thermo fluids me 439

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Thermo Fluids ME 439 Arab Academy for Science, Technology and Maritime Transportation Dr. Ahmed Khalifa Mehanna Assistant Professor [email protected] [email protected] Room No: 223 Course Assistant Lecturer: Eng. Persis Boushra

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Thermo Fluids – ME 439

Arab Academy for Science, Technology

and Maritime Transportation

Dr. Ahmed Khalifa Mehanna

Assistant Professor

[email protected]

[email protected]

Room No: 223

Course Assistant Lecturer:

Eng. Persis Boushra

Lecture 3:

Fluid Statics or (Fluids at Rest)

Thermo Fluids – ME 439

Fluid Statics

Pressure Definition

Hydrostatic Pressure in a Liquid

Pressure at a point

Variation of Pressure with Depth

Hydrostatic Pressure Distribution

Examples

Pressure Measurement Devices

Outline

Fluid Statics deals with problems associated with

fluids at rest.

In fluid statics, there is no shear stress in the fluid

trying to deform it.

The only stress in fluid statics is the normal stress

Normal Stress is due to pressure,

Variation of pressure is due only to the weight of the fluid,

Applications of fluid statics:

Pressure measurement with hydrostatics, Floating or

submerged bodies, water dams and gates, liquid storage

tanks, etc.

Fluid Statics

Pressure is defined as a

normal force exerted by a

fluid divided by the area

that the force acts over and

therefore has units of F/A .

It can be a result of an

applied force (for example

pumping) or hydrostatic

(weight of a column of

fluid).

Pressure Definition

Unit for pressure is the Pascal (Pa), which equal (N/m2 or kg/m.s2).

1 bar = 105 Pa = 0.1 MPa = 100 kPa

1 atm = 101,325 Pa

1 atm = 101.325 kPa

1 atm = 1.01325 bars

Pressure Units

P = g hP = F/A i.e: m*g/ABut m=V

P= V g / A = g (V/A)P = g h

The pressure at a given depth in a static liquid is a result of the weight of the liquid

acting on a unit area at that depth plus any pressure acting on the surface of the

liquid.

The pressure due to the liquid alone (i.e. the Gauge Pressure) at a given depth

depends only upon the density of the liquid ρ and the distance below the surface of

the liquid h.

Hydrostatic Pressure in a LiquidPressure

Hydrostatic pressure in a liquid

can determined using the

following equation:

P = ρ g h

Where

P = Pressure;

(N/m2, or Pa, or kg/m.s2)

ρ = Density of liquid (kg/m3)

g = The gravitational gravity,

constant (9.807 m/s2)

h = Depth at which the

pressure is measured (m)

Hydrostatic pressure in a water column at

(ρ =1000 kg/m3) is indicated below:

Hydrostatic Pressure in a Liquid

Barometer – an instrument that measures pressure

Mercury barometer

Measuring Pressure

vacuum

A Bh

Atmospheric Pressure P = PA = PB = Hg g h

Mean sea-level pressure: P = 1.01325x105 Pa = 101.325 kPa

= 0.101325 MPa

= 1.01325 bars

= 1 atm

P = 1013.25 hecto Pa = 1013.25 hPa

Absolute Pressure: The actual pressure at a given position. It is measured

relative to absolute vacuum (i.e., absolute zero pressure).

Gage Pressure: Most pressure-measuring devices are calibrated to read zero in

the atmosphere, and so they indicate gage pressure. For example, an ordinary

pressure gauge reading of zero does not mean there is no pressure, it means

there is no pressure in excess of atmospheric pressure

Vacuum Pressure: Pressures below atmospheric pressure.

Pabs = Patm + Pgage

Patm = Pvac + Pabs

Absolute, Gage, and Vacuum Pressures

Absolute, Gage, and Vacuum Pressures

Absolute Pressure = True Pressure.

All given values for pressure are gage pressure except if :

(abs) is mentioned beside the unit.

Dealing with atmospheric pressure.

Dealing with vapour pressure.

Pabs = Patm + Pgage

• Pressure at any point in a fluid is the same in all directions.

• Pressure has a magnitude, but not a specific direction, and thus

it is a scalar quantity.

Pressure at a Point

Pabs = Patm + Pgage

Pgage = Pabs Patm

Patm = Pvac + Pabs

Pvac = Patm PabsPressure acts equally in all directions

Pascal’s low: The pressure at point is the same in all directions

and normal to surface.

Pressure at a Point: Pascal’s Law

Free-body diagram of a rectangular

fluid element in equilibrium.

The pressure of a fluid at rest increases

with depth (as a result of added weight).

When the variation of density with

elevation is known

Variation of Pressure with Depth

Pabs = Patm + Pgage

The pressure is the same at all points on a horizontal plane in a given fluid

regardless of geometry, provided that the points are interconnected by the

same fluid.

Points a, b, c, and d are at equal depths in water and therefore have identical

pressures. Points A, B, and C are also at equal depths in water and have

identical pressures higher than a, b, c, and d. Point D has a different pressure

from A, B, and C because it is not connected to them by a water path.

Hydrostatic Pressure Distribution

The quantity is called the specific weight of the fluid, with dimensions of

weight per unit volume. The quantity (P / ) is a length called the pressure head

of the fluid.

Hydrostatic Pressure Distribution in Oceans and Atmospheres

Evaluating Pressure Changes Through a Column of Multiple Fluids

ExampleBlood pressures is usually given as the ratio of the maximum

pressure to the minimum pressure. For example, atypical value

for this ratio for a human would be 120/70, where the pressures

are in mm Hg. What would these pressures be in pascals.

Solution:

P = ρ g h = h in Pa or N/m2 and = 133,326 in N/m3

For 120 mm Hg:

P = (133.326 * 103 N/m3) * (120/1000 m) ………... in pascal (Pa)

P = (133.326 * 103 ) * (0.12 ) / 1000 = 15.999 kPa

The pressure for 120 mm Hg is approximately 16 kPa

For 70 mm Hg:

P = (133.326 * 103 N/m3) * (70/1000 m) .………... in pascal (Pa)

P = (133.326 * 103 ) * (0.07 ) / 1000 = 9.333 kPa

The pressure for 70 mm Hg is 9.333 kPa

Pascal’s law: The pressure applied to a confined fluid increases the

pressure throughout by the same amount.

Lifting of a large weight

by a small force by the

application of Pascal’s

law.

The area ratio A2/A1 is

called the ideal

mechanical advantage of

the hydraulic lift.

ExampleA 0.3 m diameter pipe is connected to

20 mm diameter pipe and both are

rigidly held in place. Both pipes are

horizontal with pistons at each end. If

the space between the pistons is filled

with water, what force will have to be

applied to the larger piston to balance

a force of 90 N applied to the smaller

piston? Neglect the friction.

Thus

Or

Solution:

The Barometer

Atmospheric pressure is measured by a device called a barometer; thus, the

atmospheric pressure is often referred to as the barometric pressure.

A frequently used pressure unit is the standard atmosphere, which is defined as

the pressure produced by a column of mercury 760 mm in height at 0°C (Hg =

13,595 kg/m3) under standard gravitational acceleration (g = 9.807 m/s2).

The basic barometer.

The length or the

cross-sectional area of

the tube has no effect

on the height of the

fluid column of a

barometer, provided

that the tube diameter

is large enough to

avoid surface tension

(capillary) effects.

Pressure Measurement Devıces

F = P A = W

Mercury barometer

Mercury Barometer:

It is a method for measuring the local atmospheric

pressure. The mercury barometer consists of a glass tube

closed at one end with the open end immersed in a

container of mercury as shown in Figure. The tube is

initially filled with mercury (inverted with its open end

up) and then turned upside down (open end down) with

the open end in the container of mercury. The column of

mercury will come to an equilibrium position where its

weight plus the force due to the vapor pressure (which

develops in the space above the column) balances the

force due to the atmospheric pressure. Thus:

Patm = h+ Pvapor

For most practical purposes the contribution of the vapor pressure can be

neglected since it is very small (about: 0.16 Pa = 0.16 N/m² = 0.0000016 bar

= 0.000016 kgf/cm²). Therefore:

Patm = h

Where is the specific weight of mercury.

Piezometer Tube

Piezometer Tube:

It is the simplest type of manometer consists of a

vertical tube, open at the top, and attached to the

container in which the pressure is desired, as

shown.

Since manometers involve columns of fluids at

rest, the fundamental equation describing their

use is :

P = h + Po

Application of this equation to the Piezometer

tube of indicates Figure that the gage pressure PA

can be determined by a measurement of h1 ,

through the relationship:PA = 1 h1

where 1 is the specific weight of the liquid in the

container.

Note that:

Since the tube is open at the top, and the pressure Po set equal to zero, then

we are now using gage pressure.

Although the Piezometer tube is a very simple and accurate pressure

measuring device, it has several disadvantages:

1. It is only suitable if the pressure in the container is greater than

atmospheric pressure (otherwise air would be sucked into the system).

2. The pressure to be measured must be relatively small so the required

height of the column is reasonable.

3. The fluid in the container in which the pressure is to be measured must

be a liquid rather than a gas.

To overcome the disadvantages noted U-Tube manometer should be used.

U-tube manometer

U-Tube Manometer:It consists of a tube formed in U shape as

shown. The fluid in the manometer is called

the gage fluid.

The pressure at points A and (1) are the

same, and as we move from point (1) to (2)

the pressure will increase by 1 h1. The

pressure at point (2) is equal to the pressure

at point (3) - since the pressures at equal

elevations in a continuous mass of fluid at

rest must be the same - at the open end

where the gage pressure is zero, as we move

vertically upward the pressure decreases by

an amount 2 h2. So:

Therefore,PA + 1 h1 2 h2 = 0

PA = 2 h2 1 h1

Differential U-tube manometer

The U-tube manometer is used to measure the

difference in pressure between two containers or

two points in a given system.

Consider a manometer connected between

containers A and B as is shown in Fig. The

difference in pressure between A and B can be

found where the pressure at A is PA, which is

equal to P1,and as we move to point (2) the

pressure increases by 1 h1. The pressure at P2 is

equal to P3, and as we move upward to point (4)

the pressure decreases by 2 h2. Similarly, as we

continue to move upward from point (4) to (5)

the pressure decreases by 3 h3.

Finally, P5 = PB , since they are at equal elevations. Thus:

and the pressure difference is:

PA + 1 h1 2 h2 3 h3 = PB

PA PB = 2 h2 + 3 h3 1 h1

Differential U-tube manometer

Inclined-Tube Manometer:

It is used to measure small pressure changes. as shown in Figure, one

leg of the manometer is inclined at an angle .

So, the difference in pressure can be expressed as:

i.e.,

Inclined-tube Manometer