SHARING GASOLINE COSTS

The Problem…

The Problem…

HOW MUCH SHOULD EACH PERSON PAY?

TRY TO FIND THE FAIREST POSSIBLE METHOD. SHOW

ALL YOUR WORK.

My Method to Solve the ProblemLara

10 Block

sto

School

20 Block

sto

School&

Back

My Method to Solve the ProblemChan

8Block

sto

School

16Block

sto

School&

Back

My Method to Solve the ProblemJason

5Block

sto

School

10Block

sto

School&

Back

My Method to Solve the ProblemMarla

2Block

sto

School

4Block

sto

School&

Back

My Method to Solve the Problem…

StudentBlocks

to School

Blocks to

School & Back

Lara 10 20Chan 8 16Jason 5 10Marla 2 4

20 (LARA) + 16 (CHAN) + 10 (JASON) + 4 (MARLA) = 50 TOTAL BLOCKS

LARA = 20/50 = 2/5 (SIMPLIFIED)CHAN = 16/50 = 8/25 (SIMPLIFIED)JASON = 10/50 = 1/5 (SIMPLIFIED)MARLA = 4/50 = 2/25 (SIMPLIFIED)

My Method to Solve the Problem

2 -------- X $300= $120

5

(LARA) (TOTAL) (MONEY OWED)

My Method to Solve the ProblemLara

8 -------- X $300= $96

25

(CHAN) (TOTAL) (MONEY OWED)

My Method to Solve the ProblemChan

1 -------- X $300= $60

5

(JASON) (TOTAL) (MONEY OWED)

My Method to Solve the ProblemJason

2 -------- X $300= $24

25

(MARLA) (TOTAL) (MONEY OWED)

My Method to Solve the ProblemMarla

My Method to Solve this Problem As I started this problem I determined how

many blocks each person was in the car. I figured it out for a one way trip and a to school and back. I compared this problem to the fraction unit we did earlier in the year and also the ratio and proportion unit. I figured out the part for each of the students in the car compared to the whole. I created fractions for each of the students to represent their time in the car. I simplified each of the fractions. I knew that the total cost was $300 so I used $300 and multiplied it by the fraction of each student to get my total cost per kid. I figured this is a fair to split the cost because if you are in the car longer you should pay more and if you are in the car less you should pay less.