spm 2014 add math modul sbp super score [lemah] k1 set 1 dan skema

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MODUL SUPER SCORE SBP 2014

KERTAS 1SET 1

NAMA : MARKAHTARIKH :

Answer all questions.Jawab semua soalan.

1. The diagram shows the relation between set X and set Y.Rajah menunjukkan hubungan di antara set X dan set Y.

State /Nyatakan(a) The range of the relation

Julat hubungan itu(b) The value of x

Nilai x [2 marks]

[2 markah]Answer / Jawapan :

2. Given the function g : x →|x−5|. Find the values of x if g(x) = 4. [2 marks]

Diberi fungsi g : x →|x−5|. Cari nilai-nilai x jika g(x) = 4. [2 markah] Answer / Jawapan :

©Panel Perunding Mata Pelajaran Matematik Tambahan,

For examiner’s

use only

x g(x)

– 4

x

1

4 6

3

2

– 2

x

Set X Set Y

3

3


3. Given the functions f(x) = 4x – m and f−1( x )=kx+ 9

16 , where k and m are constants. Find the values of k and m. [3 marks]

Diberi fungsi f(x) = 4x – m dan f−1( x )=kx+ 9

16 , dimana k dan m adalah pemalar. Cari nilai-nilai bagi k dan m. [3 markah]

Answer / Jawapan :

4. Diagram shows a graph of a quadratic function f(x) = ‒2(x + h)2 ‒ 2 where k is a constant.Rajah menunjukkan graf fungsi kuadratik f(x) = ‒2(x + h)2 ‒ 2 dimana k ialah pemalar.

FindCari

(a) the value of knilai k

(b) the value of hnilai h

(c) the equation of axis of symmetry.persamaan bagi paksi simetri.

[3 marks][3 markah]

Answer / Jawapan :


For examiner’s

use only

x0

(-3, k)

f(x) = −2(x + h)2

− 2

y

3

4

3

5


5. Find the values of p if the quadratic function f(x) = 2x2 + 2px – (p + 1) has a minimum value of – 5 [3 marks]Cari nilai-nilai bagi p jika fungsi kuadratik f(x) = 2x2 + 2px – (p + 1) mempunyai nilai minimum – 5

[3 markah] Answer / Jawapan :

6. Find the range of values of x for ( x−4 )2<24−6 x [2 marks]

Cari julat nilai x bagi ( x−4 )2<24−6 x [2 markah]

Answer / Jawapan :


For examiner’s

use only

2

6

2

7


7. One of the roots of the quadratic equation 2 x2−3 x−k=0 is – 4. Find the value of k. [

2 marks]

Satu dari punca persamaan kuadratik 2 x2−3 x−k=0 ialah – 4. Cari nilai k. [2 markah]

Answer / Jawapan :

8. One of the roots of the equation 3x2 – 6x + p = 0 is three times the other root , find the possible values of p. [3 marks]Salah satu punca bagi persamaan 3x2 – 6x + p = 0 adalah tiga kali punca yang satu lagi, cari nilai yang mungkin bagi p. [3 markah] Answer / Jawapan :


For examiner’s

use only

3

8

3

9


9. Solve the equation 216x−2−6x+4=0 . [3 marks]

Selesaikan persamaan 216x−2−6x+4=0 [3 markah]

Answer / Jawapan :

10. Solve the equation 2x • 5x +2 = 25000. [3 marks]Selesaikan persamaan 2x • 5x +2 = 25000. [3 markah]


For examiner’s

use only

3

10

3

11


Answer / Jawapan :

11. Solve the equation log2 (x – 3) = log2 4x + 1

[3 marks]Selesaikan persamaan log2 (x – 3) = log2 4x + 1

[3 markah]

Answer / Jawapan :


For examiner’s

use only

4

12

2

13


12. Given that log2 x = m and log2 y = n. Express log4 (xy2) in terms of m and

n. [3 marks]Diberi log2 x = m dan log2 y = n. Nyatakan log4 (xy2) dalam sebutan m dan

n. [3 markah]

Answer / Jawapan :

lum

13. Find the sum to infinity of the geometric progression 20, 10, 5, ... [2 marks]Cari hasil tambah ketakterhinggaan janjang geometri 20, 10, 5, ... [2 markah]

Answer / Jawapan :


For examiner’s

use only

2

14

3

15

P(– 2 , 5)

Q(4 , – 3 )

x

y


14. Given a geometric progression has the first term and the sum to infinity are 25 and 62.5 respectively. Find the common ratio of the progression. [2 marks]Diberi satu janjang geometri mempunyai sebutan pertama dan hasil tambah hingga ketakterhinggaan adalah 25 dan 62.5 masing-masing. Cari nisbah sepunya bagi janjang tersebut. [2 markah]

Answer / Jawapan :

15. Write 0.01010101... as a single fraction in the lowest terms.[3 marks]

Tulis 0.0101010... sebagai satu pecahan tunggal dalam sebutan terendah.[3 markah]

Answer / Jawapan :

16. The diagram below shows two vectors O⃗P and O⃗Q .

Rajah di bawah menunjukkan dua buah vektor O⃗P dan O⃗Q .


For examiner’s

use only

4

16


Express Ungkapkan

(a) O⃗P in the form (x

y) .

O⃗P dalam bentuk (x

y) .

(b) P⃗Q in the form x~i + y

~j

P⃗Q dalam bentuk x~i + y

~j

[4 marks]


17. Given h⃗=( 4

−3) ,k⃗=(−2

0 ) and

a h⃗+ k⃗=(6m)

, find the values of a and m. [3 marks]

Diberi h⃗=( 4

−3) , k⃗=(−2

0 ) dan

a h⃗+ k⃗=(6m)

, cari nilai bagi a dan m. [3 markah]

Answer / Jawapan :


For examiner’s

use only

3

17

4

18


18. Points A, B and C are collinear. It is given that and

, where k is a constant. Find

Titik A, B dan C adalah segaris. Diberi bahawa dan , dengan keadaan k adalah pemalar. Cari

(a) the value of knilai k

(b) the ratio AB : BCnisbah AB : BC

[4 marks]




Jawapan/Answer :No Answer

1(a) {– 2, 2, 3, 6}(b) x = 0

2 x = 1, x = 9

3k =

14 , m =

94

4(a) k = – 2(b) h = 3(c) x = – 3

5 – 4, 26 −2<x<47 k = 44

8 α=12 ,

p= 94

9 x = 510 x = 3

11x =

−37

122n+m

213 4014 0.6

151

99

16 (a)(−2

5 )(b)

6 i~−8 j

~

17 a = 2 , m = – 6

18 (a) k = −14

3

(b) AB : BC = 3 : 2


spm 2014 add math modul sbp super score [lemah] k1 set 1 dan skema

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