take me out to the ballgame mixture problems in 2 variables
TRANSCRIPT
The Problem – Stadium Chow
• On his very first trip to the concession stand, Jim bought 5 hot dogs and 7 drinks for a total of $23.00.
• On his second trip to the concession stand, Jim bought 3 hot hogs and 10 drinks for a total of $22.50.
• What is the price of a hot dog?
• What is the price of a drink?
Set up the Problem
Let h = price of one hot dog
Let d = price of one drink
You can use x and y if you prefer.
Using h and d helps you to realize what variable you have solved for when you get your answer.
Now Write the Story
5 hot dogs and 7 drinks cost $23.00
5h + 7d = 23.00
3 hot hogs and 10 drinks cost $22.50
3h + 10d = 22.50
Solve the Problem
- 3 | 5h + 7d = 23.00
+ 5 | 3h + 10d = 22.50
- 15h - 21d = - 69.00
+15h + 50d = 112.50
29d = 43.50
d = 1.50
Find the 2nd Answer
Substitute the value of d into the first equation
5h + 7 ( 1.50 ) = 23.00
5h + 10.50 = 23.00
5h = 23.00 – 10.50
5h = 12.50
h = 2.50
Answer the Question
What is the price of a hot dog? h = 2.50
What is the price of a drink? d = 1.50
The price of a hot dog is $2.50.
The price of a drink is $1.50.
Careful! Some of these are confusing!
A supplement calls for:
50 mg of vitamin C and 10 mg of vitamin D.
Your pharmacy stocks two compounds that can be mixed to create the supplement.
#1) 80% vitamin C and 10% vitamin D
#2) 40% vitamin C and 20% vitamin D.
How many mg of each compound should be used?
Base your equations on the totals
A supplement calls for
50 mg of vitamin C
10 mg of vitamin D.
Make your first equation about vitamin C
and your second equation about vitamin D
Call your compounds x and y
Let x = mg of #1 and y = mg of #2
Compound #1: 80% vitamin C and 10% vitamin D
Compound #2: 40% vitamin C and 20% vitamin D.
Vitamin C: .80x + .40y = 50
Vitamin D: .10x + .20y = 10
Notice the columns
Vitamin C: .80x + .40y = 50
Vitamin D: .10x + .20y = 10
#1
#2
Compound #1: 80% vitamin C and 10% vitamin DCompound #2: 40% vitamin C and 20% vitamin D.