percentage yield calculations. however, not all of the reactants may actually be converted into...
TRANSCRIPT
Percentage Yield Calculations.
However, not all of the reactants may actually be converted into products.
As we have seen, some reactions have 100% atom economy i.e. all the atoms of the reacting molecules are converted into useful products.
C2H4 H2O C2H6O+e.g.
There are several reasons for this :a. The reaction may be reversible.
Such reactions never go to completion and some of the reactants always remain.
N2 + 3H2 2NH3
e.g.
The Haber Process
What happens to the un reacted nitrogen and hydrogen gases ?
Unreacted gases are recycled
b. An un wanted ‘side reaction’ may occur reducing the yield of the desired product.
This often occurs in Drug manufacture.
Unwanted Impurity
Unwanted Impurity
Wanted Product
c. The product may be impure and require purification before use.
This purification process always causes mass to be ‘lost’.
e.g. pharmaceutical products
We can assess how efficient the production process will be by calculating the percentage yield.
Percentage Yield = Actual Yield of Product
Maximum possible yieldx 100
For example:
A pharmaceutical process is being used to produce aspirin.The process could produce a maximum possible yield of 350g.The actual yield of aspirin after purification is only 270g.
Calculate the Percentage Yield.Answer
Percentage Yield = Actual Yield of Product Maximum possible
yield
x 100
= 270 x 100350
= 77.1 %
e.g. 1
The Haber Process.Nitrogen reacts with Hydrogen to form Ammonia
according to the following equation:
N2 + 3H2
2NH3
200 kg of nitrogen are used to produce the ammonia.48.6 kg of ammonia are produced.
(i.) Calculate the maximum possible yield of ammonia.(ii.) Calculate the actual percentage yield.
Answer
(i.)
Step 1. Write the information under the equation.
200 kg Yield 48.6 kg
Step 2. Calculate the Mr values for each molecule.
Mr (N2) = 2 x 14 = 28
Mr (NH3) = 14 + 3 x 1 = 17
Mr (N2) = 28
Mr (NH3) = 17
Atom Economy100 %?????
Step 3
Use the equation
1 N2 produces 2 NH3Step
4Convert to masses.1 x 28 kg of N2 produces 2 x 17 kg
of NH3 28 kg of N2 produces 34 kg of NH31 kg of N2 produces 34 / 28 kg
of NH3200 kg of N2 produces 34 / 28 x 200 kg of NH3 = 243 kg of
NH3
Maximum Possible Yield
N2 + 3H2
2NH3
Mr (N2) = 28Mr (NH3) = 17
Percentage Yield = Actual Yield of Product Maximum possible
yield
x 100Answer
(ii.)
= 48.6 / 243 x 100= 20 %
Atom Economy
100%
Although the reaction has a 100% atom economy, only 20% of the reactants are actually converted into products.