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Structural Change in Non-stationary AR(1)
Models∗
May 15, 2016
Tianxiao Pang1,†, Terence Tai-Leung Chong2,3, Danna Zhang4 and Yanling Liang1,
1School of Mathematical Sciences, Yuquan Campus, Zhejiang University, Hangzhou 310027, P.R.China
2Department of Economics and Lau Chor Tak Institute of Global Economics and Finance,
The Chinese University of Hong Kong, Hong Kong
3Department of International Economics and Trade, Nanjing University, Nanjing 210093, P.R.China
4Department of Statistics, University of Chicago, 5734 S. University Ave., Chicago, Illinois 60637, USA
Abstract. This paper revisits the asymptotic inference for non-stationary AR(1) models
of Phillips and Magdalinos (2007a) by incorporating a possible structural change in the AR
parameter at an unknown time k0. Consider the model yt = β1yt−1I{t ≤ k0}+β2yt−1I{t >
k0} + εt, t = 1, 2, · · · , T, where I{·} denotes the indicator function and one of β1 and β2
depends on the sample size T and the other is equal to one. We examine four cases: Case
(I): β1 = β1T = 1 − c/kT , β2 = 1; (II): β1 = 1, β2 = β2T = 1 − c/kT , (III): β1 = 1,
β2 = β2T = 1+ c/kT , and case (IV): β1 = β1T = 1+ c/kT , β2 = 1, where c is a fixed positive
constant and kT is a sequence of positive constants increasing to ∞ such that kT = o(T ).
In addition, we assume that {εt, t ≥ 1} is a sequence of i.i.d. random variables which are
in the domain of attraction of the normal law (DAN) with zero means and possibly infinite
variances. We derive the limiting distributions of the least squares estimators of β1 and
β2 and that of the change-point estimator for the aforementioned cases under some mild
conditions. It is shown that: (1) the asymptotic properties of the least squares estimator of
the second AR parameter in mildly explosive AR(1) model with an unknown change point
∗Tianxiao Pang and Yanling Liang’s research was supported by the Department of Education of Zhejiang
Province in China (N20140202).
E-mail addresses: [email protected], [email protected], [email protected] and
[email protected].†Corresponding author.
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are very different from those in mildly explosive AR(1) model or unit root model without a
change point; (2) when a unit root model switches to a mildly integrated or mildly explo-
sive AR(1) model at time k0, the asymptotic properties of the least squares estimator of k0
remain the same, and the phase transition for the estimation error of k0 occurs when kT has
the same order of magnitude as√T . Monte Carlo simulations are conducted to examine
the finite-sample properties of the estimators.
Keywords: AR(1) model, Least squares estimator, Limiting distribution, Mildly ex-
plosive, Mildly integrated, Structural change, Unit root.
JEL Classification: C22
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1 Introduction and Main Results
The change-point problem in time series regression models has received considerable atten-
tion in the literature over the past decades. Many economic time series data are characterized
by single or multiple structural changes (Stock and Watson (1996, 1999), Hansen (2001)).
Bai and Perron (1998) provided the estimation and test procedure for the linear models
with multiple structural changes. Leybourne et al. (2003), Harvey et al. (2006), Halunga
and Osborn (2012) and Kejriwal et al. (2013) investigated structural changes in persistence.
Chong (2003), Pitarakis (2004) and Bai et al. (2008) studied the estimations and tests of
the change point under model misspecification. Qu (2008) tested for the structural change
in regression quantiles. Recent development in this area include that of Lee et al. (2016),
who investigated the change-point problem in high-dimension regression models.
An important strand of literature on structural change focuses on the autoregressive
models. Structural changes in autoregressive model are of interest as the time series prop-
erties of the model, such as stationarity, may be different before and after the change. As
a result, the rate of convergence and the asymptotic distributions of the estimators are dif-
ficult to derive. Chong (2001) investigated the statistical inference for the change point in
various AR(1) models. Berkes et al. (2011) studied the structural change from an AR(1)
model to a threshold AR(1) model. An important application of the AR(1) change-point
model was given by Mankiw and Miron (1986) and Mankiw et al. (1987), who found that
the short term interest rate has changed from a stationary process to a near random walk
since the Federal Reserve System was founded at the end of 1914. Other applications can
be found in Barsky (1987) and Burdekin and Siklos (1999) for the inflation rate series, in
Hakkio and Rush (1991) for the government budget deficits, in Phillips et al. (2011) for
1990s NASDAQ and in Phillips and Yu (2011) and Phillips et al. (2015a, 2015b, 2015c) for
financial bubbles.
This paper revisits and generalizes the model studied in Chong (2001). Consider the
following AR(1) model with a change in the AR parameter at an unknown time k0,
yt = β1yt−1I{t ≤ k0}+ β2yt−1I{t > k0}+ εt, t = 1, 2, · · · , T, (1.1)
where I{·} denotes the indicator function and {εt, t ≥ 1} is a sequence of i.i.d. random
variables. Under the regularity conditions that E(εt) = 0, V ar(εt) < ∞ and E(y20) < ∞,
the consistency and limiting distributions of the least squares estimators of fixed β1 and
β2 and the change-point estimator of τ0(= k0/T ) were developed in Chong (2001) for the
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following three cases: (1) |β1| < 1 and |β2| < 1; (2) |β1| < 1 and β2 = 1; (3) β1 = 1 and
|β2| < 1.
Since heavy-tailed distributions, such as the Student’s t distribution with degrees of
freedom 2, Pareto distribution with index 2 and stable random variables are often used
to model asset returns in empirical studies (Mandelbrot, 1963), Pang and Zhang (2015)
employed the truncation technique to weaken the moment conditions of y0 and εt’s in case
(1) of Chong (2001). For any constant c, Pang et al. (2014) examined the asymptotics for
the case where |β1| < 1 and β2 = β2T = 1− c/T and the case where β1 = β1T = 1− c/T and
|β2| < 1. In these two cases, one of the β1 and β2 is fixed and smaller than one in absolute
value while the other is local to unity. The limiting distributions obtained in Pang et al.
(2014) are complicated. In the special case of c = 0, the results in Pang et al. (2014) are
reduced to the two main theorems in Chong (2001). Both Pang et al. (2014) and Pang and
Zhang (2015) only require εt’s to be in the domain of attraction of the normal law (DAN)
with zero mean and possibly infinite variance, and y0 to be any random variable of order
smaller than√T in probability.
The asymptotic theory for the near unit root model was first studied by Phillips (1987)
and Chan and Wei (1987) independently. Their studies bridge the gap between stationary
AR(1) models and the unit root model. This paper is related to that of Phillips and
Magdalinos (2007a), who attempted to bridge the gap between the asymptotic theories of
the stationary case, explosive case and the local to unity case for AR(1) model. In particular,
they investigated the limiting distribution of the least squares estimator of the AR parameter
for the following AR(1) model: yt = βyt−1 + εt, t = 1, 2, · · · , T, with β = βT = 1 − c/kT
and β = βT = 1 + c/kT , where c is a positive constant and kT is a sequence of positive
constants increasing to ∞ such that kT = o(T ). They proved the asymptotic normality for
the least squares estimator of βT with the convergence rate√TkT for the mildly integrated
AR(1) model when β = βT = 1 − c/kT and showed a Cauchy limiting distribution for the
least squares estimator of βT with convergence rate kTβTT for the mildly explosive AR(1)
model when β = βT = 1 + c/kT . The mildly explosive AR(1) model has been widely used
to model financial bubbles. The reader is referred to Phillips and Yu (2011), Phillips et al.
(2011) and Phillips et al. (2015a, 2015b, 2015c) for more details.
Motivated by the works of Chong (2001) and Phillips and Magdalinos (2007a) and the
importance of the mildly explosive AR(1) model in modelling the bubble process, in this
article, we aim to study the structural change in mildly integrated and mildly explosive
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AR(1) models from the theoretical perspective. In particular, we are interested in the
following four cases: (I) β1 = β1T = 1−c/kT , β2 = 1; (II) β1 = 1, β2 = β2T = 1−c/kT ; (III)
β1 = 1, β2 = β2T = 1+c/kT and (IV) β1 = β1T = 1+c/kT , β2 = 1, where c > 0 and kT shares
the same assumption in Phillips and Magdalinos (2007a). Cases (III) and (IV) are related to
the works of Phillips and Yu (2011), Phillips et al. (2011) and Phillips et al. (2015a, 2015b,
2015c). In the aforementioned papers, the authors proposed a structural change model with
a bubble process occurring in a unit root process and dated the origination of the explosive
episode based on a test procedure and then estimated the explosive AR parameter by using
a demeaning procedure and the least squares method. Since the models before and after the
time k0 are both non-stationary and the difference between β1 and β2 converges to zero as
the sample size tends to infinity, obtaining the closed form limiting distributions of the least
squares estimators of β1 and β2 and the estimator of the change point will be a challenging
task. The main contribution of this paper is to derive the closed form solution of the limiting
distributions of these estimators for the aforementioned cases when the distribution of the
error term belongs to the DAN.
A sequence of i.i.d. random variables {Xi, i ≥ 1} belongs to the DAN if there exist two
constant sequences {An, n ≥ 1} and {Bn, n ≥ 1} such that Zn := B−1n (X1 + · · ·+Xn)−An
converges to a standard normal random variable in distribution as n tends to infinity (Feller,
1971), where Bn takes the form√nh(n) and h(n) is a slowly varying function at infinity.
For the models studied in this article, we make the following assumptions:
• C1: {εt, t ≥ 1} is a sequence of i.i.d. random variables which are in the domain of
attraction of the normal law with zero means and possibly infinite variances.
• C2: {kT , t ≥ 1} is a sequence of positive constants increasing to infinity slowly such
that kT = o(T ).
• C3: y0 is an arbitrary random variable with y0 = op(√kT ).
• C4: τ0 ∈ [τ , τ ] ⊂ (0, 1).
Remark 1.1 The assumption of i.i.d. in C1 is only for the convenience of exposition in the
proofs. If the DAN condition is replaced by some appropriate moment conditions, one can
extend our results to some cases that allow for dependence. One may refer to Phillips and
Magdalinos (2007b) and Magdalinos (2012) for details. Assumption C2 is the same as that
in Phillips and Magdalinos (2007a). Assumption C3 means y0 will not affect the asymptotic
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properties of the estimators of β1, β2 and the change point. Assumption C4 is standard in
the change-point literature (Bai (1997), Chong (2001) and Pitarakis (2004)), which ensures
the identifiability of the AR parameters and the change point. In empirical studies, one can
set [τ , τ ] = [0.05, 0.95].
Let [a] denote the integer part of a. For any given 0 < τ < 1, the least squares estimators
of the AR parameters β1 and β2 are given by
β1(τ) =
∑[τT ]t=1 ytyt−1∑[τT ]t=1 y2t−1
, β2(τ) =
∑Tt=[τT ]+1 ytyt−1∑Tt=[τT ]+1 y
2t−1
,
The change-point estimator is defined as
τT = argminτ∈(0,1)
RSST (τ),
where
RSST (τ) =
[τT ]∑t=1
(yt − β1(τ)yt−1
)2+
T∑t=[τT ]+1
(yt − β2(τ)yt−1
)2.
Once we obtain the change-point estimator τT , the final least squares estimators of β1 and
β2 are defined by β1(τT ) and β2(τT ) respectively.
We define some notations before proceeding to our main results. Let W (·), W (·) and
W (·) be three independent Brownian motions defined on [0, 1], [0, 1] and R+ respectively,
and W1(·) and W2(·) be two independent Brownian motions defined on R+. “⇒” denotes
the weak convergence of the associated probability measures. “p→” denotes convergence in
probability and “d=” denotes identical in distribution. The limits in this paper are all taken
as T → ∞ unless specified otherwise. In addition, we denote k = [T τT ] and the notation
aT ≍ bT means there exist two positive constants c1 and c2 such that c1 ≤ aT /bT ≤ c2 for
all large T , where aT and bT are two positive functions of T .
Under assumptions C1-C4, we have the following results.
Theorem 1.1 In Model (1.1), if β1 = β1T = 1−c/kT and β2 = 1, where c is a fixed positive
constant, under assumptions C1-C4, we have:
(a) τT is consistent and its limiting distribution is given by
cT
kT(τT − τ0) ⇒ argmax
ν∈R
{C∗(ν)
Bc(12)
− |ν|2
}, (1.2)
where Bc(12) is generated by
√c∫∞0 exp (−cs)dW1(s) and C∗(ν) is defined to be C∗(ν) =
W1(−ν) for ν ≤ 0 and
C∗(ν) = −W2(ν)−∫ ν
0
W2(s)
Bc(12)
dW2(s)−∫ ν
0
( W2(s)
2Bc(12)
+ 1)W2(s)ds
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for ν > 0.
(b) β1(τT ) is consistent and its limiting distribution is given by√τ0T
1− β21T
(β1(τT )− β1T ) ⇒ N(0, 1). (1.3)
(c) β2(τT ) is also consistent and its limiting distribution is given by
(1− τ0)T (β2(τT )− 1) ⇒ (W (1)−W (τ0))2 − (1− τ0)
2∫ 1τ0(W (s)−W (τ0))2ds/(1− τ0)
d=
W2(1)− 1
2∫ 10 W
2(s)ds
. (1.4)
Theorem 1.2 In Model (1.1), if β1 = 1 and β2 = β2T = 1−c/kT , where c is a fixed positive
constant, under assumptions C1-C4, we have:
(a) (i) When kT = o(√T ), then τT is exactly T -consistent, i.e.,
P (k = k0) → 0.
(ii) When kT ≍√T , then τT is T -consistent, i.e.,
|k − k0| = Op(1).
(iii) When√T = o(kT ), then τT is not T -consistent, but τT is consistent and its limiting
distribution is given by
c2T 2
k2T(τT − τ0) ⇒ argmax
ν∈R
{W ∗(ν)
W1(τ0)− |ν|
2
}, (1.5)
where W ∗(ν) is a two-sided Brownian motion on R defined to be W ∗(ν) = W1(−ν) for ν ≤ 0
and W ∗(ν) = W2(ν) for ν > 0.
(b) β1(τT ) is consistent and its limiting distribution is given by
τ0T (β1(τT )− 1) ⇒ W 2(τ0)− τ02∫ τ00 W 2(s)ds/τ0
d=
W 2(1)− 1
2∫ 10 W 2(s)ds
. (1.6)
(c) β2(τT ) is also consistent and its limiting distribution is given by√T
1− β22T
(β2(τT )− β2T ) ⇒W (1)
W 2(τ0) + (1− τ0). (1.7)
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Theorem 1.3 In Model (1.1), if β1 = 1 and β2 = β2T = 1+c/kT , where c is a fixed positive
constant, under assumptions C1-C4, we have:
(a) (i) When kT = o(√T ), then τT is exactly T -consistent, i.e.,
P (k = k0) → 0.
(ii) When kT ≍√T , then τT is T -consistent, i.e.,
|k − k0| = Op(1).
(iii) When√T = o(kT ), then τT is not T -consistent, but τT is consistent and its limiting
distribution is given by (1.5).
(b) β1(τT ) is consistent and its limiting distribution is given by
τ0T (β1(τT )− 1) ⇒ W 2(τ0)− τ02∫ τ00 W 2(s)ds/τ0
d=
W 2(1)− 1
2∫ 10 W 2(s)ds
. (1.8)
(c) β2(τT ) is also consistent and its limiting distribution is given by√τ0T
β22T − 1
βT−[τ0T ]2T (β2(τT )− β2T ) ⇒
√2cX
W (1)
d= ζ, (1.9)
where X is a random variable obeying N(0, 12c) and is independent of W (·), and ζ stands
for a standard Cauchy variate.
Theorem 1.4 In Model (1.1), if β1 = β1T = 1+c/kT and β2 = 1, where c is a fixed positive
constant, under assumptions C1-C4, the estimators k, β1(τT ) and β2(τT ) are all consistent
and
P (k = k0) → 0, (1.10)
β[τ0T ]1T
β21T − 1
(β1(τT )− β1T ) ⇒ ζ, (1.11)√(1− τ0)T
β21T − 1
β[τ0T ]1T (β2(τT )− 1) ⇒ W (1)−W (τ0)√
2c(1− τ0)Y
d= ζ, (1.12)
where ζ is a standard Cauchy variate, Y is a random variable obeying N(0, 12c) and inde-
pendent of W (·).
Based on these results, it follows from assumption C4 that τ0 cannot be equal to zero
or one, but it can be close to zero or one if we let the interval [τ , τ ] be close to (0, 1)
enough. If we let τ0 be close to one in Theorem 1.1 and close to zero in Theorem 1.2,
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Model (1.1) becomes an approximately mildly integrated AR(1) model. Then, since 1−(1−
c/kT )2 = 2c/kT (1+ o(1)), the limiting distributions of the statistics
√TkT (β1(τT )−β1T ) in
Theorem 1.1 and√TkT (β2(τT ) − β2T ) in Theorem 1.2 will be approximately N(0, 2c) and
W (2c), respectively, with the convergence rate√TkT . This agrees with the result in Phillips
and Magdalinos (2007a). Analogously, letting τ0 be close to zero in Theorem 1.1 and be
close to one in Theorem 1.2, Model (1.1) converges to a unit root model, and the limiting
distributions of the statistics T (β2(τT )− 1) in Theorem 1.1 and T (β1(τT )− 1) in Theorem
1.2 will be approximately W2(1)−1
2∫ 10 W
2(s)ds
and W 2(1)−1
2∫ 10 W 2(s)ds
respectively with a convergence rate
T , which agrees with the asymptotic theory for the unit root model. Therefore, when the
sample {y1, · · · , yT } is divided into two sub-samples {y1, · · · , y[τ0T ]} and {y[τ0T ]+1, · · · , yT }
if [τ0T ] is the change point in mildly integrated AR(1) model, then the first sub-sample
{y1, · · · , y[τ0T ]} will not affect the asymptotic properties of the least squares estimator of
β2. However, it is interesting to find that the results above are not applicable to Theorem
1.3 and Theorem 1.4. Even if τ0 is very close to zero, the influence of the first sub-sample
{y1, · · · , y[τ0T ]} is not negligible. In fact, it can be seen from the proofs of Theorem 1.3 and
Theorem 1.4 that the influence of the first sub-sample {y1, · · · , y[τ0T ]} dominates that of
the second sub-sample {y[τ0T ]+1, · · · , yT } even when τ0 is very close to zero, leading to the
difference in asymptotic properties of the least squares estimator of β2 from those in mildly
explosive model or unit root model. For example, in Theorem 1.3, affected by the first sub-
sample, the limiting distribution of the statistic√
τ0TkT2c β
T−[τ0T ]2T (β2(τT )− β2T ) is standard
Cauchy. This result is a little different from that in mildly explosive AR(1) model studied
in Phillips and Magdalinos (2007a). Moreover, the convergence rate for the least squares
estimator of β2 in Theorem 1.3 is slower than that in Phillips and Magdalinos (2007a).
Furthermore, the asymptotic properties of the least squares estimator of β2 are affected by
the first sub-sample more seriously in Theorem 1.4. It can be seen from Theorem 1.4 that
the limiting distribution of the least squares estimator of β2 is totally different from that
in unit root model, and the convergence rate is faster than that in unit root model. These
findings are useful in testing for a change point in mildly explosive AR(1) model.
Theorem 1.1 and Theorem 1.2 indicate that, when the two sub-samples do not dominate
each other, the convergence rate of the least squares estimator when the AR parameter
equals one is faster than that in the case when the AR parameter equals 1− c/kT , since the
signal from the regressor yt−1 in the former case is stronger than that from the regressor
yt−1 in the latter case. It should also be noted that the convergence rate of τT in Theorem
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1.2 is faster than that in Theorem 1.1. This is because the signal from the regressor yt−1
when (β1, β2) = (1, 1− c/kT ) is stronger than that from the regressor yt−1 when (β1, β2) =
(1−c/kT , 1). However, these findings are not totally applicable to Theorem 1.3 and Theorem
1.4. Note that in Theorem 1.3, the convergence rate of the least squares estimator of β2
is faster than that of the least squares estimator of β1. Moreover, the convergence rate of
τT in Theorem 1.4 is faster than that in Theorem 1.3 since the signal from the regressor
yt−1 when (β1, β2) = (1 + c/kT , 1) is stronger than that from the regressor yt−1 when
(β1, β2) = (1, 1+ c/kT ). These are consistent with Theorem 1.1 and Theorem 1.2. However,
it is surprising that the convergence rate of the least squares estimator of β2 is faster than
that of the least squares estimator of β1 in Theorem 1.4. This is completely different from
the finding from Theorem 1.1 and Theorem 1.2. Compared with Theorem 1.3, the second
sub-sample is more affected by the first sub-sample in Theorem 1.4.
The precision of the estimation of k0 depends on both the strength of the signal from
the model and the difference between β1 and β2. Note that the difference between β1 and
β2 is c/kT and the strength of the signal from the model becomes increasingly stronger from
Theorem 1.1 to Theorem 1.4. In general, the signal from the model in Theorem 1.1 is too
weak for k0 to be located for any kT = o(T ), while the signal from the model in Theorem
1.4 is too strong such that k0 can be located for any kT = o(T ). For the models in Theorems
1.2 and 1.3, although the signal from the model in Theorem 1.3 is stronger than that from
the model in Theorem 1.2, it is surprising that k0 can be located only when kT = o(√T )
in both models. This is because the increment of signal from Theorem 1.2 to Theorem
1.3 is too small such that the difference between RSST (τ0) and RSST (τ0 ± mT ) for a fixed
integer m in Theorem 1.3 is the same as that in Theorem 1.2, which can be seen from the
proofs of Theorems 1.2 and 1.3. Although the increase in strength of signal from the model
in Theorem 1.2 to the model in Theorem 1.3 does not help to locate k0, it improves the
convergence rate for the least squares estimator of β2.
It is interesting to find that the conventional T -consistent for τT occurs only when
kT ≍√T in both Theorems 1.2 and 1.3. When kT is of order higher than
√T , β1 and
β2 will be very close, and the estimation error for k0 will be huge. When kT has smaller
magnitude than√T , it implies that β1 and β2 has enough difference, and the estimation
error for k0 reduces tremendously.
Suppose c0 is a fixed constant smaller than one in absolute value. It follows from Chong
(2001) and Pang et al. (2014) that the convergence rates of the least squares estimators
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of β1 and β2 under the situations of (β1, β2) = (c0, 1 − c/T ) and (β1, β2) = (1 − c/T, c0)
with c an arbitrary fixed constant are symmetric. This is also the case in our paper when
(β1, β2) = (1−c/kT , 1) and (β1, β2) = (1, 1−c/kT ) with c a fixed positive constant. However,
it is surprising to see from Theorems 1.3 and 1.4 that the convergence rates of the least
squares estimators of β1 and β2 when (β1, β2) = (1, 1 + c/kT ) and (β1, β2) = (1 + c/kT , 1)
are asymmetric.
The rest of the paper is organized as follows. Section 2 discusses some possible extensions
for the results obtained in this section. Section 3 demonstrates some finite sample Monte
Carlo results for our estimators in the presence of structural change, and for mildly explosive
AR(1) model of Phillips and Magdalinos (2007a) which does not have a structural change.
Section 4 concludes the paper. The proofs of Theorems 1 to 4 are relegated to Appendix A
to Appendix D respectively.
2 Discussions
2.1 Pivotal explore
The statistics in the theorems in last section depend on nuisance parameters when exploring
the limiting distributions of the least squares estimators of the AR parameters, but most of
them can be rewritten pivotally. Note that τT is always a consistent estimator of τ0 with
convergence rate at least kT /T or k2T /T2 in the four theorems in last section, implying that
T τTTτ0
p→ 1 andT − T τTT − Tτ0
p→ 1.
Note also that β1(τT ) and β2(τT ) are always a consistent estimator of β1T and β2T respec-
tively in our theorems,
(1± c/kT )k2T /T → 1
and the relationship (C.16) below. In Theorem 1.3, since
[τ0T ]− [τTT ] = Op(k2T /T ) = op(kT )
and
β2(τT ) = β2T +Op
( 1√TkTβ
T−[τ0T ]2T
),
we have
(β2(τT ))T−[τTT ]
βT−[τ0T ]2T
=
(β2(τT )
β2T
)T−[τ0T ]
· (β2(τT ))[τ0T ]−[τTT ] p→ 1.
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Similarly, in Theorem 1.4, we have
(β1(τT ))[T τT ]
β[τ0T ]1T
p→ 1.
Then, the limiting distributions of the least squares estimators of AR parameters in the
theorems in last section can further be written as:
Theorem 2.1 In Theorem 1.1,
(a) β1(τT ) is consistent and its limiting distribution is given by√T τT
1− β21(τT )
(β1(τT )− β1T ) ⇒ N(0, 1),
(b) β2(τT ) is also consistent and its limiting distribution is given by
(T − T τT )(β2(τT )− 1) ⇒ W2(1)− 1
2∫ 10 W
2(s)ds
.
Theorem 2.2 In Theorem 1.2,
(a) β1(τT ) is consistent and its limiting distribution is given by
T τT (β1(τT )− 1) ⇒ W 2(1)− 1
2∫ 10 W 2(s)ds
,
(b) β2(τT ) is also consistent and its limiting distribution is given by√T
1− β22(τT )
(β2(τT )− β2T ) ⇒W (1)
W 2(τ0) + (1− τ0).
Theorem 2.3 In Theorem 1.3,
(a) β1(τT ) is consistent and its limiting distribution is given by
T τT (β1(τT )− 1) ⇒ W 2(1)− 1
2∫ 10 W 2(s)ds
,
(b) β2(τT ) is also consistent and its limiting distribution is given by√T τT
β22(τT )− 1
(β2(τT ))T−[T τT ](β2(τT )− β2T ) ⇒ ζ,
where ζ stands for a standard Cauchy variate.
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Theorem 2.4 In Theorem 1.4,
(a) β1(τT ) is consistent and its limiting distribution is given by
(β1(τT ))[T τT ]
β21(τT )− 1
(β1(τT )− β1T ) ⇒ ζ,
(b) β2(τT ) is also consistent and its limiting distribution is given by√T − T τT
β21(τT )− 1
(β1(τT ))[T τT ](β2(τT )− 1) ⇒ ζ,
where ζ stands for a standard Cauchy variate.
2.2 The presence of an intercept in the model
In most applications, AR(1) model with an intercept is more realistic. Hence, it might be
useful to extend our analysis in Section 1 to non-stationary AR(1) models with an intercept.
Suppose the true structural change model is
yt = α+ β1yt−1I{t ≤ k0}+ β2yt−1I{t > k0}+ εt, t = 1, 2, · · · , T.
After demeaning the model using yt = yt − 1T
∑Tt=1 yt, we have
yt =
β1y1,t−1 − β21T
∑Tj=k0+1 yj−1 + εt, 1 ≤ t ≤ k0
β2y2,t−1 − β11T
∑k0j=1 yj−1 + εt, k0 < t ≤ T
with
y1,t−1 = yt−1 −1
T
k0∑t=1
yt−1, y2,t−1 = yt−1 −1
T
T∑t=k0+1
yt−1 and εt = εt −1
T
T∑t=1
εt.
However, the structural-change model becomes more complicated and the previous analysis
is not applicable here.
Another possible approach is to estimate the parameters directly without the demeaning
procedure. For any given 0 < τ < 1, we use
β1(τ) =
∑[τT ]t=1 y1,ty1,t−1∑[τT ]t=1 y21,t−1
, β2(τ) =
∑Tt=[τT ]+1 y2,ty2,t−1∑Tt=[τT ]+1 y
22,t−1
and
α(τ) =1
T
T∑t=1
yt − β1(τ)1
T
[τT ]∑t=1
yt−1 − β2(τ)1
T
T∑t=[τT ]+1
yt−1
to denote the least squares estimators of β1, β2 and α respectively, where
y1,t = yt −1
[τT ]
[τT ]∑t=1
yt, y1,t−1 = yt−1 −1
[τT ]
[τT ]∑t=1
yt−1
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and
y2,t = yt −1
T − [τT ]
T∑t=[τT ]+1
yt, y2,t−1 = yt−1 −1
T − [τT ]
T∑t=[τT ]+1
yt−1.
The change-point estimator is then defined as
τT = argminτ∈(0,1)
RSST (τ),
where
RSST (τ) =
[τT ]∑t=1
(yt − α(τ)− β1(τ)yt−1
)2+
T∑t=[τT ]+1
(yt − α(τ)− β2(τ)yt−1
)2.
However, since our analysis in last section relies heavily on the existence of closed form
expression of RSST (τ)−RSST (τ0), which is not easy to be formulated here.
Therefore, the analysis of structural change in AR(1) models with an intercept is ex-
tremely complicated, and we leave it for future work.
3 Simulations
For empirical applications, we perform the following Experiments 1-4 to see how well the
finite sample properties of the estimators follow our asymptotic results. In all experiments,
the sample size is set at T = 600, the interval [τ , τ ] is taken as [0.05, 0.95] (hence the break
fraction is searched within this interval in our experiments), the true break fraction is set
at τ0 = 0.5 (hence k0 = 300) and the number of replications is set at N = 50, 000; {yt}Tt=1
is generated from Model (1.1), y0 is set at zero for simplicity and {εt}Tt=1 are generated
independently from N(0, 1). In addition, we take c = 3 and kT = Tα with α = 0.3, 0.5, 0.7
respectively. The case where α = 0.3 presents kT = o(√T ), the case where α = 0.5 presents
kT ≍√T and the case where α = 0.7 presents
√T = o(kT ). Note that the two AR
parameters have a large difference when α = 0.3 (= 3/6000.3 = 0.440), have a moderate
difference when α = 0.5 (= 3/6000.5 = 0.122) and have a very small difference when α = 0.7
(= 3/6000.7 = 0.034).
3.1 Experiment 1
First, we conduct experiments to verify Theorem 1.1. Figure 1 and Figure 2 are the his-
tograms of k and the distributions of β1(τT ) and β2(τT ) respectively. Our result predicts
that k is not a consistent estimator of k0 and the estimation error is of Op(kT ). This is
supported by Figure 1. Figure 1 also indicates that the smaller is the difference between β1
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and β2, the larger is the estimation error, which agrees with the intuition. In addition, the
bottom graph in Figure 1 demonstrates that there exists a “boundary effect” when β1 and
β2 has no enough difference. Part (b) of Theorem 1.1 predicts that β1(τT ) should have a
normal distribution and part (c) of Theorem 1.1 predicts that β2(τT ) should have a Dickey-
Fuller distribution. Figure 2 agrees with our results. This figure also depicts that the larger
is the difference between β1 and β2, the better is the finite-sample performance of β1(τT ) and
β2(τT ). Note that, in the finite-sample case, the distribution of the least squares estimator
of the AR parameter should be a mixture of normal and Dickey-Fuller distributions when
the true AR parameter is smaller than but near to one. This explains why the finite-sample
performance of β1(τT ) when α = 0.7 is not very satisfactory.
3.2 Experiment 2
Second, we conduct experiments for Theorem 1.2. Part (a) of Theorem 1.2 predicts that
k is a consistent estimator of k0 when kT = o(√T ), k has a finite estimation error in
probability when kT ≍ o(√T ) and k has a larger estimation error when
√T = o(kT ). These
theoretical findings are all supported by Figure 3. Note that, as in Figure 1, there also exists
a “boundary effect” when β1 and β2 have a very small difference. Part (b) of Theorem 1.2
predicts that β1(τT ) should have a Dickey-Fuller distribution and part (c) of Theorem 1.2
predicts that β2(τT ) should have a symmetric distribution around zero that looks like a
normal distribution. These theoretical results are all supported by Figure 4. Note that
1 − 3/6000.7 is smaller than but very near to one, hence the finite-sample distribution of
β2(τT ) when α = 0.7 is a mixture of normal and Dickey-Fuller distributions.
3.3 Experiment 3
Third, we conduct experiments for Theorem 1.3. It can be shown that: (i) Part (a) of
Theorem 1.3 is supported by Figure 5, and it is interesting to find that there exists a “right-
boundary effect” when α = 0.3 (we have also conducted the experiments for the case of
α = 0.4, which is not reported here, and found that the “right-boundary effect” is reduced).
This can be explained by (i) when α = 0.3 in our finite-sample setting, the AR parameter
equals 1 + 3/6000.3 = 1.44, which is much larger than unity, and causes a huge variation
of yt when t > k0 and a retrusion to the right boundary for k; (ii) Part (b) of Theorem
1.3 predicts that β1(τT ) has a Dickey-Fuller distribution, and this is supported by the first
column in Figure 6. However, as a consequence of “right-boundary effect” of k, the finite-
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sample distribution of β1(τT ) when α = 0.3 suffers from a shape-distortion. We have also
conducted experiments for β2(τT ) with α varying from 0.3 to 0.99995, the results also reveal
shape-distortion. We only report the results for α = 0.95, 0.97 and 0.99 here (see the second
column in Figure 6). We even increased the sample size T to 5, 000 to study the finite-sample
performance of β2(τT ) for α = 0.99 but found that the performance has no improvement.
The result is not reported here for saving space.
3.4 Experiment 4
Fourth, we conduct the experiments for Theorem 1.4. Part (a) of Theorem 1.4 predicts that
k is a consistent estimator of k0 for all kT satisfying kT = o(T ). This theoretical result is
confirmed by Figure 7. Similar to the experiment results of Theorem 1.3, the finite-sample
distributions of β1(τT ) and β2(τT ) suffer from a more or less shape-distortion, based on
experiments with α varying from 0.3 to 0.999. Only the results for α = 0.95, 0.97 and 0.99
are shown here (see Figure 8). The experiments for T = 5, 000 were also conducted for
some α’s, as is expected, the performance of β1(τT ) and β2(τT ) also has no improvement
and some of the results are even worse than the case where T = 600. The results are also
not reported for brevity.
In addition, it can be observed from Figure 1, Figure 3, Figure 5 and Figure 7 that,
as the signal of the model becoming stronger, the finite-sample performance of k improves,
although the theoretical results in Theorem 1.2 and Theorem 1.3 predict that the properties
of k under the situations of β1 = 1 and β2 = 1 − c/kT and of β1 = 1 and β2 = 1 + c/kT
should be the same as T tends to infinity.
3.5 Experiment 5
In this subsection, we conduct Monte Carlo experiments for the following mildly explosive
AR(1) model which is studied in Phillips and Magdalinos (2007a):
yt = βT yt−1 + εt, t = 1, · · · , T, (3.1)
where βT = 1+ c/kT with c > 0 and kT is a positive constant sequence increasing to infinity
such that kT = o(T ), y0 = op(√kT ), and {εt, t ≥ 1} is a sequence of i.i.d. random variables
with zero means and finite variances. Let βT stand for the least squares estimator of βT .
Phillips and Magdalinos (2007a) proved that
kTβTT
2c(βT − βT ) ⇒ ξ, (3.2)
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where ξ is a standard Cauchy variate.
We perform the following experiments to see how well the finite sample properties of
βT match with the asymptotic results (3.2). First, we set the sample size at T = 600; the
number of replications is set at N = 50, 000; {yt}Tt=1 is generated from Model (3.1), y0 is set
at zero for simplicity and {εt}Tt=1 are generated independently from N(0, 1). In addition, we
set c = 3 and kT = Tα with α = 0.90, 0.95, 0.98 respectively. Note that the AR parameter
is always larger than unity but is close to unity for large α. The first column of Figure 9
reports the results. Note that the finite-sample performance of βT when α = 0.95 appears
to be the best in our specification. However, it should be noted that it is a mixture of
Dickey-Fuller and Cauchy distributions. The finite-sample distribution of βT for α = 0.90
obviously suffers from a shape-distortion. For smaller α’s, the results for α = 0.60, 0.70 and
0.80 which are not reported here reveal that the finite-sample distributions of βT suffer from
a more severe shape-distortion.
We also conduct an experiment for the case of T=2, 000. The second column of Figure
9 reports the corresponding results. Note that, even when T is 2, 000, the finite-sample
performance of βT under various α does not have obvious improvement. The finite-sample
performance of βT with α = 0.90 and 0.95 is even worse than the case where T = 600.
Therefore, the finite-sample performance of βT is not very satisfactory. Our numerical
studies show that the finite-sample performance is very sensitive to kT and an increase in
the sample size does not improve the peformance because the AR parameter depends on
the sample size.
4 Conclusions
In this article, we examined the asymptotic properties of the least squares estimators in
mildly integrated AR(1) model and mildly explosive AR(1) model with a structural change.
Some interesting findings are obtained: (1) the stronger the signals from the model are,
the easier it is for the change point to be located. This suggests that the estimation of
the change point in mildly explosive AR(1) model is easier than that in mildly integrated
AR(1) model. However, if the first sub-sample comes from a unit root model, then it is
more difficult to locate the change point regardless of the order of the second sub-sample.
(2) In the presence of a change point, the first sub-sample will not affect the asymptotic
properties of the least squares estimator of the second AR parameter in mildly integrated
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Den
sity
0 100 200 300 400 500 6000.
00.
10.
20.
30.
4
(a) α=0.3
Den
sity
0 100 200 300 400 500 600
0.00
0.05
0.10
0.15
(b) α=0.5
Den
sity
0 100 200 300 400 500 600
0.00
00.
005
0.01
00.
015
0.02
00.
025
0.03
00.
035
(c) α=0.7
Figure 1: Histogram of k when β1T = 1− c/kT and β2 = 1, where c = 3, T = 600 and kT = Tα.
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−15 −10 −5 0 5 10 15
0.0
0.1
0.2
0.3
0.4
−20 −15 −10 −5 0 5 10 15
0.00
0.05
0.10
0.15
0.20
0.25
(a) α=0.3
−15 −10 −5 0 5 10 15
0.0
0.1
0.2
0.3
0.4
−20 −15 −10 −5 0 5 10 15
0.00
0.05
0.10
0.15
0.20
0.25
(b) α=0.5
−15 −10 −5 0 5 10 15
0.0
0.1
0.2
0.3
0.4
−20 −15 −10 −5 0 5 10 15
0.00
0.05
0.10
0.15
0.20
0.25
(c) α=0.7
Figure 2: The first column is the distribution of√
τ0T1−β2
1T(β1(τT )− β1T ) while the second column is
the distribution of (1 − τ0)T (β2(τT ) − 1) under the situation of β1T = 1 − c/kT and β2 = 1, where
c = 3, T = 600 and kT = Tα, the solid lines present the graphs when T = 600 and the dashed lines
present the graphs when T = ∞.
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Den
sity
0 100 200 300 400 500 6000.
00.
20.
40.
60.
8
(a) α=0.3
Den
sity
0 100 200 300 400 500 600
0.0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
(b) α=0.5
Den
sity
0 100 200 300 400 500 600
0.00
0.05
0.10
0.15
0.20
0.25
(c) α=0.7
Figure 3: Histogram of k when β1 = 1 and β2T = 1− c/kT , where c = 3, T = 600 and kT = Tα.
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−20 −10 −5 0 5 10 15
0.00
0.05
0.10
0.15
0.20
0.25
−15 −10 −5 0 5 10 15
0.0
0.1
0.2
0.3
0.4
(a) α=0.3
−20 −10 −5 0 5 10 15
0.00
0.10
0.20
0.30
−15 −10 −5 0 5 10 15
0.0
0.1
0.2
0.3
0.4
(b) α=0.5
−20 −15 −10 −5 0 5 10 15
0.00
0.05
0.10
0.15
0.20
0.25
0.30
−15 −10 −5 0 5 10 15
0.0
0.1
0.2
0.3
0.4
(c) α=0.7
Figure 4: The first column is the distribution of τ0T (β1(τT ) − 1) while the second column is the
distribution of√
T1−β2
2T(β2(τT ) − β2T ) under the situation of β1 = 1 and β2T = 1 − c/kT , where
c = 3, T = 600 and kT = Tα, the solid lines present the graphs when T = 600 and the dashed lines
present the graphs when T = ∞. 21
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Den
sity
0 100 200 300 400 500 6000.
00.
10.
20.
30.
40.
50.
6
(a) α=0.3
Den
sity
0 100 200 300 400 500 600
0.0
0.2
0.4
0.6
0.8
(b) α=0.5
Den
sity
0 100 200 300 400 500 600
0.00
0.05
0.10
0.15
0.20
0.25
0.30
0.35
(c) α=0.7
Figure 5: Histogram of k when β1 = 1 and β2T = 1 + c/kT , where c = 3, T = 600 and kT = Tα.
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−20 −15 −10 −5 0 5 10 15
0.00
0.05
0.10
0.15
0.20
0.25
(a) α=0.3
−15 −10 −5 0 5 10 15
0.0
0.1
0.2
0.3
0.4
0.5
0.6
(b) α=0.95
−20 −15 −10 −5 0 5 10 15
0.00
0.05
0.10
0.15
0.20
0.25
(c) α=0.5
−15 −10 −5 0 5 10 15
0.0
0.1
0.2
0.3
0.4
(d) α=0.97
−20 −15 −10 −5 0 5 10 15
0.00
0.05
0.10
0.15
0.20
0.25
(e) α=0.7
−15 −10 −5 0 5 10 15
0.00
0.05
0.10
0.15
0.20
0.25
0.30
0.35
(f) α=0.99
Figure 6: The first column is the distribution of τ0T (β1(τT ) − 1) while the second column is the
distribution of√
τ0Tβ22T−1
βT−[τ0T ]2T (β2(τT ) − β2T ) under the situation of β1 = 1 and β2T = 1 + c/kT ,
where c = 3, T = 600 and kT = Tα. The solid lines present the graphs when T = 600 and the dashed
lines present the graphs when T = ∞.
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Den
sity
0 100 200 300 400 500 6000.
00.
20.
40.
60.
81.
0
(a) α=0.3
Den
sity
0 100 200 300 400 500 600
0.0
0.2
0.4
0.6
0.8
1.0
(b) α=0.5
Den
sity
0 100 200 300 400 500 600
0.0
0.2
0.4
0.6
0.8
1.0
(c) α=0.7
Figure 7: Histogram of k when β1T = 1 + c/kT and β2 = 1, where c = 3, T = 600 and kT = Tα.
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−15 −10 −5 0 5 10 15
0.00
0.05
0.10
0.15
0.20
0.25
0.30
0.35
−15 −10 −5 0 5 10 15
0.0
0.1
0.2
0.3
0.4
(a) α=0.95
−15 −10 −5 0 5 10 15
0.00
0.05
0.10
0.15
0.20
0.25
0.30
0.35
−15 −10 −5 0 5 10 15
0.0
0.1
0.2
0.3
0.4
(b) α=0.97
−15 −10 −5 0 5 10 15
0.00
0.05
0.10
0.15
0.20
0.25
0.30
0.35
−15 −10 −5 0 5 10 15
0.0
0.1
0.2
0.3
0.4
(c) α=0.99
Figure 8: The first column is the distribution ofβ[τ0T ]
1T
β21T−1
(β1(τT ) − β1T ) while the second column is
the distribution of√
(1−τ0)Tβ21T−1
β[τ0T ]1T (β2(τT ) − 1) under the situation of β1T = 1 + c/kT and β2 = 1,
where c = 3, T = 600 and kT = Tα. The solid lines present the graphs when T = 600 and the dashed
lines present the graphs when T = ∞.
25
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−20 −10 0 10 20
0.0
0.2
0.4
0.6
0.8
−20 −10 0 10 20
0.0
0.2
0.4
0.6
0.8
1.0
(a) α=0.90
−20 −10 0 10 20
0.00
0.05
0.10
0.15
0.20
0.25
0.30
−20 −10 0 10 20
0.0
0.1
0.2
0.3
0.4
0.5
(b) α=0.95
−20 −10 0 10 20
0.00
0.05
0.10
0.15
0.20
0.25
0.30
0.35
−20 −10 0 10 20
0.00
0.05
0.10
0.15
0.20
0.25
0.30
0.35
(c) α=0.98
Figure 9: The distributions ofkT βT
T
2c (βT − βT ) with βT = Tα, where c = 3. The first column is the
distribution for T = 600 and the second column is the distribution for T = 2, 000. The solid lines
present the graphs when T = 600 or 2, 000 and the dashed lines present the graphs when T = ∞.
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AR(1) model, while it is not the case for mildly explosive AR(1) model. This suggests that
the asymptotic properties of the least squares estimator of the second AR parameter in
mildly explosive AR(1) model with a change point are might be very different from those
in mildly explosive AR(1) model or unit root model without a change point, whereas it is
not the case in the mildly integrated AR(1) model; (3) when a unit root model switches
to a mildly integrated or mildly explosive AR(1) model, the asymptotic properties of the
least squares estimator of k0 are the same. In particular, under both situations, our results
reveal that |k − k0| = op(1) when kT = o(√T ), |k − k0| = Op(1) when kT ≍
√T and
|k − k0| = Op(k2T /T ) when
√T = o(kT ). The phase transition for the estimation error of k
occurs when kT ≍√T . (4) Our simulation results show that the finite-sample performance
of the least squares estimators of the AR parameters for the mildly explosive AR(1) model
with and without a structural change suffers from different degrees of shape-distortion. The
shape-distortion phenomenon can be explained partially by a well-known fact that the least
squares estimator of the AR parameter in the autoregression models is biased, and this bias
increases as the AR parameter gets larger (see page 209 in Phillips et al. (2011) and page
1411 in Mikusheva (2007)). The finite-sample performance of the least squares estimators
of the AR parameters coming from the mildly integrated AR(1) model with a structural
change is good.
Acknowledgements. The authors would like to thank professor Peter. C. B. Phillips,
a co-editor and three anonymous referees for their constructive and illuminating comments
that have significantly improved the present article.
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Appendix A: Proof of Theorem 1.1
In order to prove theorems when the εt’s are heavy-tailed, we employ the truncation tech-
nique in this paper. Let
l(u) = E(ε21I{|ε1| ≤ u}), b = inf{u ≥ 1 : l(u) > 0},
and
ηj = inf{s : s ≥ b+ 1,l(s)
s2≤ 1
j}, for j = 1, 2, 3, · · · .
When εt is a random variable from the DAN, then l(u) is a slowly varying function ap-
proaching a constant or infinity as u tends to infinity. It can be shown that T l(ηT ) ≤ η2T for
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all T ≥ 1 and η2T ≈ T l(ηT ) for large T . In addition, for each T we let ε(1)t = εtI{|εt| ≤ ηT } − E(εtI{|εt| ≤ ηT })
ε(2)t = εtI{|εt| > ηT } − E(εtI{|εt| > ηT })
(A.1)
for t = 1, · · · , T . This is a well-known truncation technique for dealing with the weak conver-
gence of the random variables from the DAN with zero mean and possible infinite variance.
Huang et al. (2014) successfully extended the results in Phillips and Magdalinos (2007a) to
the DAN case by applying this truncation technique.
The following two lemmas are needed in the proof of Theorem 1.1.
Lemma A.1 Let {yt} be generated according to Model (1.1), where β1 = β1T = 1 − c/kT
for a positive constant c. Then under assumptions C1-C4, the following results hold jointly:
(a) 1√TkT l(ηT )
∑[τ0T ]t=1 yt−1εt ⇒ N(0, τ02c),
(b) 1TkT l(ηT )
∑[τ0T ]t=1 y2t−1
p→ τ02c ,
(c)y[rT ]√kT l(ηT )
⇒∫∞0 exp (−cs)dW (s) for any 0 < r ≤ τ0.
Proof. The proofs of (a) and (b) can be completed by following the proof of Theorem
3.2 in Phillips and Magdalinos (2007a) and by using the truncation technique as shown in
(A.1). The details are omitted. To prove part (c), it suffices to note that
y[rT ]√kT l(ηT )
=1√
kT l(ηT )
((1− c
kT)[rT ]y0 +
[rT ]−1∑i=0
(1− c
kT)iε[rT ]−i
)
=
[rT ]−1∑i=0
((1− c
kT)kT)i/kT ε[rT ]−i√
kT l(ηT )+ op(1)
⇒∫ ∞
0exp (−cs)dW (s)
by Theorem 1 in Csorgo et al. (2003), (3.4) in Gine et al. (1997) and assumptions C2 and
C3.
Q.E.D. �
Remark A.1 Part (c) can be written equivalently as follows: for any 0 < r ≤ τ0
y[rT ]√kT l(ηT )
⇒ N(0,1
2c). (A.2)
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One can employ the Lindeberg-Feller central limit theorem to prove (A.2). Using Lemma 1
in Csorgo et al. (2003) and assumptions C2 and C3, one can show that
y[rT ]√kT l(ηT )
=1√
kT l(ηT )
[rT ]∑t=1
β[rT ]−t1T εt + op(1)
=1√
kT l(ηT )
[rT ]∑t=1
β[rT ]−t1T ε
(1)t · (1 + op(1)) + op(1).
Moreover, as E(εt) = 0, we have
|E(εtI{|εt| ≤ ηT })| = |E(εtI{|εt| > ηT })| = o(l(ηT )/ηT ) (A.3)
by Lemma 1 in Csorgo et al. (2003). As a result, we have
V ar
(1√
kT l(ηT )
[rT ]∑t=1
β[rT ]−t1T ε
(1)t
)
=1
kT
[rT ]∑t=1
β2([rT ]−t)1T · (1 + o(1))
=1
kT (1− β21T )
· (1 + o(1))
=1
2c· (1 + o(1))
since V ar(ε(1)t ) = E(ε
(1)t )2 = E(ε2t I{|εt| ≤ ηT })− (E(εtI{|εt| ≤ ηT }))2 = l(ηT )(1 + o(1)) by
(A.3) and recalling η2T ≈ T l(ηT ) for large T .
To prove (A.2), it suffices to verify the Lindeberg-Feller condition. For any δ > 0, we
have
[rT ]∑t=1
E
(β[rT ]−t1 ε
(1)t√
kT l(ηT )
)2
I
{∣∣∣β[rT ]−t1 ε
(1)t√
kT l(ηT )
∣∣∣ > δ
}
≤ max1≤t≤[rT ]
E
(ε(1)t√l(ηT )
)2
I
{∣∣∣β[rT ]−t1 ε
(1)t√
l(ηT )
∣∣∣ > δ√
kT
}· 1
kT
[rT ]∑t=1
β2([rT ]−t)1
≤ max1≤t≤[rT ]
E
(ε(1)t√l(ηT )
)2
I
{∣∣∣ ε(1)t√l(ηT )
∣∣∣ > δ√
kT
}· 1
2c· (1 + o(1))
= o(1)
since the variance of ε(1)1 /√
l(ηT ) exists and kT → ∞. Hence, (A.2) is proved.
Another approach to proving (A.2) is applying Ito isometry theorem to show that∫∞0 exp (−cs)dW (s)
and N(0, 12c) are identical in distribution. To this purpose, it suffices to show that the vari-
ance of∫∞0 exp (−cs)dW (s) is 1
2c . Applying Ito isometry theorem, one has
V ar
(∫ ∞
0exp (−cs)dW (s)
)= E
(∫ ∞
0exp (−cs)dW (s)
)2
=
∫ ∞
0e−2csds =
1
2c.
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Lemma A.2 Let {yt} be generated according to Model (1.1), where β1 = β1T = 1 − c/kT
for a positive constant c and β2 = 1. Then under assumptions C1-C4, the following results
hold jointly:
(a) 1T l(ηT )
∑Tt=[τ0T ]+1 yt−1εt ⇒ 1
2(W (1)−W (τ0))2 − 1
2(1− τ0),
(b) 1T 2l(ηT )
∑Tt=[τ0T ]+1 y
2t−1 ⇒
∫ 1τ0(W (s)−W (τ0))
2ds.
Proof. To prove part (a), note that
yt−1εt =1
2(y2t − y2t−1 − ε2t ), t = [τ0T ] + 1, · · · , T,
which implies that
1
T l(ηT )
T∑t=[τ0T ]+1
yt−1εt =1
2T l(ηT )
(y2T − y2[τ0T ] −
T∑t=[τ0T ]+1
ε2t
). (A.4)
Note also thaty[τ0T ]√T l(ηT )
= op(1) (A.5)
by part (c) of Lemma A.1. Denote
ST (τ0, s) :=1√
T l(ηT )
[sT ]∑t=[τ0T ]+1
εt.
Then
ST (τ0, s) ⇒ W (s)−W (τ0) (A.6)
for any τ0 ≤ s ≤ 1 by the functional central limit theorem for the i.i.d. random variables
from the DAN (see Theorem 1 in Csorgo et al. (2003) and (3.4) in Gine et al. (1997)).
Combining this result with (A.5) immediately leads to
y2T − y2[τ0T ]
2T l(ηT )=
(y[τ0T ] +∑T
i=[τ0T ]+1 εi)2 − y2[τ0T ]
2T l(ηT )⇒ 1
2(W (1)−W (τ0))
2. (A.7)
In addition, it is trivial that ∑Tt=[τ0T ]+1 ε
2t
2T l(ηT )
p→ 1− τ02
(A.8)
when ε′ts are i.i.d. in the DAN. Now, it follows from (A.4), (A.7) and (A.8) that part (a)
holds.
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To prove part (b), using (A.5) and (A.6), we have
1
T 2l(ηT )
T∑t=[τ0T ]+1
y2t−1
=1
T 2l(ηT )
T∑t=[τ0T ]+1
(y[τ0T ] +
t−1∑i=[τ0T ]+1
εi
)2=
1
T
T∑t=[τ0T ]+1
( y[τ0T ]√T l(ηT )
+ ST (τ0,t− 1
T))2
=
T∑t=[τ0T ]+1
∫ tT
t−1T
( y[τ0T ]√T l(ηT )
+ ST (τ0,t− 1
T))2
ds
=
T∑t=[τ0T ]+1
∫ tT
t−1T
( y[τ0T ]√T l(ηT )
+ ST (τ0, s))2
ds · (1 + op(1))
=
∫ 1
τ0
( y[τ0T ]√T l(ηT )
+ ST (τ0, s))2
ds · (1 + op(1))
⇒∫ 1
τ0
(W (s)−W (τ0))2ds. (A.9)
Finally, since part (a) and part (b) hold jointly, this completes our proof.
Q.E.D. �
Proof of Theorem 1.1. To derive the limiting distribution of τT , one can follow Appendix
G in Chong (2001) with the following two main modifications: (1) Let g(T ) = kT /c in
Appendix G in Chong (2001), (2) Replace∫∞0 exp(−s)dW1(s) by
√c∫∞0 exp (−cs)dW1(s),
which is the limiting distribution of y[τ0T ]−t−1/√
g(T )l(ηT ) for 0 ≤ t ≤ [|ν|g(T )]− 1 (where
ν is a constant) by noting that
y[τ0T ]−t−1√g(T )l(ηT )
=1√
g(T )l(ηT )
((1− c
kT)[τ0T ]−t−1y0 +
[τ0T ]−t−2∑i=0
(1− c
kT)iε[τ0T ]−t−1−i
)
=√c ·
[τ0T ]−t−2∑i=0
((1− c
kT)kT)i/kT ε[τ0T ]−t−1−i√
kT l(ηT )+ op(1)
⇒√c
∫ ∞
0exp(−cs)dW1(s) = Bc(
1
2).
Moreover, it is worth mentioning that (1.2) is a special case of the limiting distribution of
τT in Theorem 3 in Chong (2001) when the moment conditions E(y20) < ∞ and E(ε4t ) < ∞
in his paper are satisfied and c = 1. To relax these moment conditions, we only need to
apply the truncation technique (A.1). The details are omitted for brevity.
To find the limiting distribution of β1(τT ), note that |τT − τ0| = Op(kT /T ), the limit-
ing distribution in Lemma A.1(c) is irrespective of the constant r and it suffices to study
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the magnitude of∑[τ0T ]
t=[τ0T−kT ]+1 y2t−1 in order to obtain the magnitude of
∑[τ0T ]t=[τTT ]+1 y
2t−1.
Therefore, when τT ≤ τ0, Lemma A.1(c) implies that
[τ0T ]∑t=[τ0T−kT ]+1
y2t−1 = Op(kT l(ηT )) · kT = Op(k2T l(ηT )), (A.10)
yielding[τ0T ]∑
t=[τTT ]+1
y2t−1 = Op(k2T l(ηT )). (A.11)
In addition, to obtain the magnitude of∑[τ0T ]
t=[τTT ]+1 yt−1εt, it suffices to study the magnitude
of∑[τ0T ]
t=[τ0T−kT ] yt−1εt. By squaring yt = β1T yt−1 + εt and summing over t ∈ {[τ0T − kT ] +
1, · · · , [τ0T ]} we obtain
[τ0T ]∑t=[τ0T−kT ]+1
yt−1εt =1− β2
1T
2β1T
[τ0T ]∑t=[τ0T−kT ]+1
y2t−1 −β1T2
(y2[τ0T−kT ] − y2[τ0T ])
− 1
2β1T
[τ0T ]∑t=[τ0T−kT ]+1
ε2t . (A.12)
It follows from (A.10) and Lemma A.1(c) respectively that
1− β21T
2β1T
[τ0T ]∑t=[τ0T−kT ]+1
y2t−1 = Op(kT l(ηT )), (A.13)
β1T2
(y2[τ0T−kT ] − y2[τ0T ]) =β1T2
(y[τ0T−kT ] − y[τ0T ])(y[τ0T−kT ] + y[τ0T ]) = Op(kT l(ηT )).
(A.14)
Moreover, by applying the Law of Large Numbers, we have
1
2β1T
[τ0T ]∑t=[τ0T−kT ]+1
ε2t = Op(kT l(ηT )). (A.15)
Combining (A.12)-(A.15) leads to
[τ0T ]∑t=[τ0T−kT ]+1
yt−1εt = Op(kT l(ηT )),
yielding[τ0T ]∑
t=[τTT ]+1
yt−1εt = Op(kT l(ηT )). (A.16)
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Similarly, if τT > τ0, we have
[τ0T+kT ]∑t=[τ0T ]+1
y2t−1 =
[τ0T+kT ]∑t=[τ0T ]+1
(y[τ0T ] +
t−1−[τ0T ]∑i=1
ε[τ0T ]+i
)2
≤ 2
[τ0T+kT ]∑t=[τ0T ]+1
y2[τ0T ] + 2
[τ0T+kT ]∑t=[τ0T ]+1
( t−1−[τ0T ]∑i=1
ε[τ0T ]+i
)2= Op(k
2T l(ηT )) +Op(k
2T l(ηT ))
= Op(k2T l(ηT )),
leading to[τTT ]∑
t=[τ0T ]+1
y2t−1 = Op(k2T l(ηT )). (A.17)
In addition, by squaring yt = yt−1+ εt and summing over t ∈ {[τ0T ] + 1, · · · , [τ0T + kT ]} we
obtain
[τ0T+kT ]∑t=[τ0T ]+1
yt−1εt =1
2
(y2[τ0T+kT ] − y2[τ0T ]
)− 1
2
[τ0T+kT ]∑t=[τ0T ]+1
ε2t
=1
2
2y[τ0T ]
[τ0T+kT ]∑t=[τ0T ]+1
εt +( [τ0T+kT ]∑
t=[τ0T ]+1
εt
)2− 1
2
[τ0T+kT ]∑t=[τ0T ]+1
ε2t .
Similarly to the derivation of (A.16), we have
[τTT ]∑t=[τ0T ]+1
yt−1εt = Op(kT l(ηT )). (A.18)
Suppose kT = o(T ), applying (A.11), (A.16), (A.17), (A.18) and Lemma A.1 and following
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Appendix G in Chong (2001), we have
√TkT (β1(τT )− β1(τ0))
=√
TkT
(∑[τTT ]t=1 ytyt−1∑[τTT ]
t=1 y2t−∑[τ0T ]
t=1 ytyt−1∑[τ0T ]t=1 y2t
)
= I{τT ≤ τ0}√
TkT
(∑[τ0T ]t=[τTT ]+1 y
2t−1∑[τTT ]
t=1 y2t−1
∑[τ0T ]t=1 yt−1εt∑[τ0T ]t=1 y2t−1
−∑[τ0T ]
t=[τTT ]+1 yt−1εt∑[τTT ]t=1 y2t−1
)
+I{τT > τ0}√
TkT
(−∑[τTT ]
t=[τ0T ]+1 y2t−1∑[τTT ]
t=1 y2t−1
∑[τ0T ]t=1 yt−1εt∑[τ0T ]t=1 y2t−1
+
∑[τTT ]t=[τ0T ]+1 yt−1εt∑[τTT ]
t=1 y2t−1
+ (β2 − β1T )
∑[τTT ]t=[τ0T ]+1 y
2t−1∑[τTT ]
t=1 y2t−1
)= I{τT ≤ τ0}
√TkT
(Op(
k2T l(ηT )
TkT l(ηT ))Op(
1√TkT
) +Op(kT l(ηT )
TkT l(ηT )))
+I{τT > τ0}√
TkT
(Op(
k2T l(ηT )
TkT l(ηT ))Op(
1√TkT
) +Op(kT l(ηT )
TkT l(ηT )) +Op(
k2T l(ηT )
Tk2T l(ηT )))
= op(1).
Thus, β1(τT ) and β1(τ0) have the same asymptotic distribution. Applying Lemma A.1, we
have √TkT (β1(τ0)− β1) =
1√TkT l(ηT )
∑[τ0T ]t=1 yt−1εt
1TkT l(ηT )
∑[τ0T ]t=1 y2t−1
⇒ N(0,2c
τ0),
which immediately implies that
√TkT (β1(τT )− β1) ⇒ N(0,
2c
τ0).
The above result is equivalent to (1.3) by the fact 1− β21T = 2c/kT (1 + o(1)).
To find the limiting distribution of β2(τT ), suppose kT = o(T ), applying (A.11), (A.16),
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(A.17), (A.18) and Lemma A.2 and following Appendix G in Chong (2001), we have
T (β2(τT )− β2(τ0))
= T
(∑Tt=[τTT ]+1 ytyt−1∑T
t=[τTT ]+1 y2t
−∑T
t=[τ0T ]+1 ytyt−1∑Tt=[τ0T ]+1 y
2t
)
= I{τT ≤ τ0}T(−∑[τ0T ]
t=[τTT ]+1 y2t−1∑T
t=[τTT ]+1 y2t−1
∑Tt=[τ0T ]+1 yt−1εt∑Tt=[τ0T ]+1 y
2t−1
+
∑[τ0T ]t=[τTT ]+1 yt−1εt∑Tt=[τTT ]+1 y
2t−1
+ (β1T − β2)
∑[τ0T ]t=[τTT ]+1 y
2t−1∑T
t=[τTT ]+1 y2t−1
)
+I{τT > τ0}T(∑[τTT ]
t=[τ0T ]+1 y2t−1∑T
t=[τTT ]+1 y2t−1
∑Tt=[τ0T ]+1 yt−1εt∑Tt=[τ0T ]+1 y
2t−1
−∑[τTT ]
t=[τ0T ]+1 yt−1εt∑Tt=[τTT ]+1 y
2t−1
)= I{τT ≤ τ0}T
(Op(
k2T l(ηT )
T 2l(ηT ))Op(
1
T) +Op(
kT l(ηT )
T 2l(ηT )) +Op(
k2T l(ηT )
kTT 2l(ηT )))
+I{τT > τ0}T(Op(
k2T l(ηT )
T 2l(ηT ))Op(
1
T) +Op(
kT l(ηT )
T 2l(ηT )))
= op(1).
Thus, β2(τT ) and β2(τ0) also have the same asymptotic distribution. Applying Lemma A.2,
we have
T (β2(τ0)− β2) =
1T l(ηT )
∑Tt=[τ0T ]+1 yt−1εt
1T 2l(ηT )
∑Tt=[τ0T ]+1 y
2t−1
⇒ (W (1)−W (τ0))2 − (1− τ0)
2∫ 1τ0(W (s)−W (τ0))2ds
,
which immediately implies that
T (β2(τT )− β2) ⇒(W (1)−W (τ0))
2 − (1− τ0)
2∫ 1τ0(W (s)−W (τ0))2ds
.
It is trivial that
(W (1)−W (τ0))2 − (1− τ0)
2∫ 1τ0(W (s)−W (τ0))2ds
d=
W2(1)− 1
2(1− τ0)∫ 10 W
2(s)ds
by the facts
{W (s)−W (τ0), τ0 < s ≤ 1} d= {W (s− τ0), τ0 < s ≤ 1}
and {W (s− τ0)√1− τ0
, τ0 < s ≤ 1}
d={W (
s− τ01− τ0
), τ0 < s ≤ 1}
and applying the change of variables. Hence, (1.4) holds.
Q.E.D. �
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Appendix B: Proof of Theorem 1.2
The following three lemmas are used in the proof of Theorem 1.2.
Lemma B.1 Let {yt} be generated by Model (1.1) with β1 = 1. Then under the assumptions
C1-C4, the following results hold jointly:
(a) 1T l(ηT )
∑[τ0T ]t=1 yt−1εt ⇒ 1
2(W2(τ0)− τ0),
(b) 1T 2l(ηT )
∑[τ0T ]t=1 y2t−1 ⇒
∫ τ00 W 2(s)ds.
Proof. This lemma can easily be proved by using the standard arguments in the unit root
model with finite variance and by applying the truncation technique (A.1). The details are
omitted.
Q.E.D. �
Lemma B.2 Let β2 = β2T = 1− c/kT with c > 0. Then under the assumptions C1-C4, we
have, for any τ0 < s ≤ 1
1√kT l(ηT )
[sT ]∑t=[τ0T ]+1
β[sT ]−t2T εt ⇒ N(0,
1
2c).
Proof. The proof can be completed by following the proof of part (c) of Lemma A.1 or
Remark A.1. The details are therefore omitted.
Q.E.D. �
Lemma B.3 Let {yt} be generated by Model (1.1), where β1 = 1 and β2 = β2T = 1− c/kT
with c > 0. Then, under the assumptions C1-C4, the following results hold jointly:
(a) 1√TkT l(ηT )
∑Tt=[τ0T ]+1 yt−1εt ⇒ W ( 1
2c),
(b) 1TkT l(ηT )
∑Tt=[τ0T ]+1 y
2t−1 ⇒ 1
2c(W2(τ0) + 1− τ0).
Proof. To prove part (a), note that the following decomposition holds,
1√TkT l(ηT )
T∑t=[τ0T ]+1
yt−1εt
=1√
TkT l(ηT )
T∑t=[τ0T ]+1
(βt−[τ0T ]−12T y[τ0T ] +
t−1∑i=[τ0T ]+1
βt−i−12T εi
)εt
=1√
TkT l(ηT )
((y0 +
[τ0T ]∑j=1
εj
) T∑t=[τ0T ]+1
βt−[τ0T ]−12T εt +
T∑t=[τ0T ]+1
εt
t−1∑i=[τ0T ]+1
βt−i−12T εi
):= I1 + I2, (B.1)
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where
I1 =1√
TkT l(ηT )
(y0 +
[τ0T ]∑j=1
εj
) T∑t=[τ0T ]+1
βt−[τ0T ]−12T εt
=1 + op(1)√TkT l(ηT )
[τ0T ]∑j=1
εj
T∑t=[τ0T ]+1
βt−[τ0T ]−12T εt
=1 + op(1)√TkT l(ηT )
[τ0T ]∑j=1
ε(1)j
T∑t=[τ0T ]+1
βt−[τ0T ]−12T ε
(1)t
and
I2 =1√
TkT l(ηT )
T∑t=[τ0T ]+1
εt
t−1∑i=[τ0T ]+1
βt−i−12T εi
=1 + op(1)√TkT l(ηT )
T∑t=[τ0T ]+1
ε(1)t
t−1∑i=[τ0T ]+1
βt−i−12T ε
(1)i
by assumptions C1-C3 and Lemma 1 in Csorgo et al. (2003).
Consider the term I1. It is obvious that{ε(1)j√l(ηT )
T∑t=[τ0T ]+1
βt−[τ0T ]−12T
ε(1)t√l(ηT )
}[τ0T ]
j=1
(B.2)
is a sequence of martingale difference with respect to the filtration Fj = σ(ε1, · · · , εj) with
E( ε
(1)j√l(ηT )
T∑t=[τ0T ]+1
βt−[τ0T ]−12T
ε(1)t√l(ηT )
|Fj−1
)= 0
and
1
TkT
[τ0T ]∑j=1
E(( ε
(1)j√l(ηT )
T∑t=[τ0T ]+1
βt−[τ0T ]−12T
ε(1)t√l(ηT )
)2|Fj−1
)=
τ02c
· (1 + o(1)).
Then, applying the central limit theorem for martingale difference sequences, we have
I1 ⇒ N(0,τ02c
). (B.3)
Analogously, for I2, {ε(1)t√l(ηT )
t−1∑i=[τ0T ]+1
βt−i−12T
ε(1)i√l(ηT )
}T
t=[τ0T ]+1
(B.4)
is a sequence of martingale difference with respect to the filtration Ft = σ(ε[τ0T ], · · · , εt)
with
E( ε
(1)t√l(ηT )
t−1∑i=[τ0T ]+1
βt−i−12T
ε(1)i√l(ηT )
|Ft−1
)= 0
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and
1
TkT
T∑t=[τ0T ]+1
E(( ε
(1)t√l(ηT )
t−1∑i=[τ0T ]+1
βt−i−12T
ε(1)i√l(ηT )
)2|Ft−1
)p→ 1− τ0
2c· (1 + o(1)).
Hence, applying the central limit theorem for martingale difference sequences leads to
I2 ⇒ N(0,1− τ02c
). (B.5)
Note that the two martingale difference sequences (B.2) and (B.4) are independent. The
proof for part (a) is completed by combining (B.1), (B.3) and (B.5).
To prove part (b), by squaring yt = (1− c/kT )yt−1 + εt and summing over t ∈ {[τ0T ] +
1, · · · , T}, we obtain
T∑t=[τ0T ]+1
y2t = (1− c
kT)2
T∑t=[τ0T ]+1
y2t−1 +
T∑t=[τ0T ]+1
ε2t + 2(1− c
kT)
T∑t=[τ0T ]+1
yt−1εt.
This implies that
(2c
kT− c2
k2T)
T∑t=[τ0T ]+1
y2t−1 = y2[τ0T ] − y2T +
T∑t=[τ0T ]+1
ε2t + 2(1− c
kT)
T∑t=[τ0T ]+1
yt−1εt. (B.6)
Note thaty[τ0T ]√T l(ηT )
⇒ W (τ0) (B.7)
since β1 = 1, it follows from Lemma B.2 and assumption C2 that
yT√T l(ηT )
=βT−[τ0T ]2T y[τ0T ] +
∑Ti=[τ0T ]+1 β
T−i2T εi√
T l(ηT )= op(1). (B.8)
In addition,
2(1− c
kT)
T∑t=[τ0T ]+1
yt−1εt = op(T l(ηT )) (B.9)
by part (a). Then, combining (B.6)-(B.9) and (A.8) together yields
1
TkT l(ηT )
T∑t=[τ0T ]+1
y2t−1 ⇒1
2c(W 2(τ0) + 1− τ0).
Note that the random part (i.e.,W 2(τ0)) of the limiting distribution of 1TkT l(ηT )
∑Tt=[τ0T ]+1 y
2t−1
is due to the limiting behavior of (∑[τ0T ]
i=1 εi)2, while the limiting distribution of 1√
TkT l(ηT )
∑Tt=[τ0T ]+1 yt−1εt
is determined by the limiting behavior of
[τ0T ]∑j=1
εj
T∑t=[τ0T ]+1
βt−[τ0T ]−12T εt and
T∑t=[τ0T ]+1
εt
t−1∑i=[τ0T ]+1
βt−i−12T εi.
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Note also that∑[τ0T ]
i=1 εi and∑T
t=[τ0T ]+1 εt∑t−1
i=[τ0T ]+1 βt−i−12T εi are independent of each other,
and∑[τ0T ]
i=1 εi and∑[τ0T ]
j=1 εj∑T
t=[τ0T ]+1 βt−[τ0T ]−12T εt are uncorrelated. Hence, the two limiting
distributions in part (a) and part (b) are independent. Therefore, part (a) and part (b) hold
jointly.
Q.E.D. �
Lemma B.4 Let {yt} be generated according to Model (1.1), where β1 = 1 and β2 = β2T =
1 − c/kT with c > 0. Then under assumptions C1-C4 with kT = o(√T ), we have for any
fixed integer m ≥ 0,
(a)k2T
T l(ηT )
(RSST (τ0 − m
T )−RSST (τ0))⇒ c2mW 2(τ0),
(b)k2T
T l(ηT )
(RSST (τ0 +
mT )−RSST (τ0)
)⇒ c2mW 2(τ0).
Proof. To prove part (a), from equation (B.2) in Chong (2001), we have
RSST (τ0 −m
T)−RSST (τ0)
= 2(β2T − β1)
(∑[τ0T ]t=[τ0T ]−m+1 y
2t−1
∑Tt=[τ0T ]+1 yt−1εt∑T
t=[τ0T ]−m+1 y2t−1
−∑T
t=[τ0T ]+1 y2t−1
∑[τ0T ]t=[τ0T ]−m+1 yt−1εt∑T
t=[τ0T ]−m+1 y2t−1
)
+ (β2T − β1)2
∑Tt=[τ0T ]+1 y
2t−1
∑[τ0T ]t=[τ0T ]−m+1 y
2t−1∑T
t=[τ0T ]−m+1 y2t−1
+ ΛT (τ0 −m
T)
where
ΛT (τ0 −m
T)
=
(∑[τ0T ]t=1 yt−1εt
)2∑[τ0T ]
t=1 y2t−1
−
(∑[τ0T ]−mt=1 yt−1εt
)2∑[τ0T ]−m
t=1 y2t−1
+
(∑Tt=[τ0T ]+1 yt−1εt
)2∑T
t=[τ0T ]+1 y2t−1
−
(∑Tt=[τ0T ]−m+1 yt−1εt
)2∑T
t=[τ0T ]−m+1 y2t−1
.
Obviously, ΛT (τ0 − mT ) = Op(l(ηT )). Then it follows that
k2TT l(ηT )
(RSST (τ0 −
m
T)−RSST (τ0)
)=
k2TT l(ηT )
·(− 2c
kT
)·(
Op(T l(ηT ))Op(√TkT l(ηT ))
Op(T l(ηT )) +Op(TkT l(ηT ))+
Op(TkT l(ηT ))Op(√T l(ηT ))
Op(T l(ηT )) +Op(TkT l(ηT ))
)
+k2T
T l(ηT )· c
2
k2T· Op(TkT l(ηT ))
Op(T l(ηT )) +Op(TkT l(ηT ))
[τ0T ]∑[τ0T ]−m+1
y2t−1 + op(1)
=c2(1 + op(1))
T l(ηT )
[τ0T ]∑[τ0T ]−m+1
y2t−1 + op(1)
⇒ c2mW 2(τ0)
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by Lemma B.3, kT = o(√T ) and the observation∣∣∣∣∣∣
[τ0T ]∑t=[τ0T ]−m+1
yt−1εt
∣∣∣∣∣∣ ≤√√√√√ [τ0T ]∑
t=[τ0T ]−m+1
ε2t ·
√√√√ T∑t=[τ0T ]−m+1
y2t−1 = Op(√T l(ηT )).
To prove part (b), from equation (B.4) in Chong (2001), we have
RSST (τ0 +m
T)−RSST (τ0)
= 2(β2T − β1)
(∑[τ0T ]t=1 y2t−1
∑[τ0T ]+mt=[τ0T ]+1 yt−1εt∑[τ0T ]+m
t=1 y2t−1
−∑[τ0T ]+m
t=[τ0T ]+1 y2t−1
∑[τ0T ]t=1 yt−1εt∑[τ0T ]+m
t=1 y2t−1
)
+ (β2T − β1)2
∑[τ0T ]+mt=[τ0T ]+1 y
2t−1
∑[τ0T ]t=1 y2t−1∑[τ0T ]+m
t=1 y2t−1
+ ΛT (τ0 +m
T)
where
ΛT (τ0 +m
T)
=
(∑[τ0T ]t=1 yt−1εt
)2∑[τ0T ]
t=1 y2t−1
−
(∑[τ0T ]+mt=1 yt−1εt
)2∑[τ0T ]+m
t=1 y2t−1
+
(∑Tt=[τ0T ]+1 yt−1εt
)2∑T
t=[τ0T ]+1 y2t−1
−
(∑Tt=[τ0T ]+m+1 yt−1εt
)2∑T
t=[τ0T ]+m+1 y2t−1
.
Since ΛT (τ0 +mT ) = Op(l(ηT )) and∣∣∣∣∣∣
[τ0T ]+m∑t=[τ0T ]+1
yt−1εt
∣∣∣∣∣∣ ≤√√√√√ [τ0T ]+m∑
t=[τ0T ]+1
ε2t ·
√√√√√ [τ0T ]+m∑t=[τ0T ]+1
y2t−1 = Op(√T l(ηT )),
we have
k2TT l(ηT )
(RSST (τ0 +
m
T)−RSST (τ0)
)=
k2TT l(ηT )
·(− 2c
kT
)·(
Op(T2l(ηT ))Op(
√T l(ηT ))
Op(T 2l(ηT )) +Op(T l(ηT ))+
Op(T l(ηT ))Op(T l(ηT ))
Op(T 2l(ηT )) +Op(T l(ηT ))
)
+k2T
T l(ηT )· c
2
k2T· Op(T
2l(ηT ))
Op(T 2l(ηT )) +Op(T l(ηT ))
[τ0T ]+m∑t=[τ0T ]+1
y2t−1 + op(1)
=c2(1 + op(1))
T l(ηT )
[τ0T ]+m∑t=[τ0T ]+1
y2t−1 + op(1)
⇒ c2mW 2(τ0)
by Lemma B.1 and kT = o(√T ).
Q.E.D. �
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Proof of Theorem 1.2. To derive the first and second parts of Theorem 1.2(a), i.e., to
prove P (k = k0) → 0 when kT = o(√T ) and |k − k0| = Op(1) when kT ≍
√T , we prove
|τT − τ0| = Op(1/T ) when kT = O(√T ) (B.10)
first. According to the proof of Theorem 3 in Chong (2001), it is sufficient to show
P (λ2T + 2λTA1 − 2λTA2 −A3 < 0) + P (λ2
T − 2λTA4 + 2λTA5 −A6 < 0) → 0,
where
λT = β2T − β1 = − c
kT,
A1 =
∑Tt=[τ0T ]+1 yt−1εt∑Tt=[τ0T ]+1 y
2t−1
,
A2 = supm∈D1T
∑[τ0T ]t=m+1 yt−1εt∑[τ0T ]t=m+1 y
2t−1
,
A3 = supm∈D1T
∣∣∣ ∑Tt=m+1 y
2t−1∑T
t=[τ0T ]+1 y2t−1
∑[τ0T ]t=m+1 y
2t−1
ΛT (m
T)∣∣∣,
A4 =
∑[τ0T ]t=1 yt−1εt∑[τ0T ]t=1 y2t−1
,
A5 = supm∈D2T
∑mt=[τ0T ]+1 yt−1εt∑mt=[τ0T ]+1 y
2t−1
,
A6 = supm∈D2T
∣∣∣ ∑mt=1 y
2t−1∑m
t=[τ0T ]+1 y2t−1
∑[τ0T ]t=1 y2t−1
ΛT (m
T)∣∣∣,
(B.11)
the definition of ΛT (mT ) can be found in the proof of Lemma B.4 and D1T = {m : m ∈ ZT ,m < [τ0T ]−MT }
D2T = {m : m ∈ ZT ,m > [τ0T ] +MT }
with MT > 0 such that MT → ∞ arbitrary slowly, where ZT denotes the set {0, 1, 2, · · · , T}.
Since λ2T > 0, it suffices to prove that, under the case of kT = O(
√T ),
Ai = op(1/kT ), i = 1, 2, 4, 5 and Aj = op(1/k2T ), j = 3, 6
in order to prove (B.10).
By applying Lemmas B.1 and B.3, it is trivial that A1 = Op(1/√TkT ) = op(1/kT ) and
A4 = Op(1/T ) = op(1/kT ). To find the order of the term A2, note that since β1 = 1, it is
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not difficult to see that
[τ0T ]∑t=m+1
yt−1εt = y0
[τ0T ]∑t=m+1
εt +
[τ0T ]∑t=m+1
(t−1∑i=1
εi
)εt
=
y0
[τ0T ]∑t=m+1
ε(1)t +
[τ0T ]∑t=m+1
(t−1∑i=1
ε(1)i
)ε(1)t
· (1 + op(1))
= op
(√kT ([τ0T ]−m)l(ηT )
)+Op
√√√√ [τ0T ]∑
t=m+1
E
(t−1∑i=1
ε(1)i
)2
l(ηT )
= op
(√kT ([τ0T ]−m)l(ηT )
)+Op
(√([τ0T ]−m)([τ0T ] +m)l(ηT )
)= Op
(√([τ0T ]−m)([τ0T ] +m)l(ηT )
)and
[τ0T ]∑t=m+1
y2t−1 = T ([τ0T ]−m)l(ηT ) ·1
[τ0T ]−m
[τ0T ]∑t=m+1
(yt−1√T l(ηT )
)2
= Op(T ([τ0T ]−m)l(ηT )).
Consequently, we have
A2 = Op
(sup
m∈D1T
√([τ0T ]−m)([τ0T ] +m)
T ([τ0T ]−m)
)≤ Op
(1√TMT
)= op(1/kT ). (B.12)
To find the order of the term A5, note that for any small 0 < δ < 1, there exist two large
constantsN1 = N1(δ) such that βkT /N1
2T → e−c/N1 > 1−δ andN2 = N2(δ) such that βN2kT2T →
e−cN2 < δ. We then divide the set {MT +1, · · · , T − [τ0T ]}, which is the domain of m− [τ0T ]
when m ∈ D2T , into three subsets: {MT + 1, · · · , [kT /N1]}, {[kT /N1] + 1, · · · , [N2kT ]} and
{[N2kT ] + 1, · · · , T − [τ0T ]}. Note that
m∑t=[τ0T ]+1
yt−1εt =m∑
t=[τ0T ]+1
βt−1−[τ0T ]2T y[τ0T ] +
t−1∑i=[τ0T ]+1
βt−1−i2T εi
εt,
y[τ0T ]
m∑t=[τ0T ]+1
βt−1−[τ0T ]2T εt
= Op(√
T l(ηT )) ·Op
(√kT (1− β
2(m−[τ0T ])2T )l(ηT )
)= Op
(√TkT (1− β
2(m−[τ0T ])2T )l(ηT )
)
=
Op
(√T (m− [τ0T ])l(ηT )
), if MT < m− [τ0T ] ≤ [kT /N1]
Op
(√TkT l(ηT )
), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op
(√TkT l(ηT )
), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
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since
(1− (1− c/kT )aT ) = O(aT /kT ) if aT = o(kT )
and
m∑t=[τ0T ]+1
t−1∑i=[τ0T ]+1
βt−1−i2T εi
εt
= Op
√√√√ m∑t=[τ0T ]+1
t−1∑i=[τ0T ]+1
β2(t−1−i)2T l(ηT )
= Op
(√kT (m− [τ0T ])− k2T (1− β
2(m−[τ0T ])2T )l(ηT )
)
=
Op
(√kT (m− [τ0T ])l(ηT )
), if MT < m− [τ0T ] ≤ [kT /N1]
Op (kT l(ηT )) , if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op
(√kT (m− [τ0T ])l(ηT )
), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
We then have
m∑t=[τ0T ]+1
yt−1εt
=
Op
(√T (m− [τ0T ])l(ηT )
), if MT < m− [τ0T ] ≤ [kT /N1]
Op
(√TkT l(ηT )
), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op
(√TkT l(ηT )
), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
. (B.13)
Moreover, we also have
m∑t=[τ0T ]+1
y2t−1
= − 1
1− β22T
(y2m − y2[τ0T ]) +1
1− β22T
m∑t=[τ0T ]+1
ε2t +2β2T
1− β22T
m∑t=[τ0T ]+1
yt−1εt, (B.14)
2β2T1− β2
2T
m∑t=[τ0T ]+1
yt−1εt
=
Op
(kT√T (m− [τ0T ])l(ηT )
), if MT < m− [τ0T ] ≤ [kT /N1]
Op
(√Tk
3/2T l(ηT )
), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op
(√Tk
3/2T l(ηT )
), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
(B.15)
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by (B.13),
1
1− β22T
m∑t=[τ0T ]+1
ε2t
= Op (kT (m− [τ0T ])l(ηT ))
=
Op (kT (m− [τ0T ])l(ηT )) , if MT < m− [τ0T ] ≤ [kT /N1]
Op
(k2T l(ηT )
), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op (kT (m− [τ0T ])l(ηT )) , if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
(B.16)
and
− 1
1− β22T
(y2m − y2[τ0T ])
= − 1
1− β22T
(ym + y[τ0T ])(ym − y[τ0T ])
= − 1
1− β22T
m∑i=[τ0T ]+1
βm−i2T εi +
(βm−[τ0T ]2T + 1
)y[τ0T ]
·
m∑i=[τ0T ]+1
βm−i2T εi +
(βm−[τ0T ]2T − 1
)y[τ0T ]
= kT ·
(Op
(√kT (1− β
2(m−[τ0T ])2T )l(ηT )
)+Op(
√T l(ηT ))
)·(Op
(√kT (1− β
2(m−[τ0T ])2T )l(ηT )
)+Op
((1− β
m−[τ0T ]2T )
√T l(ηT )
))= Op(kT
√T l(ηT )) ·
(Op
(√kT (1− β
2(m−[τ0T ])2T )l(ηT )
)+Op
((1− β
m−[τ0T ]2T )
√T l(ηT )
))
=
Op(kT
√T l(ηT )) ·Op
(m−[τ0T ]
kT
√T l(ηT )
), if MT < m− [τ0T ] ≤ [kT /N1]
Op(kT√
T l(ηT )) ·Op(√T l(ηT )), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op(kT√
T l(ηT )) ·Op(√T l(ηT )), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
=
Op (T (m− [τ0T ])l(ηT )) , if MT < m− [τ0T ] ≤ [kT /N1]
Op(TkT l(ηT )), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op(TkT l(ηT )), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
. (B.17)
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Combining (B.14)-(B.17), we have
m∑t=[τ0T ]+1
y2t−1
=
Op
(max
{kT√
T (m− [τ0T ])l(ηT ), T (m− [τ0T ])l(ηT )})
,
if MT < m− [τ0T ] ≤ [kT /N1]
Op(TkT l(ηT )), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op (max {kT (m− [τ0T ])l(ηT ), TkT l(ηT )}) , if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
=
Op (T (m− [τ0T ])l(ηT )) , if MT < m− [τ0T ] ≤ [kT /N1]
Op(TkT l(ηT )), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op(TkT l(ηT )), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
.
(B.18)
Hence, it follows from (B.13) and (B.18) that, when MT < m− [τ0T ] ≤ [kT /N1], we have∑mt=[τ0T ]+1 yt−1εt∑mt=[τ0T ]+1 y
2t−1
= Op
(√T (m− [τ0T ])l(ηT )
T (m− [τ0T ])l(ηT )
)≤ Op
(1√TMT
)= op(1/kT )
since kT = O(√T ) and MT → ∞. When [kT /N1] < m − [τ0T ] ≤ [N2kT ] or [N2kT ] <
m− [τ0T ] ≤ T − [τ0T ], we have∑mt=[τ0T ]+1 yt−1εt∑mt=[τ0T ]+1 y
2t−1
= Op
(√TkT l(ηT )
TkT l(ηT )
)= op(1/kT ).
Using the above arguments, we have
A5 = supm∈D2T
∑mt=[τ0T ]+1 yt−1εt∑mt=[τ0T ]+1 y
2t−1
= op(1/kT ).
Note also that
A3 = supm∈D1T
∣∣∣ ∑Tt=m+1 y
2t−1∑T
t=[τ0T ]+1 y2t−1
∑[τ0T ]t=m+1 y
2t−1
ΛT (m
T)∣∣∣
≤(
1∑Tt=[τ0T ]+1 y
2t−1
+1∑[τ0T ]
t=[τ0T ]−MTy2t−1
)(sup
m∈D1T
∣∣∣(∑[τ0T ]t=1 yt−1εt)
2∑[τ0T ]t=1 y2t−1
−(∑m
t=1 yt−1εt)2∑m
t=1 y2t−1
∣∣∣+ sup
m∈D1T
∣∣∣(∑Tt=[τ0T ]+1 yt−1εt)
2∑Tt=[τ0T ]+1 y
2t−1
−(∑T
t=m+1 yt−1εt)2∑T
t=m+1 y2t−1
∣∣∣)=
(Op
( 1
TkT l(ηT )
)+Op
( 1
TMT l(ηT )
))·Op(l(ηT ))
= op(1/k2T ),
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and
A6 = supm∈D2T
∣∣∣ ∑mt=1 y
2t−1∑m
t=[τ0T ]+1 y2t−1
∑[τ0T ]t=1 y2t−1
ΛT (m
T)∣∣∣
≤(
1∑[τ0T ]t=1 y2t−1
+1∑[τ0T ]+MT
t=[τ0T ]+1 y2t−1
)(sup
m∈D2T
∣∣∣(∑[τ0T ]t=1 yt−1εt)
2∑[τ0T ]t=1 y2t−1
−(∑m
t=1 yt−1εt)2∑m
t=1 y2t−1
∣∣∣+ sup
m∈D2T
∣∣∣(∑Tt=[τ0T ]+1 yt−1εt)
2∑Tt=[τ0T ]+1 y
2t−1
−(∑T
t=m+1 yt−1εt)2∑T
t=m+1 y2t−1
∣∣∣)≤
(Op(
1
T 2l(ηT )) +Op(
1
TMT l(ηT )))·Op(l(ηT ))
= op(1/k2T ).
Hence, |τT − τ0| = Op(1/T ) when kT = O(√T ) is proved, implying the second part of
Theorem 1.2(a).
To prove the first part of Theorem 1.2(a), i.e., to prove P (k = k0) → 0 when kT = o(√T ),
note that we have proven that |τT − τ0| = Op(1/T ). Thus, for any η > 0, there exists a
positive integer M such that
P (k = k0) = P (|k − k0| > M) + P (|k − k0| ≤ M, k = k0)
≤ η +M∑
m=1
P( k2TT l(ηT )
(RSST (τ0 −
m
T)−RSST (τ0)
)< 0)
+
M∑m=1
P( k2TT l(ηT )
(RSST (τ0 +
m
T)−RSST (τ0)
)< 0).
Applying Lemma B.4 to the above inequality, one immediately has P (k = k0) → 0 due to
the finiteness of M and arbitrariness of η.
We turn to the proof of the third part of Theorem 1.2(a), i.e., the limiting distribution
of τT when√T = o(kT ). We follow Appendix K in Chong (2001) and let g(T ) = k2T /(c
2T ).
Note that (1.5) is a special case of the limiting distribution of τT in Theorem 4 in Chong
(2001) when√T = o(kT )
∗, the moment conditions E(y20) < ∞ and E(ε4t ) < ∞ in his
paper are satisfied and c = 1. One can apply the truncation technique (A.1) to weaken the
∗In Theorem 4 in Chong (2001), the condition T 3/4(1 − β2T ) → ∞, that is kT = o(T 3/4) in
our case, is imposed so as to derive the limiting distribution of τT . By checking his proof carefully,
this condition is imposed only for showing that g(T )√T
∑[|v|g(T )]−1t=0
(1√g(T )
∑ti=0 ε[τ0T ]−iε[τ0T ]−t
)1
g(T )=
op(1) when εt’s have finite 4-th moments (see page 153 in Chong (2001)). However, since∑[|v|g(T )]−1t=0
(1√g(T )
∑ti=0 ε[τ0T ]−iε[τ0T ]−t
)1√g(T )
=∑[|v|g(T )]−1
t=0
(1√g(T )
∑t−1i=0 ε[τ0T ]−i
)ε[τ0T ]−t√
g(T )+ Op(1) =
Op(1), the condition√
g(T )T
= o(1) is sufficient to achieve the goal. Note that g(T ) ≍ k2T /T , hence, the
condition kT = o(T ) is sufficient. Therefore, the condition T 3/4(1− β2T ) → ∞ is not needed in Theorem 4
in Chong (2001).
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conditions E(y20) < ∞ and E(ε4t ) < ∞ and accommodate assumptions C1 and C3. The
details are omitted for brevity.
To find the limiting distribution of β1(τT ). Note that we have proven that |τT − τ0| =
op(1/T ) when kT = o(√T ), |τT − τ0| = Op(1/T ) when kT ≍
√T and |τT − τ0| = Op(k
2T /T
2)
when√T = o(kT ), we consider the limiting distribution of β1(τT ) under the above three
cases separately.
Consider the case where√T = o(kT ) first. In this case, note that |τT −τ0| = Op(k
2T /T
2),
then, for τT ≤ τ0, we have
[τ0T ]∑t=[τ0T−k2T /T ]+1
y2t−1 =
[τ0T ]∑t=[τ0T−k2T /T ]+1
(y[τ0T ] −
[τ0T ]∑i=t
εi
)2
=
[τ0T ]∑t=[τ0T−k2T /T ]+1
y2[τ0T ] · (1 + op(1))
= Op(k2T l(ηT )), (B.19)
implying[τ0T ]∑
t=[τTT ]+1
y2t−1 = Op(k2T l(ηT )). (B.20)
In addition, squaring yt = yt−1+ εt and sum over t ∈ {[τ0T −k2T /T ]+1, · · · , [τ0T ]}, we have
[τ0T ]∑t=[τ0T−k2T /T ]+1
yt−1εt
=1
2
y2[τ0T ] − y2[τ0T−k2T /T ] −[τ0T ]∑
t=[τ0T−k2T /T ]+1
ε2t
=
1
2
(y[τ0T ] + y[τ0T−k2T /T ]
)(y[τ0T ] − y[τ0T−k2T /T ]
)− 1
2
[τ0T ]∑t=[τ0T−k2T /T ]+1
ε2t
= Op(√
T l(ηT ))Op(√
k2T l(ηT )/T ) +Op(k2T l(ηT )/T )
= Op(kT l(ηT )).
As a result,[τ0T ]∑
t=[τTT ]+1
yt−1εt = Op(kT l(ηT )). (B.21)
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Similarly, if τT > τ0, it follows from Lemma B.2 that
[τ0T+k2T /T ]∑t=[τ0T ]+1
y2t−1 =
[τ0T+k2T /T ]∑t=[τ0T ]+1
(βt−1−[τ0T ]2T y[τ0T ] +
t−1∑i=[τ0T ]+1
βt−1−i2T εi
)2
=
[τ0T+k2T /T ]∑t=[τ0T ]+1
β2(t−1−[τ0T ])2T y2[τ0T ] · (1 + op(1))
= k2T /T ·Op(T l(ηT ))
= Op(k2T l(ηT )), (B.22)
implying that[τTT ]∑
t=[τ0T ]+1
y2t−1 = Op(k2T l(ηT )). (B.23)
By squaring yt = β2T yt−1 + εt and summing over t ∈ {[τ0T ] + 1, · · · , [τ0T + k2T /T ]}, we
obtain
[τ0T+k2T /T ]∑t=[τ0T ]+1
yt−1εt =1− β2
2T
2β2T
[τ0T+k2T /T ]∑t=[τ0T ]+1
y2t−1 +y2[τ0T+k2T /T ]
− y2[τ0T ]
2β2T− 1
2β2T
[τ0T+k2T /T ]∑t=[τ0T ]+1
ε2t .
(B.24)
First, applying (B.22) immediately yields
1− β22T
2β2T
[τ0T+k2T /T ]∑t=[τ0T ]+1
y2t−1 = Op(kT l(ηT )). (B.25)
Secondly, since√T = o(kT ), we have
1
2β2T
[τ0T+k2T /T ]∑t=[τ0T ]+1
ε2t = Op(k2T l(ηT )/T ). (B.26)
Thirdly, since |β2T | < 1, we have
[k2T /T ]−1∑i=0
β2i2T = O(k2T /T )
which implies that
[k2T /T ]−1∑i=0
βi2T ε[τ0T+k2T /T ]−i = Op(kT
√l(ηT )/
√T ).
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We have
y2[τ0T+k2T /T ] − y2[τ0T ]
=(y[τ0T+k2T /T ] + y[τ0T ]
)(y[τ0T+k2T /T ] − y[τ0T ]
)=
[k2T /T ]−1∑i=0
βi2T ε[τ0T+k2T /T ]−i + (β
[k2T /T ]2T + 1)y[τ0T ]
·
[k2T /T ]−1∑i=0
βi2T ε[τ0T+k2T /T ]−i + (β
[k2T /T ]2T − 1)y[τ0T ]
=
(Op(kT
√l(ηT )/
√T ) +Op(
√T l(ηT ))
)(Op(kT
√l(ηT )/
√T ) +
k2T /T
kTOp(
√T l(ηT )
)= Op(
√T l(ηT ))Op(kT
√l(ηT )/
√T )
= Op(kT l(ηT )). (B.27)
Combining (B.24)-(B.27) together leads to
[τ0T+k2T /T ]∑t=[τ0T ]+1
yt−1εt = Op(kT l(ηT )), (B.28)
yielding[τTT ]∑
t=[τ0T ]+1
yt−1εt = Op(kT l(ηT )). (B.29)
Now, applying (B.20), (B.21), (B.23), (B.29) and Lemma B.1 and following Appendix
G in Chong (2001), we have
T (β1(τT )− β1(τ0))
= T
(∑[τTT ]t=1 ytyt−1∑[τTT ]
t=1 y2t−∑[τ0T ]
t=1 ytyt−1∑[τ0T ]t=1 y2t
)
= I{τT ≤ τ0}T(∑[τ0T ]
t=[τTT ]+1 y2t−1∑[τTT ]
t=1 y2t−1
∑[τ0T ]t=1 yt−1εt∑[τ0T ]t=1 y2t−1
−∑[τ0T ]
t=[τTT ]+1 yt−1εt∑[τTT ]t=1 y2t−1
)
+I{τT > τ0}T(−∑[τTT ]
t=[τ0T ]+1 y2t−1∑[τTT ]
t=1 y2t−1
∑[τ0T ]t=1 yt−1εt∑[τ0T ]t=1 y2t−1
+
∑[τTT ]t=[τ0T ]+1 yt−1εt∑[τTT ]
t=1 y2t−1
+ (β2T − β1)
∑[τTT ]t=[τ0T ]+1 y
2t−1∑[τTT ]
t=1 y2t−1
)= I{τT ≤ τ0}T
(Op(
k2T l(ηT )
T 2l(ηT ))Op(
1
T) +Op(
kT l(ηT )
T 2l(ηT )))
+I{τT > τ0}T(Op(
k2T l(ηT )
T 2l(ηT ))Op(
1
T) +Op(
kT l(ηT )
T 2l(ηT )) +Op(
k2T l(ηT )
kTT 2l(ηT )))
= op(1). (B.30)
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Thus, β1(τT ) and β1(τ0) have the same asymptotic distribution. We then invoke Lemma
B.1 to obtain
T (β1(τ0)− β1) =
1T l(ηT )
∑[τ0T ]t=1 yt−1εt
1T 2l(ηT )
∑[τ0T ]t=1 y2t−1
⇒ W 2(τ0)− τ02∫ τ00 W 2(s)ds
,
which immediately leads to
T (β1(τT )− β1) ⇒W 2(τ0)− τ02∫ τ00 W 2(s)ds
. (B.31)
It is trivial thatW 2(τ0)− τ02∫ τ00 W 2(s)ds
d=
W 2(1)− 1
2τ0∫ 10 W 2(s)ds
by the fact {W (s)√τ0
, 0 < s ≤ τ0
}d={W (
s
τ0), 0 < s ≤ τ0
}and applying the change of variables. Hence, (B.31) is equivalent to (1.6).
Consider the case where kT ≍√T . Note that |τT − τ0| = Op(1/T ) under this situation.
It is trivial that
[τ0T ]∑t=[τTT ]+1
y2t−1 = Op(T l(ηT )),
[τ0T ]∑t=[τTT ]+1
yt−1εt = Op(√T l(ηT )) (B.32)
and[τTT ]∑
t=[τ0T ]+1
y2t−1 = Op(T l(ηT )),
[τTT ]∑t=[τ0T ]+1
yt−1εt = Op(√T l(ηT )). (B.33)
Consequently, similar to (B.30), we have
T (β1(τT )− β1(τ0))
= I{τT ≤ τ0}T(∑[τ0T ]
t=[τTT ]+1 y2t−1∑[τTT ]
t=1 y2t−1
∑[τ0T ]t=1 yt−1εt∑[τ0T ]t=1 y2t−1
−∑[τ0T ]
t=[τTT ]+1 yt−1εt∑[τTT ]t=1 y2t−1
)
+I{τT > τ0}T(−∑[τTT ]
t=[τ0T ]+1 y2t−1∑[τTT ]
t=1 y2t−1
∑[τ0T ]t=1 yt−1εt∑[τ0T ]t=1 y2t−1
+
∑[τTT ]t=[τ0T ]+1 yt−1εt∑[τTT ]
t=1 y2t−1
+ (β2T − β1)
∑[τTT ]t=[τ0T ]+1 y
2t−1∑[τTT ]
t=1 y2t−1
)
= I{τT ≤ τ0}T(Op(
T l(ηT )
T 2l(ηT ))Op(
1
T) +Op(
√T l(ηT )
T 2l(ηT )))
+I{τT > τ0}T(Op(
T l(ηT )
T 2l(ηT ))Op(
1
T) +Op(
√T l(ηT )
T 2l(ηT )) +Op(
T l(ηT )
kTT 2l(ηT )))
= op(1),
which means (B.31) still holds when kT ≍√T .
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Consider the case where kT = o(√T ). Note that we have proven that P (k = k0) → 0
under this situation. Hence, following the proof of Theorem 4 in Chong (2001), one can
show that (B.31) still holds. The details are omitted.
To find the limiting distribution of β2(τT ), we also consider the following three cases
where√T = o(kT ), kT ≍
√T and kT = o(
√T ) separately.
When√T = o(kT ), applying (B.20), (B.21), (B.23) and (B.29) and Lemma B.3 and
following Appendix G in Chong (2001), we have
√TkT (β2(τT )− β2(τ0))
=√
TkT
(∑Tt=[τTT ]+1 ytyt−1∑T
t=[τTT ]+1 y2t
−∑T
t=[τ0T ]+1 ytyt−1∑Tt=[τ0T ]+1 y
2t
)
= I{τT ≤ τ0}√
TkT
(−∑[τ0T ]
t=[τTT ]+1 y2t−1∑T
t=[τTT ]+1 y2t−1
∑Tt=[τ0T ]+1 yt−1εt∑Tt=[τ0T ]+1 y
2t−1
+
∑[τ0T ]t=[τTT ]+1 yt−1εt∑Tt=[τTT ]+1 y
2t−1
+ (β1 − β2T )
∑[τ0T ]t=[τTT ]+1 y
2t−1∑T
t=[τTT ]+1 y2t−1
)
+I{τT > τ0}√TkT
(∑[τTT ]t=[τ0T ]+1 y
2t−1∑T
t=[τTT ]+1 y2t−1
∑Tt=[τ0T ]+1 yt−1εt∑Tt=[τ0T ]+1 y
2t−1
−∑[τTT ]
t=[τ0T ]+1 yt−1εt∑Tt=[τTT ]+1 y
2t−1
)= I{τT ≤ τ0}
√TkT
(Op(
k2T l(ηT )
TkT l(ηT ))Op(
1√TkT
) +Op(kT l(ηT )
TkT l(ηT )) +Op(
k2T l(ηT )
Tk2T l(ηT )))
+I{τT > τ0}√TkT
(Op(
k2T l(ηT )
TkT l(ηT ))Op(
1√TkT
) +Op(kT l(ηT )
TkT l(ηT )))
= op(1).
Thus, β2(τT ) and β2(τ0) have the same asymptotic distribution. Applying Lemma B.3, we
have √TkT (β2(τ0)− β2T ) =
1√TkT l(ηT )
∑Tt=[τ0T ]+1 yt−1εt
1TkT l(ηT )
∑Tt=[τ0T ]+1 y
2t−1
⇒ W (2c)
W 2(τ0) + 1− τ0,
which immediately leads to
√TkT (β2(τT )− β2T ) ⇒
W (2c)
W 2(τ0) + 1− τ0. (B.34)
(B.34) is equivalent to (1.7) by noting that 1− β22T = 2c/kT (1 + o(1)).
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When kT ≍√T , applying (B.32) and (B.33), we have√
TkT (β2(τT )− β2(τ0))
= I{τT ≤ τ0}√
TkT
(−∑[τ0T ]
t=[τTT ]+1 y2t−1∑T
t=[τTT ]+1 y2t−1
∑Tt=[τ0T ]+1 yt−1εt∑Tt=[τ0T ]+1 y
2t−1
+
∑[τ0T ]t=[τTT ]+1 yt−1εt∑Tt=[τTT ]+1 y
2t−1
+ (β1 − β2T )
∑[τ0T ]t=[τTT ]+1 y
2t−1∑T
t=[τTT ]+1 y2t−1
)
+I{τT > τ0}√TkT
(∑[τTT ]t=[τ0T ]+1 y
2t−1∑T
t=[τTT ]+1 y2t−1
∑Tt=[τ0T ]+1 yt−1εt∑Tt=[τ0T ]+1 y
2t−1
−∑[τTT ]
t=[τ0T ]+1 yt−1εt∑Tt=[τTT ]+1 y
2t−1
)
= I{τT ≤ τ0}√
TkT
(Op(
T l(ηT )
TkT l(ηT ))Op(
1√TkT
) +Op(
√T l(ηT )
TkT l(ηT )) +Op(
T l(ηT )
Tk2T l(ηT )))
+I{τT > τ0}√TkT
(Op(
T l(ηT )
TkT l(ηT ))Op(
1√TkT
) +Op(
√T l(ηT )
TkT l(ηT )))
= op(1),
which means that (B.34) still holds.
When kT = o(√T ), following the proof of Theorem 4 in Chong (2001), one can show
that (B.34) holds. The details are omitted.
Q.E.D. �
Appendix C: Proof of Theorem 1.3
Lemma B.1 and the following two lemmas are key ingredients in the proof of Theorem 1.3.
Lemma C.1 Suppose assumptions C1 and C2 are fulfilled and c > 0, then
(a) for any 0 < τ ≤ 1, 1√kT l(ηT )
∑[τT ]t=1 (1 +
ckT
)t−1−[τT ]εt ⇒ X,
(b) for any 0 < τ ≤ 1, 1√kT l(ηT )
∑[τT ]t=1 (1 +
ckT
)−tεt ⇒ Y,
where, X and Y are independent N(0, 12c) random variables.
Proof. The proof can be completed by following the proof of Lemma 4.2 in Phillips and
Magdalinos (2007a) and the truncation technique (A.1). Thus the details are omitted.
Q.E.D. �
Lemma C.2 Let {yt} be generated according to Model (1.1), where β1 = 1 and β2 = β2T =
1 + c/kT with c > 0. Then under assumptions C1-C4, the following results hold jointly:
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(a)β−(T−[τ0T ])2T√TkT l(ηT )
∑Tt=[τ0T ]+1 yt−1εt ⇒ XW (τ0),
(b)β−2(T−[τ0T ])2TTkT l(ηT )
∑Tt=[τ0T ]+1 y
2t−1 ⇒ 1
2cW2(τ0),
where X is a random variable obeying N(0, 12c) and is independent of W (τ0).
Proof. To prove part (a), note that the following decomposition holds:
1
βT−[τ0T ]2T
√TkT l(ηT )
T∑t=[τ0T ]+1
yt−1εt
=1
βT−[τ0T ]2T
√TkT l(ηT )
T∑t=[τ0T ]+1
(βt−[τ0T ]−12T y[τ0T ] +
t−1∑i=[τ0T ]+1
βt−i−12T εi
)εt
=1
βT−[τ0T ]2T
√TkT l(ηT )
(y0 + [τ0T ]∑j=1
εj
) T∑t=[τ0T ]+1
βt−[τ0T ]−12T εt +
T∑t=[τ0T ]+1
εt
t−1∑i=[τ0T ]+1
βt−i−12T εi
:= II1 + II2, (C.1)
where
II1 =1
βT−[τ0T ]2T
√TkT l(ηT )
(y0 +
[τ0T ]∑j=1
εj
) T∑t=[τ0T ]+1
βt−[τ0T ]−12T εt
=1
βT−[τ0T ]2T
√TkT l(ηT )
[τ0T ]∑j=1
εj
T∑t=[τ0T ]+1
βt−[τ0T ]−12T εt · (1 + op(1))
and
II2 =1
βT−[τ0T ]2T
√TkT l(ηT )
T∑t=[τ0T ]+1
εt
t−1∑i=[τ0T ]+1
βt−i−12T εi
=1
βT−[τ0T ]2T
√TkT l(ηT )
T∑t=[τ0T ]+1
ε(1)t
t−1∑i=[τ0T ]+1
βt−i−12T ε
(1)i · (1 + op(1))
by the truncation technique (A.1) and some simple calculus.
To handle the term II1. Applying part (a) of Lemma C.1 and observing the fact∑[τ0T ]t=1 εt√T l(ηT )
⇒ W (τ0), it can be shown that
II1 ⇒ XW (τ0) (C.2)
by noting that
1
βT−[τ0T ]2T
√kT l(ηT )
T∑t=[τ0T ]+1
βt−[τ0T ]−12T εt
=1
βT−[τ0T ]2T
√kT l(ηT )
T−[τ0T ]∑s=1
βs−12T ε[τ0T ]+s
=1√
kT l(ηT )
[(1−τ0)T ]∑s=1
βs−1−[(1−τ0)T ]2T ε[τ0T ]+s · (1 + op(1))
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and
1√kT l(ηT )
[(1−τ0)T ]∑s=1
βs−1−[(1−τ0)T ]2T ε[τ0T ]+s
d=
1√kT l(ηT )
[(1−τ0)T ]∑s=1
βs−1−[(1−τ0)T ]2T εs ⇒ X.
Consider the term II2. It is trivial that
E( 1
βT−[τ0T ]2T
√TkT l(ηT )
T∑t=[τ0T ]+1
ε(1)t
t−1∑i=[τ0T ]+1
βt−i−12T ε
(1)i
)= 0
and
V ar( 1
βT−[τ0T ]2T
√TkT l(ηT )
T∑t=[τ0T ]+1
ε(1)t
t−1∑i=[τ0T ]+1
βt−i−12T ε
(1)i
)
=1
β2(T−[τ0T ])2T TkT
T∑t=[τ0T ]+1
t−1∑i=[τ0T ]+1
β2(t−i−1)2T · (1 + o(1))
=1
β2(T−[τ0T ])2T T
· 1
kT (β22T − 1)
·(β2(T−[τ0T ])
2T − 1
β22T − 1
− (T − [τ0T ]))· (1 + o(1))
= o(1) (C.3)
by kT = o(T ). Consequently,
II2 = op(1). (C.4)
Obviously, combining (C.1), (C.2) and (C.4) yields part (a).
To prove part (b). Observe that
1
β2(T−[τ0T ])2T TkT l(ηT )
T∑t=[τ0T ]+1
y2t−1
=1
β2(T−[τ0T ])2T TkT l(ηT )
T∑t=[τ0T ]+1
(βt−[τ0T ]−12T y[τ0T ] +
t−1∑i=[τ0T ]+1
βt−i−12T εi
)2=
y2[τ0T ]
β2(T−[τ0T ])2T TkT l(ηT )
T∑t=[τ0T ]+1
β2(t−[τ0T ]−1)2T +
1
β2(T−[τ0T ])2T TkT l(ηT )
T∑t=[τ0T ]+1
( t−1∑i=[τ0T ]+1
βt−i−12T εi
)2+
2y[τ0T ]
β2(T−[τ0T ])2T TkT l(ηT )
T∑t=[τ0T ]+1
(βt−[τ0T ]−12T
t−1∑i=[τ0T ]+1
βt−i−12T εi
):= III1 + III2 + III3, (C.5)
where
III1 =y2[τ0T ]
β2(T−[τ0T ])2T TkT l(ηT )
T∑t=[τ0T ]+1
β2(t−[τ0T ]−1)2T ,
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III2 =1
β2(T−[τ0T ])2T TkT l(ηT )
T∑t=[τ0T ]+1
( t−1∑i=[τ0T ]+1
βt−i−12T εi
)2and
III3 =2y[τ0T ]
β2(T−[τ0T ])2T TkT l(ηT )
T∑t=[τ0T ]+1
(βt−[τ0T ]−12T
t−1∑i=[τ0T ]+1
βt−i−12T εi
).
Obviously,
III1 ⇒1
2cW 2(τ0). (C.6)
Consider the term III2. Note that
III2 =1
β2(T−[τ0T ])2T TkT l(ηT )
T∑t=[τ0T ]+1
( t−1∑i=[τ0T ]+1
βt−i−12T ε
(1)i
)2· (1 + op(1))
and
E
1
β2(T−[τ0T ])2T TkT l(ηT )
T∑t=[τ0T ]+1
( t−1∑i=[τ0T ]+1
βt−i−12T ε
(1)i
)2=
1
β2(T−[τ0T ])2T TkT
T∑t=[τ0T ]+1
t−1∑i=[τ0T ]+1
β2(t−i−1)2T · (1 + o(1))
= o(1)
by similar arguments as in (C.3). Hence, we have
III2 = op(1). (C.7)
For the term III3, using (C.6) and (C.7) and applying Cauchy-Schwarz inequality im-
mediately leads to
III3 = op(1). (C.8)
Combining (C.5)-(C.8), we show part (b).
Moreover, by checking the above proofs carefully, one can find that parts (a) and (b)
hold jointly and X and W (τ0) are mutually independent.
Q.E.D. �
Lemma C.3 Let {yt} be generated according to Model (1.1), where β1 = 1 and β2 = β2T =
1 + c/kT , where c is a fixed positive constant. Then under the assumptions C1-C4 with
kT = o(√T ), we have for any fixed integer m ≥ 0,
(a)k2T
T l(ηT )
(RSST (τ0 − m
T )−RSST (τ0))⇒ c2mW 2(τ0),
(b)k2T
T l(ηT )
(RSST (τ0 +
mT )−RSST (τ0)
)⇒ c2mW 2(τ0).
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Proof. The proof is similar to that of Lemma B.4, with the use of the result in (C.16)
below. The details are omitted.
Q.E.D. �
Proof of Theorem 1.3. We first prove the first and second parts of Theorem 1.3(a).
Similarly to the proof of Theorem 1.2(a), we first prove (B.10) when kT = O(√T ). The
definitions of Ai, i = 1, · · · , 6 can be found in (B.11). First, it is trivial that
A1 = op(1/kT ), A4 = op(1/kT ) (C.9)
by Lemma B.1 and Lemma C.2. Secondly, note that the same reasoning in (B.12) also
implies
A2 = op(1/kT ). (C.10)
For the term A5, following the proof of Theorem 1.2, we have
y[τ0T ]
m∑t=[τ0T ]+1
βt−1−[τ0T ]2T εt
= Op
(√TkT (β
2(m−[τ0T ])2T − 1)l(ηT )
)
=
Op
(√T (m− [τ0T ])l(ηT )
), if MT < m− [τ0T ] ≤ [kT /N1]
Op
(√TkT l(ηT )
), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op
(√TkTβ
(m−[τ0T ])2T l(ηT )
), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
and
m∑t=[τ0T ]+1
t−1∑i=[τ0T ]+1
βt−1−i2T εi
εt
= Op
(√kT (m− [τ0T ]) + k2T (β
2(m−[τ0T ])2T − 1)l(ηT )
)
=
Op
(√kT (m− [τ0T ])l(ηT )
), if MT < m− [τ0T ] ≤ [kT /N1]
Op (kT l(ηT )) , if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op
(kTβ
m−[τ0T ]2T l(ηT )
), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
.
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Hence,
m∑t=[τ0T ]+1
yt−1εt
= y[τ0T ]
m∑t=[τ0T ]+1
βt−1−[τ0T ]2T εt +
m∑t=[τ0T ]+1
t−1∑i=[τ0T ]+1
βt−1−i2T εi
εt
=
Op
(√T (m− [τ0T ])l(ηT )
), if MT < m− [τ0T ] ≤ [kT /N1]
Op
(√TkT l(ηT )
), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op
(√TkTβ
(m−[τ0T ])2T l(ηT )
), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
. (C.11)
Moreover, we also have
2β2T1− β2
2T
m∑t=[τ0T ]+1
yt−1εt
=
Op
(kT√
T (m− [τ0T ])l(ηT )), if MT < m− [τ0T ] ≤ [kT /N1]
Op
(√Tk
3/2T l(ηT )
), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op
(√Tk
3/2T β
(m−[τ0T ])2T l(ηT )
), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
,
1
1− β22T
m∑t=[τ0T ]+1
ε2t
= Op (kT (m− [τ0T ])l(ηT ))
=
Op (kT (m− [τ0T ])l(ηT )) , if MT < m− [τ0T ] ≤ [kT /N1]
Op
(k2T l(ηT )
), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op (kT (m− [τ0T ])l(ηT )) , if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
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and
− 1
1− β22T
(y2m − y2[τ0T ])
= − 1
1− β22T
(ym + y[τ0T ])(ym − y[τ0T ])
= − 1
1− β22T
m∑i=[τ0T ]+1
βm−i2T εi +
(βm−[τ0T ]2T + 1
)y[τ0T ]
·
m∑i=[τ0T ]+1
βm−i2T εi +
(βm−[τ0T ]2T − 1
)y[τ0T ]
= kT ·
(Op
(√kT (β
2(m−[τ0T ])2T − 1)l(ηT )
)+Op(β
m−[τ0T ]2T
√T l(ηT ))
)·(Op
(√kT (β
2(m−[τ0T ])2T − 1)l(ηT )
)+Op
((β
m−[τ0T ]2T − 1)
√T l(ηT )
))
=
Op(kT
√T l(ηT )) ·Op
(m−[τ0T ]
kT
√T l(ηT )
), if MT < m− [τ0T ] ≤ [kT /N1]
Op(kT√
T l(ηT )) ·Op(√T l(ηT )), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op(kTβm−[τ0T ]2T
√T l(ηT )) ·Op(β
m−[τ0T ]2T
√T l(ηT )), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
=
Op (T (m− [τ0T ])l(ηT )) , if MT < m− [τ0T ] ≤ [kT /N1]
Op(TkT l(ηT )), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op(TkTβ2(m−[τ0T ])2T l(ηT )), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
.
Thus,
m∑t=[τ0T ]+1
y2t−1
= − 1
1− β22T
(y2m − y2[τ0T ]) +1
1− β22T
m∑t=[τ0T ]+1
ε2t +2β2T
1− β22T
m∑t=[τ0T ]+1
yt−1εt
=
Op (T (m− [τ0T ])l(ηT )) , if MT < m− [τ0T ] ≤ [kT /N1]
Op(TkT l(ηT )), if [kT /N1] < m− [τ0T ] ≤ [N2kT ]
Op(TkTβ2(m−[τ0T ])2T l(ηT )), if [N2kT ] < m− [τ0T ] ≤ T − [τ0T ]
. (C.12)
Consequently, it follows from (C.11) and (C.12) that∑mt=[τ0T ]+1 yt−1εt∑mt=[τ0T ]+1 y
2t−1
= Op
(√T (m− [τ0T ])l(ηT )
T (m− [τ0T ])l(ηT )
)≤ Op(1/
√TMT ) = op(1/kT )
by kT = O(√T ) and MT → ∞ when MT < m− [τ0T ] ≤ [kT /N1],∑m
t=[τ0T ]+1 yt−1εt∑mt=[τ0T ]+1 y
2t−1
= Op
(√TkT l(ηT )
TkT l(ηT )
)= op(1/kT )
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when [kT /N1] < m− [τ0T ] ≤ [N2kT ] and∑mt=[τ0T ]+1 yt−1εt∑mt=[τ0T ]+1 y
2t−1
= Op
(√TkTβ
m−[τ0T ]2T l(ηT )
TkTβ2(m−[τ0T ])2T l(ηT )
)= op(1/kT )
when [N2kT ] < m− [τ0T ] ≤ T − [τ0T ], yielding
A5 = supm∈D2T
∑mt=[τ0T ]+1 yt−1εt∑mt=[τ0T ]+1 y
2t−1
= op(1/kT ). (C.13)
Thirdly, note that
A3 ≤(Op
( 1
TkTβ2(T−[τ0T ])2T l(ηT )
)+Op
( 1
TMT l(ηT )
))·Op(l(ηT )) = op(1/k
2T ) (C.14)
and
A6 ≤(Op(
1
T 2l(ηT )) +Op(
1
TMT l(ηT )))·Op(l(ηT )) = op(1/k
2T ). (C.15)
The readers are referred to the proof of Theorem 1.2(a) for more details. Hence, (B.10)
is proved by combining (C.9), (C.10), (C.13), (C.14) and (C.15). Therefore, |τT − τ0| =
Op(1/T ) under kT = O(√T ) is proved. This implies the second part of Theorem 1.3(a).
To prove the first part of Theorem 1.3(a), i.e., to prove P (k = k0) → 0 when kT = o(√T ),
one can refer to the proof of Theorem 1.2(a) and applying Lemma C.3. The details are not
provided here for brevity.
To derive the third part of Theorem 1.3(a), we follow Appendix K in Chong (2001).
Since the asymptotic analysis in mildly explosive model is more complicated than that in
mildly integrated model, we offer more details for the proof. We write β2T = 1+ c/kT = 1+
1/(√
Tg(T )) with g(T ) = k2T /(c2T ). Then, g(T ) → ∞ and g(T ) = o(kT ) since
√T = o(kT )
and kT = o(T ). Denote
ΛT (τ) =
(∑[τ0T ]t=1 yt−1εt
)2∑[τ0T ]
t=1 y2t−1
−
(∑[τT ]t=1 yt−1εt
)2∑[τT ]
t=1 y2t−1
+
(∑Tt=[τ0T ]+1 yt−1εt
)2∑T
t=[τ0T ]+1 y2t−1
−
(∑Tt=[τT ]+1 yt−1εt
)2∑T
t=[τT ]+1 y2t−1
.
The following observation is a simple generalization of Proposition A.1 in Phillips and Mag-
dalinos (2007), hence the proof is omitted:(T
kT
)a
= o((1 + c/kT )bT ), for any a > 0 and b > 0. (C.16)
For τ = τ0 + νg(T )/T and ν ≤ 0, by applying (C.16) and Lemmas B.1 and C.2 and by
the proof of (B.19), we have the following results:
ΛT (τ)
l(ηT )= Op(1);
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∣∣∣∣(β2T − 1)
l(ηT )
∑[τ0T ]t=[τT ]+1 y
2t−1
∑Tt=[τ0T ]+1 yt−1εt∑T
t=[τT ]+1 y2t−1
∣∣∣∣= Op
(Tg(T )
√TkTβ
T−[τ0T ]2T
kT (Tg(T ) + TkTβ2(T−[τ0T ])2T )
)= Op
(Tg(T )
√TkT
Tk2Tβ(T−[τ0T ])2T
)
= op
((T
kT
)1/2
· 1
β(T−[τ0T ])2T
)= op(1); ∑T
t=[τ0T ]+1 y2t−1∑T
t=[τT ]+1 y2t−1
p→ 1;
1√Tg(T )l(ηT )
[|ν|g(T )]−1∑t=0
y[τ0T ]−t−1ε[τ0T ]−t
= −y[τ0T ]√T l(ηT )
· 1√g(T )l(ηT )
[|ν|g(T )]−1∑t=0
(−ε[τ0T ]−t) · (1 + op(1))
⇒ −W1(τ0)W1(|ν|);
and
1
Tg(T )l(ηT )
[|ν|g(T )]−1∑t=0
y2[τ0T ]−t−1 ⇒ |ν|W 21 (τ0).
One is referred to Appendix K in Chong (2001) for more details.
Then, using equation (B.2) in Chong (2001), we have
RSST (τ)−RSST (τ0)
l(ηT )
= −2(β2T − 1)
l(ηT )
[τ0T ]∑t=[τT ]+1
yt−1εt · (1 + op(1)) +(β2T − 1)2
l(ηT )
[τ0T ]∑t=[τT ]+1
y2t−1 · (1 + op(1)) + op(1)
= − 2(1 + op(1))√Tg(T )l(ηT )
[|ν|g(T )]−1∑t=0
y[τ0T ]−t−1ε[τ0T ]−t +1 + op(1)
Tg(T )l(ηT )
[|ν|g(T )]−1∑t=0
y2[τ0T ]−t−1 + op(1)
⇒ −2W1(τ0)W1(|ν|) + |ν|W 21 (τ0). (C.17)
For τ = τ0 + νg(T )/T and ν > 0, note that
[τ0T+νg(T )]∑t=[τ0T ]+1
y2t−1 =
[τ0T+νg(T )]∑t=[τ0T ]+1
(βt−1−[τ0T ]2T y[τ0T ] +
t−1∑i=[τ0T ]+1
βt−1−i2T εi
)2
= y2[τ0T ]
[τ0T+νg(T )]∑t=[τ0T ]+1
β2(t−1−[τ0T ])2T +
[τ0T+νg(T )]∑t=[τ0T ]+1
( t−1∑i=[τ0T ]+1
βt−1−i2T εi
)2
+2y[τ0T ]
[τ0T+νg(T )]∑t=[τ0T ]+1
βt−1−[τ0T ]2T
t−1∑i=[τ0T ]+1
βt−1−i2T εi. (C.18)
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Note that
[τ0T+νg(T )]∑t=[τ0T ]+1
β2(t−1−[τ0T ])2T = O
( ∣∣∣∣∣kT (1− β2[νg(T )]2T )
kT (1− β22T )
∣∣∣∣∣ )= O
( ∣∣∣∣kT · g(T )/kTkT (1− β2
2T )
∣∣∣∣ )= O(g(T )), (C.19)
yielding
y2[τ0T ]
[τ0T+νg(T )]∑t=[τ0T ]+1
β2(t−1−[τ0T ])2T = Op(Tg(T )l(ηT )). (C.20)
In addition, it can be shown that
E
[τ0T+νg(T )]∑t=[τ0T ]+1
( t−1∑i=[τ0T ]+1
βt−1−i2T ε
(1)i
)2=
[τ0T+νg(T )]∑t=[τ0T ]+1
t−1∑i=[τ0T ]+1
β2(t−1−i)2T l(ηT ) · (1 + o(1))
= O
(g(T )
β22T − 1
l(ηT )
)+O
((1− β
νg(T )2T )l(ηT )
(1− β22T )
2
)= O(kT g(T )l(ηT )) +O(k2T l(ηT ) · g(T )/kT )
= O(kT g(T )l(ηT )),
implying
[τ0T+νg(T )]∑t=[τ0T ]+1
( t−1∑i=[τ0T ]+1
βt−1−i2T εi
)2= Op(kT g(T )l(ηT )) = op(Tg(T )l(ηT )). (C.21)
Combining (C.18), (C.20) and (C.21) and applying Cauchy-Schwarz inequality, we have
[τ0T+νg(T )]∑t=[τ0T ]+1
y2t−1 = Op(Tg(T )l(ηT )). (C.22)
Note that the above arguments also imply that
max1≤t≤[νg(T )]−1
|y[τ0T ]+t − y[τ0T ]| = op(√
T l(ηT )).
Then, applying (C.22), we have the following results:
ΛT (τ)
l(ηT )= Op(1);
∣∣∣∣(β2T − 1)
l(ηT )·−∑[τ0T ]
t=1 yt−1εt∑[τT ]
t=[τ0T ]+1 y2t−1∑[τT ]
t=1 y2t−1
∣∣∣∣ = Op
(T 2g(T )
kT (T 2 + Tg(T ))
)= Op
(g(T )kT
)= op(1)
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by Lemma B.1 and g(T ) = o(kT ); and∑[τ0T ]t=1 y2t−1∑[τT ]t=1 y2t−1
p→ 1.
Now, making use of equation (B.4) in Chong (2001), we have
RSST (τ)−RSST (τ0)
l(ηT )
=2(β2T − 1)
l(ηT )
[τT ]∑t=[τ0T ]+1
yt−1εt · (1 + op(1)) +(β2T − 1)2
l(ηT )
[τT ]∑t=[τ0T ]+1
y2t−1 · (1 + op(1)) + op(1)
=2(1 + op(1))√Tg(T )l(ηT )
[|ν|g(T )]−1∑t=0
y[τ0T ]+tε[τ0T ]+t+1 +1 + op(1)
Tg(T )l(ηT )
[|ν|g(T )]−1∑t=0
y2[τ0T ]+t+1 + op(1)
=−2y[τ0T ]√T l(ηT )
· 1 + op(1)√g(T )l(ηT )
[|ν|g(T )]−1∑t=0
(−ε[τ0T ]+t+1) + νy2[τ0T ]
T l(ηT )· (1 + op(1)) + op(1)
⇒ −2W1(τ0)W2(ν) + νW 21 (τ0). (C.23)
Finally, applying the continuous mapping theorem for argmax/argmin functionals (cf.
Kim and Pollard (1990)), it follows from (C.17) and (C.23) that
c2T 2
k2T(τT − τ0) =
T
g(T )(τT − τ0) = ν
= argminν∈R
{RSST (τ)−RSST (τ0)}
= argminν∈R
{RSST (τ)−RSST (τ0)
l(ηT )
}⇒ argmin
ν∈R
{− 2W 2
1 (τ0) ·(W ∗(ν)
W1(τ0)− |ν|
2
)}= argmax
ν∈R
{W ∗(ν)
W1(τ0)− |ν|
2
},
where W ∗(ν) is a two-sided Brownian motion on R defined to be W ∗(ν) = W1(−ν) for ν ≤ 0
and W ∗(ν) = W2(ν) for ν > 0.
To prove Theorem 1.3(b), since we have shown that |τT − τ0| = op(1/T ) when kT =
o(√T ), |τT − τ0| = Op(1/T ) when kT ≍
√T and |τT − τ0| = Op(k
2T /T
2) when√T = o(kT ),
we study the limiting distribution of β1(τT ) under the above three cases separately.
Consider the case where√T = o(kT ) first. In this case, note that |τT −τ0| = Op(k
2T /T
2).
Then, for τT ≤ τ0, we have
[τ0T ]∑t=[τTT ]+1
y2t−1 = Op(k2T l(ηT )) (C.24)
and[τ0T ]∑
t=[τTT ]+1
yt−1εt = Op(kT l(ηT )) (C.25)
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by (B.20) and (B.21). For τT > τ0, it follows from the similar arguments in the proofs of
(B.22) and (B.28) respectively that
[τ0T+k2T /T ]∑t=[τ0T ]+1
y2t−1 =
[τ0T+k2T /T ]∑t=[τ0T ]+1
(βt−1−[τ0T ]2T y[τ0T ] +
t−1∑i=[τ0T ]+1
βt−1−i2T εi
)2
=
[τ0T+k2T /T ]∑t=[τ0T ]+1
(βt−1−[τ0T ]2T y[τ0T ] +Op(
√kTβ
t−1−[τ0T ]2T l(ηT ))
)2
=
[τ0T+k2T /T ]∑t=[τ0T ]+1
β2(t−1−[τ0T ])2T y2[τ0T ] · (1 + op(1))
= k2T /T ·Op(T l(ηT ))
= Op(k2T l(ηT )),
yielding[τTT ]∑
t=[τ0T ]+1
y2t−1 = Op(k2T l(ηT )) (C.26)
and
[τ0T+k2T /T ]∑t=[τ0T ]+1
yt−1εt =1− β2
2T
2β2T
[τ0T+k2T /T ]∑t=[τ0T ]+1
y2t−1 +y2[τ0T+k2T /T ]
− y2[τ0T ]
2β2T− 1
2β2T
[τ0T+k2T /T ]∑t=[τ0T ]+1
ε2t
= Op(kT l(ηT )) +Op(√
T l(ηT )) ·Op(kT√
l(ηT )/√T ) +Op(k
2T l(ηT )/T )
= Op(kT l(ηT )),
yielding[τTT ]∑
t=[τ0T ]+1
yt−1εt = Op(kT l(ηT )). (C.27)
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Applying (C.24)-(C.27) and following Appendix G in Chong (2001), we have
T (β1(τT )− β1(τ0))
= T
(∑[τTT ]t=1 ytyt−1∑[τTT ]
t=1 y2t−∑[τ0T ]
t=1 ytyt−1∑[τ0T ]t=1 y2t
)
= I{τT ≤ τ0}T(∑[τ0T ]
t=[τTT ]+1 y2t−1∑[τTT ]
t=1 y2t−1
∑[τ0T ]t=1 yt−1εt∑[τ0T ]t=1 y2t−1
−∑[τ0T ]
t=[τTT ]+1 yt−1εt∑[τTT ]t=1 y2t−1
)
+I{τT > τ0}T(−∑[τTT ]
t=[τ0T ]+1 y2t−1∑[τTT ]
t=1 y2t−1
∑[τ0T ]t=1 yt−1εt∑[τ0T ]t=1 y2t−1
+
∑[τTT ]t=[τ0T ]+1 yt−1εt∑[τTT ]
t=1 y2t−1
+ (β2T − β1)
∑[τTT ]t=[τ0T ]+1 y
2t−1∑[τTT ]
t=1 y2t−1
)= I{τT ≤ τ0}T
(Op(
k2T l(ηT )
T 2l(ηT ))Op(
1
T) +Op(
kT l(ηT )
T 2l(ηT )))
+I{τT > τ0}T(Op(
k2T l(ηT )
T 2l(ηT ))Op(
1
T) +Op(
kT l(ηT )
T 2l(ηT )) +Op(
k2T l(ηT )
kTT 2l(ηT )))
= op(1). (C.28)
Thus, β1(τT ) and β1(τ0) have the same asymptotic distribution. Then, applying Lemma
B.1 we have
T (β1(τ0)− β1) =
1T l(ηT )
∑[τ0T ]t=1 yt−1εt
1T 2l(ηT )
∑[τ0T ]t=1 y2t−1
⇒ W 2(τ0)− τ02∫ τ00 W 2(t)dt
,
implying
T (β1(τT )− β1) ⇒W 2(τ0)− τ02∫ τ00 W 2(t)dt
. (C.29)
This is equivalent to (1.8).
Consider the case where kT ≍√T . In this case, since |k−k0| = Op(1), one can follow the
proofs in Theorem 1.2 to show that T (β1(τT ) − β1(τ0)) = op(1) still holds by using (B.32)
and (B.33). The details are omitted here. Hence, (C.29) still holds when kT ≍√T .
Consider the case where kT = o(√T ). In this case, since P (k = k0) → 0, one can follow
the lines in the proof of Theorem 4 in Chong (2001) to show that (C.29) still holds. The
details are also omitted.
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To prove Theorem 1.3(c). Similarly, when√T = o(kT ), making use of (C.24)-(C.27)
and following Appendix G in Chong (2001), we have
βT−[τ0T ]2T
√TkT (β2(τT )− β2(τ0))
= βT−[τ0T ]2T
√TkT
(∑Tt=[τTT ]+1 ytyt−1∑T
t=[τTT ]+1 y2t
−∑T
t=[τ0T ]+1 ytyt−1∑Tt=[τ0T ]+1 y
2t
)
= I{τT ≤ τ0}βT−[τ0T ]2T
√TkT
(−∑[τ0T ]
t=[τTT ]+1 y2t−1∑T
t=[τTT ]+1 y2t−1
∑Tt=[τ0T ]+1 yt−1εt∑Tt=[τ0T ]+1 y
2t−1
+
∑[τ0T ]t=[τTT ]+1 yt−1εt∑Tt=[τTT ]+1 y
2t−1
+ (β1 − β2T )
∑[τ0T ]t=[τTT ]+1 y
2t−1∑T
t=[τTT ]+1 y2t−1
)
+I{τT > τ0}βT−[τ0T ]2T
√TkT
(∑[τTT ]t=[τ0T ]+1 y
2t−1∑T
t=[τTT ]+1 y2t−1
∑Tt=[τ0T ]+1 yt−1εt∑Tt=[τ0T ]+1 y
2t−1
−∑[τTT ]
t=[τ0T ]+1 yt−1εt∑Tt=[τTT ]+1 y
2t−1
)= I{τT ≤ τ0}βT−[τ0T ]
2T
√TkT
(Op(
k2T l(ηT )
β2(T−[τ0T ])2T TkT l(ηT )
)Op(1
βT−[τ0T ]2T
√TkT l(ηT )
)
+Op(kT l(ηT )
β2(T−[τ0T ])2T TkT l(ηT )
) +Op(k2T l(ηT )
β2(T−[τ0T ])2T Tk2T l(ηT )
))
+I{τT > τ0}βT−[τ0T ]2T
√TkT
(Op(
k2T l(ηT )
β2(T−[τ0T ])2T TkT l(ηT )
)Op(1
βT−[τ0T ]2T
√TkT
)
+Op(kT l(ηT )
β2(T−[τ0T ])2T TkT l(ηT )
))
= op(1)
by using (C.16). Thus, β2(τT ) and β2(τ0) also have the same asymptotic distribution.
Applying Lemma C.2, we have
βT−[τ0T ]2T
√TkT (β2(τ0)− β2T ) =
β−(T−[τ0T ])2T√TkT l(ηT )
∑Tt=[τ0T ]+1 yt−1εt
β−2(T−[τ0T ])2TTkT l(ηT )
∑Tt=[τ0T ]+1 y
2t−1
⇒ 2cX
W (τ0),
implying
βT−[τ0T ]2T
√TkT (β2(τT )− β2T ) ⇒
2cX
W (τ0). (C.30)
This is equivalent to (1.9) since β22T − 1 = 2c/kT (1 + o(1)).
βT−[τ0T ]2T
√TkT (β2(τT ) − β2(τ0)) = op(1) when kT ≍
√T or kT = o(
√T ) can also be
proved by similar arguments in the proof of Theorem 1.2, and the details are omitted.
Hence, (C.30) still holds.
Q.E.D. �
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Appendix D: Proof of Theorem 1.4
The following three lemmas are needed in the proof of Theorem 1.4.
Lemma D.1 Let {yt} be generated according to Model (1.1), where β1 = β1T = 1 + c/kT
with c > 0. Then under the assumptions C1-C4, the following results hold jointly:
(a)β−[τ0T ]1T
kT l(ηT )
∑[τ0T ]t=1 yt−1εt ⇒ XY,
(b)β−2[τ0T ]1T
k2T l(ηT )
∑[τ0T ]t=1 y2t−1 ⇒ 1
2cY2,
where, X and Y are independent N(0, 12c) random variables.
Proof. Following the proof of Theorem 4.3 in Phillips and Magdalinos (2007a) and applying
the truncation technique as shown in (A.1). The details are omitted.
Q.E.D. �
Lemma D.2 Let {yt} be generated according to Model (1.1), where β1 = β1T = 1 + c/kT
with c > 0 and β2 = 1. Then under the assumptions C1-C4, the following results hold
jointly:
(a)β−[τ0T ]1T√
TkT l(ηT )
∑Tt=[τ0T ]+1 yt−1εt ⇒ Y (W (1)−W (τ0)),
(b)β−2[τ0T ]1T
TkT l(ηT )
∑Tt=[τ0T ]+1 y
2t−1 ⇒ (1− τ0)Y
2,
where Y is that as in Lemma D.1 and is independent of W (1)−W (τ0).
Proof. To prove part (a), note that
β−[τ0T ]1T√
TkT l(ηT )
T∑t=[τ0T ]+1
yt−1εt
=β−[τ0T ]1T√
TkT l(ηT )
T∑t=[τ0T ]+1
(y[τ0T ] +
t−1∑i=[τ0T ]+1
εi
)εt
=β−[τ0T ]1T√
TkT l(ηT )
(β[τ0T ]1T y0 +
[τ0T ]∑j=1
β[τ0T ]−j1T εj
) T∑t=[τ0T ]+1
εt +
T∑t=[τ0T ]+1
εt
t−1∑i=[τ0T ]+1
εi
:= IV1 + IV2, (D.1)
where
IV1 =β−[τ0T ]1T√
TkT l(ηT )
(β[τ0T ]1T y0 +
[τ0T ]∑j=1
β[τ0T ]−j1T εj
) T∑t=[τ0T ]+1
εt
and
IV2 =β−[τ0T ]1T√
TkT l(ηT )
T∑t=[τ0T ]+1
εt
t−1∑i=[τ0T ]+1
εi.
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Applying part (b) of Lemma C.1 and assumption C3, it can be shown that
IV1 =1√
kT l(ηT )
[τ0T ]∑j=1
β−j1T εj ·
1√T l(ηT )
T∑t=[τ0T ]+1
εt + op(1) ⇒ Y (W (1)−W (τ0)). (D.2)
In addition, it is not difficult to show that
IV2 = Op
( β−[τ0T ]1T√
TkT l(ηT )· T l(ηT )
)= op(1) (D.3)
by (C.16).
Combining (D.1), (D.2) and (D.3) leads to part (a).
To prove part (b), note that
β−2[τ0T ]1T
TkT l(ηT )
T∑t=[τ0T ]+1
y2t−1
=β−2[τ0T ]1T
TkT l(ηT )
T∑t=[τ0T ]+1
(y[τ0T ] +
t−1∑i=[τ0T ]+1
εi
)2
=β−2[τ0T ]1T
TkT l(ηT )
T∑t=[τ0T ]+1
( [τ0T ]∑j=1
β[τ0T ]−j1T εj +
t−1∑i=[τ0T ]+1
εi
)2· (1 + op(1))
:= (V1 + V2 + V3) · (1 + op(1)), (D.4)
where
V1 =1
TkT l(ηT )
T∑t=[τ0T ]+1
( [τ0T ]∑j=1
β−j1T εj
)2,
V2 =β−2[τ0T ]1T
TkT l(ηT )
T∑t=[τ0T ]+1
( t−1∑i=[τ0T ]+1
εi
)2and
V3 =2β
−2[τ0T ]1T
TkT l(ηT )·[τ0T ]∑j=1
β[τ0T ]−j1T εj ·
T∑t=[τ0T ]+1
t−1∑i=[τ0T ]+1
εi
Obviously,
V1 ⇒ (1− τ0)Y2 (D.5)
by applying part (b) of Lemma C.1.
For the term V2, we have
V2 = Op
( β−2[τ0T ]1T
TkT l(ηT )· T 2l(ηT )
)= op(1) (D.6)
by making use of (C.16).
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Finally, applying Cauchy-Schwarz inequality, it follows from (D.5) and (D.6) that
V3 = op(1). (D.7)
It is ready to see that part (b) is proved by combining (D.4)-(D.7).
One can also verfiy that parts (a) and (b) hold jointly and Y and W (1) − W (τ0) are
mutually independent.
Q.E.D. �
Lemma D.3 Let {yt} be generated according to Model (1.1), where β1 = β1T = 1 + c/kT
and β2 = 1 with c > 0. Then under the assumptions C1-C4, we have for any fixed integer
m ≥ 0,
(a) kT
β2[τ0T ]1T l(ηT )
(RSST (τ0 − m
T )−RSST (τ0))⇒ c2mY 2,
(b) kT
β2[τ0T ]1T l(ηT )
(RSST (τ0 +
mT )−RSST (τ0)
)⇒ c2mY 2.
Proof. To prove part (a), from equation (B.2) in Chong (2001), we have
RSST (τ0 −m
T)−RSST (τ0)
= 2(β2 − β1T )
(∑[τ0T ]t=[τ0T ]−m+1 y
2t−1
∑Tt=[τ0T ]+1 yt−1εt∑T
t=[τ0T ]−m+1 y2t−1
−∑T
t=[τ0T ]+1 y2t−1
∑[τ0T ]t=[τ0T ]−m+1 yt−1εt∑T
t=[τ0T ]−m+1 y2t−1
)
+ (β2 − β1T )2
∑Tt=[τ0T ]+1 y
2t−1
∑[τ0T ]t=[τ0T ]−m+1 y
2t−1∑T
t=[τ0T ]−m+1 y2t−1
+ ΛT (τ0 −m
T)
where
ΛT (τ0 −m
T)
=
(∑[τ0T ]t=1 yt−1εt
)2∑[τ0T ]
t=1 y2t−1
−
(∑[τ0T ]−mt=1 yt−1εt
)2∑[τ0T ]−m
t=1 y2t−1
+
(∑Tt=[τ0T ]+1 yt−1εt
)2∑T
t=[τ0T ]+1 y2t−1
−
(∑Tt=[τ0T ]−m+1 yt−1εt
)2∑T
t=[τ0T ]−m+1 y2t−1
.
Obviously, ΛT (τ0 − mT ) = Op(l(ηT )). It follows that
kT
β2[τ0T ]1T l(ηT )
(RSST (τ0 −
m
T)−RSST (τ0)
)=
kT
β2[τ0T ]1T l(ηT )
·(− 2c
kT
)( Op(mkTβ2[τ0T ]1T l(ηT ))Op(
√TkTβ
[τ0T ]1T l(ηT ))
Op(mkTβ2[τ0T ]1T l(ηT )) +Op(TkTβ
2[τ0T ]1T l(ηT ))
+Op(TkTβ
2[τ0T ]1T l(ηT ))
Op(√kTβ
[τ0T ]1T )
)
+c2
kTβ2[τ0T ]1T l(ηT )
·Op(TkTβ
2[τ0T ]1T l(ηT ))
Op(mkTβ2[τ0T ]1T l(ηT )) +Op(TkTβ
2[τ0T ]1T l(ηT ))
[τ0T ]∑[τ0T ]−m+1
y2t−1 + op(1)
=c2(1 + op(1))
kTβ2[τ0T ]1T l(ηT )
[τ0T ]∑[τ0T ]−m+1
y2t−1 + op(1)
⇒ c2mY 2
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by Lemmas C.1 and D.2 and the observations
∣∣∣∣∑[τ0T ]
t=[τ0T ]−m+1 yt−1εt∑Tt=[τ0T ]−m+1 y
2t−1
∣∣∣∣ ≤√∑[τ0T ]
t=[τ0T ]−m+1 ε2t√∑T
t=[τ0T ]−m+1 y2t−1
= Op(1
√kTβ
[τ0T ]1T
)
and ∑[τ0T ]t=[τ0T ]−m+1 y
2t−1
my2[τ0T ]
p→ 1.
To prove part (b), from equation (B.4) in Chong (2001), we have
RSST (τ0 +m
T)−RSST (τ0)
= 2(β2 − β1T )
(∑[τ0T ]t=1 y2t−1
∑[τ0T ]+mt=[τ0T ]+1 yt−1εt∑[τ0T ]+m
t=1 y2t−1
−∑[τ0T ]+m
t=[τ0T ]+1 y2t−1
∑[τ0T ]t=1 yt−1εt∑[τ0T ]+m
t=1 y2t−1
)
+ (β2 − β1T )2
∑[τ0T ]+mt=[τ0T ]+1 y
2t−1
∑[τ0T ]t=1 y2t−1∑[τ0T ]+m
t=1 y2t−1
+ ΛT (τ0 +m
T)
where
ΛT (τ0 +m
T)
=
(∑[τ0T ]t=1 yt−1εt
)2∑[τ0T ]
t=1 y2t−1
−
(∑[τ0T ]+mt=1 yt−1εt
)2∑[τ0T ]+m
t=1 y2t−1
+
(∑Tt=[τ0T ]+1 yt−1εt
)2∑T
t=[τ0T ]+1 y2t−1
−
(∑Tt=[τ0T ]+m+1 yt−1εt
)2∑T
t=[τ0T ]+m+1 y2t−1
.
Then, using the facts ΛT (τ0 +mT ) = Op(l(ηT )) and
∣∣∣∣∑[τ0T ]+m
t=[τ0T ]+1 yt−1εt∑[τ0T ]+mt=[τ0T ]+1 y
2t−1
∣∣∣∣ ≤√∑[τ0T ]+m
t=[τ0T ]+1 ε2t√∑[τ0T ]+m
t=[τ0T ]+1 y2t−1
= Op(1
√kTβ
[τ0T ]1T
),
we have
kT
β2[τ0T ]1T l(ηT )
(RSST (τ0 +
m
T)−RSST (τ0)
)=
kT
β2[τ0T ]1T l(ηT )
·(− 2c
kT
)(Op(k2Tβ
2[τ0T ]1T l(ηT ))
√kTβ
[τ0T ]1T
+Op(mkTβ
2[τ0T ]1T l(ηT ))Op(kTβ
[τ0T ]1T l(ηT ))
Op(k2Tβ2[τ0T ]1T l(ηT )) +Op(mkTβ
2[τ0T ]1T l(ηT ))
)
+c2
kTβ2[τ0T ]1T l(ηT )
·Op(k
2Tβ
2[τ0T ]1T l(ηT ))
Op(k2Tβ2[τ0T ]1T l(ηT )) +Op(mkTβ
2[τ0T ]1T l(ηT ))
[τ0T ]+m∑t=[τ0T ]+1
y2t−1 + op(1)
=c2(1 + op(1))
kTβ2[τ0T ]1T l(ηT )
[τ0T ]+m∑t=[τ0T ]+1
y2t−1 + op(1)
⇒ c2mY 2
by Lemmas C.1 and D.1.
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Q.E.D. �
Proof of Theorem 1.4. Consider the first part of (1.4). We prove |τT − τ0| = Op(1/T )
first, and we only need to show that
Ai = op(1/kT ), i = 1, 2, 4, 5 and Aj = op(1/k2T ), j = 3, 6.
The definition of Ai’s can be found in equation (B.11).
First, by applying Lemmas D.1 and D.2, it can be shown that
A1 = op(1/kT ) and A4 = op(1/kT ).
Secondly, we investigate the magnitude of the terms A2 and A5 in probability. For A2, note
that Cauchy-Schwarz inequality implies
supm∈D1T
∣∣∣∣∣∑[τ0T ]
t=m+1 yt−1εt∑[τ0T ]t=m+1 y
2t−1
∣∣∣∣∣ ≤ supm∈D1T
√√√√ ∑[τ0T ]t=m+1 ε
2t∑[τ0T ]
t=m+1 y2t−1
,
it suffices to prove that the magnitude of the right hand side of the above inequality is
op(1/kT ). Applying Lemma C.1, we immediately have
supm∈D1T
√√√√∑[τ0T ]t=m+1 ε
2t∑[τ0T ]
t=1 y2t−1
≤
√√√√∑[τ0T ]t=1 ε2t
y2[τ0T ]−1
≤ Op
(√T l(ηT )
kTβ2[τ0T ]1T l(ηT )
)= op(1/kT )
by (C.16), which implies that
A2 ≤ supm∈D1T
√√√√∑[τ0T ]t=m+1 ε
2t∑[τ0T ]
t=1 y2t−1
= op(1/kT ).
Similarly, for the term A5, we have
supm∈D2T
∣∣∣∣∣∑m
t=[τ0T ]+1 yt−1εt∑mt=[τ0T ]+1 y
2t−1
∣∣∣∣∣ ≤ supm∈D2T
√√√√ ∑mt=[τ0T ]+1 ε
2t∑m
t=[τ0T ]+1 y2t−1
≤
√√√√∑Tt=[τ0T ]+1 ε
2t
y2[τ0T ]
= Op
(√T l(ηT )
kTβ2[τ0T ]1T l(ηT )
)= op(1/kT ),
which implies that
A5 = op(1/kT ).
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Note also that
A3 = supm∈D1T
∣∣∣ ∑Tt=m+1 y
2t−1∑T
t=[τ0T ]+1 y2t−1
∑[τ0T ]t=m+1 y
2t−1
ΛT (m
T)∣∣∣
≤(
1∑Tt=[τ0T ]+1 y
2t−1
+1∑[τ0T ]
t=[τ0T ]−MTy2t−1
)(sup
m∈D1T
∣∣∣(∑[τ0T ]t=1 yt−1εt)
2∑[τ0T ]t=1 y2t−1
−(∑m
t=1 yt−1εt)2∑m
t=1 y2t−1
∣∣∣+ sup
m∈D1T
∣∣∣(∑Tt=[τ0T ]+1 yt−1εt)
2∑Tt=[τ0T ]+1 y
2t−1
−(∑T
t=m+1 yt−1εt)2∑T
t=m+1 y2t−1
∣∣∣)≤
(Op
( 1
TkTβ2[τ0T ]1T l(ηT )
)+Op
( 1
kTβ2[τ0T ]1T l(ηT )
))·Op(l(ηT ))
= op(1/k2T ),
and
A6 = supm∈D2T
∣∣∣ ∑mt=1 y
2t−1∑m
t=[τ0T ]+1 y2t−1
∑[τ0T ]t=1 y2t−1
ΛT (m
T)∣∣∣
≤(
1∑[τ0T ]t=1 y2t−1
+1∑[τ0T ]+MT
t=[τ0T ]+1 y2t−1
)(sup
m∈D2T
∣∣∣(∑[τ0T ]t=1 yt−1εt)
2∑[τ0T ]t=1 y2t−1
−(∑m
t=1 yt−1εt)2∑m
t=1 y2t−1
∣∣∣+ sup
m∈D2T
∣∣∣(∑Tt=[τ0T ]+1 yt−1εt)
2∑Tt=[τ0T ]+1 y
2t−1
−(∑T
t=m+1 yt−1εt)2∑T
t=m+1 y2t−1
∣∣∣)≤
(Op(
1
k2Tβ2[τ0T ]1T l(ηT )
) +Op(1
kTβ2[τ0T ]1T l(ηT )
))·Op(l(ηT ))
= op(1/k2T ).
Hence, |τT − τ0| = Op(1/T ) is proved, and the proof of P (k = k0) → 0 can be completed by
using Lemma D.3. The details are omitted.
To find the limiting distribution of β1(τT ), note that the limiting distributions of β1(τT )
and β1(τ0) are the same by recalling the fact P (k = k0) → 0 and the similar arguments in
the proof of Theorem 4 in Chong (2001). The details are omitted. Then, invoke Lemma
D.1, we have
kTβ[τ0T ]1T (β1(τ0)− β1T ) =
β−[τ0T ]1T
kT l(ηT )
∑[τ0T ]t=1 yt−1εt
β−2[τ0T ]1T
k2T l(ηT )
∑[τ0T ]t=1 y2t−1
⇒ 2cX/Yd= 2cζ,
which implies
kTβ[τ0T ]1T (β1(τT )− β1T ) ⇒ 2cζ.
This is equivalent to (1.11) since β21T − 1 = 2c/kT (1 + o(1)).
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Analogously, β2(τT ) and β2(τ0) have the same asymptotic distribution. Then, applying
Lemma D.2 leads to
√TkTβ
[τ0T ]1T (β2(τ0)− β2) =
β−[τ0T ]1T√
TkT l(ηT )
∑Tt=[τ0T ]+1 yt−1εt
β−2[τ0T ]1T
TkT l(ηT )
∑Tt=[τ0T ]+1 y
2t−1
⇒ W (1)−W (τ0)
(1− τ0)Y,
which implies
√TkTβ
[τ0T ]1T (β2(τT )− β2) ⇒
W (1)−W (τ0)
(1− τ0)Y.
This is equivalent to (1.12).
Q.E.D. �
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