.0837

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 2.305561214

CABLE SIZE CHOSEN = 3.5CX25 sq.mm Al XLPE Cable

.

!"#$%&"-"

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

558

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1.0 Formula Used:

1.1 Working Load in kVA = L. F.

1.2 System P. F. = P. F.

D. F.

Effi.

2.0

UnitTotal

(kW)Unit

Total

(kW)

2.1 18.5 0.913 0.83 0.95 1 2 37 1 17.575

2.2 9.3 0.892 0.81 0.95 1 2 18.6 2 17.67

2.3 30 0.925 0.84 0.95 1 2 60 1 28.5

2.4 0.5 0.67 0.82 1 1 8 4 8 4

2.4 7.5 0.87 0.82 1 2 1 7.5 1 3.75

2.5 11.314 0.8 0.8 1 1.5 Lumpsum 11.314 Lumpsum 7.5426667

138.414 79.037667

3.0 = 130.38 kVA

4.0 = 0.73

5.05.1 = 160 kVA

5.2 = 4.5 %

5.3 = 30 KW

5.4 = 0.415 kV

5.5 = 0.84

5.6 = 0.925

5.9 = 121.39 kVA

5.10 = 231.66 kVA

5.11 = 77.22 kVA

5.14 = 3555.6 kVA

The selected rating of transformer is 160 kVA

%[Motor Starting kVA (S/D) + Base Load kVA] x 100

(within 10%)S.C capacity of transformer

5.16Voltage drop at transformer terminal when largest

motor start with Star-Delta starting= 5.6

S.C capacity of transformer 1.7321 x kV x I SC

5.15Voltage drop at transformer terminal when largest

motor start with DOL starting= 9.9295 %

[Motor Starting kVA (DOL) + Base Load kVA] x 100(within 10%)

3.5556

S.C capacity of transformer

MVARating of transformer in MVA x 100

Impedance of transformer in %kA

Fault Level in MVA

1.7321 x kV

(Rating in kVA of transformer assumed - Largest motor KVA)

Motor starting Kva with DOL start = 6 x 1.7321 x kV x I FLC

5.13 Fault current of transformer secondary side (ISC) = 4.9464

5.12 Fault Level at transformer secondary side =

Motor starting Kva with Star-Delta start = 3 x 1.7321 x kV x I FLC

5.8 Rating of largest size motor in kVA = 38.61 kVAkW

P.F x Efficiency

Base load on transformer before starting fourth

largest motor

5.7 FLC of motor = 53.713 AkW x 1000

1.7321 x V x p.f x efficiency

Supply voltage System voltage

P.F of largest size motor From the above table

Efficiency of largest size motor From the above table

Pump-3

Total Load

Exhaust Fan

Lighting and small power (indoor and outdoor) 11.79

108.65

36.68

7.28

Calculation to check the starting of largest size motorRating of transformer assumed Nearest staanddard size (Confg. 11/0.433KV,Dyn11,Delta-star)

% impedance of transformer assumed From IS 2026

Pump -1 23.19

Pump-2 24.46

Rating of the largest size motor From the above table

Considering 20% contingency

System P. F.

TRANSFORMER SIZING FOR KHORDA (JAMADEI) PUMPING STATION

[ Working Load (kW) x L. F. ] / [ D. F. x P. F. x Effi. ] = Load Factor

Crane 5.26

= Diversity Factor

= Motor Efficiency

Sr.

No.Item Description

Rating in

kW

Total Working Load (kW) / Total Working Load (kVA) = Motor Power Factor

Effi.Working Load

(kVA)

Input Data and Calculations:

P. F. L. F. D. F.Connected Load Working Load

559

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CAPACITOR BANK SIZING ACROSS BUS

1 Average Power factor (pf1) 0.727

2 Total Working load 79 kW

3 Power factor To be improved (pf2) 0.98

Total kVAR to be connected across Bus

4 Total kVAR to be connected across Bus 59 KVAR

Working load ( Tan ( Cos-1

pf1) - Tan (Cos-1

pf2))

560

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1.0 Formula Used:

1.1 Working Load in kVA = L. F.

1.2 System P. F. = P. F.

D. F.

Effi.

2.0

UnitTotal

(kW)Unit

Total

(kW)

2.1 22 0.917 0.83 0.95 1 2 44 1 20.9Pump -1 27.46

= Diversity Factor

= Motor Efficiency

Item DescriptionRating in

kWEffi.

Working Load

(kVA)

Input Data and Calculations:

P. F. L. F. D. F.Connected Load Working Load

Total Working Load (kW) / Total Working Load (kVA) = Motor Power Factor

TRANSFORMER SIZING FOR KHORDA ( Gurjanga) PUMPING STATION

[ Working Load (kW) x L. F. ] / [ D. F. x P. F. x Effi. ] = Load Factor

Sr.

No.

-. . .

2.3 7.5 0.87 0.82 0.9 2 1 7.5 1 3.375

2.4 0.5 0.67 0.82 1 1 8 4 8 4

2.5 10.646 0.8 0.8 1 1.3 Lumpsum 10.646 Lumpsum 8.1892308

88.146 58.464231

3.0 = 99.26 kVA

4.0 = 0.71

5.0

5.1 = 100 kVA

5.2 = 4.5 %

5.3 = 22 KW5.4 = 0.415 kV

5.5 = 0.83

5.6 = 0.917

5.9 = 71.095 kVABase load on transformer before starting fourth

lar est motor(Rating in kVA of transformer assumed - Largest motor KVA)

1.7321 x V x p.f x efficiency

5.8 Rating of largest size motor in kVA = 28.905 kVAkW

P.F x Efficiency

P.F of largest size motor From the above table

Efficiency of largest size motor From the above table

5.7 FLC of motor = 40.212 AkW x 1000

Total Load

Crane

Exhaust Fan

82.72

Supply voltage System voltage

Calculation to check the starting of largest size motor

Rating of transformer assumed Nearest staanddard size (Confg. 11/0.433KV,Dyn11,Delta-star)

Rating of the largest size motor From the above table

Considering 20% contingency

System P. F.

% impedance of transformer assumed From IS 2026

Lighting 12.80

7.28

4.73

- .

5.10 = 173.43 kVA

5.11 = 57.81 kVA

5.14 = 2222.2 kVA

The selected rating of transformer is 100 kVA

%[Motor Starting kVA (S/D) + Base Load kVA] x 100

(within 10%)S.C capacity of transformer

5.16Voltage drop at transformer terminal when largest

motor start with Star-Delta starting= 5.8

S.C capacity of transformer 1.7321 x kV x I SC

5.15Voltage drop at transformer terminal when largest

motor start with DOL starting= 11.004 %

[Motor Starting kVA (DOL) + Base Load kVA] x 100(within 10%)

= 2.2222

S.C capacity of transformer

MVARating of transformer in MVA x 100

Impedance of transformer in %

kAFault Level in MVA

1.7321 x kV

 

Motor starting Kva with DOL start = 6 x 1.7321 x kV x I FLC

5.13 Fault current of transformer secondary side (ISC) = 3.0915

5.12 Fault Level at transformer secondary side

Motor starting Kva with Star-Delta start = 3 x 1.7321 x kV x I FLC

561

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CAPACITOR BANK SIZING ACROSS BUS

1 Average Power factor (pf1) 0.707

2 Total Working load 58 kW

3 Power factor To be improved (pf2) 0.98

Total kVAR to be connected across Bus

4 Total kVAR to be connected across Bus 47 KVAR

Working load ( Tan ( Cos-1

pf1) - Tan (Cos-1

pf2))

562

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 100

2VOLTAGE (V) = 0.4153 PF = 0.8

4 FAULT CURRENT Ish = 3.09

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 60

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 9.297701931

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABL = Cable laid in ground (3 cables touching)

RATING FACTOR = 0.69

3 OVERALL DERATING FACTOR = 0.6555

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 139.12

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

212.24

3 Current carring capacity of 3.5C x120 Sqmm = 223

4 No of cable required = 0.95

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x120 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 120 SQ = 0.21

3 X AT CONDUCTOR TEMP. (3.5C x 120 Qm = 0.0718

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.735363623

CABLE SIZE CHOSEN = 3.5CX120 sq.mm Al XLPE Cable

!"#

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

563

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 16

2 VOLTAGE (V) = 0.415

3 PF = 0.84 FAULT CURRENT Ish = 3.09

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 55

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 9.297701931

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.952 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE x 1.732

= 12.85

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

20.50

3 Current carring capacity of 3C x10 Sqmm AL = 67

4 No of cable required = 0.31

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x10Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 10 SQmm = 3.94

3 X AT CONDUCTOR TEMP. (3C x 10 Qmm = 0.0837

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.944690954

CABLE SIZE CHOSEN = 2X3CX10 sq.mm Al XLPE Cable

$!"#%

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

564

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 29

2 VOLTAGE (V) = 0.415

3 PF = 0.84 FAULT CURRENT Ish = 3.09

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 9.297701931

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.952 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE x 1.732

= 23.29

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

37.15

3 Current carring capacity of 3C x10 Sqmm AL = 67

4 No of cable required = 0.55

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x10 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 10 SQmm = 3.94

3 X AT CONDUCTOR TEMP. (3C x 10 Qmm = 0.0837

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.245274439

CABLE SIZE CHOSEN = 2X3CX10 sq.mm Al XLPE Cable

$!"#&&%

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

565

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A) FEEDER DATA

1 WORKING LOAD (KW) 12

2 WORKING LOAD (KVA) = 15

2 VOLTAGE (V) = 0.415

3 PF = 0.84 FAULT CURRENT Ish = 3.09

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 9.297701931

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.952 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 20.87

2 CURRENT RATING REQ.AFTER CONSIDERING DERATIN = FULL LOAD CURRENT/DERATING FACTOR

33.28

3 Current carring capacity of 4C x10 Sqmm AL XLPE cable is = 67

4 No of cable required = 0.50

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 4C x10 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (4C x 10 SQmm AL XLPE Cable = 3.94

3 X AT CONDUCTOR TEMP. (4C x 10 Qmm AL XLPE Cable) = 0.0837

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.115594136

CABLE SIZE CHOSEN = 4CX10 sq.mm Al XLPE Cable

$!"#

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

566

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 25

2VOLTAGE (V) = 0.4153 PF = 0.8

4 FAULT CURRENT Ish = 3.09

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 9.297701931

2 CABLE SIZE CHOSEN = 10 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 34.78

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

55.47

Considering 35% extra current 74.89

3 Current carring capacity of 3.5C x25 Sqmm = 96

4 No of cable required = 0.78

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x25 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 25 SQ = 3.94

3 X AT CONDUCTOR TEMP. (3.5C x 25 Qm = 0.0837

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.859323559

CABLE SIZE CHOSEN = 3.5CX25 sq.mm Al XLPE Cable

.

$!"#&'(

(FULL LOAD CURRENT X LENGTH XIMPEDENCE)/NO OF RUNS X VOLTAGE

567

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1.0 Formula Used:

1.1 Working Load in kVA = L. F.

1.2 System P. F. = P. F.

D. F.

Effi.

2.0

UnitTotal

(kW)Unit

Total

(kW)

2.1 90 0.95 0.85 0.9 1 2 180 1 81

2.2 45 0.936 0.86 0.9 1 2 90 2 81

2.3 7.5 0.87 0.82 0.9 2 1 7.5 1 3.375

2.3 0.5 0.67 0.82 1 1 8 4 8 4

2.4 15 0.8 0.8 1 1.5 Lumpsum 15 Lumpsum 10

296.5 179.375

3.0 = 274.29 kVA

4.0 = 0.78

5.0

5.1 = 315 kVA

5.2 = 4.5 %

5.3 = 90 KW5.4 = 0.415 kV

5.5 = 0.85

5.6 = 0.95

5.9 = 203.54 kVA

5.10 = 668.73 kVA

5.11 = 222.91 kVA

5.14 = 7000 kVA

The selected rating of transformer is 315 kVA

%[Motor Starting kVA (S/D) + Base Load kVA] x 100

(within 10%)S.C capacity of transformer

5.16Voltage drop at transformer terminal when largest

motor start with Star-Delta starting= 6.1

S.C capacity of transformer 1.7321 x kV x I SC

5.15Voltage drop at transformer terminal when largest

motor start with DOL starting= 12.461 %

[Motor Starting kVA (DOL) + Base Load kVA] x 100(within 10%)

= 7

S.C capacity of transformer

MVARating of transformer in MVA x 100

Impedance of transformer in %

kAFault Level in MVA

1.7321 x kV

Base load on transformer before starting largest

motor(Rating in kVA of transformer assumed - Largest motor KVA)

Motor starting Kva with DOL start = 6 x 1.7321 x kV x I FLC

5.13 Fault current of transformer secondary side (ISC) = 9.7382

5.12 Fault Level at transformer secondary side

1.7321 x V x p.f x efficiency

Motor starting Kva with Star-Delta start = 3 x 1.7321 x kV x I FLC

5.8 Rating of largest size motor in kVA = 111.46 kVAkW

P.F x Efficiency

P.F of largest size motor From the above table

Efficiency of largest size motor From the above table

5.7 FLC of motor = 155.05 AkW x 1000

Total Load

Crane

Exhaust Fan

228.57

Supply voltage System voltage

Calculation to check the starting of largest size motor

Rating of transformer assumed Nearest staanddard size (Confg. 11/0.433KV,Dyn11,Delta-star)

Pump -1 100.31

= Diversity Factor

= Motor Efficiency

Item DescriptionRating in

kWEffi.

Working Load

(kVA)

Input Data and Calculations:

P. F.

Rating of the largest size motor From the above table

Considering 20% contingency

System P. F.

% impedance of transformer assumed From IS 2026

L. F. D. F.Connected Load Working Load

Total Working Load (kW) / Total Working Load (kVA) = Motor Power Factor

TRANSFORMER SIZING FOR KHORDA ( PHED) PUMPING STATION

[ Working Load (kW) x L. F. ] / [ D. F. x P. F. x Effi. ] = Load Factor

Lighting 15.63

7.28

4.73

Sr.

No.

Pump -2 100.63

568

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CAPACITOR BANK SIZING ACROSS BUS

1 Average Power factor (pf1) 0.785

2 Total Working load 179 kW

3 Power factor To be improved (pf2) 0.98

Total kVAR to be connected across Bus

4 Total kVAR to be connected across Bus 105 KVAR

Working load ( Tan ( Cos -1 pf1) - Tan (Cos-1 pf2))

569

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 315

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 9.7385 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 30

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 29.30130143

2 CABLE SIZE CHOSEN = 35 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in ground (3 cables touching)

RATING FACTOR = 0.69

3 OVERALL DERATING FACTOR = 0.6555

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 438.24

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

668.56

3 Current carring capacity of 3.5C x240 Sqmm AL XLPE cable is = 326

4 No of cable required = 2.05

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x240 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 240 SQmm AL XLPE Cable) = 0.16

3 X AT CONDUCTOR TEMP. (3.5C x 240 Qmm AL XLPE Cable) = 0.071

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 2

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.468041806

CABLE SIZE CHOSEN = 2X3.5CX240 sq.mm Al XLPE Cable

!

(FULL LOAD CURRENT X LENGTH XIMPEDENCE)/NO OF RUNS X VOLTAGE

570

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 112

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 9.73

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 55

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 29.27722971

2 CABLE SIZE CHOSEN = 35 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE x 1.732

= 89.97

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

143.49

3 Current carring capacity of 3C x50 Sqmm AL = 142

4 No of cable required = 1.01

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x50 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 50 SQmm = 0.82

3 X AT CONDUCTOR TEMP. (3C x 50 Qmm = 0.0754 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.447620248

CABLE SIZE CHOSEN = 2X3CX50 sq.mm Al XLPE Cable

"!#$%

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

571

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 56

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 9.27

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 65

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 27.89310579

2 CABLE SIZE CHOSEN = 35 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (6 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE x 1.732

= 44.98

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

71.74

3 Current carring capacity of 3C x35 Sqmm AL = 117

4 No of cable required = 0.61

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x35 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 35 SQmm = 1.11

3 X AT CONDUCTOR TEMP. (3C x 35 Qmm = 0.07834 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 1.140931639

CABLE SIZE CHOSEN = 2X3CX35 sq.mm Al XLPE Cable

"!&'%

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

572

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 55

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 9.275 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 27.89310579

2 CABLE SIZE CHOSEN = 35 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 76.52

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

122.04

Considering 35% extra current 164.75

3 Current carring capacity of 3.5C x70 Sqmm AL XLPE cable is = 179

4 No of cable required = 0.92

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x70 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 70 SQmm AL XLPE Cable) = 0.567

3 X AT CONDUCTOR TEMP. (3.5C x 70 Qmm AL XLPE Cable) = 0.074

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.636144578

CABLE SIZE CHOSEN = 3.5CX70 sq.mm Al XLPE Cable

.

"!''(

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

573

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1.0 Formula Used:

1.1 Working Load in kVA = L. F.

1.2 System P. F. = P. F.

D. F.

Effi.2.0

UnitTotal

(kW)Unit

Total

(kW)

2.1 132 0.957 0.86 0.9 1 3 396 2 237.6

2.2 Dewatering pump 1.5 0.79 0.81 1 1.5 1 1.5 1 1

2.3 EOT crane 15 0.902 0.81 0.9 2 1 15 1 6.75

2.4 Chain pully 3.7 0.83 0.82 0.9 2 1 3.7 1 1.665

2.5 Exhaust fan 0.5 0.67 0.82 1 1 6 3 6 3

2.6 Lighting (Indoor & Outdoor) 10 0.9 0.8 1 1.5 Lumsum 10 Lumsum 6.6666667

Total Load 429.2 256.68167

3.0 = 376.29 kVA

4.0 = 0.8186

5.0

5.1 = 400 kVA

5.2 = 4.5 %5.3 = 132 KW

5.4 = 0.415 kV

5.5 = 0.86

5.6 = 0.957

5.9 = 239.6150762 kVA

5.10 = 962.3095429 kVA

5.11 = 320.7698476 kVA

5.14 = 8888.888889 kVA

(within 10%)S.C capacity of transformer

The selected rating of transformer is 400 kVA

5.16 Voltage drop at transformer terminal when largestmotor start with Star Delta starting

= 6.3 % [Motor Starting kVA (S/D) + Base Load kVA] x 100

S.C capacity of transformer 1.7321 x kV x I SC

5.15Voltage drop at transformer terminal when largest

motor start with DOL starting= 13.52165196 %

[Motor Starting kVA (DOL) + Base Load kVA] x 100(within 10%)

S.C capacity of transformer

5.13 Fault current of transformer secondary side (ISC) = 12.36591962 kAFault Level in MVA

1.7321 x kV

5.12 Fault Level at transformer secondary side = 8.888888889 MVARating of transformer in MVA x 100

Impedance of transformer in %

Base load on transformer before starting fourth

largest motor(Rating in kVA of transformer assumed - Largest motor KVA)

Motor starting Kva with DOL start = 6 x 1.7321 x kV x I FLC

Motor starting Kva with Star Delta start = 3 x 1.7321 x kV x I FLC

5.8 Rating of largest size motor in kVA = 160.3849238 kVAkW

P.F x Efficiency

Efficiency of largest size motor From the above table

5.7 FLC of motor = 223.122046 AkW x 1000

1.7321 x V x p.f x efficiency

Rating of the largest size motor From the above table

Supply voltage System voltage

P.F of largest size motor From the above table

System P. F.

Calculation to check the starting of largest size motor

Rating of transformer assumed Nearest staanddard size (Confg. 33/0.433KV,Dyn11,Delta-star)

% impedance of transformer assumed From IS 2026

313.57

Considering 20% contingency

1.56

9.24

5.46

6.17

2.45

Sr.

No.Item Description

Rating in

kWEffi. P. F. L. F.

TRANSFORMER SIZING FOR RWPS PLANT

[ Working Load (kW) x L. F. ] / [ D. F. x P. F. x Effi. ] = Load Factor

Total Working Load (kW) / Total Working Load (kVA) = Motor Power Factor

= Diversity Factor

Vertcal Pump 288.69

= Motor EfficiencyInput Data and Calculations:

D. F.

Connected Load Working LoadWorking Load

(kVA)

574

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CAPACITOR BANK SIZING ACROSS BUS

Intermediate Pumping Station

1 Average Power factor (pf1) 0.819

2 Total Working load in IPS 257 kW

3 Power factor To be improved (pf2) 0.98

Total kVAR to be connected across Bus

4 Total kVAR to be connected across Bus 128 KVAR

Working load ( Tan ( Cos-1

pf1) - Tan (Cos-1

pf2))

575

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Short circuit calculation RWPS

Assumptions

1 Fault level at 220kV bus 20000 MVA (as per IS :2026)

2 Base MVA 2000

Ratio = 220kV / 132kV

Capacity = 100.00 MVA

Z= 9.27%

Qty 1 Nos

Considering negative tolerance Z = 8.34%

Net Z for transformers single transformer= 8.34%

3

Ratio = 132kV / 33kV

Capacity = 40.00 MVA

Z= 10.18%

Qty 1 Nos

Considering negative tolerance Z = 9.16%

Net Z for transformers single transformer= 9.16%

4

Line length = 18 kM

Conductor Type = DOG Assumed

Conductor Resiatance = 0.2733 ohm/kM

Z,Considering Reactance Negligible = 4.9194 ohm

5

Ratio = 33kV / 0.415kV

Capacity = 0.40 MVA

Z= 4.5%

Qty 1 Nos

Considering negative tolerance Z = 4.1%

Net Z for transformers single transformer= 4.1%

6 K' Constant for XLPE AL cable= 94

K' Constant for PVC AL cable= 75

K' Constant for PVC CU cable= 112

7 Fault clearing time for 33kV Breaker (t) = 1 Sec

Fault clearing t ime for 0.415kV ACB Breaker (t) = 0.08 Sec

Fault c learing t ime for 0.415kV MCCB Breaker (t) = 0.04 Sec

10 Starting Voltage dip = 15%

11 Starting current for DOL= 6 times

12 Starting current for Y-D= 2 times

13 Starting current for FCMA softstarter= 2.5 times

Formula used

1

2

3 Zline =

4 Zcable =

Transformer Details at Chandaka220KV/132KV

Transformer Details at Chandaka 132KV/33KV

33kV Over head line from Chandaka to CWPS

Transformer at CWPS

Zsource =Base MVA

Fault level at 220kV bus

Ztransformer =Base MVA

X tranformer Z%Transformer capacity in MVA

Base MVAX Line Z

kV2

Base MVAX Cable Z

kV2

576

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Calculation

a chandaka Grid Substation

220KV Bus 0.1 20000 52

220KV/132KV,100MVA transformer 1.7

1 132kV Bus 1.8 1130.8 5

2 132kV/33kV,40MVA transformer 4.6

3 33kV Bus 6.3 315.0 5.51

b RWPS

1 18 kM 33kV O/H line from Chandaka Substation to RWPS 9.03

2 33kV Bus 15.38 130.0 2.27 24.2

3 33kV/0.415kV, 0.4MVA transformer 202.50

4 0.415kV side of 0.4MVA transformer 217.88 9.2 12.77 38.4

(XLPE,AL,0.415kV)

5

0.415kV , XLPE ,3 X 3.5core x 185sqmm cable from

transformer to RWPS PMCC 30.07

6 RWPS PMCC 247.95 8.1 11.22 33.8

(,AL,0.415 kV)

7

0.415kV , XLPE ,3.5core x 50sqmm cable from RWPS

PMCC to RWPS Auxilary MCC 286.87

8 RWPS Auxilary MCC 534.82 3.7 5.20 11.1

Sr No Description

Impedance

" Z"

Fault level

"MVA"

Fault Current

"kA"

Minimum Cable

size "SQMM"

577

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 400

2 VOLTAGE (V) = 0.415

3 PF = 0.84 FAULT CURRENT Ish = 12.22

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 35

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 36.76955262

2 CABLE SIZE CHOSEN = 50 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in Ground (3 cables touching)

RATING FACTOR = 0.69

3 OVERALL DERATING FACTOR = 0.6555

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 556.50

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

848.97

3 Current carring capacity of 3.5C x185 Sqmm AL XLPE cable is = 282

4 No of cable required = 3.01

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x185 Sqmm AL XLPE cable2 R AT CONDUCTOR TEMP. (3.5C x 185SQmm AL XLPE Cable) = 0.21

3 X AT CONDUCTOR TEMP. (3.5C x 185 Qmm AL XLPE Cable) = 0.0718

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 3

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.571949485

CABLE SIZE CHOSEN = 3X3.5CX185 sq.mm Al XLPE Cable

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

578

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 160

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 10.335 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 45

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 31.08260872

2 CABLE SIZE CHOSEN = 35 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.69

3 OVERALL DERATING FACTOR = 0.6555

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE x 1.732

= 128.52

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

196.07

3 Current carring capacity of 3C x95 Sqmm AL XLPE cable is = 221

4 No of cable required = 0.89

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3C x95 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3C x 70SQmm AL XLPE Cable) = 0.41

3 X AT CONDUCTOR TEMP. (3C x 70SQmm AL XLPE Cable) = 0.0724

4 COSø = 0.8

5 SINø = 0.66 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.896555308

CABLE SIZE CHOSEN = 2X3CX95 sq.mm Al XLPE Cable

!"#

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

579

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 59

2 VOLTAGE (V) = 0.415

3 PF = 0.8

4 FAULT CURRENT Ish = 10.33

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 30

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 31.08260872

2 CABLE SIZE CHOSEN = 35 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS

1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABLES = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.69

3 OVERALL DERATING FACTOR = 0.6555

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 82.08

2 CURRENT RATING REQ.AFTER CONSIDERING DERATING = FULL LOAD CURRENT/DERATING FACTOR

125.22

3 Current carring capacity of 3.5C x50 Sqmm AL XLPE cable is = 142

4 No of cable required = 0.88

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x50 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 50SQmm AL XLPE Cable) = 0.823 X AT CONDUCTOR TEMP. (3.5C x 50 Qmm AL XLPE Cable) = 0.075

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.720435477

CABLE SIZE CHOSEN = 3.5CX50 sq.mm Al XLPE Cable

$%&'(

(FULL LOAD CURRENT X LENGTH X

IMPEDENCE)/NO OF RUNS X VOLTAGE

580

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A) FEEDER DATA

1 WORKING LOAD (KW)

2 WORKING LOAD (KVA) = 75

2VOLTAGE (V) = 0.4153 PF = 0.8

4 FAULT CURRENT Ish = 10.63

5 FAULT CLEARING TIME t = 0.08

6 CONSTANT K = 94

7 LENGTH = 40

B)

1 AREA OF CONDUCTOR = Ish*t/K

= 31.98529823

2 CABLE SIZE CHOSEN = 35 SQ.MM AL

(AS PER SHORT CIRCUIT CALCULATION)

C) LAYING CONDITIONS1 AMBIENT AIR TEMPERATURE = 45

RATING FACTOR = 0.95

2 GROUPING/SPACING WITH OTHER CABL = Cable laid in trench (9 cables touching)

RATING FACTOR = 0.66

3 OVERALL DERATING FACTOR = 0.627

D)

1 FULL LOAD CURRENT Ifl = WORLING LOAD (KVA)/1.732 x VOLTAGE

= 104.34

2 CURRENT RATING REQ.AFTER CONSIDE = FULL LOAD CURRENT/DERATING FACTOR

166.42

Considering 35% extra current 224.66

3 Current carring capacity of 3.5C x95 Sqmm = 221

4 No of cable required = 1.02

E) CHECK FOR VOLTAGE DROP

1 CABLE SIZE = 3.5C x95 Sqmm AL XLPE cable

2 R AT CONDUCTOR TEMP. (3.5C x 95 SQ = 0.41

3 X AT CONDUCTOR TEMP. (3.5C x 95 Qm = 0.0724

4 COSø = 0.8

5 SINø = 0.6

6 No of runs: = 1

% VOLTAGE DROP =

7 % VOLTAGE DROP = 0.64701408

CABLE SIZE CHOSEN 3 5CX95 sq mm Al XLPE Cable

)*+,+&

(FULL LOAD CURRENT X LENGTH XIMPEDENCE)/NO OF RUNS X VOLTAGE