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11
b) Rango de Edades Xi fi Fi xi fi (xi - x ) 2 (xi - x ) 2 . fi [18 – 28 > [28 – 38> [38 – 48> [48 – 58> [58 a 68> 23 33,5 43,5 53,5 0 63 40 20 15 15 10 40 60 75 90 100 920 670 652,5 0 802,5 0 630 189.06 10,56 45,56 280,56 689,06 7562,40 211,20 683,4 4208,4 6890,6 100 3675, 00 1214,80 1955,6 MEDIA x= 920+670 +652,50+802,50 +630 100 x= 3675 100 x=36,75

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b)

Rango de Edades Xi fi Fi xi fi (xi - x)2 (xi - x)2 . fi

[18 – 28 >

[28 – 38>

[38 – 48>

[48 – 58>

[58 a 68>

23

33,5

43,5

53,50

63

40

20

15

15

10

40

60

75

90

100

920

670

652,50

802,50

630

189.06

10,56

45,56

280,56

689,06

7562,40

211,20

683,4

4208,4

6890,6

100 3675,00 1214,80 1955,6

MEDIA

x=920+670+652,50+802,50+630100

x=3675100

x=36,75

MODA

Mo = 18 + 10 ( 40−0(40−0 )+(40−20))

Mo = 18 + 10 ( 4040+20 )

Mo = 18 + 10 (0,67)

Mo = 24,70

Rango de Edades18 28 38 48 58 68

40

30

20

10

fi

MEDIANA

Me = 28 + 10 ( 50−4040 )

Me = 28 + 10 ( 1040 )

Me = 28 + 10 (0,25)

Me = 30,50

DESVIACIÓN ESTÁNDAR

S2 = 1955,6

100

S2 = 4,42

d)

Ingreso mensual Xi fi Fi xi fi (xi - x)2 (xi - x)2 . fi

[0 - 750 >

[750 - 1500>

[1500 - 2250>

[2250 - 3000>

375

1125

1875

2625

35

40

15

10

35

75

90

100

13125

45000

28125

26250

562 500

0

562 500

2250 000

19687500

0

19687500

22500000

100 112500 3375000 61875000

MEDIA

x=112500100

x=¿ 1125

MODA

Mo = 750 + 750 ( 40−35(40−35 )+(40−15) )

Mo = 750+ 750 [ 55+30 ]

Mo = 750 + 107,14

Mo = 857,14

Ingreso mensual (soles) 750 1500 2250 3000

40

30

20

10

fi

MEDIANA

Me = 750 + 750 ( 50−3540 )

Me = 750 + 750 ( 1540 )

Me = 750 + 750 (0,375)

Me = 1031,25

DESVIACIÓN ESTÁNDAR

S2 = 61875000

100

S = 786,6

f)

Horario de preferencia

Xi fi Fi xi fi (xi - x)2 (xi - x)2 . fi

[10 am – 13 pm >

[13 pm – 16 pm>

[16 pm – 19 pm>

[19 pm – 22 pm>

11,5

14,05

17,5

20,5

25

10

25

40

25

35

60

100

287.5

145

437,5

820

29,16

5,76

0,36

12,96

729

57,6

9

518,4

100 1690 48,24 1314

MEDIA

x=1690100

=16,9

x=¿ 16,9

MODA

Mo = 19 + 3 ( 40−25(40−25 )+(40−0))

Mo = 19 + 3 ( 1515+40 )

Mo = 19 + 3 ( 1555 )

Mo = 19,82

MEDIANA

Me = 16 + 3 ( 50−3540 )

Me = 16 + 3 ( 1540 )

Me = 17,125

DESVIACIÓN ESTÁNDAR

S2 = 1314100

S = 3,62

40

30

20

10

fi

9)

Tiempo de espera Xi fi Fi xi fi (xi - x)2 (xi - x)2 . fi[0 – 10 >

[10 – 20 >

[20 – 30 >

[30 – 40 >

[40 – 50 >

5

15

25

35

45

5

10

16

50

20

5

15

30

80

100

25

150

375

1750

900

715,56

280,56

45,56

10,56

175,56

3577,8

2805,6

683,4

528

3511,2

100 3175 1227,80 11106

MEDIA

x=3175100

x=¿ 31,75

MODA

Mo = 30 + 10 ( 50−15(50−15 )+ (50−20 ) )

Mo = 30 + 10 ( 3535+30 )

Mo = 30 + 10 ( 3565 )

Mo = 35,38

Horario de preferencia

10 13 16 19 22am pm pm pm pm

Tiempo de espera minutos10 20 30 40 50

50

40

30

20

10

fi

MEDIANA

Me = 30 + 10 ( 50−3050 )

Me = 30 + 10 ( 2050 )

Me = 34

DESVIACIÓN ESTÁNDAR

S2 = 11106100

S = 10,54