timber final requirement
TRANSCRIPT
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COMPILATION OF NOTES TIMBERDESIGN
TIMBER DESIGN
Generally refers to the proper evaluation of wood or lu!er eleents su"h as individual
plan#s$ %oist$ !eas$ post or "oluns whi"h in"lude the "onne"tion of eleents to the other
eleents and the foundation$ and the perforan"e of eleents and "onne"tions a#in& up
stru"tural syste'
The desi&n of a ti!er stru"tures re(uires all "oponents of the stru"ture to !e of su)"ient
si*e and stren&th to withstand the for"es to whi"h the stru"ture i&ht !e reasona!ly !e
su!%e"ted durin& its useful life' Proper desi&n also re(uires su)"ient sti+ness in e!ers
and stru"tural syste to prevent deforations asso"iated with reasona!le loads fro
ipairin& the servi"e a!ility of non stru"tural syste or "ausin& the stru"tures to feel or
appear unsafe'
Timber construction Manual (5thedition)
this anual is developed !y AITC to provide state,of,the,art te"hni"al inforation
and re"oendations on en&ineered ti!er "onstru"tions
AITC - Aeri"an Institute of Ti!er Constru"tion
T!es o" Timber#$umber
.' Sa%n $umber- is the produ"t of lu!er ills and is produ"ed fro any spe"ies &lain Sa%n Cut
, The ost !asi" way to "ut lu!er !y sli"in& the lu!er in "ontinuous parallel
otion', This ethod of "uttin& pro"edures di+erent &rain patterns dependin& on the
lo"ation it was "ut on the lo&', It is #nown to shrin# and e/pand ost !e"ause the &rains run left to ri&ht on the
width of the !oard', The illin& is fast with a iniu aount of waste of raw aterial'
'uarter Sa%n Cut, The lu!ers are "ut on the (uarters', The wood &rains of this spe"i0" ethod of "uttin& are ore "onsistent and ti&ht
and when the &rains are ti&hter$ it a#es the aterial sturdier', All the &rains run ore in an up ri&ht dire"tion$ eanin& the wood will not e/pand
and shrin# as u"h$ "opared to the plain sawn "ut', The illin& is ediu fast with a ediu aount of waste of raw aterials
Ri"t sa%n Cut, Alost siilar to the (uarter sawn "ut$ the rift sawn is illed in sli&htly di+erent
an&le', This ethod allows the &rain to sit ore ti&ht to one another', The &rains run verti"ally with the thi"#ness of the !oard$ eanin& it will only
shrin# and e/pand in hei&ht', It is the ost e/pensive illin& te"hni(ue !ut re(uires least aount of
aintenan"e'
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Con"lusion2
, If it is used for renovation of a for rent house$ it would !e ideal to use plain sawn
plan#s for e"onoi" reason', If it is used for the renovation of our own house$ it would !e ideal to use (uarter
sawn plan#s for a little ore (uality aterials', If it re(uires usin& hi&h (uality aterials with very little aintenan"e$ then the
!est aterials would !e rift sawn plan#s' Glued $aminated timber (Gluelam)
, Is a type of stru"tural ti!er produ"t "oposed of several layers of diensioned
ti!er !ounded toðer with dura!le$ oisture,resistant adhesives' This
aterial is "alled a lainatin& sto"# or lasto"# for short', 3y lainatin& several pie"es of ti!er$ a sin&le lar&e$ stron& stru"tural ti!er is
anufa"tured fro saller pie"es'
, These stru"tural e!ers are used as verti"al "oluns and hori*ontal !eas$ aswell as "urved and ar"hed shapes' Gluela is readily produ"ed in "urved shapes
and its availa!le in ran&e of spe"ies and appearan"e "hara"teristi"s to eet
varied,end use re(uireent' Conne"tions are usually ade with !olts$ dowels and
steel plates', Gluela has u"h lower e!odied ener&y than reinfor"ed "on"rete and steel4
althou&h of "ourse it des entail ore e!odied ener&y than solid ti!er' Can !e
used in u"h lon&er span$ heavier load and "ople/ shapes'
Gluela 5 6 wei&ht of Steel 5 7 wei&ht of Con"rete
Gluela 8 9 ties Stren&th of Steel
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Sim!le Beam
is a e!er that is supported only at its ends ; siple or pinned end "onditions< and
resist loads a"ross a sin&le span' The !ea ends are allowed to rotate freely'
Desi*n shall satis" the three conditions+
.' 3endin& Stress:' Shear Stress parallel to the &rain=' >e?e"tion@' 3earin& Stress
= 1 P a & e
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Bendin* Stress ,ormula
fb=mc
I
fb=m
s 4s=
I
c
Shearin* Stress
fv=VQ
I b
'
Q=a y
- Deri.e "b and ". "or Rectan*ularSection
a Bendin* Stress
fb=mc
I 5m
s
I=bd
3
12
c=
d
2
s=bd
3
d
2
=bd
2
6
fb=m
s=
m
bd2
6
fb=6m
bd2
b Shearin* Stress
fv=VQ
I b'
Q=a y A=bd
(b d2 )( d4 )
Q=bd
2
8 b '=b
fv=V
(bd
2
8
)( bd3
12) (b )
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V
2
db
3
=3
2 (V
db )=32 (V
A)=1.5V
A
fv=1.5V
A
/0ERE+
"b5 e/tree 0!er !endin& stress
m 5 applied !endin& oent
I 5 area oent of inertia w respe"t tothe NA
c 5 distan"e fro the NA to the e/tree0!er
s5 se"tion odulus
".5 hori*ontal shear stress ;shear parallelto &rainL 5 ;D.
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"t' HT 5 H>LJ HLL J H3
"u' 5 ='B J '=B J ':.
"v' 5 .='9 #N
"w'
a) Com!ute M and S ("b> m#s)
"/' 5WTL
2
8
"y' 5(13.06 )(3.662)
8
"*' 5 :.'D #N,
da' I 5b d
3
12 5( .130 )( .305)
3
12 5 ='D / .,@ @
d!' C 5.305
2 5 '.B:B
d"' S 5I
C 53.07x 10
4
.1525 5 :'. / .,=
dd' f!521.87(106)
2.01x103
x109 5 .' MPa
de' or use
df' f!56m
b d2 5
6 (21.87x106)
(130)(305)2 5 .'B MPa
d&' Note+Cvor CL will !e used only for the estiate or sele"tion of "ross,se"tion
dh' Ti!er Constru"tion Manual BthEdition ;AITC -9 (%et ser.ice "actor (.isuall *raded timber 5in
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dl &58T Cv5 ;
130.18
b
304.8
d
6.4
L
1
x
8 .' 1olume ,actor
d' 5 ;
130.18
130
304.8
305
6.4
4.88
1
x
8 .'
dn' 5 .'9 8 .' use Cv5 .'
do' CC 5 .,: ;
t
r
2Cur.ature ,actor ( "or cur.e member onl and use
CC > - i" not a cur.e)
d! &3 T36 Ci>979 Incisin* ,actor
d(' T, ='9 Ct > -9
dr ,2b> -7(-)(-)(-)(-)(979)(-) > -6 44M&a
ds " b ,2b
dt' .'MPa 8 .D'@@ MPa SafeKKK
du'
b) Com!ute Shearin* Stress (".>VQ
I b ' )
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dv' Note2 the !ea has a !earin& at the support$ the "ode re(uires the shear for"e to
"he"# ay e/"lude he distri!uted load applied within d of the end'
dw' R5WTL
2 513.06 (3.66)
2 5 :=' #N
d/'
dy'15 , WT(d) 5 :=', ;.='9
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er' LL55w L
2
384EI 5
3.6642
5(9.35)
5 '@
es'et' >eadload >e?e"tion
eu' >L5 LL;WDL+WB
W< 5
'@;3.5+0.21
9.35 < 5 ='==
e.
e% ,rom T 38 ! TCMAITCe/' e"oended >e?e"tion Criteria
ey' Coer"ial Q Institutional Liveload 5L
360 53660
360 5 .'.D R'@
SafeKKKe*'
fa' App!"d#ad p$s D" ad#ad=
L
240=
3660
240=15.25mm
f!'
f"' .B':B R ..'DSafeKKK
fd'
fe' Che"# ratios of a"tual values to allowa!le values2+'
f&'
fh' 3endin&2
fb
fb1 5
10.88
17.44 5'9: 8 .' GD
0'f%'
f#' Shear2
fv
fv1 5
0.75
2.40 5'=. 8 .' GD
?'f'
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fn' >e?e"tion;LL< 5
L/360
58.40
10.17 5'= 8 .' GD
fo'fp'
f(' >e?e"tion ;>L< 511.70
15.25 5'DD% .' GD
fr'fs'ft'fu'
fv'fw'f/'fy'f*'&a'&!'&"'&d'&e'&f'&&'&h'
&i'
*: IN1ESTIGATIN , SIM&$E BEAM
*; E
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&t' 5Afv
1.5 5
(125)(375)(1.75)(103)
1.5 5B@'9n&u'
!' S!an $ o" Beam ("b>,b?e"tionhy'
h*' max= 5w
4
384EI
ia' I=bd
3
12=
(180) (240)3
12=207.36x 106 mm
i!' max= 5w
4
384EI=
5 (8 ) (103 )(3500 )4
384 (6480 )(207.36x106mm )=11.63mm
ic IN1ESTIGATIN # DESIGN , SIM&$E BEAM (%ith o.erhan* at ends)
id EFeterine the value of V at the end supports so that the shear stress in the !ea is
as sall as possi!le'!' >eterine the in shear stress if d 5 : and ! 5 9 "' >eterine the value of depth d for a a/' ?e/ural stress of 'B MPa with the sae
width !'
if'
i&'
ih'
ii'
i%'
i#'
il'
i'
in' SOLXTION
a' alue of V for in shear stress
io' /
1+/
2=4 (3.5)
where/
1=/
2
ip' 2/
1=14
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i(' /1=
14
2=7 )(
ir' Assue shear in4Vm!0=
7
2 5 ='B #N
is' Vm!0=/1Wx
it' 3.5=714 (x )
iu' V5 'DB iv'!' Miniu Shear Stress
iw' fv=
VQ
I b'=
1 .5V
A =
1.5 (3500 )(200 ) (60) 5 '@@ MPa
i/'
"' >epth d at a/iu !endin& stresss
iy' fb=
6m
bd2 m=2x
2=1 .53)( m
i*' d2=
6m
bf b=
6 (1 .53)(106 )8 .5 (60 )
=18 1000
%a' d=1800=134mm
:b (Sim!le Beam %ith su!!ort !ro.ided b "ramin*)
:c E5 .'
%l' CM5 .'
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%' C5 .'
%n' CC5 .'
%o' Ci5 '
%p' Ct5 .'
%('
%r' Solution2 ;Lu,une/pe"ted len&thesi&nn' 5 :9'= ;.5. B@: =='== =
/' .B / B@ S>5D : ' =
y' .9 / BDB S>5 .9 999'9D =
*' . / 9@B S>5.: @ DB' =
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na'
n!' A< Try .9 / BDB
n"' f
b
=*
,=
150(10)6
8816666.67=17.01*+a
nd' 3< olue Fa"tor
ne' Cv=( 130.18160 )1
10 ( 304.8575)1
10 (6.4018)1
10=0.8291
nf' C< 3ea Sta!ility Fa"tor
n&' L$=18m7.5m=10.50m
nh'L$
d=
10500
575=18.26
ni' For Sin&le Span 3ea ;Xniforly distri!uted andL$
d 27
n%'
n#' Xse Le 5 .'9=Lu J =d
nl' 5 .'9= ;. B< J = ;BDB Load Co!ination
r*' DL+75 [+L/+(WLEL1.4 )]
sa' DLd"ad#ad
s!' !v" #ad
s"' L/r##f !v"#ad
sd' WLw!0d#ad
se' EL"art48$a)" #ad
sf'
,!0c"t4!s pr# b"mt4" ar7"st #ad !s t4" r##f !v"#ad w4!c4 !s L/=11.68 (9 )=105.12 )(
s&' ,# :L#ad C#mb!0at!#0;175(L/+WL)
sh' Then ultiply S/ and Sy !y .DBW 5 .'DB
si' ,x=1.75(10090443.69 )=17658276.46 m m3
s%' ,y=1.75 (3293585.53 )=3819482.29mm3
s#' =' Assue a trial se"tion
sl' Try :: / D=B "ross,se"tion
s'
,x=bd
2
6=
220(735 )2
6=19808250 mm3
= 1 P a & e
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sn' ,y=db
2
6=
735 (220)2
6=5929000mm3
so'
sp'
s(' Note2by
dy should !e% .' then use CL
sr' Ix=bd
3
12=
220 (735)2
12=7279531875 mm4
ss' Iy=
db3
12 =
735 (220)3
6 =652190000mm4
st'
su' *DLx=5.84(9)2
8=59.13 )( . m
sv' *L/x=11.68(9)2
8=118.26 ) ( . m
sw' *WLy=17.8(9)2
4=40.05 )( . m
s/'
sy' - 'bx=-bx CD Cv-bx CD CL w4!c4 "v"r #f CvCL c#0tr#s($s"#w"st va$")
s*' CD=1.60w!0d #ad
ta' Copute Cand CLthen "opare use /5.
t!'
t"' Cv=( 130.18220 )1
10 ( 304.8735)1
10 (6.409)1
10=0.8398
=. 1 P a & e
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to' $s"CL=0.8139
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ue'
u" Desi*n o" &urlins
u* E
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v"' C!=0.80
vd'
ve'
vf'
v&'
vh'
vi'
v%'
v#'
vl'
v'
vn'vo'
vp'
v('
fbx
-'
bx
+ fby
-'
by
%1.0 !0v"st!7at!#0vr'
fbx
- 'bx+
fby
- 'by [1( fbx-bE )2
]%1.0d"s!70!07
vs'
vt' Solution2
vu' L5 '== #N
w"'HLL5 '9DB #N
wd'
we'
wf'
w&'
wh'
wi'
=B 1 P a & e
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COMPILATION OF NOTES TIMBERDESIGN
w%'
w#'
wl'
w'
wn'wo'
wp'
w('
wr'
ws'
wt'
wu'
wv'
ww' H/5 HtsinCCCCiCtyd' F!/5 .9'BB ;.'< ;'< ;.'< ;'< ;'CCCCiCtyh' F!y5 ..'= ;.'< ;'< ;.'< ;'< ;'L J DBW ;L J HL
a&%' F]!/5 .9'BB ;.'9< ;Cfueterine F]" and E
al"' F]C5 FCC>ald' 5 '. ;.':Beterine the slenderness ratio
alt'
L"
d
alu' .'B
L"
d=
1500
127=11.81
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COMPILATION OF NOTES TIMBERDESIGN
a!' =' FCE 5 ='.= MPa
a"' @'B FCE5.'= MPa
ad' 9' FCE 5 'D MPa
ae'
af' B' >eterine Colun
Sta!ility fa"tor
a&'
-CE
-
C
ah' .'B 5 .'::B
ai' =' 5 '=9
a%' @'B 5 '.=B
a#' 9' 5 'D9:al'
CD=
1+-CE
-
C
2c (
1+-CE
-
C
2c)
2
1+-CE
-
C
c
a' .'B U C>5 'DB9=
an' =' U C>5':=9
ao' @'B U C>5 '.=.ap' 9' U C>5 'DB
a('
ar' 9' >eterine FCas' FC5F]CC>at' .'B U FC5 D'D@
MPa
au' =' U FC 5 :'
MPa
av' @'B U FC5 .'=B
MPaaw' 9' U FC5 'DD
MPa
a/'
ay'
a*' D' >eterine P
ana' A 5 ;.:D
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aoi'
ao%' M/5W yL
2
8
ao#' M/56.984
(5
)
2
8
aol' M/521.825 )(m
ao' My5W yL
2
8
aon Combined A
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apl' f!.- !endin& stress due to loads applied to the narrow fa"e ;!endin& in stron&dire"tionw"t s"rv!c" fact#r (T3.5p .58 )
atr' Ct=1.0 (W"tdry ) T"mp"rat$r" fact#r (T3.6p .62)
ats'att Ste! Determine ,t and ,2bL and @@$B N for SL,snow load