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International Conference on Engineering Graphics and Design - Bucharest,Romania 2005
THE CAM DESIGN FOR A BETHER EFFICIENCY
Florian PETRESCU, Relly PETRESCU
Abstract: The paper presents an original method to determine the efficiency of a mechanism with cam
and follower. The originality of this method consists in eliminate of the friction modulus. In this paper on
analyze three types of cam mechanisms: 1.The mechanism with rotary cam and plate translated follower;
2.The mechanism with rotary cam and translated follower with roll; 3.The mechanism with rotary cam
and rocking-follower with roll. In every kind of cam and follower mechanism on utilize a different
method for the best efficiency design.
Key Words: efficiency, power, cam, follower, roll, force, speed.
1. INTRODUCTION
FIn this paper the authors present an original method
to calculate the efficiency of the cam mechanisms.
The originality consists in the eliminating of frictionforces and friction coefficients. On determine just the
mechanical efficiency of cam mechanism.
In every kind of cam and follower mechanism on are
utilizing a different method for the design with maximal
efficiency.
In this paper on analyze three kinds of cam and
follower mechanisms.
2. DETERMINING THE MOMENTARY
MECHANICAL EFFICIENCY OF THE ROTARY
CAM AND PLATE TRANSLATED FOLLOWER
The consumed motor force, Fc, perpendicular in A onthe vector rA, is dividing in two components, [1]:
1. Fm, which represents the useful force, or the motor
force reduced to the follower;
2. F, which is the sliding force between the two
profiles of cam and follower, (see the picture 1).
Pc is the consumed power and Pu represents the useful
power.
The written relations are the next:
sin= cm FF (2.1)
sin12 = vv (2.2)
212 sin== vFvFP cmu (2.3)
1vFP cc = (2.4)
22
1
21
cossin
sin
==
=
==
vF
vF
P
P
c
c
c
ui (2.5)
220
2
2
22
')(
''sin
ssr
s
r
s
A ++== (2.6)
cos= cFF (2.7)
cos112 = vv (2.8)
(2.9)2
112 cos== vFvFP c
Fig. 1. Forces and speeds to the cam with plate
translated follower. Determining the efficiency.
22
1
21
sincos
cos
==
=
==
vF
vF
P
P
c
c
ci (2.10)
In the relation number (2.11) on determine the
mechanical efficiency:
}]')[(
')(1{5.0
220
0
MM
MM
ssr
ssr
M
++
+= (2.11)
3. DETERMINING THE MOMENTARY
MECHANICAL EFFICIENCY OF THE ROTARY
CAM AND TRANSLATED FOLLOWER WITH
ROLL
The written relations are the next:
20
22B s)(ser ++= (3.1)
2BB rr = (3.2)
B
B
r
e= sincos (3.3)
B
Br
ss += 0cossin (3.4)
O
A
r0
s
s
rA
1vr
2v r
1v 2r
B
C
D
Fr
mFr
cFr
E
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0A
A
B
A-
Fn, vn
Fm
, vm
Fa, va
Fi, viFn, vn
Fu, v2
B
B0
A0
A
O
x
e
s0
r0
rA
rB
s
n
C
rb
Fig. 2. Forces and speeds to the cam with translated follower with roll. Determining the efficiency.
The pressure angle, , is determined by the relations(3.5-3.6):
220
0
)'()(
cos
esss
ss
++
+= (3.5)
220 )'()(
'sin
esss
es
++
= (3.6)
sinsincoscos)cos( =+ (3.7)
)cos(2222
++= BbbBA rrrrr (3.8)
220
220
)'()(
)'()'()(
cos
esssr
esressse
A
b
A
++
+++=
=
(3.9)
220
2200
)'()(
])'()([)(
sin
esssr
resssss
A
b
A
++
+++=
=
(3.10)
cos'
)'()(
')(
)cos(
220
0 =++
+=
=
AA
A
r
s
esssr
sss (3.11)
2cos'
cos)cos( =A
Ar
s(3.12)
On can write the next forces and speeds (see the
picture 2):
Fm, vm, are perpendicular on the vector rA in A.
Fm is dividing in Fa (the sliding force) and Fn (the
normal force).
Fn is dividing too in Fi (the bending force) and Fu (the
useful force).
=
=
)sin(
)sin(
Ama
Ama
FF
vv(3.13)
(3.14)
=
=
)cos(
)cos(
Amn
Amn
FF
vv
=
=
sin
sin
ni
ni
FF
vv(3.15)
==
==
cos)cos(cos
cos)cos(cos2
Amnu
Amn
FFF
vvv(3.16)
(3.17)22
2 cos)(cos == Ammuu vFvFP
mmc vFP = (3.18)
The momentary mechanical efficiency can be
obtained by the relation (3.19):
4
2
222
2
22
22
cos'
]cos'
[
]cos)[cos(
cos)(cos
cos)(cos
==
==
==
=
=
==
AA
A
A
mm
Amm
c
ui
r
s
r
s
vF
vF
P
P
(3.19)
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4. DETERMINING THE MOMENTARY
MECHANICAL EFFICIENCY OF THE ROTARY
CAM AND ROCKING FOLLOWER WITH ROLL
The written relations are the next:
db
rrdb b
++=
2
)(cos
2022
0 (4.1)
02 += (4.2)
2222 cos)'1(2)'1( +=
=
bdbd
RAD(4.3)
RAD
bbd +=
'cossin 2
(4.4)
RAD
d 2sincos
= (4.5)
2222
cos2 += dbdbrB (4.6)
B
BB
rd
brd
+=
2cos
222
(4.7)
B
Br
b 2sinsin
= (4.8)
cossincossin)sin( 222 +=+ (4.9)
sinsincoscos)cos( 222 =+ (4.10)
22
++= BB (4.11)
)sin(cos 2 BB ++= (4.12)
)cos(sin 2 BB ++= (4.13)
)cos(sin
cos)sin(cos
2
2
++++=
B
BB(4.14)
)cos(cos
sin)sin(sin
2
2
+
+=
B
BB(4.15)
Brrrrr BbbBA cos2222 += (4.16)
BA
bBA
rr
rrr
+=
2cos
222
(4.17)
Br
r
A
b sinsin = (4.18)
+= BA (4.19)
sinsincoscoscos BBA = (4.20)
sincoscossinsin BBA += (4.21)
= 2A (4.22)
A
A
A
cos)cos(
sin)sin(
)cos(cos
2
2
2
+
+=
=++=
(4.23)
cos'
cos
=Ar
b(4.24)
2cos
'coscos
=
Ar
b(4.25)
Forces and speeds are writhing in the relations (4.26)
and the efficiency is writhen in the relation (4.27):
=
==
==
==
==
=
=
=
=
mmc
mmuu
mn
mnu
nc
nc
mn
mn
ma
ma
vFP
vFvFP
vvv
FFF
vv
FF
vv
FF
vv
FF
222
2
coscos
coscoscos
coscoscos
sin
sin
cos
cos
sin
sin
(4.26)
4
2
22
222
22
cos'
)cos'
()cos(cos
coscos
=
=
==
===
A
A
c
ui
r
b
r
b
P
P
(4.27)
On demonstrate now the mode of deduction for the
relation (4.24). On can see now a very difficult algorithm
for the obtained of this relation (4.24):
RAD
bd )'1(cossincos
cossin)sin(
22
22
=+
+=+(4.28)
]cos)cos(sin)[sin(
sinsin
22 BB
A
b
A
br
rB
r
r
++
== (4.29)
]sin)cos(cos)[sin(
coscos
22 BB
A
b
A
B
A
bB
r
r
r
r
r
Brr
+++
=
=(4.30)
RAD
b )'1(sinsinsin
coscos)cos(
22
22
=
=+(4.31)
])'1(cos
cos[1
)]sin(cos[1
)]sin(cos[1
]cossin)cos(
sin)sin(
cossin)cos(
cos)[sin(cos
sinsincoscoscos
2
2
22
2
2
22
2
22
RAD
bdr
bd
r
rbdr
rrr
r
r
r
r
b
A
b
A
bBB
A
BB
B
BB
B
A
bB
A
B
BBA
=
=+=
=+=
=+
++
+++
+=
==
(4.32)
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Fig. 3. Forces and speeds to the cam with rockingfollower with roll. Determining the efficiency.
])'1(sin
sin[1
)cos(sin
)cos(sin
]cos)cos(
cossin)sin(
cossin)sin(
sin)[cos(sin
sincoscossinsin
22
22
2
22
2
2
22
RAD
brb
r
r
r
r
b
r
r
r
r
r
r
r
r
b
A
A
b
A
A
bB
A
B
B
BB
BB
B
A
bB
A
B
BBA
=
=+=
=+=
=++
++
++
+=
=+=
(4.33)
RAD
bd )'1(cos)sin( 22
=+ (4.34)
RAD
b )'1(sin)cos( 22
=+ (4.35)
])'1(sin
sin[1
sin 22RAD
brb
r
b
A
A
= (4.36)
])'1(cos
cos[1cos
2
2
RAD
drbr
bdr
bb
A
A
+
+=
(4.37)
In figure number three, on can see the forces and the
speeds of the mechanism with rotary cam and rocking
follower with roll.
The cam and the follower are represented in two
positions, successively.
The distance between the two rotary centers is noted
by d. The radius of follower is b.
The movement laws are known: , , , .On can write the next forces and speeds (see the
picture 3):
Fm, vm, are perpendicular
on the vector rA in A.
Fm is dividing in Fa (the
sliding force) and Fn (the
normal force).
Fn is dividing too in Fc
(the compressed force) and Fu(the useful force).
For the mechanisms, with
rotary cam and diverse kind
of followers, on must utilize
different methods for
realizing the design with
maximal efficiency to every
type of follower.
cos'sin'sin'
])'1(sin
)'1(cossin
)'1(cossin)'1(sin
)'1(cossin
)'1(sin
)'1(cossinsin[1
cos)cos(sin)sin(cos
22
2
222
2
222
2
222
2
2
222
2
22
=
=
=
=
+
+
+
+
+
=
=++=
AAA
b
b
b
b
A
AA
r
b
RAD
d
r
b
RADr
db
RAD
dbr
RAD
br
bdb
RAD
br
RAD
dbr
bdbRADr
(4.38)
0
A
A
2
B
Fn, vn
Fm, vmFa, va
Fc, vc
Fn, vn
Fu, v2
B
B0
A0
x
rbr0
rA
rB
A
B
OD
0d
b
b
5. CONCLUSION
The follower with roll, make input-force, to be
divided in more components. This is the motive for that,
the dynamic and the precisely-kinematics of mechanism
with rotary cam and follower with roll, are more
different and difficult.
6. REFERENCES
[1] Petrescu, R., Petrescu, F. The gear synthesis with the
best efficiency. ESFA 03, Bucharest, Romania, 2003,
Vol. 2, p. 63-70.
[2] Antonescu P., Oprean M., Petrescu, Fl.,La projection
de la came oscillante chez les mechanismes a
distribution variable. CONAT MATMA 85, Braov,
Romania, 1985.
Authors: Drd. Eng. Florian-Ion PETRESCU, proffesor-
asisstent, Univ. POLITEHNICA Bucureti, chair TMR,
phone: 021. 4029632;Dr. Eng. Relly-Victoria PETRESCU, lecturer,
Univ. POLITEHNICA Bucureti, chair GDGI, phone:
0722.529.840.
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