Problem Explication

Group #3Amber Gipson

Erin KeyKelly Lee

Amy Ozley

#64 Calculate ∆H° for each of the following reactions using the data in

Appendix 4:

4Na(s) + O2(g) 2Na2O(s)

2Na(s) +2H2O(l) 2NaOH(aq) + H2(g)

2Na(s) + CO2(g) NA2O(s) + CO(g)

Explain why a water or carbon dioxide fire extinguisher might not be effective

in putting out a sodium fire.

Equation:*Product - Reactant = ΔH*

4Na(s) + O2(g) 2Na2O(s)

4 (0) + 0 2(-416) -832 – 0 ΔH= -832

EXOTHERMIC!

Equation:*Product - Reactant = ΔH*

2Na(s) +2H2O(l) 2NaOH(aq) + H2(g)

0 + 2(-286) 2(-470) + 0-940 - (-572) ΔH= -368

EXOTHERMIC!

Equation:*Product - Reactant = ΔH*

2Na(s) + CO2(g) NA2O(s) + CO(g)

2 (0) + -395.5 -416 + -110.5 -526.5 - -393.5 ΔH= -133.0

EXOTHERMIC!

Answer:

The reaction of water and sodium release heat.

The reaction of carbon dioxide and sodium release heat also.They are both exothermic

reactions.