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    International Conference on Engineering Graphics and Design - Bucharest,Romania 2005

    THE CAM DESIGN FOR A BETHER EFFICIENCY

    Florian PETRESCU, Relly PETRESCU

    Abstract: The paper presents an original method to determine the efficiency of a mechanism with cam

    and follower. The originality of this method consists in eliminate of the friction modulus. In this paper on

    analyze three types of cam mechanisms: 1.The mechanism with rotary cam and plate translated follower;

    2.The mechanism with rotary cam and translated follower with roll; 3.The mechanism with rotary cam

    and rocking-follower with roll. In every kind of cam and follower mechanism on utilize a different

    method for the best efficiency design.

    Key Words: efficiency, power, cam, follower, roll, force, speed.

    1. INTRODUCTION

    FIn this paper the authors present an original method

    to calculate the efficiency of the cam mechanisms.

    The originality consists in the eliminating of frictionforces and friction coefficients. On determine just the

    mechanical efficiency of cam mechanism.

    In every kind of cam and follower mechanism on are

    utilizing a different method for the design with maximal

    efficiency.

    In this paper on analyze three kinds of cam and

    follower mechanisms.

    2. DETERMINING THE MOMENTARY

    MECHANICAL EFFICIENCY OF THE ROTARY

    CAM AND PLATE TRANSLATED FOLLOWER

    The consumed motor force, Fc, perpendicular in A onthe vector rA, is dividing in two components, [1]:

    1. Fm, which represents the useful force, or the motor

    force reduced to the follower;

    2. F, which is the sliding force between the two

    profiles of cam and follower, (see the picture 1).

    Pc is the consumed power and Pu represents the useful

    power.

    The written relations are the next:

    sin= cm FF (2.1)

    sin12 = vv (2.2)

    212 sin== vFvFP cmu (2.3)

    1vFP cc = (2.4)

    22

    1

    21

    cossin

    sin

    ==

    =

    ==

    vF

    vF

    P

    P

    c

    c

    c

    ui (2.5)

    220

    2

    2

    22

    ')(

    ''sin

    ssr

    s

    r

    s

    A ++== (2.6)

    cos= cFF (2.7)

    cos112 = vv (2.8)

    (2.9)2

    112 cos== vFvFP c

    Fig. 1. Forces and speeds to the cam with plate

    translated follower. Determining the efficiency.

    22

    1

    21

    sincos

    cos

    ==

    =

    ==

    vF

    vF

    P

    P

    c

    c

    ci (2.10)

    In the relation number (2.11) on determine the

    mechanical efficiency:

    }]')[(

    ')(1{5.0

    220

    0

    MM

    MM

    ssr

    ssr

    M

    ++

    += (2.11)

    3. DETERMINING THE MOMENTARY

    MECHANICAL EFFICIENCY OF THE ROTARY

    CAM AND TRANSLATED FOLLOWER WITH

    ROLL

    The written relations are the next:

    20

    22B s)(ser ++= (3.1)

    2BB rr = (3.2)

    B

    B

    r

    e= sincos (3.3)

    B

    Br

    ss += 0cossin (3.4)

    O

    A

    r0

    s

    s

    rA

    1vr

    2v r

    1v 2r

    B

    C

    D

    Fr

    mFr

    cFr

    E

    245

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    0A

    A

    B

    A-

    Fn, vn

    Fm

    , vm

    Fa, va

    Fi, viFn, vn

    Fu, v2

    B

    B0

    A0

    A

    O

    x

    e

    s0

    r0

    rA

    rB

    s

    n

    C

    rb

    Fig. 2. Forces and speeds to the cam with translated follower with roll. Determining the efficiency.

    The pressure angle, , is determined by the relations(3.5-3.6):

    220

    0

    )'()(

    cos

    esss

    ss

    ++

    += (3.5)

    220 )'()(

    'sin

    esss

    es

    ++

    = (3.6)

    sinsincoscos)cos( =+ (3.7)

    )cos(2222

    ++= BbbBA rrrrr (3.8)

    220

    220

    )'()(

    )'()'()(

    cos

    esssr

    esressse

    A

    b

    A

    ++

    +++=

    =

    (3.9)

    220

    2200

    )'()(

    ])'()([)(

    sin

    esssr

    resssss

    A

    b

    A

    ++

    +++=

    =

    (3.10)

    cos'

    )'()(

    ')(

    )cos(

    220

    0 =++

    +=

    =

    AA

    A

    r

    s

    esssr

    sss (3.11)

    2cos'

    cos)cos( =A

    Ar

    s(3.12)

    On can write the next forces and speeds (see the

    picture 2):

    Fm, vm, are perpendicular on the vector rA in A.

    Fm is dividing in Fa (the sliding force) and Fn (the

    normal force).

    Fn is dividing too in Fi (the bending force) and Fu (the

    useful force).

    =

    =

    )sin(

    )sin(

    Ama

    Ama

    FF

    vv(3.13)

    (3.14)

    =

    =

    )cos(

    )cos(

    Amn

    Amn

    FF

    vv

    =

    =

    sin

    sin

    ni

    ni

    FF

    vv(3.15)

    ==

    ==

    cos)cos(cos

    cos)cos(cos2

    Amnu

    Amn

    FFF

    vvv(3.16)

    (3.17)22

    2 cos)(cos == Ammuu vFvFP

    mmc vFP = (3.18)

    The momentary mechanical efficiency can be

    obtained by the relation (3.19):

    4

    2

    222

    2

    22

    22

    cos'

    ]cos'

    [

    ]cos)[cos(

    cos)(cos

    cos)(cos

    ==

    ==

    ==

    =

    =

    ==

    AA

    A

    A

    mm

    Amm

    c

    ui

    r

    s

    r

    s

    vF

    vF

    P

    P

    (3.19)

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    4. DETERMINING THE MOMENTARY

    MECHANICAL EFFICIENCY OF THE ROTARY

    CAM AND ROCKING FOLLOWER WITH ROLL

    The written relations are the next:

    db

    rrdb b

    ++=

    2

    )(cos

    2022

    0 (4.1)

    02 += (4.2)

    2222 cos)'1(2)'1( +=

    =

    bdbd

    RAD(4.3)

    RAD

    bbd +=

    'cossin 2

    (4.4)

    RAD

    d 2sincos

    = (4.5)

    2222

    cos2 += dbdbrB (4.6)

    B

    BB

    rd

    brd

    +=

    2cos

    222

    (4.7)

    B

    Br

    b 2sinsin

    = (4.8)

    cossincossin)sin( 222 +=+ (4.9)

    sinsincoscos)cos( 222 =+ (4.10)

    22

    ++= BB (4.11)

    )sin(cos 2 BB ++= (4.12)

    )cos(sin 2 BB ++= (4.13)

    )cos(sin

    cos)sin(cos

    2

    2

    ++++=

    B

    BB(4.14)

    )cos(cos

    sin)sin(sin

    2

    2

    +

    +=

    B

    BB(4.15)

    Brrrrr BbbBA cos2222 += (4.16)

    BA

    bBA

    rr

    rrr

    +=

    2cos

    222

    (4.17)

    Br

    r

    A

    b sinsin = (4.18)

    += BA (4.19)

    sinsincoscoscos BBA = (4.20)

    sincoscossinsin BBA += (4.21)

    = 2A (4.22)

    A

    A

    A

    cos)cos(

    sin)sin(

    )cos(cos

    2

    2

    2

    +

    +=

    =++=

    (4.23)

    cos'

    cos

    =Ar

    b(4.24)

    2cos

    'coscos

    =

    Ar

    b(4.25)

    Forces and speeds are writhing in the relations (4.26)

    and the efficiency is writhen in the relation (4.27):

    =

    ==

    ==

    ==

    ==

    =

    =

    =

    =

    mmc

    mmuu

    mn

    mnu

    nc

    nc

    mn

    mn

    ma

    ma

    vFP

    vFvFP

    vvv

    FFF

    vv

    FF

    vv

    FF

    vv

    FF

    222

    2

    coscos

    coscoscos

    coscoscos

    sin

    sin

    cos

    cos

    sin

    sin

    (4.26)

    4

    2

    22

    222

    22

    cos'

    )cos'

    ()cos(cos

    coscos

    =

    =

    ==

    ===

    A

    A

    c

    ui

    r

    b

    r

    b

    P

    P

    (4.27)

    On demonstrate now the mode of deduction for the

    relation (4.24). On can see now a very difficult algorithm

    for the obtained of this relation (4.24):

    RAD

    bd )'1(cossincos

    cossin)sin(

    22

    22

    =+

    +=+(4.28)

    ]cos)cos(sin)[sin(

    sinsin

    22 BB

    A

    b

    A

    br

    rB

    r

    r

    ++

    == (4.29)

    ]sin)cos(cos)[sin(

    coscos

    22 BB

    A

    b

    A

    B

    A

    bB

    r

    r

    r

    r

    r

    Brr

    +++

    =

    =(4.30)

    RAD

    b )'1(sinsinsin

    coscos)cos(

    22

    22

    =

    =+(4.31)

    ])'1(cos

    cos[1

    )]sin(cos[1

    )]sin(cos[1

    ]cossin)cos(

    sin)sin(

    cossin)cos(

    cos)[sin(cos

    sinsincoscoscos

    2

    2

    22

    2

    2

    22

    2

    22

    RAD

    bdr

    bd

    r

    rbdr

    rrr

    r

    r

    r

    r

    b

    A

    b

    A

    bBB

    A

    BB

    B

    BB

    B

    A

    bB

    A

    B

    BBA

    =

    =+=

    =+=

    =+

    ++

    +++

    +=

    ==

    (4.32)

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    Fig. 3. Forces and speeds to the cam with rockingfollower with roll. Determining the efficiency.

    ])'1(sin

    sin[1

    )cos(sin

    )cos(sin

    ]cos)cos(

    cossin)sin(

    cossin)sin(

    sin)[cos(sin

    sincoscossinsin

    22

    22

    2

    22

    2

    2

    22

    RAD

    brb

    r

    r

    r

    r

    b

    r

    r

    r

    r

    r

    r

    r

    r

    b

    A

    A

    b

    A

    A

    bB

    A

    B

    B

    BB

    BB

    B

    A

    bB

    A

    B

    BBA

    =

    =+=

    =+=

    =++

    ++

    ++

    +=

    =+=

    (4.33)

    RAD

    bd )'1(cos)sin( 22

    =+ (4.34)

    RAD

    b )'1(sin)cos( 22

    =+ (4.35)

    ])'1(sin

    sin[1

    sin 22RAD

    brb

    r

    b

    A

    A

    = (4.36)

    ])'1(cos

    cos[1cos

    2

    2

    RAD

    drbr

    bdr

    bb

    A

    A

    +

    +=

    (4.37)

    In figure number three, on can see the forces and the

    speeds of the mechanism with rotary cam and rocking

    follower with roll.

    The cam and the follower are represented in two

    positions, successively.

    The distance between the two rotary centers is noted

    by d. The radius of follower is b.

    The movement laws are known: , , , .On can write the next forces and speeds (see the

    picture 3):

    Fm, vm, are perpendicular

    on the vector rA in A.

    Fm is dividing in Fa (the

    sliding force) and Fn (the

    normal force).

    Fn is dividing too in Fc

    (the compressed force) and Fu(the useful force).

    For the mechanisms, with

    rotary cam and diverse kind

    of followers, on must utilize

    different methods for

    realizing the design with

    maximal efficiency to every

    type of follower.

    cos'sin'sin'

    ])'1(sin

    )'1(cossin

    )'1(cossin)'1(sin

    )'1(cossin

    )'1(sin

    )'1(cossinsin[1

    cos)cos(sin)sin(cos

    22

    2

    222

    2

    222

    2

    222

    2

    2

    222

    2

    22

    =

    =

    =

    =

    +

    +

    +

    +

    +

    =

    =++=

    AAA

    b

    b

    b

    b

    A

    AA

    r

    b

    RAD

    d

    r

    b

    RADr

    db

    RAD

    dbr

    RAD

    br

    bdb

    RAD

    br

    RAD

    dbr

    bdbRADr

    (4.38)

    0

    A

    A

    2

    B

    Fn, vn

    Fm, vmFa, va

    Fc, vc

    Fn, vn

    Fu, v2

    B

    B0

    A0

    x

    rbr0

    rA

    rB

    A

    B

    OD

    0d

    b

    b

    5. CONCLUSION

    The follower with roll, make input-force, to be

    divided in more components. This is the motive for that,

    the dynamic and the precisely-kinematics of mechanism

    with rotary cam and follower with roll, are more

    different and difficult.

    6. REFERENCES

    [1] Petrescu, R., Petrescu, F. The gear synthesis with the

    best efficiency. ESFA 03, Bucharest, Romania, 2003,

    Vol. 2, p. 63-70.

    [2] Antonescu P., Oprean M., Petrescu, Fl.,La projection

    de la came oscillante chez les mechanismes a

    distribution variable. CONAT MATMA 85, Braov,

    Romania, 1985.

    Authors: Drd. Eng. Florian-Ion PETRESCU, proffesor-

    asisstent, Univ. POLITEHNICA Bucureti, chair TMR,

    phone: 021. 4029632;Dr. Eng. Relly-Victoria PETRESCU, lecturer,

    Univ. POLITEHNICA Bucureti, chair GDGI, phone:

    0722.529.840.

    248