power flow and return loss

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  • 7/29/2019 Power Flow and Return Loss

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    Power Flow and

    Return LossWe have discovered that two waves propagate along a

    transmission line, one in each direction ( 0 0andj z j zV e V e ++ ).

    The result is that electromagnetic energy flows along the

    transmission line at a given rate (i.e., power).

    Q: How much power flows along a transmission line, and

    where does that power go?

    A: We can answer that question by determining the

    power absorbed by the load!

    0

    0

    ( ) j z j zV

    I z e e

    Z

    +

    + =

    +

    ( ) 0j z j zV z V e e ++ = +

    -

    +

    VL

    -

    A

    ZL

    IL

    z = A 0z =

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    The time average power absorbed by an impedance ZL is:

    { }

    { }

    ( ) ( ){ }

    ( ){ }

    ( )

    Re

    Re

    Re

    Re

    0 0 0 00 0

    0

    2

    20

    0

    2

    20

    0

    1

    2

    1 ( 0) ( 0)2

    1

    2

    12

    12

    abs L L

    j j j j

    P V I

    V z I z

    V e e V e e Z

    V

    Z

    VZ

    + ++ +

    +

    +

    =

    = = =

    = +

    =

    =

    The significance of this result can be seen by rewriting the

    expression as:

    ( )

    2

    20

    0

    2 2

    0 0

    0 0

    2 2

    0 0

    0 0

    12

    2 2

    2 2

    abs VP Z

    V V

    Z Z

    V V

    Z Z

    +

    + +

    +

    =

    =

    =

    The two terms in above expression have a very definite physical

    meaning. The first term is the time-averaged powerof the

    wave propagating along the transmission line toward the load.

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    We say that this wave is incident on the load:

    2

    0

    0

    inc

    VP P

    Z

    +

    += =

    Likewise, the second term of the Pabsequation describes the

    power of the wave moving in the other direction (away from

    the load). We refer to this as the wave reflected from the

    load:

    2 22

    20 0

    0 02 2incref

    V VP P PZ Z

    +

    = = = =

    Thus, the power absorbed by the load is simply:

    abs inc refP P P=

    or, rearranging, we find:

    inc abs refP P P= +

    This equation is simply an expression of the conservation of

    energy !

    It says that power flowing toward the load (Pinc) is either

    absorbed by the load (Pabs) or reflected back from the load

    (Pref).

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    Note that if2

    1 = , then Pinc= Pref, and therefore no power is

    absorbed by the load.

    This of course makes sense !

    The magnitude of the reflection coefficient ( ) is equal to one

    only when the load impedance is purely reactive (i.e., purely

    imaginary).

    Of course, a purely reactive element (e.g., capacitor or inductor)

    cannot absorb any powerall the power must be reflected!

    Return Loss

    The ratio of the reflected power to the incident power is known

    as return loss. Typically, return loss is expressed in dB:

    2

    10 1010 10. . log log ref

    inc

    PR L

    P

    = =

    ZL

    Pabs

    Pinc Pref

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    For example, if the return loss is 10dB, then 10% of the

    incident power is reflected at the load, with the remaining 90%

    being absorbed by the loadwe lose 10% of the incident

    power

    Likewise, if the return loss is 30dB, then 0.1 % of the incident

    power is reflected at the load, with the remaining 99.9% being

    absorbed by the loadwe lose 0.1% of the incident power.

    Thus, a larger numeric value for return loss actually indicates

    less lost power. An ideal return loss would be dB, whereas a

    return loss of 0 dB indicates that 1 = --the load is reactive!