phy cc 10 17-12-unit 5b_help_session_pub
DESCRIPTION
Slides from the Help Session going over the Study Guide for Unit 5.TRANSCRIPT
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Mrs. Reynolds
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About twenty percent of the National Football
League weighs more than 300 pounds. At this
weight, their Body Mass Index (BMI) places
them at Grade 2 obesity, which is one step
below morbid obesity. Determine the mass of a
300 pound (1330 N) football player.
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About twenty percent of the National Football
League weighs more than 300 pounds. At this
weight, their Body Mass Index (BMI) places
them at Grade 2 obesity, which is one step
below morbid obesity. Determine the mass of a
300 pound (1330 N) football player.
Fg = 300 lb. = 1330 N Fg = mg
g = 9.8 m/s^2 m = Fg/g
m = ? m = 1330 N/9.8 m/s^2
m = 136 kg
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According to the National Center for Health Statistics, the average mass of an adult American male is 86 kg. Determine the mass and the weight of an 86-kg man on the moon where the gravitational field is one-sixth that of the Earth. mearth = 86 kgGmoon = (1/6)g
= (1/6)*(9.8)mmoon = ?Fg moon = ?
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According to the National Center for Health Statistics, the average mass of an adult American male is 86 kg. Determine the mass and the weight of an 86-kg man on the moon where the gravitational field is one-sixth that of the Earth. mearth = 86 kg mass doesn’t changeGmoon = (1/6)g so mmoon = 86 kg
= (1/6)*(9.8)mmoon = ?Fg moon = ?
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According to the National Center for Health Statistics, the average mass of an adult American male is 86 kg. Determine the mass and the weight of an 86-kg man on the moon where the gravitational field is one-sixth that of the Earth. mearth = 86 kg Fg moon = mmoon Gmoon
Gmoon = (1/6)g Fg moon = (86)(9.8/6)= (1/6)*(9.8)Fg moon = 140 N
mmoon = ?Fg moon = ?
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a. Determine the net force required to
accelerate a 540-kg ultralight car from 0 to
27 m/s (60 mph) in 10.0 seconds.
b. Determine the net force required to
accelerate a 2160-kg Ford Expedition from 0
to 27 m/s (60 mph) in 10.0 seconds.
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a. Determine the net force required to
accelerate a 540-kg ultralight car from 0 to
27 m/s (60 mph) in 10.0 seconds.
m = 540 kg
vi = 0
vf = 27 m/s
t = 10.0 s
Fnet = ?
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a. Determine the net force required to
accelerate a 540-kg ultralight car from 0 to 27
m/s (60 mph) in 10.0 seconds.
m = 540 kg To find Fnet we need
vi = 0 mass and accel. We
vf = 27 m/s have mass, but not accel.
t = 10.0 s So we need to find accel.
Fnet = ?
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a. Determine the net force required to
accelerate a 540-kg ultralight car from 0 to 27
m/s (60 mph) in 10.0 seconds.
m = 540 kg Fnet = ma
vi = 0 Fnet = (540 kg)(2.7 m/s^2)
vf = 27 m/s Fnet = 1458 N
t = 10.0 s
a = 2.7 m/s^2
Fnet = ?
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b. Determine the net force required to
accelerate a 2160-kg Ford Expedition from 0
to 27 m/s (60 mph) in 10.0 seconds.
m = 2160 kg
vi = 0
vf = 27 m/s
t = 10.0 s
Fnet = ?
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b. Determine the net force required to
accelerate a 2160-kg Ford Expedition from 0 to
27 m/s (60 mph) in 10.0 seconds.
m = 2160 kg Fnet = ma
vi = 0 Fnet = (2160 kg)(2.7 m/s^2)
vf = 27 m/s Fnet = 5832 N
t = 10.0 s
a = 2.7 m/s^2
Fnet = ?
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The Top Thrill Dragster stratacoaster at Cedar Point Amusement Park in Ohio uses a hydraulic launching system to accelerate riders from 0 to 54 m/s (120 mi/hr) in 3.8 seconds before climbing a completely vertical 420-foot hill . Determine the net force required to accelerate an 86-kg man. vi = 0 m/s Fnet = ?vf = 54 m/st = 3.8 s To find Fnet we need to findd = 420 ft acceleration.m = 86 kg
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The Top Thrill Dragster stratacoaster at Cedar Point Amusement Park in Ohio uses a hydraulic launching system to accelerate riders from 0 to 54 m/s (120 mi/hr) in 3.8 seconds before climbing a completely vertical 420-foot hill . Determine the net force required to accelerate an 86-kg man. vi = 0 m/s Fnet = ?vf = 54 m/st = 3.8 sd = 420 ftm = 86 kga = 14.2 m/s^2
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Blake is dragging a bag of grass from the
garage to the street on the evening before
garbage pick-up day with a force of 40.2 N.
The frictional force between the bag and
the ground is 5.7 N. What is the net force
acting on the bag?
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Blake is dragging a bag of grass from the
garage to the street on the evening before
garbage pick-up day with a force of 40.2 N.
The frictional force between the bag and
the ground is 5.7 N. What is the net force
acting on the bag?
40.2
N
5.7 N
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Silas and Ivey are members of the stage crew
for the Variety Show. Between acts, they must
quickly move a Baby Grand Piano onto stage.
After the curtain closes, they exert a sudden
forward force of 524 N to budge the piano from
rest and get it up to speed. The 158-kg piano
experiences 418 N of friction.a. What is the piano's acceleration during this phase of
its motion?
b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
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They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.a. What is the piano's acceleration during this phase of
its motion?
F1 = 524 N forward
F2 = 418 N backward
m = 158 kg
a = ?
524 N418 N
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They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.a. What is the piano's acceleration during this phase of
its motion?
F1 = 524 N forward Fnet = 524 N – 418 N = 106 N
F2 = 418 N backward
m = 158 kg
a = ?
524 N418 N
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They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.a. What is the piano's acceleration during this phase of
its motion?
F1 = 524 N forward Fnet = 524 N – 418 N = 106 N
F2 = 418 N backward Fnet = ma, so a = Fnet/m
m = 158 kg a = (106 N)/(158 kg)
a = ? a = 0.671 m/s^2
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They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
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They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
a = 0.671 m/s^2
t = 1.44 s
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They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
a = 0.671 m/s^2
t = 1.44 s
vi = 0 m/s
vf = ?
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They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
a = 0.671 m/s^2
t = 1.44 s
vi = 0 m/s
vf = ?
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They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
a = 0.671 m/s^2 vf = vi + at
t = 1.44 s
vi = 0 m/s
vf = ?
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They exert a sudden forward force of 524 N to
budge the piano from rest and get it up to
speed. The 158-kg piano experiences 418 N of
friction.b. If Silas and Ivey maintain this forward force for 1.44
seconds, then what speed will the piano have?
a = 0.671 m/s^2 vf = vi + at
t = 1.44 s vf = 0 + (0.671 m/s^2)(1.44 s)
vi = 0 m/s vf = 0.966 m/s
vf = ?
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