notes 21.1a solving equations by factoring · example: factor…!!+11!+30 look at c: if c is...
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Notes21.1a
SolvingEquationsbyFactoring𝒙𝟐 + 𝒃𝒙+ 𝒄(part1)Rememberthatthequadraticexpression;𝑥! + 𝑏𝑥 + 𝑐istheproductoftwopolynomialfactors 𝑥 + 𝑑 𝑥 + 𝑒 .
𝑥 + 𝑑 𝑥 + 𝑒 = 𝑥! + 𝑏𝑥 + 𝑐Forexample: 𝑥 + 5 𝑥 + 2 = 𝑥! + 7𝑥 + 10
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WhenweFactoraQuadraticExpressionwesimplygointheotherdirection:convertfromthequadraticformbackintoitspolynomialfactors.
𝑥! + 𝑏𝑥 + 𝑐 = 𝑥 + 𝑑 𝑥 + 𝑒 Forexample:
𝑥! + 7𝑥 + 10 = 𝑥 + 5 𝑥 + 2
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Because… 𝒙+ 𝒅 𝒙+ 𝒆
= 𝒙𝟐 + 𝒅𝒙+ 𝒆𝒙+ 𝒅𝒆
= 𝒙𝟐 + 𝒃𝒙+ 𝒄Tofactorthiskindofquadratic:𝒙𝟐 + 𝒃𝒙+ 𝒄…Weneedtofindtwonumbers𝒅 and 𝒆,thatwhen:1. multipledtogetherequalthec2. addedtogetherequaltotheb
𝒅 ∙ 𝒆 = 𝒄 𝐚𝐧𝐝 𝒅+ 𝒆 = 𝒃
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Example:Factor…𝑥! + 11𝑥 + 30𝒙𝟐 + 𝒃𝒙 + 𝒄
Lookatc:Ifcispositive𝒅 and 𝒆havethesamesign:positivebecause𝒃ispositive.Ifcisnegative𝒅 and 𝒆havedifferentsigns.1)Signs:
2)Listallofthefactorpairsforcandtheirsums:
3)Usethefactorpairthatworksforbothcandb
4)Makethefactors: 𝑥! + 11𝑥 + 30 =
Factorsof Theirsum
1and30 1+30=31
2and15 2+15=17
3and10 3+10=13
5and6 5+6=11
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Example:𝑥! + 11𝑥 + 30
1)cispositvethesignswillbethesame.2)Listallofthefactorpairsforc30andtheirsums:3)Usethefactorpairthatworksforbothc30andb11,thatis:5and6
4)Makethefactors: 𝑥! + 11𝑥 + 30 = (𝒙 + 𝟓)(𝒙 + 𝟔)
Factorsof30 Theirsum1and30 1+30=31
2and15 2+15=17
3and10 3+10=13
5and6 5+6=11
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Example:𝑥! + 13𝑥 − 30
1)Signs
2)Listallofthefactorpairsforcandtheirsums:
3)Usethefactorpairthatworksforbothcandb:
4)Makethefactors: 𝑥! + 13𝑥 − 30 =
Factorsof Theirsum
1and–30 1–30=–29
2and–15 2–15=–13
3and–10 3–10=–7
5and–6 5–6=–1
–1and30 –1+30=29
–2and15 –2+15=13
–3and10 –3+10=7
–5and6 –5+6=1
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Example:𝑥! + 13𝑥 − 30
1)cisnegativethesignswillbedifferent.
2)Listallofthefactorpairsforc–30andtheirsums:
3)Usethefactorpairthatworksforbothc–30andb13:–2and15
4)Plugthemin: 𝑥! + 13𝑥 − 30 = (𝒙 − 𝟐)(𝒙 + 𝟏𝟓)
Factorsof–30 Theirsum
1and–30 1+(–30)=–29
2and–15 2+(–15)=–13
3and–10 3+(–10)=–7
5and–6 5+(–6)=–1
–1and30 –1+30=29
–2and15 –2+15=13
–3and10 –3+10=7
–5and6 –5+6=1