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MCE 473: Mini Project 1 Sadikujjaman Bachu 45254 Submitted to: Dr Jin-Hyuk Lee In this report the maximum stress and deflection of a support structure (shelf) is analyzed using ANSYS APDL. 3/24/2015

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  • MCE 473: Mini Project 1 Sadikujjaman Bachu 45254

    Submitted to: Dr Jin-Hyuk Lee

    In this report the maximum stress and deflection of a support structure (shelf) is analyzed

    using ANSYS APDL.

    3/24/2015

  • 1 | P a g e

    List of Figures and Tables

    Figure 1: Steel Shelf and Element Cross Section ............................................................... 2

    Figure 2: Simplified structure ............................................................................................. 3

    Figure 3: Preference ............................................................................................................ 4

    Figure 4: Element type ........................................................................................................ 4

    Figure 5: Cross-sectional area (0.125 in2) .......................................................................... 5

    Figure 6: Material Props ..................................................................................................... 5

    Figure 7: Keypoints............................................................................................................. 6

    Figure 8: Lines .................................................................................................................... 6

    Figure 9: Number of elements ............................................................................................ 7

    Figure 10: Mesh .................................................................................................................. 7

    Figure 11: Boundary Conditions and Forces ...................................................................... 8

    Figure 12: Deformed (+ un-deformed) plot ........................................................................ 9

    Figure 13: Stress ............................................................................................................... 10

    Figure 14: Support reactions ............................................................................................. 11

    Figure 15: Deformed (+ un-deformed) plot using a composite tube ................................ 12

    Figure 16: Stress using a composite tube .......................................................................... 13

    Figure 17: Support reactions using a composite tube ....................................................... 14

    Table 1: Given data ............................................................................................................. 3

  • 2 | P a g e

    Introduction

    In this report the maximum stress and deflection of the support structure shown below is

    analyzed using ANSYS APDL.

    Figure 1: Steel Shelf and Element Cross Section

    To simplify the problem a 2-D model of the pin-jointed structure that supports each joint

    of the shelf is considered. This is possible because of the symmetry of the shelf, therfore,

    saving time required by ANSYS to compute the results. Furthermore, twisting of the

    structure is neglected by using truss element for simplicity of the problem.

  • 3 | P a g e

    Figure 2: Simplified structure

    The force of 1200 lbf acting on the middle of the shelf is divided by the four corners to

    give 300 lbf at each.

    Table 1: Given data

    Cross Sectional Area

    (in^2)

    Youngs Modulus

    (Psi)

    Possoins

    ratio

    Steel 0.125 30E6 0.27

    Composite

    tube

    0.35 1.2E7 0.3

  • 4 | P a g e

    Procedure

    Click Preference and then select Structural

    Figure 3: Preference

    Define the Element type from Preprocessor and select link

    Figure 4: Element type

  • 5 | P a g e

    Click on Real Constants and add the cross-sectional area

    Figure 5: Cross-sectional area (0.125 in2)

    From Material Props click on Material Models and add the properties (Youngs

    modulus and the Poissons ratio)

    Figure 6: Material Props

  • 6 | P a g e

    From Modelling select Create and click Keypoints and then In Active CS

    Add the coordinate and click on Apply

    Figure 7: Keypoints

    From Modelling select Create and click Lines, Lines and then In Active Coord

    Figure 8: Lines

  • 7 | P a g e

    From Meshing, Mesh Attributes, Size Cntrls, Lines select All Lines and type 1

    in number of elements

    Figure 9: Number of elements

    From Meshing, Mesh, Lines select All Lines and click OK

    Figure 10: Mesh

  • 8 | P a g e

    From Solution, Apply, Structural, Displacement, click on On Nodes and select

    UX and UY to add the Boundary Conditions on nodes 1 and 3

    From Solution, Apply, Structural, Force, add the force on nodes 1 and 2

    Figure 11: Boundary Conditions and Forces

    For the 5th part the material is assigned by going to Meshing, Mesh Attributes,

    Picked Lines and select the lines and set the material.

  • 9 | P a g e

    Results

    Figure 12: Deformed (+ un-deformed) plot

    1. From the above figure it can be seen that the maximum deformation is at node 2.

    The value of the deformation is 0.00867 in. This is a valid result since all the

    other nodes are constrained, it makes sense that the node 2 will deform.

  • 10 | P a g e

    Figure 13: Stress

    2. From the above figure it can be seen that the maximum stress is on element 2 and

    the value is 4000 psi. This is because of the diagonal setting of the truss and since

    it has no fixed ends. While the minimum stress is on element 1 and the value is -

    3200 psi.

    3. The yield strength of commonly used steel is 280 1600 MPa, but by converting

    the max stress of 4000 psi it turns out to be 27.58 MPa. This shows that it is much

    smaller than the yield strength; therefore, the steel shelf is safe.

  • 11 | P a g e

    Figure 14: Support reactions

    4. h

  • 12 | P a g e

    Figure 15: Deformed (+ un-deformed) plot using a composite tube

    5. From the above figure it can be seen that the maximum deformation is at node 2

    again. The value of the deformation is 0.008091 in. This is a valid result since all

    the other nodes are constrained, it make sense that the node 2 will deform.

  • 13 | P a g e

    Figure 16: Stress using a composite tube

    From the above figure it can be seen that the maximum stress is on element 2 and

    the value is 1428.57 psi. This is because of the diagonal setting of the truss and

    since it has no fixed ends. This value is much smaller than that of steel trusses.

    Therefore, by adding a composite tube for element 2 we successfully reduced the

    stress acting in the steel shelf. While the minimum stress is still on element 1 and

    the value is -3200 psi. An important thing here that can be seen is that the min

    stress is larger than the max stress but it is compressive due to the negative sign.

    The yield strength of commonly used steel is 280 1600 MPa, but by converting

    the max stress of 1428.57 psi it turns out to be 9.85 MPa. This shows that it is

    much smaller than the yield strength, even smaller than the only steel truss;

    therefore, the steel shelf is much safer when the composite tube is used.

  • 14 | P a g e

    Figure 17: Support reactions using a composite tube

    The support reactions remain the same since the forces acting on the elements are

    the same.

  • 15 | P a g e

    Conclusion

    In this project we learned to analyze the displacement and stresses on a 2-D truss

    structure. In the 1st part the truss is made using all steel elements. The maximum stress is

    found to be 4000 psi and the max displacement is 0.00867 in. In the 2nd part the element

    2 material is changed to composite tube and the other elements were kept as steel. This

    resulted in a significantly lower max stress, 1428.57 psi. The max displacement did not

    change much, it decreased very slightly. When compared to the yield strength both the

    truss models were found to be safe since the values of the max stresses are much lower

    than the yield strength.

    The use of ANSYS APDL has made it much easier to solve FEM problems such as this

    project and others. It is also very helpful to be able to apply the analytical procedure in

    this program due to its method of input, which is very similar to that of how we solve by

    hand.