spring 2009: section 4 – lecture 4 reading: chapter 4 chapter 7

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Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

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Page 1: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

Spring 2009: Section 4 – Lecture 4

Reading: Chapter 4

Chapter 7

Page 2: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

Variation in Mendelian ratios

- incomplete dominance

- over-dominance

- co-dominance

- multiple alleles

- environment

- epigenetics

- epistasis (gene interactions)

- lethal genes

- gene linkage

Page 3: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

Multiple alleles - when there are more than two alleles for a given gene. Can result in combinations of complete dominance and co-dominance expression.

Page 4: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

examples:

- eye color in Drosophila

- self-incompatibility in plants

- blood type in humans

- coat color in animals

Page 5: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

White eye alleles in Drosophila

Page 6: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

Self-incompatibility in plants

example: Brassica - four allele system

S1, S2, S3, and S4

If the same allele is present in the male and female gamete the pollen tube will stop growing before it reaches the ovary.

Page 7: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

Cross S1S2 x S1S2

sterile

Page 8: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

Cross S1S2 x S2S3

S2S3

S1S3

Page 9: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

Cross S1S2 x S3S4

S1S3

S1S4

S2S3

S2S4

Page 10: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

Blood type in humans

- Three alleles, A, B, and O

- A and B are co-dominant

- Both A and B are dominant to O

Page 11: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

blood type genotype

A IAIA or IAIO

B IBIB or IBIO

AB IAIB

O IOIO

AB - universal recipient

O - universal donor

Page 12: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7
Page 13: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

Coat color in rabbits

c+ - wild type

ch - himalayan

cch - chinchilla

c – albino

There is a gradation in dominance for coat color

c+ cch ch c

Page 14: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

With multiple alleles the number of possible genotypes increases greatly.

You can calculate the number of different genotypes with the following formula: n(n+1)/2

Where n is the number of alleles

Page 15: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

examples:

rabbit coat color: n = 4number of genotypes = 4(4+1)/2

= 20/2 = 10

blood type: n = 3number of genotypes = 3(3+1)/2

= 12/2 = 6

Page 16: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

With the presence of multiple alleles it can be difficult at times to determine if the observed variation for a trait is due to two genes or allelic variation at one gene locus.

The way to determine if the variation you are observing is allelic is to do a complementation test.

Page 17: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

example:

You have two individuals that are both white variants from the normal red flower color.

If you cross them and the progeny are red then the trait is controlled by more than one gene and the two white variants have a mutation in different genes.

Page 18: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

But if you cross them and the progeny are all white then the two variants have a mutation in the same gene and the trait may be controlled by only one gene.

Page 19: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

Biochemically it would work like this:

substrate intermediate product (white) A (white) B (red)

‘A’ is an enzyme that converts the substrate to an intermediate and is controlled by gene A.

‘B’ is an enzyme that converts the intermediate to the final product and is controlled by gene B.

Page 20: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

2 gene model

plant 1 white aaBB x plant 2 white AAbb F1 AaBb all red

The flowers are red because the F1 individuals have one functional gene/allele at each gene loci. Hence the genes compliment each other.

Page 21: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

1 gene model

plant 1 white a1a1 x plant 2 white a2a2

F1 a1a2 all white

The flowers in the F1 individuals are white because they do not have a dominant allele at the A locus. The shades of white may vary depending on the mutation in each parent.

Page 22: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

So it is possible to have multiple alleles (a1, a2, a3, etc.) at a single gene locus that give various shades of white depending on the location of the mutation in the gene.

Page 23: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

Environment - the environment can influence the expression and level of expression of a gene. Factors such as temperature, light, and nutrition can reduce or prevent expression of a gene or genes.

Page 24: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

Example: temperature response in fur color.

Rabbits – Himalayan

As temperature decreases the fur on the extremities darkens.

Page 25: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

How to measure environmental effects:

plants - grow large populations of a single genotype in several environments then compare the differences in expression of a trait. Any differences observed have to be due to the different environments.

Page 26: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

animals - multiple matings to produce individuals with similar genotypes and study the F1 progeny in several environments.

Page 27: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

humans - work with twins

1. Separate identical twins at birth and place them in separate environments.

2. Study difference between identical and fraternal twins for expression of various traits.

Page 28: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

If the similarity (concordance) within the sets of twins for a trait is the same between identical and fraternal twins than the expression of that trait is under more environmental than genetic control.

Page 29: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

If the level of concordance differs significantly between identical and fraternal twins with a higher level of concordance in the sets of identical twins then the trait is under more genetic control than environmental control.

Page 30: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

Level of concordance among identical and fraternal twins.

percent concordance

trait identical fraternal

hair color 89 22

diabetes mellitus 65 18

measles 95 87

schizophrenia 80 13

manic-depressive 77 19

coffee drinking 94 79

Page 31: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

You can also see the effect of environment by looking at just the concordance of identical twins.

example: diabetes mellitus

Page 32: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

A concordance of 65% in identical twins means that out of 100 sets of identical twins 65 sets were the same for the trait while 35 sets had only one of the two showing the genetic disorder.

Page 33: Spring 2009: Section 4 – Lecture 4 Reading: Chapter 4 Chapter 7

The difference observed is due to the environment. Differences in the environment (diet?) must be causing the differences because with identical twins there are no genetic differences.