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    FACULTY OF ENGINEERING AND BUILD ENVIRONMENT

    DEPARTMENT OF MECHANICAL AND MATERIAL ENGINEERING

    KKKP 4214 Automation and Robotics

    Lab Report 2

    Title:

    Formulize The Forward And Inverse Kinematics Of The FANUC Robot

    Lecturer:

    Dr. Rizauddin Ramli

    Group 2

    Name : CHAN KIEN HO

    Matric No. : A125070

    Department : JKMB/4

    Due Date : 11 June 2012

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    1.0 Dimension of the Fanuc Robot ARC Mate 100iC

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    2.0 Frame Assignment

    1) The joint and link configuration is simplified as shown in figure below:

    *unit in millimeter (mm)

    2) The D-H algorithm table is shown as below:

    Link i di ai i

    1 1 450 0 -90

    2 2 0 600 0

    3 3 200 0 90

    4 4 860 0 -905 5 100 0 90

    6 0 0 50 0

    *In this report, assume 6 = 0

    z1

    x1

    z2

    x2

    x3

    z3

    x4

    z4

    x5

    z5

    x6

    z6

    1

    2

    3

    4

    5

    6

    d5 =100

    d1 =450

    d2=600

    d3=200

    d4= 860

    d6 =50

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    3.0 Forward Kinematics Solution

    Using the D-H transformation matrix to obtain forward kinematic

    Matlab software is used to obtain , , , script is written and thenevaluation is done in the Matlab command window as shown below:

    The script file for all , , is shown in the following page.

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    Let , , for the corresponding D-Hmatrices

    The position and orientation of the robot tool frame with respect to the base frame are

    shown in the transformation matrix .

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    The computation is done using Matlab software, the results are:

    *( cos(x5) means cos 5 and so forth )

    nx = - cos(x5)*{sin(x1)*sin(x4) + cos(x4)*[cos(x1)*sin(x2)*sin(x3) -

    cos(x1)*cos(x2)*cos(x3)]}- sin(x5)*[cos(x1)*cos(x2)*sin(x3) +

    cos(x1)*cos(x3)*sin(x2)]

    ny = cos(x5)*{cos(x1)*sin(x4) + cos(x4)*[cos(x2)*cos(x3)*sin(x1) -

    sin(x1)*sin(x2)*sin(x3)]} - sin(x5)*(cos(x2)*sin(x1)*sin(x3) +

    cos(x3)*sin(x1)*sin(x2)

    nz = - sin(x5)*[cos(x2)*cos(x3) - sin(x2)*sin(x3)] - cos(x4)*cos(x5)*(cos(x2)*sin(x3) +

    cos(x3)*sin(x2))

    sx = sin(x4)*[cos(x1)*sin(x2)*sin(x3) - cos(x1)*cos(x2)*cos(x3)] - cos(x4)*sin(x1)sy = cos(x1)*cos(x4) - sin(x4)*[cos(x2)*cos(x3)*sin(x1) - sin(x1)*sin(x2)*sin(x3)]

    sz = sin(x4)*[cos(x2)*sin(x3) + cos(x3)*sin(x2)]

    ax = cos(x5)*(cos(x1)*cos(x2)*sin(x3) + cos(x1)*cos(x3)*sin(x2)) -sin(x5)*(sin(x1)*sin(x4) + cos(x4)*(cos(x1)*sin(x2)*sin(x3) -

    cos(x1)*cos(x2)*cos(x3)))

    ay = sin(x5)*(cos(x1)*sin(x4) + cos(x4)*(cos(x2)*cos(x3)*sin(x1) -sin(x1)*sin(x2)*sin(x3))) + cos(x5)*(cos(x2)*sin(x1)*sin(x3) +

    cos(x3)*sin(x1)*sin(x2))

    az = cos(x5)*[cos(x2)*cos(x3) - sin(x2)*sin(x3)]- cos(x4)*sin(x5)*[cos(x2)*sin(x3) +

    cos(x3)*sin(x2)]

    px = 600*cos(x1)*cos(x2) - 200*sin(x1) - 100*cos(x4)*sin(x1) -

    50*cos(x5)*{sin(x1)*sin(x4) + cos(x4)*[cos(x1)*sin(x2)*sin(x3) -

    cos(x1)*cos(x2)*cos(x3)]} + 100*sin(x4)*[cos(x1)*sin(x2)*sin(x3) -

    cos(x1)*cos(x2)*cos(x3)] - 50*sin(x5)*[cos(x1)*cos(x2)*sin(x3) +cos(x1)*cos(x3)*sin(x2)] + 860*cos(x1)*cos(x2)*sin(x3) +

    860*cos(x1)*cos(x3)*sin(x2)

    py = 200*cos(x1) + 100*cos(x1)*cos(x4) + 600*cos(x2)*sin(x1) +

    50*cos(x5)*{cos(x1)*sin(x4) + cos(x4)*[cos(x2)*cos(x3)*sin(x1) -

    sin(x1)*sin(x2)*sin(x3)]} - 100*sin(x4)*[cos(x2)*cos(x3)*sin(x1) -sin(x1)*sin(x2)*sin(x3)] - 50*sin(x5)*[cos(x2)*sin(x1)*sin(x3) +cos(x3)*sin(x1)*sin(x2)] + 860*cos(x2)*sin(x1)*sin(x3) +

    860*cos(x3)*sin(x1)*sin(x2)

    pz = 860*cos(x2)*cos(x3) - 600*sin(x2) - 860*sin(x2)*sin(x3) +

    100*sin(x4)*[cos(x2)*sin(x3) + cos(x3)*sin(x2)] - 50*sin(x5)*[cos(x2)*cos(x3) -

    sin(x2)*sin(x3)] - 50*cos(x4)*cos(x5)*[cos(x2)*sin(x3) + cos(x3)*sin(x2)]+ 450

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    4.0 Inverse Kinematics Solution

    Since there is only 3 equation which is Px, Pyand Pz , the five unknown 1 ,2 , 3 , 4 and

    5 are unable to be solved. Therefore, the unknown are solved separately by reducing the

    equation into 3 unknown.

    =

    Hence,

    Px = 600*cos(x1)*cos(x2) - 200*sin(x1) 1

    Py = 200*cos(x1) + 600*cos(x2)*sin(x1) 2

    Pz = 450 - 600*sin(x2) 3

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    Multiplying 1 and 2 with sin(x1) and cos(x1) respectively:

    Px*sin(x1) = 600*cos(x1)*cos(x2)*sin(x1)200*sin2(x1)

    Py*cos(x1)=200*cos2(x1) + 600*cos(x1)*cos(x2)*sin(x1)

    Px*sin(x1) - Py*cos(x1) = -200 [sin2(x1) + cos

    2(x1)]

    Px*sin(x1) - Py*cos(x1) = -200

    Let Px = d*cos()

    Py = d*sin()

    d =

    From

    3 , rewrite equation:

    600*sin(x2) = 450 - Pz

    (

    )

    1

    sin (x1 - ) =

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    Solving the remaining unknown,

    =

    Hence,

    Px = 860*sin(x3) - 100*cos(x3)*sin(x4) 4

    Py = -860*cos(x3) - 100*sin(x3)*sin(x4) 5

    Pz = 100*cos(x4) + 200 6

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    Solving the remaining unknown,

    =

    Hence,

    Px = 50*cos(x4)*cos(x5) - 100*sin(x4) 7

    Py = 100*cos(x4) + 50*cos(x5)*sin(x4) 8

    Pz = 860 - 50*sin(x5) 9

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    Multiplying 7 and8 with sin(x4) and cos(x4) respectively:

    Px*sin(x4) = 50*cos(x4)*cos(x5)*sin(x4) - 100*sin2(x4)

    Py*cos(x4)= 100*cos2(x4) + 50* cos(x4)*cos(x5)*sin(x4)

    Px*sin(x4) - Py*cos(x4) = -100 [sin2(x4) + cos

    2(x4)]

    Px*sin(x4) - Py*cos(x4) = -100

    Let Px = d*cos()

    Py = d*sin()

    d =

    From9 , rewrite equation:

    50*sin(x5) = 860 - Pz

    =

    (

    )

    1

    sin (x4 - ) =