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    Unit 5 - Turning

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    CA1 (35 %) Assignments -15% (review, sketching,

    case study)

    2 BB Quizzes -10% (turning and milling)

    General Performance -10% (attitude,attendance..)

    CA2 (40%) Practical (machining tape holder -

    individual)

    CA3 (25%) Mini Project (machining car chassis and

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    Learning Objectives:

    List the components of a centre lathe

    Discuss the safety rules Discuss the use of tool holding devices Discuss the characteristics of cutting tool

    materials and inserts Watch and discuss video VC2495/8

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    What is the primary function of a centrelathe?

    Can you name the components of a lathe?

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    What 2 movements are necessary beforeturning process can take place?

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    a) Saddle

    b) cross slide

    c) compound slide

    d) tool post

    e) apron

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    Knurling toolPartingtool Chamferingtool

    Facing andturning tool

    Knife

    turning tool

    toolRadius forming

    Undercuttingtool

    Facing tool

    Boringtool

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    Can you give other examples ofturning besides facing and parallel

    turning?

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    Compare and contrast the differences of a4-way tool-post (above) and quick changetool-post?

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    On Centre good finish

    Above Centre -not cutting

    Below Centre poor finish

    = Front Clearance

    = Wedge Angle

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    Locking screw

    Insert

    Insert holder

    Chip

    Breaker

    The carbide insert is locked by a lockingscrew or cam. Shape may be triangular(as above) or diamond, square or round.

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    2. Define Turning Operation.

    3. State the effects of improper tool setting.

    4. List 10 safety precautions in the machine shop

    and how would you categorised them?5. State the 3 purposes of facing operation.

    6. What is the main advantage of quick changetool post?

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    Learning Objectives:

    Compare and contrast 3-jaw and 4-jaw

    chucks Explain the use of work holding support used

    in between centres Discuss the use of other work holding

    devices like faceplate, mandrels andsteadies.

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    Normally used for holding round orhexagonal stock.

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    Suitable for round, square, octagonal andodd-shaped workpieces.

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    Long Workpiece

    Normally used for turning a longworkpiece supported betweenbetween centres. It requires 2centres, a drive plate and a lathe dog.

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    Drive Plates

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    Compare and contrast live and plaincentres.

    Morse standard taper

    Plain

    Live

    Sleeve

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    Plain solid mandrel one

    size of bore

    Gang mandrel manyworkpieces with sameInternal diameter

    Expansion mandrel slight difference (up to2mm variation) indiameter

    Cone mandrel largevariation in diameterallowed.

    Workpiece

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    Fixed

    Steady

    Travelling

    Steady

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    1. How would you hold a hollow thin wall roundpipe for turning?

    2. When is a faceplate used?

    3. Explain the reason why the 3-jaw chuck is

    self-centred.4. State the advantages of a 4-jaw chuck.

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    Learning Objectives:

    Distinguish between Orthogonal and obliquecutting.

    Discuss the tool geometry of a single-pointedtool.

    Discuss the factors that influence metal cuttingoperations.

    Discuss the types of chips

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    Cutting edge is set at 90 to the direction of movement. Chips in the form of a clock spring or a flat spiral Chips disposal problem & damage to workpiece surface.

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    Cutting edge is set at any angle other than 90 to

    the direction of tool movement. Chips able to move freely away from workpiece Taking deeper cuts is possible surface finish is better with a nose radius

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    Side Rake angle :provides a cutting edgeto allow chips to escapeduring cutting.

    Back Rake angle :

    promotes smooth chipflow and good finishing

    Front Relief angle :prevents tool end fromrubbing

    Side Relief angle: allowsthe tool to feed into thework

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    Minor cutting edge

    Minor cutting edge

    angle

    Major cutting edge

    angle

    Major cutting

    edge

    Nose Radius

    Side (Major) cutting edge angle - Mainly responsible for the chipremoval

    End (Minor) Cutting edge angle - Mainly responsible for producingthe finished workpiece surface

    Nose radius - Influences the surface finish of the workpiece

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    Continuous ------------ Discontinuous Chips

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    1. Compressive stress cause movement ofmetal.

    2. Then, compression increases until plasticflow or rupture (or fracture) occurs.

    Ductile material - continuous chip is formed

    Brittle materials - rupture takes place withsmall discontinuous fractured chip

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    Brittle material, small rake angle, largedepth of cut or feedrate and no cutting fluid

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    Ductile materials, large rake angle, smalldepth of cut or feedrate and efficient use ofcutting fluid.

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    2. Compare and contrast orthogonal and obliquecutting.

    3. With simple sketches, show the tool geometry

    of single-pointed cutters.4. List the three types of chip formation.

    5. State the conditions for the formation ofcontinuous chip.

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    Learning Objectives:

    Describe 3 cutting forces acting on the tool Discuss the relationship of cutting forces and the

    following:

    rake angle

    depth of cut

    feedrate

    cutting speed, and

    plan approach angle

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    Tangential and Axial Forces

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    Besides Tangential and Axial Forces, there isalso a Radial Force.

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    Tangential Force (Ft) tangential to thework surface, main power-consuming.

    Axial Force (Fa) parallel to the work axisand opposing the lengthwise feed direction.

    Radial Force (Fr) present only in oblique

    cutting and opposing the crosswise feeddirection.

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    Use a Force Dynamometer - calibrate before use. Units - Newton

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    A Test pieceFt

    Rake angle ()

    Dry

    With coolant

    Uniform thickness

    Side Rake angle varies from 0 to 40 in steps of 5 Lower Tangential force when Rake angle is smaller.

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    Ft Ft

    Fa

    Test piece with

    stepped-wall

    Depth of cut (mm)

    Depth of Cut varies from 2 to 10 mm. Bigger Tangential and Axial forces

    encountered when Depth of cut increases.

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    Test piece with

    uniformed wall thickness

    Ft Fa

    Fa

    Ft

    Feed rate (mm)

    Feedrate varies from 0.1 to 1.0 mm/rev Axial force increases exponentially when Feedrate

    increases.

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    Ft

    Breakage point of cutter

    Cutting speeds (m/min)

    Cutting Speed varies from 30 to 80 of allowablespeed value

    No change in tangential force before tool break-up.

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    Plan Approach Angle varies from 45 to 90. Axial force equals to Radial force at 45. Radial force equals to zero at 90 and

    tangential force is at maximum.

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    2. Describe the forces acting on the cutterduring orthogonal and oblique cutting.

    3. Sketch the graph and explain test resultswhen the rake angle was varied.

    4. Explain the effects of depth of cut andfeedrate on the following:

    Chip thickness

    Cutting force

    5. Explain the effects of the cutting forceswhen plan approach angle is set at 45.

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    Learning Objectives: Discuss the differences of cutting speed, spindle

    speed and feedrate. Calculate the machining time, cutting power,

    feed power and specific metal removal rate. Discuss the different types of cutting tool

    materials. Describe the effects of positive and negative

    back rake angle Explain the functions of cutting fluid.

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    WORKPIECE

    MATERIALS

    FEED (mm/rev) CUTTING

    SPEED (m/min)

    Aluminium 0.2 1.0 70 100

    Brass (Alpha,Ductile)

    0.2 1.0 50 80

    Brass (free-cutting) 0.2 1.5 70 100

    Bronze (phosphor) 0.2 1.0 35 70

    Cast iron (grey) 0.15 1.0 25 40

    Copper 0.2 1.0 35 - 70

    Steel (mild) 0.2 1.0 35 - 70

    Steel (medium

    carbon)0.15 0.7 30 - 35

    Steel (alloy, high-tensile)

    0.08 0.3 5 10

    Thermo-settingplastic

    0.2 1.0 35 - 50

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    0

    sec

    1

    min

    1 rev = d

    The rate at which a point in the circumference of the worktravels past the cutting tool (V=m/min).

    Depends on work material, tool material, type of operation,machine condition, coolant type, type of cuts.

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    The spindle speed is the number orrevolutions turned in one min.

    N = 1000V (rev/min) d

    The Spindle Speed, N depends on:

    3. the cutting speed, V and4. the diameter, d of the workpiece.

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    Feedrate is the distance the tool bit advances alongthe work for each revolution of the spindle(F=mm/rev)

    Depends on work material, tool material, type ofcut, cutting speed.

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    Calculate the spindle speed, to the nearest rev/min,for turning a 50 mm diameter bar at a cutting speedof 40 m/min.

    1000 * V where, N = spindle speed

    N = ---------------- V = 40 m/min D D = 50 mm1000 * 40

    = ------------------ = 255 (rev / min)

    3.142 * 50

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    Calculate the time taken to turn a brass component 65mm diameter by 95 mm long, if the cutting speed is45 m/min and the feed is 0.6 mm/rev. Only one cut isto be taken.

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    Use Ft

    Work done = force * dist moved

    = force * Circumference * N

    = F * 2 r N= F * d NPower is the rate of doing work

    = work done time taken

    = F * d N Nm or watts 1000*60 sec

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    D NWORKDONE = Ft (Newtons) x ---------- (Nm/min) or (Joules /

    min)

    1000

    D N 1CUTTING POWER (watts) = Ft x ------------- x ------ (Nm / sec)

    1000 60

    Where, Ft = tangential force; = 3.142D = diameter of workpiece (mm);N = rotational speed in rpm

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    Feed x NWORKDONE = Fa (Newtons) x --------- (Joules / min)

    1000

    Fa x Feed x NFEED POWER = ------------------------ (Joules / s or Watts)

    1000 x 60

    Where, Fa = Axial force;Feed = mm / rev;

    N = spindle speed in rpm

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    During turning on the lathe, the workpiece has adiameter of 75 mm & the spindle speed was set at 200rpm. If the feed rate was 0.33 mm / rev & the

    dynamometer readings for the tangential force and theaxial force were 1,600 N & 900 N respectively, find thecutting & feed power.

    3.142 x 75 mm x 200 rpm

    Cutting power = 1600 N x ---------------------------------------1000 x 60

    = 1,257 watts

    900 N x 0.33 mm / rev x 200 rpmFeed power = ----------------------------------------------

    1000 x 60

    = 0.99 Watts

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    V=25m/min

    D=3mmF=1.5mm/rev

    The volume of metal removed perminute is

    = V * D * F

    = 25000 * 3 * 1.5

    = 112500 mm3/min = 112.5 cm3/min

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    = Volume removed per min

    Power consumed

    = (mm/min)/watt

    N.B. Power consumed is the sum of the

    power at the cutting tool and including thepower to drive the mechanical systems.

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    High Carbon steel HSS

    Cemented carbide(contains 90% carbidepowder and 10% cobalt as binder) Cemented ceramic(contains 95% Al2O3)

    Diamond

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    Ability to: Retain hardness at high temperature

    Resist Shock i.e. toughness Resist Wear Reasonably cheap

    Acceptable mechanical properties

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    Good abrasion resistance Slow rate of wear Hot Hardness properties

    Vibration and chatter must be avoided Very brittle Unable to withstand shock and bending

    loads

    Used it as a throwaway tip or insert.

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    Normal force, N,on unsupportedpart

    Tendency to break

    Lower cutting

    forces

    positive rake

    Cutting tool

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    Normal force, N, onsupported part

    Less likely to break

    Operate at higherspeed Higher compressive

    forces

    Nnegative rake

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    Functions: Cooling and lubrication Better surface finish and accuracy Flushing away chips Longer Tool life Preventing chip welding, corrosion

    Permits higher speed and feedrate

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    1. Explain the difference between cuttingspeed and spindle speed.

    2. What are the factors that determinecutting speed?

    3. What is SMRR used for?

    4. Explain the toughness of cutting toolmaterial.

    5. Compare and contrast positive andnegative back rake angle.

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