sbi associates (clerk) mock test - 155 … number. with the help of the question part we can...

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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT BAHADURGARH PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD

SBI ASSOCIATES (Clerk) MOCK TEST - 155 (SOLUTION)

REASONING1. (2) All others are forms of wind while

volcano is a terrestrial eruption.2. (2)

Hence, there are eight suchletters.

3. (2) The letters are coded as +3, +5,+7 ... forward as in Englishalphabet.

4. (1) SCOTLAND : 12345678 ... (i)LOAN : 1435 ... (ii)LOTS : 8124 ... (iii)DAN : 537 ... (iv)SON : 458 ... (v)All the digits except 6 have beenused at least once in (ii), (iii), (iv)and (v) together. Similarly, all theletters except C have been used atleast once. Hence, code for C is 6.

5. (3) Except it others are written withthe help of eight digits only.

6. (*) In the context of the givenquestion each of the optionsholds true

(7-10):7. (3) The given words are as follows:

LAP BUT CAR SON HIDWhen positions of first and thirdalphabets of each of the words areinterchanged, we havePAL TUB RAC NOS DIHClearly, PAL and TUB are the onlymeaningful words. These wordsare obtained from LAP and BUTrespectively. Hence, option (3) isthe correct answer.

8. (1) When the given words arearranged as in dictionary, wehave,BUT CAR HID LAP SONClearly, LAP is the fourth wordfrom the left.

9. (4) After making necessary changes,we haveKBQ AVS BBQ RPO GJCClearly, there are three words inwhich no vowel appears. Thesewords are KBQ, BBQ and GJC.

10. (5) When the second alphabet in eachof the word is changed to the nextalphabet in the Englishalphabetical order, we haveLBP BVT CBR NPS HJDClearly, in all the above five words,there is no vowel.

11. (5) None is true(12-16):

hope to see you re so na di... (i)

please come to see the party fige na di ke zo ... (ii)hope to come di so ge... (iii)see you the party re fi zo na

... (iv)12. (2) From (i) and (ii), to see na di

From (i), (ii) and (iii), to di... (v)

Hence, the code for 'see' is 'na'From (ii) and (iii), come 'ge'

... (vi)From (ii), (iv), (v) and (vi), please 'ke'

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13. (1) From (i), (ii) and (iii), to 'di'hence so stands for 'hope'.

14. (3) From (ii), (iv) and Q.No. 12, codefor 'party' is either 'fi' or 'zo'.

15. (1) From (i), (iv) and Q.No. 12, codefor 'see' is 'na'; code for 'you' is're' and code for 'please' is 'ke'.

16. (5) From Q.No. 13 and 14,so di re you hope to

(17-18):

17. (1) PQ = 10 + 6 = 16 km18. (4) West

(19-23):With the help of definiteinformations, we get the followingtable:

19. (4)20. (4)21. (2) Mr. Aiyar is the other one.22. (3)23. (3) 2 + 3 + 0 + 2 + 4 (at least) + 4 (at

least) = 15(24-28):24. (5) Drawing family tree of the given

expression, we have

Hence, T is the daughter of S.

25. (2) Drawing family tree of the givenexpression, we have

26. (4) Drawing family tree of the givenexpression, we have

S is either nephew or niece of T.27. (3) Option (1):

Option (2):

S is nephew or niece of T. Abusrdrelationship.Option (3):

S is husband of T.We need not go further.Quicker Method:If S is to be husband of T, T shoulddefinitely be wife of S, i.e. T shouldbe female. Therefore, T should befollowed by either '×' and '-'.Clearly, option (4) is rejected. Now,we check the generation gapbetween S and T. Since T is wifeof S, generation gap between Tand S should be '0'. Now checkthe generation gap of theremaining choices with the helpof the chart given below:

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Choice (1):T × R ÷ V + S T(0) R (–1) V (0) S 0 – 1 + (0) =1 (Rejected)Choice (2):T – R ÷ V × S T (+1) R (–1) V (0)S +1 – 1 + 0 = 0 (Not Rejected)Choice (3):T – R + V ÷ S T(+1) R(0) V(–1) S +1 + 0 – 1 (Not rejected)Clearly, either option (2) or (3) or(5) is the answer. Now, draw thefamily tree for the choices (2) and(3). From the above it is clear thatthe option (3) is the correctanswer.

28. (1) Drawing family tree, we have

Hence, V is the aunt of T.29. (5) From I:

Meena's present age is not asingle-digit number. With the helpof the question part we canconclude that Meena's presentage is a two-digit number.Suppose Meena's present age be(10x + y) years.Now from I and II:(10y + x) – (10x + y) =

(10 ) (10 )11

y x x y

or, 9(y – x) = 11( )11y x

or, 9(y – x) = y + x

or, y – x = 9y x

... (i)

Now, if y + x is divisible by 9 thenvalue of y + x will be 9 or 18. Butif y + x = 18 then y = 9 and x = 9.Same value of y and x is notpossible. Therefore, y + x = 9 andif y + x = 9 then y – x = 1 where y

> x. Therefore, possible value of yand x will be the bolded part givenbelow:

Since y > x therefore y = 5 and x =4 thus Meena's age is (10x + y =)45 years.

30. (5) From II:The 3rd, 6th, 9th, 12th, 15th, 18th,21st ,24th and 27th positions areoccupied by girls.From I:Sridhar is 14th from the right.Hence, using I and II, we can getthe no. of boys required.

31. (1) The distance from Ranchi toRohtak is the same as thedistance from Rohtak to Ranchi.So I answers the questioncompletely. II has no relevance.

32. (4) From I: S M From II: S R PUsing I and II, we get

Hence, 'P' may be east of 'R', or 'P'may be south-east of 'R' may benorth-east of 'R'.

33. (4) At 7.30 pm, the hour hand of theclock will be between 7 and 8. Thealphabet code of 8 cannot knownfrom the given statements

34. (1) From the statement 'Someteachers are professors' there arepossibilities that 'All teachers areprofessors' and 'All professors areteachers'. Similarly, from thestatement 'Some lecturers are

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teachers' there is a possibility that'All teachers are lecturers'. Again,All professors are teachers + Allteachers are lecturers = A + A = A= All professors are lecturers.Hence, All teachers andprofessors are lecturers is apossibility. But conclusion II doesnot follow.

35. (2) From the above, conclusion I doesnot follow. Again, from the above,we have the following possibilities:'All lecturers are teachers' and 'Allteachers are professors'. Now, Alllecturers are teachers + Allteachers are professors = A + A =A = All lecturers are professors.Therefore conclusion II, i.e. 'Alllecturers being professors is apossibility' follows.

36. (2) All institutes are academies+ Allacademies are schools = A + A = A= All institutes are schools. Henceconclusion I does not follow.Again, Some institutes are banks(I)conversion Some banks areinstitutes (I) + All institutes areacademies = I + A = I = Somebanks are academies. Now,drawing all possible venn-diagrams for this conclusion, wehave as given below;Possibility I:

[Some banks are not academies.]Possibility II:

[All banks are academies.]

Possibility III:

[All academies are banks.]Hence, conclusion II follows.

37. (2) Some institutes are banks (I)conversion some banks areinstitutes + All institutes areacademies + All academies areschools = I + A + A = (I + A) + A= I + A = I = Some banks areschools. By drawing venn-diagrams, we conclude that "Allbanks are schools" can be apossibility. Hence conclusion Idoes not follow. Again, All banksare institute (because 'Any bankwhich is an institutes' means 'Allbanks are institues) + Allinstitutes are academies + Allacademies are schools = A + A +A = A = A + A = All banks areschools. Hence, conclusion IIfollows.

38. (2) Some metals are papers + Allpapers are glasses = I + A = I =Some metals are glasses.Therefore, conclusion I does notfollow. Some metals are papers+ All papers are glass = I + A =I = Some metals are glasses conversion Some glasses aremetals (I). 'At least some glassesare metals' implies 'Someglasses are metals'.

39. (5) Both have been assumed by therailway authority while puttingthe revised timing on thewebsite.

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40. (1) I is implicit; otherwise moreplayers would have been selected.II is not implicit because evenwithout the captain, there will besufficient number of players.

MATHS(81-120):81. (3) ? = 10.8 × 5.5 × 8.4 = 498.9682. (1) ?= 683.46 – 227.39 – 341.85

= 683.46 – 569.24 = 114.22

83. (3)725 725 725 371 371 371725 725 725 371 371 371

= 725 + 371 = 1096

3 3 2 2

2 2 2 2

( )( )( )

a b a b a ab ba ab b a ab b

a b

84. (2) Given expression2 2 2 2

2 2 2 2

( ) ( ) 2( ) 2( )

a b a b a ba b a b

Where a = 238, b = 13185. (4) Given expression

=6 [9 {18 (15 12 9)}]

= 6 – [9 – {18 – (15 – 12 + 9)}]= 6 – [9 – {18 – 12)}]= 6 – [9 – 6] = 6 – 3 = 3

86. (5) 3.3 + 13.33 + 31.31 + 13.31 + 1.3 = ?= 57.95 + 4.6= 62.55

87. (1) 3 310648 5832 ?

33 22 22 22 18 18 18 x

22 × 18 = x x = 396

88. (4) ?= 127.007 × 7.998 + 6.005 + 15.999 × 15.001

= 127 × 8 + 6 × 4= 1016 + 24= 1040

89. (3) ?= 9876 215.005 309.9924.96

= 9875 215 31025

= 395 + 215 – 310 = 30090. (4) ?= 30.9 × 3000 – 10.1 × 1100 +

8298 – 4302= 92700 – 11110 + 8298 – 4302= 85586 85000

91. (3)

92. (3)93. (4) Series pattern

7 × 0.5 + 0.5 = 46 × 7 = 4242 × 6 = 252should come in place of '?'252 × 5 = 12601260 × 4 = 50405040 × 3 = 1512015120 × 2 = 30240

94. (3) Series pattern50 × 1.2 = 60;60 × 1.25 = 75;75 × 1.3 = 97.5;97.5 × 1.35 = 131.625

95. (4) Series pattern9 × 7 – 1 = 6262 × 6 – 1 = 371should come in place of '?'371 × 5 – 1 = 18541854 × 4 – 1 = 74157415 × 3 – 1 = 22244

96. (5) Let ten's digit be x and unit's digitbe x2.Original number = 10x + x2

New number = 10x2 + xAccording to the question,(10x2 + x) – (10x + x2) = 54 10x2 + x – 10x – x2 = 54

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9x2 – 9x = 54 9(x2 – x) = 54 x2 – x – 6 = 0 x2 – 3x + 2x – 6 = 0 x(x – 3) + 2(x – 3) = 0 (x – 3)(x + 2) = 0x = 3, – 2Ten's digit = x = 3Unit's digit = x2 = 32 = 9Original number = 39Required number

4039 15.6100

97. (1) Let the number of papers = x.According the question,64x + 18 + 4 = 66x 2x = 22

x = 222 = 11

98. (5) Net effect

= ( 12)( 4)12 4 %

100

= (–16 + 0.48)%= –15.52%

99. (5) Profit on one calculator

= 2501001114

= ` 30.70

Total amount of the profit= 19 × 7 × 30.70 = ` 4083.10

100. (1) Let the entire sum = PAccording to the question,

2 1 2 13% 6% 13 6 3 6

P P

P × 12%

2 3 63 100 6 100P P

+ 4 1 121

6 100P

= 25

2 2100 100 100

P P P = 25

5P = 2500, P = 500Fast track Method:Given, R1 = 3%, R2 = 6%, R3 = 12%

1 2 1 1, ,3 6x y

1 2 113 6z

6 (4 1) 6 5 16 6 6

I = Rs. 25Now, according to the formula,

P = 2 31

100IR RR

x y z

= 25 100

2 1 13 6 123 6 6

= 2500

2 1 2 = ` 500

101. (3)Percentage growth

= 1 100 %8

= 12.5%

Height after 2 yr

= 64 × 212.51

100

= 64 9 98 8

= 81 cm

102. (5)Let the side of the square be x cm.

Breadth of rectangle = 23

x cm

According to the question,

= 90 × 23

x

4x = 60 x = 604

= 15 cm

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103. (1)Let the distance be x km.Speed downstream = (5 + 2) = 7km/hand speed of upstream = (5 – 2) = 3km/hAccording to the question,

3 7x x = 2 7x – 3x = 21 × 2

x = 21 24 = 10.5 km

Fast Track Method:Here, a = 5 km/h, b = 2 km/h, T= 2hAccording to the formula,Required distance

= 2 2

2a b

b

× T

= 2 25 22 2

× 2 =

25 42

= 212 = 10.5

km104. (2)Let time taken to cover the

distance = tSpeed = (2t + 1)

t(2t + 1) = 1830 2t2 + t = 1830 2t2 + t – 1830 = 0

t =21 (1) 4 2 ( 1830)

2 2

= 1 1 146404

= 1 1214

Taking '+' sign,

t = 1 1214

= 1204

= 30

Required ratio= (2 × 30 + 1) : 30 = 61 : 30

105. (3)According to the question,

5 men's 1 day's work = 1

15 ... (i)

5 men's 5 day's work = 1

15 × 5 = 13

Remaining work = 1 – 13 =

23

5 men + 10 women can do 23 of

the work in 5 days.5 men + 10 women can do the

whole of the work in 152 days.

(5 men + 10 women's) 1 day's

work = 2

15 ... (ii)

10 women's 1 day's work

= 2

15 – 5 men's 1 day's work

= 2

15 – 1

15 = 1

15

10 women can finish the workin 15 days.

(106-110):Total number of employees= 2400Number of male employees

= 85

× 2400 = 1500

Number of female employees

= 83

× 2400 = 900

Number of males in HRdepartment

= 12 × 1001500

= 180

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Number of females in HRdepartment

= 611

× 180 = 330

Number of females in Accountsdepartment= (1500 – 180 – 185 – 630 – 330)= 175Number of females in ITdepartment

= 91 × 900 = 100

Number of males in ITdepartment= 285 – 100 = 185Number of males in Production

department = 42 × 1001500

= 630

Number of females in Production

department = 10063010

= 63

Number of males in Marketing

department = 100150022

= 330

Number of females in Marketingdepartment= (900 – 330 – 216 – 100 – 63) =191Number of males in AccountDepartment= (1500 – 180 – 185 – 630 – 330)= 175

106. (2)Required percentage

= 1500185

× 100 12

107. (5)Number of males in Accountdepartment= 175


=

2400216175

× 100 = 16.29%


= 90063

× 100 = 7

110. (4)Number of females in HR andMarketing department= 330 + 191 = 521

(111-115):111. (2)Required Ratio

120 130 140 13 13 : 23210 230 250 23


220 100 22%120 220 160 210 160 130

113. (4)Difference between total numberof studying all six coursestogether from institutes 'X' and'Z'= 1100 – 1000 = 100


(160 210) 100 30%(160 180 190 210 230 250)

115. (4)Required ratio

140 190 11 11: 7210 7

(116-120):No. of students in class V

4500 18 810100

Boys 810 4 360

9

Girls 810 5 4509

No. of students in class VI

4500 16 720100

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Boys 720 5 450

8

Girls 720 3 270

8

No. of students in class VII

450 17 765100

Boys 765 8 36017

Girls 765 9405

17

No. of students in VIII

4500 15 675100

Boys 675 3 405

5

Girls 675 2 2705

No. of students in class IX

4500 16 720100

Boys 720 5 400

9

Girls 720 4 320

9

No. of students in class X

4500 18 810100

Boys 810 7 378

15

Girls 810 8 43215


= 8102353 × 100 = 34% (approx.)

117. (2)Difference between total numberof boys and total number of girlsin all the standard together= 2353 – 2147 = 206


360 400 19 :18450 270


405 15 :14378


= (360 450 360) 100(270 320 432)

= 114 (approx.)

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1. (2)2. (2)3. (2)4. (1)5. (2)6. (*)7. (4)8. (2)9. (3)10. (3)11. (5)12. (2)13. (1)14. (3)15. (1)16. (5)17. (1)18. (4)19. (4)20. (4)21. (2)22. (3)23. (3)24. (5)25. (2)26. (4)27. (3)28. (1)29. (5)30. (5)31. (1)32. (4)33. (4)34. (1)35. (2)36. (2)37. (2)38. (2)39. (5)40. (1)

41. (1)42. (2)43. (5)44. (1)45. (1)46. (4)47. (2)48. (3)49. (1)50. (3)51. (3)52. (5)53. (1)54. (4)55. (2)56. (4)57. (3)58. (5)59. (1)60. (1)61. (3)62. (4)63. (2)64. (3)65. (3)66. (5)67. (3)68. (1)69. (4)70. (2)71. (4)72. (2)73. (2)74. (3)75. (2)76. (5)77. (1)78. (2)79. (5)80. (3)

SBI ASSOCIATES (Clerk) MOCK TEST - 155 [ANSWER KEY]

81. (3)82. (1)83. (3)84. (2)85. (4)86. (5)87. (1)88. (4)89. (3)90. (4)91. (3)92. (4)93. (3)94. (3)95. (4)96. (5)97. (4)98. (5)99. (5)100. (1)101. (3)102. (5)103. (1)104. (2)105. (3)106. (2)107. (5)108. (2)109. (1)110. (4)111. (3)112. (1)113. (4)114. (4)115. (4)116. (4)117. (2)118. (1)119. (2)120. (4)

121. (2)122. (4)123. (2)124. (4)125. (2)126. (3)127. (3)128. (3)129. (2)130. (2)131. (2)132. (4)133. (3)134. (3)135. (3)136. (4)137. (4)138. (3)139. (1)140. (2)141. (1)142. (1)143. (4)144. (3)145. (2)146. (3)147. (3)148. (4)149. (4)150. (3)151. (3)152. (3)153. (3)154. (3)155. (4)156. (1)157. (4)158. (4)159. (2)160. (2)

161. (3)162. (3)163. (2)164. (1)165. (2)166. (1)167. (3)168. (1)169. (4)170. (1)171. (3)172. (1)173. (1)174. (2)175. (2)176. (5)177. (3)178. (1)179. (4)180. (2)181. (5)182. (3)183. (1)184. (2)185. (1)186. (5)187. (5)188. (2)189. (5)190. (5)191. (3)192. (5)193. (4)194. (5)195. (4)196. (4)197. (4)198. (3)199. (3)200. (4)

sbi associates (clerk) mock test - 155 … number. with the help of the question part we can...

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