prac 5 biodiversity

Upload: ytengku

Post on 07-Apr-2018

222 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/6/2019 Prac 5 Biodiversity

    1/5

    Prac 5 Understanding population Trends

    Task 1 Rhinoceros

    Step 2 both populations show exponential growth

    Step 4 Growth factor is approximately equal (~2) for both populations

    Question: The difference in population size at time interval 5 is due to differences in

    initial population size (ie. 30 vs 20). They both grow at the same rate.

    Rhinoceros Populations

    0

    200

    400

    600

    800

    1000

    1200

    1 2 3 4 5 6

    Time

    PopulationS

    ize

    Rhinocerus population A

    Rhinoceros Population B

  • 8/6/2019 Prac 5 Biodiversity

    2/5

    Task 2 Koala

    Step 2 both populations show exponential growth

    Step 4 Koala population A has the highest growth factor (approx 1.8) vs population B

    (approx 1.5)

    Question: The difference in population size at time interval 5 is due to differences in

    growth factor. Both populations have the same initial population size (20) but population Agrows more quickly.

    Task 2 Koalas

    0

    50

    100

    150

    200

    250

    300

    350

    400

    1 2 3 4 5 6

    Time

    Popul

    ation

    Size

    Koala population A

    Koala Population B

  • 8/6/2019 Prac 5 Biodiversity

    3/5

    Task 3 Zebra carrying capacity

    Step 2 both populations show sigmoidal growth.

    Step 4 Questions

    o Growth factor is not constant for either zebra population.

    o The growth factor is initially high in the first few time intervals, then

    progressively decreases as the size of the population grows (and approaches carrying capacity).

    o Zebra population A has the highest growth factor as its population size increases

    more rapidly than zebra population B. They both have the same population size at time 0 (ie

    N=20).

    o The carrying capacity for zebra population A is 600 as the curve reaches an

    asymptote. The carrying capacity for zebra population B is higher than 600 as the curve has not

    reached an asymptote, and the growth factor is still >1.0 (ie. 1.03) at population 600. However,

    its population size at K will not be much greater than 600.

    Zebra Populations Task 3

    0

    100

    200

    300

    400

    500

    600

    700

    1 2 3 4 5 6 7 8 9 10 11

    Time

    Population

    Size

    Zebra population A

    Zebra Population B

  • 8/6/2019 Prac 5 Biodiversity

    4/5

    Task 4 Zebra competition

    Step 2 both populations show sigmoidal growth.

    Step 4 Questions

    o Growth factor is not constant. Population A has the highest growth factor

    o For zebra population A growth factor follows the expected pattern for sigmoidal

    growth. It is high at first then decreases as population size approaches carrying capacity. Zebra

    population B follows the same sigmoidal growth pattern (but with a smaller growth factor) untilit approaches carrying capacity, but it then becomes less than 1.0 and population size decreases

    until it reaches a new carrying capacity.

    o The carrying capacity for zebra population A is now approximately 450 compared

    with 600 in Task 3. Carrying capacity for zebra population B is also lower than in Task 3 (now

    approx 150 compared to approx. 600).o Zebra population A has out-competed population B (ie. it has a larger population

    size). This can be attributed to a larger growth factor ie. population size grew more quickly.

    o The effect of competition has been to decrease R for both species (ie. both species

    are affected by competition).

    Zebra Task 4

    0

    50

    100

    150

    200

    250

    300

    350

    400

    450

    500

    1 2 3 4 5 6 7 8 9 10 11

    Time

    PopulationS

    iz

    Zebra population A

    Zebra Population B

  • 8/6/2019 Prac 5 Biodiversity

    5/5

    Other questions

    Graphs and tables either from the prac or an Excel spreadsheet, but labeled with R.

    the next four from the text book (Miller (2001) Ch 7).

    Because the quota for commercial harvesting eg. fishing is determined by dividing total

    biomass in the population by the number of fishers, random changes in K mean that the quotawill vary from year to year. This may be OK in good years, but in poor years when K is low, the

    quota will be low. This means a reduced quantity of fish for sale and reduced incomes for the

    fishers. Because people like to have a stable or growing income, there is pressure to maintain

    quotas (or increase them) even though the carrying capacity may have declined. This then putseven more pressure on the population (possibly threatening its survival).

    Do not carry out calculations for this last question. Basically either increase the number

    of licenses, or increase the quota to absorb the predicted increase in biomass (population size).