major test-6.pdf

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CHEMISTRY

Q.1 In which of the following pairs are both the ions coloured in aqueous solution ?

[At. Nos. Sc = 21, Ti = 22, Ni = 28 and Cu = 29] (1) Sc3+, Co2+ (2) Ni2+, Cu+ (3) Ni2+, Ti3+ (4) Sc3+, Ti3+ Q.2 Calculate the standard free energy change for the

reaction, 2 Ag + 2H+ → H2 + 2Ag+, E° for Ag+ + e– → Ag is 0.80 V (1) + 154.4 kJ (2) + 308.8 kJ (3) – 154.4 kJ (4) – 308.8 kJ Q.3 Which of these is not a method for preparation

of dihydrogen - (1) Passing steam over hot iron (2) Reaction of hydrolith with water (3) mixture of water gas & steam is passed over

suitable catalyst (4) Reaction of sodium hydride with water Q.4 Which of the following compounds on reaction

with CH3MgBr will give a tertiary alcohol ? (1) CH3CH––CHCH3

O

(2) C2H5CO2CH3

(3) C6H5CHO (4) C2H5COOH Q.5 Consider the equilibrium

CO2(g) CO(g) + 2

1O2(g)

The equilibrium constant K is given by (when α <<< 1) :

(1) 2

K2/3α= (2)

2K

3α=

(3) 2

K2/3α= (4)

3K

2/3α=

Q.1 fuEu esa ls fdl ;qXe esa tyh; foy;u esa nksuksa vk;u jaxhu gS ?

[ijek.kq Øekad Sc = 21, Ti = 22, Ni = 28 o Cu = 29] (1) Sc3+, Co2+ (2) Ni2+, Cu+ (3) Ni2+, Ti3+ (4) Sc3+, Ti3+

Q.2 2 Ag + 2H+ → H2 + 2Ag+ vfHkfØ;k ds fy,, ekud eqä ÅtkZ ifjorZu Kkr dhft,

Ag+ + e– → Ag ds fy, E° = 0.80 V gS (1) + 154.4 kJ (2) + 308.8 kJ (3) – 154.4 kJ (4) – 308.8 kJ

Q.3 fuEu esa ls dkSulh MkbZgkbMªkstu ds fuekZ.k dh fof/k ugha gS -

(1) xeZ vk;ju ds Åij ok"i xqtkjuk (2) ty ds lkFk gkbMªksfyFk dh vfHkfØ;k (3) ty xSl o Hkki dk feJ.k mi;qDr mRizsjd ls

xqtkjuk (4) ty ds lkFk lksfM;e gkbMªkbM dh vfHkfØ;k

Q.4 fuEu esa ls dkSulk ;kSfxd CH3MgBr ds lkFk vfHkfØ;k ij r`rh;d ,YdksgkWy nsxk ?

(1) CH3CH––CHCH3

O

(2) C2H5CO2CH3

(3) C6H5CHO (4) C2H5COOH

Q.5 fuEu lkE; ij fopkj dhft,

CO2(g) CO(g) + 2

1O2(g)

lkE; fLFkjkad K fdl izdkj fn;k tkrk gS (tc α <<< 1) :

(1) 2

K2/3α= (2)

2K

3α=

(3) 2

K2/3α= (4)

3K

2/3α=



Q.6 The reaction, 2CH3COCH3 → − ether,HgMggives :

(1)

OH OH

(2) O

(3) CH3CH2CH2CH2CH–CH2

OH OH

(4) C2H5

C2H5 C––C

OH OH

CH3

CH3

Q.7

X

E2

elimination Saytzeff product

+Hofmann product

In the above reaction, maximum saytzeff product will be obtained where X is :

(1) ––I (2) ––Cl (3) ––Br (4) ––F Q.8 Cellulose and starch are - (1) Homo polymer (2) Hetero polymer (3) Bio monomer (4) Addition polymers Q.9 A mixture of Acetone & Methanol can be

separated by - (1) Solvent extraction (2) Sublimation (3) Distillation (4) Distillation under reduced pressure Q.10 The region which is greatly affected by air

pollution is : (1) Thermosphere (2) Stratosphere (3) Mesosphere (4) Troposphere

Q.6 vfHkfØ;k, 2CH3COCH3 → − ether,HgMgnsrh gS :

(1)

OH OH

(2) O

(3) CH3CH2CH2CH2CH–CH2

OH OH

(4) C2H5

C2H5 C––C

OH OH

CH3

CH3

Q.7

X

E2

foyksiu lsRtsQmRikn

+gkWQekumRikn

mijksDr vfHkfØ;k esa] vf/kdre lsRtsQ mRikn izkIr gksxk tgk¡ X gS : (1) ––I (2) ––Cl (3) ––Br (4) ––F

Q.8 lsY;qyksl rFkk LVkpZ gS -

(1) lecgqyd (2) fo"ke cgqyd

(3) tSo ,dyd (4) ;ksxkRed cgqyd

Q.9 ,lhVksu rFkk esFksukWy ds feJ.k dks dSls iFkd fd;k tk ldrk gS -

(1) foyk;d fu"d"kZ.k (2) m/oZikru (3) vklou (4) de nkc ij vklou

Q.10 ks=k tks ok;q iznq"k.k ls lokZf/kd izHkkfor gksrk gS :

(1) rkih; e.My (2) lerki e.My

(3) e/;e.My (4) kksHk e.My



Q.11 Layers of carbon atoms in graphite are held together by :

(1) coordinate covalent bond (2) covalent bonds (3) van der waals forces (4) double bonds

Q.12 The rate of reaction at different time is found as

follows

t (in min) R(in m/l l l l /sec)

0 2.8 × 10–2

10 2.78 × 10–2

20 2.81 × 10–2

30 2.79 × 10–2

order of reaction is (1) Zero (2) One (3) Two (4) Three

Q.13 Which of the following metals imparts green

colour to the Bunsen flame ? (1) Sr (2) Cs (3) Ca (4) Ba Q.14 The osmotic pressure of a solution at 300 K is 3

atm. What will be the osmotic pressure if its concentration is reduced to half and its temperature is raised to 400 K ?

(1) 1 atm (2) 2 atm (3) 4 atm (4) None Q.15 Which of the following compounds possesses the

C-H bond with the lowest bond dissociation energy -

(1) Toluene (2) Benzene

(3) n-Pentane (4) 2, 2-Dimethyl propane

Q.11 xzsQkbV esa dkcZu ijek.kqvksa dh ijrsa fuEu kjk ,d

lkFk ca/kh gksrh gS :

(1) milgla;kstd ca/k

(2) lgla;kstd ca/k

(3) ok.Mjoky cy

(4) fvkca/k

Q.12 fHkUu le; ij vfHkfØ;k dh nj fuEu izdkj ik;h

tkrh gS

t (in min) R(in m/l l l l /sec) 0 2.8 × 10–2 10 2.78 × 10–2 20 2.81 × 10–2 30 2.79 × 10–2

vfHkfØ;k dh dksfV gS

(1) 'kwU; (2) ,d

(3) nks (4) rhu

Q.13 fuEu esa ls dkSulh /kkrq cqUlu Tokyk esa gjk jax nsrh

gS ?

(1) Sr (2) Cs (3) Ca (4) Ba

Q.14 300 K ij foy;u dk ijklj.kh nkc 3 atm gSA ;fn

bldh lkanzrk dks vk/kk dj fn;k tk, rFkk blds rki

dks 400 K rd c<+k fn;k tk, rks ijklj.kh nkc D;k

gksxk ? (1) 1 atm (2) 2 atm (3) 4 atm (4) dksbZ ugha

Q.15 fuEufyf[kr ;ksfxdksa esa ls fdlesa C-H vkcU/k dh cU/k

fo;kstu ÅtkZ (bond dissociation energy) U;wure gS &

(1) VkWywbZu (2) csUthu

(3) n-isUVsu (4) 2, 2-MkbesfFky izksisu



Q.16 The decreasing order of basic characters of the following is :

(I)

N. .

(II) N. .

H

(III)

NH2

NH

. .

(IV)

NH2

. .

(1) III > IV > I > II (2) III > I > IV > II (3) IV > III > II > I (4) I > II > III > IV Q.17 A primary nitroalkane is treated with nitrous

acid, which of the following will be the main product ?

(1) Pseudonitrol (2) Nitrolic acid (3) A primary amine (4) Primary alcohol Q.18 The oxidation no. of Fe in brown ring complex is - (1) + 1 (2) + 2 (3) + 3 (4) + 4 Q.19 Calculate equivalent weight of Fe in Fe3O4 (Fe = 56)

(1) 56 (2) 56/2 (3) 56/3 (4) 8

563×

Q.20 C7H8O shows how many isomers (aromatic) ? (1) 2 (2) 3 (3) 4 (4) 5

Q.21 ψ310 has :

(1) 1 radial node and 1 angular node




Q.16 fuEu dk kkjh; yk.kksa dk ?kVrk Øe gS : (I)

N. .

(II) N. .

H

(III)

NH2

NH

. .

(IV)

NH2

. .

(1) III > IV > I > II (2) III > I > IV > II (3) IV > III > II > I (4) I > II > III > IV Q.17 ,d izkFkfed ukbVªks,Ydsu dks ukbVªl vEy ls

mipkfjr fd;k tkrk gS] rks fuEu esa ls dkSulk eq[;

mRikn gksxk ?

(1) L;wMksukbVªksy (2) ukbVªksfyd vEy

(3) izkFkfed ,ehu (4) izkFkfed ,YdksgkWy Q.18 Hkwjh oy; ladqy esa Fe dh vkWDlhdj.k la[;k gS - (1) + 1 (2) + 2 (3) + 3 (4) + 4

Q.19 Fe3O4 esa Fe ds rqY;akdh Hkkj dh x.kuk dhft, (Fe = 56)

(1) 56 (2) 56/2 (3) 56/3 (4) 8

563×

Q.20 C7H8O fdrus leko;oh n'kkZ,xk ¼,sjksesfVd½ ?

(1) 2 (2) 3 (3) 4 (4) 5

Q.21 ψ310 esa gS :

(1) 1 f=kT;h; uksM+ rFkk 1 dks.kh; uksM






Q.22 Product of the reaction would be

OH + C2H5 – I

EtO– Na+

Anhy. C2H5OH (1) C2H5–O–C2H5 (2) C6H5–O–C6H5

(3)

I (4)

O––C2H5

Q.23 Which of the following statements are correct ? a. The smaller the gold number of lyophobic

colloid, the larger will be its protective power. b. Lyophilic sols, are generally chargeless. c. Ferric chloride solution is used to stop

bleeding from a fresh cut because it coagulates the blood.

d. The flocculation value of arsenious sulphide sol is independent of the anion of the coagulating electrolyte.

(1) a, b and c (2) a, c, and d (3) b, c and d (4) a, b Passage based Questions : (Q.24 to 25)

Phosphorus forms two hydrides, phosphine and diphosphine, P2H4, being analogous to NH3 and N2H4. Elementary phosphorus reacts with H2 at

300° C to form PH3. The hydrolysis of metal phosphides is a convenient route of prepration of PH3. White phosphorus also reacts with hot water to produce phosphine and hypophosphorus acid.

Hydrazine, N2H4, may be viewed as an oxidation product of NH3 and may linked to H2O2 which

may be viewed as an oxidation product of H2O. It is obtained by oxidising aqueous ammonia by hypochlorite under boiling in the presence of glue or gelatin.

NH3 + NaOCl → NH2Cl + NaOH NH2Cl + NH3 → N2H4 + HCl

Q.22 vfHkfØ;k dk mRikn gksxk

OH + C2H5 – I

EtO– Na+

Anhy. C2H5OH (1) C2H5–O–C2H5 (2) C6H5–O–C6H5

(3)

I (4)

O––C2H5

Q.23 fuEu esa ls dkSuls dFku lR; gS ? a. nzo fojks/kh dksykbZM dh Lo.kZ la[;k ftruh de

gksxh bldh jk.k kerk mruh gh vf/kd gksxhA b. nzo fojks/kh lksy lkekU;r% vkos'kjfgr gksrs gSA c. Qsfjd DyksjkbZM foy;u dks rktk dVs ?kko ls jDr

ds cgus dks jksdus esa iz;qDr fd;k tkrk gS D;ksafd ;g jDr dks LdfUnr djrk gSA

d. vflZfu;l lYQkbZM lksy dk LdUnu eku] LdUnuh; oS|qr vi?kV~; ds _.kk;u ls Lora=k gksrk gSA

(1) a, b o c (2) a, c, o d (3) b, c o d (4) a, b

x|ka'k ij vk/kkfjr iz'u : (Q.24 to 25)

QkWLQksjl] nks gkbMªkbM QkWLQhu o MkbZQkWLQhu P2H4

fufeZr djrk gS] tks NH3 and N2H4 ds letkr gksrk gS

izk:fid QkWLQksjl 300° C ij H2 ls fØ;k djds PH3

cukrk gSA /kkrq QkWLQkbM dk ty vi?kVu] PH3 ds fuekZ.k

dk vklku rjhdk gSA 'osr QkWLQksjl xeZ ty ls fØ;k

djds QkWLQhu o gkbiksQkWLQksjl vEy mRiUu djrk gSA

gkbMªsthu N2H4, NH3 ds vkWDlhdj.k mRikn ds :i esa gks

ldrk gS rFkk H2O2 ls caf/kr gks ldrk gS tks H2O ds

vkWDlhdj.k mRikn ds :i esa gks ldrk gSA ;s xksan ;k

ftysVhu dh mifLFkfr esa xeZ djus ij gkbiksDyksjkbV ls

vkWDlhd`r tyh; veksfu;k kjk izkIr gksrk gSA

NH3 + NaOCl → NH2Cl + NaOH

NH2Cl + NH3 → N2H4 + HCl



Q.24 PH5 is not known Because

(1) P5+ is reduced by the H– (2) PH5 so produced decomposed to PH3&H 2. (3) H form 3 centre 2 electron bond between the

two PH3 molecules (4) To attain the five valent state, d orbital must

be used and hydrogen is not sufficiently electronegative to make d orbitals contract sufficiently.

Q.25 On heating Pb(NO3)2 produces a pale yellow gas

which on strong heating produces– (1) N2O4, brown gas (2) N2, colourless gas (3) NO2, brown gas (4) N2O3 , pale blue gas

Q.26

C OH

OPCl5 A

Me2NH . .

B

Find structure of compound B :

(1)

C N

OMe

Me

(2)

CH2 N

Me

Me

(3)

C O N

OMe

Me

(4)

O

C–N ⊕

Cl

Q.27 Semi essential amino acids are - (1) Lysine and Glycine (2) Arginine and Aspartic acid (3) Glutamic acid and Histidine (4) Histidine and arginine

Q.24 PH5 Kkr ugha gS D;ksafd

(1) P5+, H– kjk vipf;r gksrk gS

(2) PH5 vr% mRiUu PH3o H2 esa vi?kfVr gksrs gS

(3) H, nks PH3 v.kqvksa ds e/; 3 dsUnz 2 bysDVªkWu ca/k

fufeZr djrk gS

(4) ikap la;ksth voLFkk izkIr djus ds fy,] d dkd dk

mi;ksx djrk gS rFkk i;kZIr d dkd ladqpu gksus

ds fy, gkbMªkstu i;kZIr fo|qr_.kh ugha gksrk gS Q.25 Pb(NO3)2 dks xeZ djus ij gYdh ihyh xSl mRiUu

gksrh gS tks vf/kd xeZ djus ij mRiUu djsxk – (1) N2O4, Hkwjh xSl (2) N2, jaxghu xSl (3) NO2, Hkwjh xSl (4) N2O3 , gYdh uhyh xSl

Q.26

C OH

OPCl5 A

Me2NH . .

B

;kSfxd B dh lajpuk Kkr dhft, :

(1)

C N

OMe

Me

(2)

CH2 N

Me

Me

(3)

C O N

OMe

Me

(4)

O

C–N ⊕

Cl

Q.27 v)Zvfuok;Z ,ehuks vEy gS - (1) ykblhu rFkk Xyk;lhu (2) ,thZukbu rFkk ,LikfVZd vEy (3) XyqVsfed vEy rFkk fgLVhMhu (4) fgLVhMhu rFkk ,thZukbu



Q.28 Morphine and codiene are - (1) Non narcotic analgesics (2) Tranquillizers (3) Analgesics (4) Hypnotic Tranquillizers Q.29 If the ionization constant of acetic acid is

1.8 × 10–5, at what concentration will it be dissociated to 2% ?

(1) 1M (2) 0.018 M (3) 0.18 M (4) 0.045 M Q.30 In a container, m gm of gas placed. After some

time, some gas is allowed to escape from container. The pressure of gas become half and its absolute temp 2/3 rd. The amount of gas escaped is

(1) 3

2m (2)

2

1 m (3)

4

1m (4)

6

1m

Q.31 Which of the following order is incorrect ? (1) O2

–2 > O2– > O2 > O2

+ (Order of bond length) (2) Li2SO4 < Na2SO4 < K2SO4 < Cs2SO4 (Order of thermally stable) (3) H2O > H2S > H2Se > H2Te (Order of volatility) (4) ClF3 < H2O < CH4 < NO2

+ (Order of bond angle) Q.32 Calculate the enthalpy of combustion for the

following reaction : 2HC ≡ CH + 5O2 → 4CO2 + 2H2O

The bond energies of C–H, C ≡ C, O = O, C = O and O–H bonds are 414, 812, 494, 707 and 463 kJ mol–1 respectively.

(1) –1758 kJ (2) + 1758 kJ (3) – 819 kJ (4) None

Q.28 ekWQhZu rFkk dksMhu gS - (1) vukdksZfVd nnZfuokjd (2) iz'kkUrd ¼funzkdkjh½ (3) nnZfuokjd (4) lEeksgd iz'kkUrd

Q.29 ;fn ,lhfVd vEy dk vk;uu fLFkjkad 1.8 × 10–5 gS]

rks fdl lkanzrk ij ;s 2% fo;ksftr gks tk,xk ?

(1) 1M (2) 0.018 M

(3) 0.18 M (4) 0.045 M Q.30 ,d ik=k esa] m gm xSl mifLFkr gSA dqN le;

i'pkr~ dqN xSl ik=k ls fu"dkflr gks tkrh gSA xSl

dk nkc vk/kk gks tkrk gS rFkk bldk ije rki 2/3

jg tkrk gSA fu"dkflr xSl dh ek=kk gS

(1) 3

2m (2)

2

1 m (3)

4

1m (4)

6

1m

Q.31 fuEu esa ls dkSulk Øe xyr gS ?

(1) O2–2 > O2

– > O2 > O2+ (ca/k yEckbZ dk Øe)

(2) Li2SO4 < Na2SO4 < K2SO4 < Cs2SO4 (Å"eh; LFkkf;Ro dk Øe) (3) H2O > H2S > H2Se > H2Te (ok"i'khyrk dk Øe) (4) ClF3 < H2O < CH4 < NO2

+ (ca/kdks.k dk Øe)

Q.32 fuEu vfHkfØ;k ds fy, ngu dh ,UFkSYih Kkr dhft, :

2HC ≡ CH + 5O2 → 4CO2 + 2H2O

C–H, C ≡ C, O = O, C = O rFkk O–H cU/kksa dh ca/k

ÅtkZ,sa Øe'k% 414, 812, 494, 707 o 463 kJ mol–1

gS

(1) –1758 kJ (2) + 1758 kJ

(3) – 819 kJ (4) dksbZ ugha



Q.33

Ph–CH=C–CH3 + HBr | CH3

Peroxide[X]

Major product [X]is

(1)

Ph–CH–CH–CH3

| Br

| CH3

(2)

Ph–CH2–C–CH3 |

| Br

CH3

(3) Ph–CH2–CH–CH2–Br | CH3

(4) Ph–CH=C–CH2–Br | CH3

Q.34 The main product of the following reaction is

?)CH(CH)OH(CHCHHC 42SOH.conc23256 →

(1) H5C6CH2CH2

H3C C=CH2

(2) H5C6

H

C=C

H

CH(CH3)2

(3) C6H5CH2

H

C=C

CH3

CH3

(4)

C6H5

H

C=C

CH(CH3)2

H

Q-33

Ph–CH=C–CH3 + HBr | CH3

Peroxide[X]

eq[; mRikn 'X' gS -

(1)

Ph–CH–CH–CH3

| Br

| CH3

(2)

Ph–CH2–C–CH3 |

| Br

CH3

(3) Ph–CH2–CH–CH2–Br | CH3

(4) Ph–CH=C–CH2–Br | CH3

Q.34 fuEu vfHkfØ;k dk eq[; mRikn gS

?)CH(CH)OH(CHCHHC 42SOH.conc23256 →

(1) H5C6CH2CH2

H3C C=CH2

(2) H5C6

H

C=C

H

CH(CH3)2

(3) C6H5CH2

H

C=C

CH3

CH3

(4) C6H5

H

C=C

CH(CH3)2

H



Passage based Questions : (Q.35 & Q.36) Four rearrangement reactions are given : (I) MeO CONH2

Br2/OH (B)

(II) MeO CONHOH OH

(B)

(A)

(A)

(III) MeO CON3∆

(B)

(IV) MeO COOHN3H/H⊕

∆ (B)

H3O⊕

H3O⊕

H3O⊕

H3O⊕

Compound (C)

Q.35 Which statement (s) is/are wrong about the

reactions ? (1) All the reactions proceed via the formation of

acyl nitrene

MeO C–N.. . .

O as

intermediate species

(2) All the reactions procced via the formation of alkyl isocyanate as the intermediate compound

(3) In all the reactions, the product (C) is p-methoxy aniline

(4) In all the reactions, the product (C) is aniline Q.36 Which statements (s) is/are wrong about the

reaction ? (1) EDG (e-donating group) at o-and p-position

of a migrating aryl group accelerates the reaction

(2) Slow and rate-determining step (R.D.S) is the formation of isocyanate from acyl nitrene

(3) The overall reaction involves the elimination of (CO) as CO2

(4) Using optically active reactant, there is retention of configuration in the product

x|ka'k ij vk/kkfjr iz'u: (iz.35o iz-36) pkj iquZfoU;kflr vfHkfØ;k,sa nh xbZ gS : (I) MeO CONH2

Br2/OH (B)

(II) MeO CONHOH OH

(B)

(A)

(A)

(III) MeO CON3∆

(B)

(IV) MeO COOHN3H/H⊕

∆ (B)

H3O⊕

H3O⊕

H3O⊕

H3O⊕

Compound (C)

Q.35 dkSulk dFku vfHkfØ;kvksa ds lanHkZ esa xyr gS ? (1) lHkh vfHkfØ;k,sa e/;orhZ Lih'kht ds :i esa

,fly ukbVªhu

MeO C–N.. . .

O ds

fuekZ.k kjk lEiUu gksrh gS (2) lHkh vfHkfØ;k,sa e/;orhZ ;kSfxd ds :i esa

,fYdy vkblkslk;usV ds fuekZ.k kjk lEiUu gksrh gS

(3) lHkh vfHkfØ;kvksa esa] mRikn (C) p-esFkksDlh ,uhyhu gksrk gS

(4) lHkh vfHkfØ;kvksa esa] mRikn (C) ,uhyhu gksrk gS Q.36 dkSulk dFku vfHkfØ;k ds lanHkZ esa xyr gS ?

(1) izfrLFkkih ,fjy lewg dh o o p-fLFkfr ij

EDG (e -nkrk lewg) vfHkfØ;k dks Rofjr djrk gS

(2) /khek ,oa nj fu/kkZj.k in (RDS) ,fly ukbVªhu

ls vkblkslk;usV dk fuekZ.k djrk gS

(3) iw.kZ vfHkfØ;k esa CO2 ds :i esa (CO) dk

foyksiu lfEefyr gksrk gS

(4) izdk'k lfØ; fØ;kdkjd ds mi;ksx ij] ;gka

mRikn esa foU;kl dk izrhiu gksrk gS



Q.37 The lanthanide contraction is responsible for the

fact that :

(1) Zr and Y have about the same radius

(2) Zr and Nb have similar oxidation state

(3) Zr and Hf have about the same radius

(4) Zr and Zn have the same oxidation state

Q.38 A gaseous alkane exploded with oxygen. The

volume of O2 & CO2 in reaction is 7 : 4.

Calculate molecular formula of alkane.

(1) CH4 (2) C2H6

(3) C3H8 (4) C4H10

Q.39 Which is a pair of geometrical isomers ?

(I) ClH C=C

BrBr

(II) ClH C=C

BrCH3

(III) Cl Br C=C

CH3

H (IV)

HCl C=C

Br

CH3

(1) (I) and (II) (2) (I) and (III)

(3) (II) and (IV) (4) (III) and (IV)

Q.40 In which of the following pairs both the

complexes show optical isomerism ?

(1) cis-[Cr(C2O4)2Cl2]3–, cis-[Co(NH3)4Cl2]

(2) [Co(en)3]Cl3,cis-[Co(en)2Cl2]Cl

(3) cis-[Pt(en)2Cl2]+2, [Ni(en)2]

(4) [Co(NO3)3(NH3)3], cis-[Pt(en)2Cl2]

Q.37 ysaFksukbM ladqpu fuEu rF; ds fy, mÙkjnk;ha gS :

(1) Zr o Y yxHkx leku f=kT;k j[krs gS

(2) Zr o Nb leku vkWDlhdj.k voLFkk j[krs gS

(3) Zr o Hf yxHkx leku f=kT;k j[krs gS

(4) Zr o Zn leku vkWDlhdj.k voLFkk j[krs gS

Q.38 ,d xSlh; ,Ydsu dks vkWDlhtu ds lkFk j[kk x;k

gSA vfHkfØ;k esa O2 o CO2 dk vk;ru 7 : 4 gSA

,Ydsu ds v.kqlw=k dh x.kuk dhft,A

(1) CH4 (2) C2H6 (3) C3H8 (4) C4H10

Q.39 dkSulk T;kferh leko;fo;ksa dk ;qXe gS ?

(I) ClH C=C

BrBr

(II) ClH C=C

BrCH3

(III) Cl Br C=C

CH3

H (IV)

HCl C=C

Br

CH3

(1) (I) o (II) (2) (I) o (III)

(3) (II) o (IV) (4) (III) o (IV)

Q.40 fuEu esa ls fdl ;qXe esa nksuksa ladqy izdkf'kd

leko;ork n'kkZrs gS ?

(1) leik-[Cr(C2O4)2Cl2]3–, leik-[Co(NH3)4Cl2]

(2) [Co(en)3]Cl3, leik-[Co(en)2Cl2]Cl

(3) leik-[Pt(en)2Cl2]+2, [Ni(en)2]

(4) [Co(NO3)3(NH3)3], leik-[Pt(en)2Cl2]



MATHEMATICS

Q.41 N is the set of natural numbers. The relation R is

defined on N × N as -

(a, b) R (c, d) : a + d = b + c is

(1) Reflexive (2) Symmetric

(3) Transitive (4) All of these

Q.42 If 1, ω, ω2, …ωn–1 are nth roots of unity then

1n2 2

1....

2

1

2

1−ω−

++ω−

+ω−

=

(1) 12

1

−n (2)

12

)12(

+−

n

nn

(3) 12

2)2( 1

−− −

n

nn (4) None

Passage based (Q.43 & 44 )

Let f(x) = x2 + b1x + c1, g(x) = x2 + b2x + c2. Let

real roots of f(x) = 0 be α, β & real roots of

g(x) = 0 be α + δ, β + δ, also assume that least

value of f(x) is 4

1− & least value of g(x) occurs at

x = 7/2 -

Q.43 The least value of g(x) is -

(1) –1 (2) 2

1−

(3) 4

1− (4)

3

1−

Q.44 The value of b2 is -

(1) 0 (2) –7

(3) 6 (4) 8

Q.41 N izkd`r la[;kvks dk leqPp; gSA lEcU/k R, N × N

ij bl izdkj ifjHkkf"kr gS fd

(a, b) R (c, d) : a + d = b + c gS] rc R gS

(1) LorqY; (2) lefer

(3) laØked (4) mijksDr lHkh

Q.42 ;fn 1, ω, ω2, …. ,ωn–1 bdkbZ ds n os ewy gS rc

12 2

1....

2

1

2

1−ω−

++ω−

+ω− n

=

(1) 12

1

−n (2)

12

)12(

+−

n

nn

(3) 12

2)2( 1

−− −

n

nn (4) dksbZ ugha

x|ka'k ij vk/kkfjr(Q.43 & 44 )

ekuk f(x) = x2 + b1x + c1, g(x) = x2 +b2x + c2 gSA

ekuk f(x) = 0 ds okLrfod ewy α, β gS vkSj

g(x) = 0 ds okLrfod ewy α + δ , β + δ gSA ekuk fd

f(x) dk U;wure eku 4

1− gS vkSj g(x) dk U;wure eku

x = 7/2 ij gSA

Q.43 g(x) dk U;wure eku gS-

(1) –1 (2) 2

1−

(3) 4

1− (4)

3

1−

Q.44 b2 dk eku gSA

(1) 0 (2) –7

(3) 6 (4) 8



Q.45 If the mean of the set of numbers x1, x2, …,xn is

x , then mean of the numbers xi + 2i, 1≤ i ≤ n is -

(1) x +2n (2) x + n +1

(3) x + 2 (4) x + n

Q.46 A(α, β) =

αα−αα

βe00

0cossin

0sincos

, thenA(α, β)–1 is

equal to -

(1) A(–α, β) (2) A(–α, –β)

(3) A(α, –β) (4) A(α, β)

Q.47 Adj

−−

−=

−−b

a

22

011

25

120

211

201

.Then

[a b] is equal to -

(1) [–4 1] (2) [–4 –1]

(3) [4 1] (4) [4 –1]

Q.48 If non-zero vectors a and b are equally

inclined to vector c , then c is-

(1) bba

ba

ba

a

||||

||

||2||

||

++

+

(2) bba

aa

ba

b

||||

||

||||

||

++

+

(3) bba

ba

ba

a

||2||

||

||2||

||

++

+

(4) None of these

Q.45 ;fn la[;vks x1, x2, …,xn ds leqPp; dk ek/; x gS]

rc la[;kvksa xi + 2i, 1≤ i ≤ n dk ek/; gS -

(1) x +2n (2) x + n +1

(3) x + 2 (4) x + n

Q.46 A(α, β) =

αα−αα

βe00

0cossin

0sincos

gS] rc A(α, β)–1

cjkcj gS -

(1) A(–α, β) (2) A(–α, –β)

(3) A(α, –β) (4) A(α, β)

Q.47 Adj

−−

−=

−−b

a

22

011

25

120

211

201

gSA rc

[a b] cjkcj gS -

(1) [–4 1] (2) [–4 –1]

(3) [4 1] (4) [4 –1]

Q.48 ;fn v'kwU; lfn'k a rFkk b lfn'k c ds lkFk

leku dks.k cukrh gS] rc c gS-

(1) bba

ba

ba

a

||||

||

||2||

||

++

+

(2) bba

aa

ba

b

||||

||

||||

||

++

+

(3) bba

ba

ba

a

||2||

||

||2||

||

++

+

(4) buesa ls dksbZ ugha



Q.49 The position vectors of the vertices A, B and C of

a triangle are three unit vectors ba ˆ,ˆ and c ,

respectively. A vector d is such that d . a =

d . b = d . c and d = λ ( b + c ). Then triangle

ABC is -

(1) acute angled (2) obtuse angled

(3) right angled (4) none of these

Q.50 The direction ratios of a normal to the plane

through (1, 0, 0) and (0, 1, 0), which makes an

angle of 4

π with the plane x + y = 3 are -

(1) < 1, 2 , 1 > (2) < 1, 1, 2 >

(3) < 1, 1, 2 > (4) < 2 , 1, 1 >

Q.51 The coordinates of the point P on the line

)ˆˆˆ()ˆˆˆ( kjikjir −+−λ+++=→

which is nearest

to the origin is -

(1)

3

2,

3

4,

3

2 (2)

−−3

2,

3

4,

3

2

(3)

−3

2,

3

4,

3

2 (4) none of these

Q.52 I1 = ∫π

+

2/

02

2

cos1

cosdx

x

x, I2 = ∫

π

+

2/

02

2

sin1

sindx

x

x

I3 = ∫π

++2/

022

22

sincos24

sincos21

xx

xx dx then-

(1) I1 = I2 > I3 (2) I3 > I1 = I2

(3) I1 = I2 = I3 (4) none

Q.49 ,d f=kHkqt ds 'kh"kZ A, B rFkk C ds fLFkfr lfn'k

Øe'k% rhu bdkbZ lfn'k ba ˆ,ˆ rFkk c gSA ,d lfn'k

d bl izdkj gS dh d . a = d . b = d . c rFkk

d = λ ( b + c )gSA rc f=kHkqt ABC gS -

(1) U;wu dks.kh; (2) vf/kd dks.kh;

(3) ledks.kh; (4) buesa ls dksbZ ugha

Q.50 (1, 0, 0) rFkk (0, 1, 0) ls xqtjus okys lery ds

vfHkyEc ds fnd~ vuqikr] tks lery x + y = 3 ds

lkFk 4

π dk dks.k cukrk gS] gS -

(1) < 1, 2 , 1 > (2) < 1, 1, 2 >

(3) < 1, 1, 2 > (4) < 2 , 1, 1 >

Q.51 js[kk )ˆˆˆ()ˆˆˆ( kjikjir −+−λ+++=→

ij fcUnq P ds

funsZ'kkad tks ewy fcUnq ds utnhd gS] gS-

(1)

3

2,

3

4,

3

2 (2)

−−3

2,

3

4,

3

2

(3)

−3

2,

3

4,

3

2 (4) buesa ls dksbZ ugha

Q.52 I1 = ∫π

+

2/

02

2

cos1

cosdx

x

x, I2 = ∫

π

+

2/

02

2

sin1

sindx

x

x

I3 = ∫π

++2/

022

22

sincos24

sincos21

xx

xx dx rc -

(1) I1 = I2 > I3 (2) I3 > I1 = I2

(3) I1 = I2 = I3 (4) dksbZ ugha



Q.53 ∫π

π

3/

4/

)(sincos xdcxe for 0 < x < π/2 is -

(1) ln2 (2) – ln2

(3) ln

2/1sin

2/1sin (4) none

Q.54 If the derivative of f(x) w. r. to x is )(

sin21 2

xf

x−

then f(x) is a periodic function with period -

(1) π (2) 2π

(3) π/2 (4) none

Q.55 The given function

f(x) =

≥−<<−−++

−≤

1,||

11,]1[]1[

1,||

xxx

xxx

xxx

is

(1) even (2) odd

(3) nither even nor odd (4) none

Q.56 Tangent having slope of 3

4− to the ellipse

3218

22 yx + =1 intersects the major and minor axes

at points A and B respectively . If C is the centre

of the ellipse, then the area of the ∆ABC is -

(1) 12 sq. units (2) 24 sq. units

(3) 36 sq. units (4) 48 sq. units

Q.53 0 < x < π/2 ds fy, ∫π

π

3/

4/

)(sincos xdcxe gS -

(1) ln2 (2) – ln2

(3) ln

2/1sin

2/1sin (4) dksbZ ugha

Q.54 ;fn x ds lkisk f(x) dk vodyu )(

sin21 2

xf

x− gS] rc

f(x) vkorhZ Qyu gS ftldk vkorZukad -

(1) π (2) 2π

(3) π/2 (4) dksbZ ugha

Q.55 fn;k x;k Qyu

f(x) =

≥−<<−−++

−≤

1,||

11,]1[]1[

1,||

xxx

xxx

xxx

, gS

(1) le (2) fo"ke

(3) u rks le u gha fo"ke (4) dksbZ ugha

Q.56 nh?kZoÙk 3218

22 yx + =1 ij Li'kZ js[kk dh izo.krk 3

4−gS]

nh?kZ rFkk y?kq vkks dks Øe'k% A rFkk B ij dkVrh

gSA ;fn C nh?kZoÙk dk dsUnz gS] rc ∆ABC dk

ks=kQy gS-

(1) 12 oxZ bdkbZ (2) 24 oxZ bdkbZ

(3) 36 oxZ bdkbZ (4) 48 oxZ bdkbZ



Note : Statement based questions : (Q. No.57-58)

Each of these questions contains two statements. Statement-I and Statement-II. Each of these has four alternatives choices. You have to select the correct choice.

(1) If both statement-I and statement-II are true but statement-II is not the correct explanation of statement-I.

(2) If both statement-I and statement- II are true, and statement-II is correct explanation of Statement-I.

(3) If statement-I is true but statement-II is false. (4) If statement-I is false but statement-II is true Q.57 Statement-I: If (3, 4) is a point on a hyperbola

having focus (3, 0) and (α, 0) and length of the

transverse axis being 1 unit, then "α" can take

the value as 0 or 3.

Statement-II: |S'P–SP| = 2a, where S and S' are

the two foci, 2a = length of the transverse axis

and P be any point on the hyperbola.

Q.58 Staement-I : If 4a –2b + c = 0, then line

ax + by + c = 0 always passes through . a fixed

point.

Statement-II : If L1 = 0 and L2 = 0 are equation

of two lines then, L1 + λL2 = 0 represents

equation of line passing through point of

intersection of L1 and L2 .

Note : dFku ij vk/kkfjr iz'u : (Q. No.57-58) izR;sd iz'u esa nks dFku% dFku-I ,oa dFku-II gSA

bueas izR;sd ds pkj fodYi gSaA vkidks lgh mÙkj p;u djuk gS-

(1) dFku-I o dFku-II nksuksa lR; gSa ijarq dFku-II ]

dFku-I dk lgh Li"Vhdj.k ugha gS

(2) dFku-I o dFku-II nksuksa lR; gSa rFkk dFku-II

dFku-I dk lgh Li"Vhdj.k gS

(3) dFku-I lR; gS ijUrq dFku-II vlR; gS

(4) dFku-I vlR; gS ijUrq dFku-II lR; gS

Q.57 dFku-I: ;fn ukfHk;k¡ (3, 0) rFkk (α, 0) j[kus okys

rFkk vuqizLFk vk dh yEckbZ 1 bdkbZ okys

vfrijoy; ij ,d fcUnq (3, 4) gS] rc "α" dk eku

0 ;k 3 gSA

dFku-II: |S'P–SP| = 2a gS, tgk¡ S rFkk S' nks ukfHk;k¡

gS] 2a = vuqizLFk vk dh yEckbZ rFkk vfrijoy; ij

dksbZ fcUnq P gS

Q.58 dFku-I : ;fn 4a –2b + c = 0 gS, rc js[kk

ax + by + c = 0 ges'kk ,d fLFkj fcUnq ls xqtjrh gSA

dFku-II : ;fn L1 = 0 rFkk L2 = 0 nks js[kkvks dh

lehdj.k gS] rc L1 rFkk L2 ds izfrPNsnu fcUnq ls

xqtjus okyh js[kk dh lehdj.k dks L1 + λL2 = 0

iznf'kZr djrk gSA



Q.59 Locus of midpoint of the portion between the

axes of x cos α + y sin α = p, where p is a

constant is -

(1) x2 + y2 = 2

4

p (2) x2 + y2 = 4p2

(3) 222

211

pyx=+ (4)

222

411

pyx=+

Q.60 The equations of tangent drawn from the origin

to the circle x2 + y2 – 2rx – 2hy + h2 = 0 are -

h

O

r

y

x

(1) (h2 – r2)x + 2rhy = 0 (2) (h2 – r2)x – 2rhy = 0 (3) y = 0 (4) none of these

Q.61. The triangle with verties (xi, yi), i = 1,2,3 is

inscribed in the circle x2 + y2 = a2 the

orthocentre of the triangle is -

(1) (– ∑xi, – ∑yi) (2) (2

1∑xi,

2

1∑yi)

(3) (∑xi, ∑yi) (4) (3

1∑xi,

3

1∑yi)

Q.62 Area bounded by the parabola x2 = 4y and the

line x = 4y –2 is -

(1) 9/8 (2) 9/4

(3) 9/2 (4) 9

Q.59 x cos α + y sin α = p ds vkks ds e/; Hkkx ds e/;

fcUnq dk fcUnqiFk] tgk¡ p ,d vpj gS] gS -

(1) x2 + y2 = 2

4

p (2) x2 + y2 = 4p2

(3) 222

211

pyx=+ (4)

222

411

pyx=+

Q.60 ewy fcUnq ls oÙk x2 + y2 – 2rx – 2hy + h2 = 0 ij [khaph xbZ Li'kZ js[kk dh lehdj.k gS -

h

O

r

y

x

(1) (h2 – r2)x + 2rhy = 0 (2) (h2 – r2)x – 2rhy = 0 (3) y = 0 (4) buesa ls dksbZ ugha

Q.61. ,d f=kHkqt ftlds 'kh"kZ (xi, yi), i = 1,2,3 gS] oÙk x2 + y2 = a2 ds vUrxZr cuk;k x;k gS] f=kHkqt dk yEcdsUnz gS -

(1) (– ∑xi, – ∑yi) (2) (2

1∑xi,

2

1∑yi)

(3) (∑xi, ∑yi) (4) (3

1∑xi,

3

1∑yi)

Q.62 ijoy; x2 = 4y rFkk js[kk x = 4y –2 kjk ifjc)

ks=kQy gS-

(1) 9/8 (2) 9/4

(3) 9/2 (4) 9



Q.63 Let f be a differentiable function satisfying

f(x)+f(y)+f(z)+f(x)f(y)f(z) = 14, ∀ x, y, z ∈ R then

(1) f '(x) < 0, ∀x ∈ R (2) f '(x) = 0, ∀ x ∈ R

(3) f '(x) > 0, ∀ x ∈ R (4) none

Q.64 If sin (α+β)=4

3&cos(α–β) =

5

4, ∀ 0 ≤ α, β ≤

4

π

then cos2α =

(1) 20

974 ± (2)

20

749±

(3) 20

749+ (4)

20

749−

Q.65 If

π=

πnn

3sin

1

2sin

1 and n ∈ I then no. of 'n'

satisfying equation is -

(1) 3 (2) 2

(3) 4 (4) 1

Q.66 The value of m

mmx ))/(cos(lim

∞→ is -

(1) 1 (2) e

(3) 1/e (4) does not exist

Q.67 Angle formed by the positive y-axis and the

tangent to y = x2 + 4x –17 at (5/2, –3/4) is -

(1) tan–1(9) (2) π/2 – tan–1(9)

(3) π/2 + tan–1(9) (4) none of these

Q.63 ekuk x, y, z ∈ R ds fy, f(x)+f(y)+f(z)+f(x)f(y)f(z) = 14

dks lUrq"V djus okyk larr~ Qyu f gks] rc

(1) f '(x) < 0, ∀x ∈ R (2) f '(x) = 0, ∀ x ∈ R

(3) f '(x) > 0, ∀ x ∈ R (4) dksbZ ugha

Q.64 ;fn lHkh 0 ≤ α, β ≤ 4

π ds fy, sin (α+β)=

4

3rFkk

cos(α–β) =5

4gS] rc cos2α =

(1) 20

974 ± (2)

20

749±

(3) 20

749+ (4)

20

749−

Q.65 ;fn

π=

πnn

3sin

1

2sin

1 rFkk n ∈ I gS] rc

lehdj.k dks lUrq"B djus okys 'n' dh la[;k gS -

(1) 3 (2) 2

(3) 4 (4) 1 Q.66 m

mmx ))/(cos(lim

∞→ dk eku gS -

(1) 1 (2) e

(3) 1/e (4) fo|eku ugha

Q.67 /kukRed y-vk rFkk ijoy; y = x2 + 4x –17 ds

(5/2, –3/4) ij Li'kZ js[kk ls cuk dks.k gS -

(1) tan–1(9) (2) π/2 – tan–1(9)

(3) π/2 + tan–1(9) (4) buesa ls dksbZ ugha



Q.68 The point at which the slope of the tangent of the

function f(x) = ex. cos x attains minima, when

x ∈ [0, 2π] is

(1) 4

π (2)

2

π

(3) 2

3π (4) π

Q.69 If f is twice differentiable such that f " (x) = – f (x),

f '(x) = g(x), h' (x) = ( f (x))2 + (g(x))2 and h(0) = 2,

h(1) = 4, then the equation y = h(x) represents - -

(1) a curve of degree 2

(2) a curve passing through the origin

(3) a straight line with slope 2

(4) a straight line with slope –2

Q.70 The minimum value of atan2x + bcot2x equals the

maximum value of asin2θ + bcos2θ, where

a > b > 0, when -

(1) a = b (2) a = 2b

(3) a = 3b (4) a = 4b

Q.71 If angle between lines ax + by + p = 0 and

x cosα + y sinα = p is 4

π and these lines are

concurrent with line x sin α – y cos α = 0, then a2 + b2 =

(1) 1 (2) 2 (3) 3 (4) 4

Q.68 ,d fcUnq ftl ij Qyu f(x) = ex. cos x dh Li'kZ

js[kk dk >qdko U;wure gS] tc x ∈ [0, 2π] gS] gS

(1) 4

π (2)

2

π

(3) 2

3π (4) π

Q.69 ;fn f nks ckj vodyuh; bl izdkj gS dh f " (x) = – f (x), f '(x) = g(x), h' (x) = ( f (x))2 + (g(x))2 rFkk h(0) = 2, h(1) = 4 gS] rc lehdj.k

y = h(x) iznf'kZr djrh gS -

(1) 2 ?kkr dk ,d oØ

(2) ewy fcUnq ls xqtjus okyk oØ

(3) 2 >qdko ds lkFk ,d ljy js[kk

(4) –2 >qdko ds lkFk ,d ljy js[kk

Q.70 atan2x + bcot2x dk fuEure eku] asin2θ + bcos2θ

ds mPpre eku ds cjkcj gS] tgk¡ a > b > 0 gS]

tc -

(1) a = b (2) a = 2b

(3) a = 3b (4) a = 4b

Q.71 ;fn js[kkvksa ax + by + p = 0 rFkk x cosα + y sinα = p

ds e/; dks.k 4

π gS rFkk ;g js[kk,sa] js[kk

x sin α – y cos α = 0 ds lkFk laxkeh gS] rc a2 + b2 =

(1) 1 (2) 2

(3) 3 (4) 4



Q.72 If the tangents at P and Q on a parabola meet in

T, then SP, ST and SQ are in (where S is focus )

(1) A.P. (2) G.P.

(3) H.P. (4) none

Q.73 ∑=

+−2012

0

)()1(r

r rda =

(1) a + 2012 d (2) a + 1007 d

(3) a + 1006 d (4) none of these

Q.74 In an A.P. the sum of the first n terms bears a

constant ratio λ with the sum of the next n terms,

then λ =

(1) 2

1 (2)

3

1

(3) 4

1 (4)

5

2

Q.75 The coefficient of x13 in the expansion of

(1 – x)5 (1 + x + x2 + x3)4 is -

(1) 4 (2) – 4

(3) 0 (4) –2

Q.76 f(x) =

1tan

2sin2

1cos2

xx

xxx

xx

. The value of x

xfx

)(lim

0→

is equal to -

(1) 1 (2) –1

(3) zero (4) none of these

Q.72 ;fn ,d ijoy; ds P rFkk Q ij Li'kZ js[kk,as] T ij feyrh gS] rc SP, ST rFkk SQ fdlesa gS (tgk¡ S ukfHk gS)

(1) lekUrj Js<+h (2) xq.kksÙkj Js<+h

(3) gjkRed Js<+h (4) dksbZ ugha

Q.73 ∑=

+−2012

0

)()1(r

r rda =

(1) a + 2012 d (2) a + 1007 d

(3) a + 1006 d (4) buesa ls dksbZ ugha

Q.74 ,d lekUrj Js<+h esa izFke n inks dk ;ksx] vxys n

inks ds ;ksx ds lkFk ,d vpj vuqikr λ j[krk gS

rc λ =

(1) 2

1 (2)

3

1

(3) 4

1 (4)

5

2

Q.75 (1 – x)5 (1 + x + x2 + x3)4 ds izlkj esa x13 dk xq.kkad

gS - (1) 4 (2) – 4 (3) 0 (4) –2

Q.76 f(x) =

1tan

2sin2

1cos2

xx

xxx

xx

gSA x

xfx

)(lim

0→ dk eku

cjkcj gS -

(1) 1 (2) –1

(3) zero (4) buesa ls dksbZ ugha



Q.77 If all words formed from the letters of the word

"HORROR" are arranged in the possible order as

they are in a dictionary, then the rank of the word

"HORROR" is -

(1) 7 (2) 8

(3) 3 (4) 9

Q.78 A bell rings at an interval of every 2min, second

bell rings at every 5 min, third bell rings at every

6 min and fourth bell ring in every 8 min. In a

span of 8 howrs how many times all 4 bells be

ringing simultaneously -

(1) 60 (2) 32

(3) 16 (4) 4

Q.79 A box contans 3 red, 4 green and 5 white balls. A

ball is taken randomly, if it is red it replaced in to

the box with an other red ball. If it is green it is

kept out side. If it is white another white ball is

with drawn and kept out. After this a ball is

drawn randomly and found to be red what is the

probability that the first ball with drawn was also

red -

(1) 335

88 (2)

335

80

(3) 335

84 (4)

335

92

Q.77 ;fn 'kCn "HORROR" ds vkjks ls cus lHkh 'kCnks

dks bl laHko Øe esa O;ofLFkr djrs gS dh os

'kCndks'k ds tSls gks] rc "HORROR" 'kCn dk Øe

gS-

(1) 7 (2) 8

(3) 3 (4) 9

Q.78 ,d ?kaVh izR;sd 2min ds vUrjky ij ctrh gS]

frh; ?kaVh izR;sd 5 min ij ctrh gS] rhljh ?kaVh

izR;sd 6 min ij ctrh gS] prqFkZ ?kaVh izR;sd 8 min

ij ctrh gSA 8 ?kaVs dh le;kof/k esa lHkh 4 ?kaVh;k

,d lkFk fdruh ckj ctsxh -

(1) 60 (2) 32

(3) 16 (4) 4

Q.79 ,d cDlk 3 yky] 4 gjh rFkk 5 lQsn xsans j[krk gSA

,d xsan ;knPN;k fudkyh tkrh gS] ;fn ;g yky gS

rks bls cDls esa vU; yky xsan ds lkFk j[k fn;k

tkrk gSA ;fn ;g gjh gS rks bldks ckgj ,d rjQ

j[k nsrs gSA ;fn ;g lQsn gS rks vU; lQsn xsan

fudkyh tkrh gS] rFkk ckgj j[k nsrs gSA blds ckn

,d xsan ;kn`PN;k fudkyh tkrh gS rFkk yky ikbZ

tkrh gS] izFke xsan tks fudyh xbZ Fkh] ds Hkh yky

gksus dh izkf;drk gS -

(1) 335

88 (2)

335

80

(3) 335

84 (4)

335

92



Q.80 A boy is throwing stones at target. The

probability of hitting the target at any trial is 2

1.

The Probability of hitting the target 5th time at

the 10th throw is -

(1) 102

5 (2)

92

63

(3) 10

510

2

C (4)

104

10

2

C

Q.80 ,d yM+dk y; ij iRFkj Qsadrk gSA fdlh Hkh

iz;kl esa y; Hksnus dh izkf;drk 2

1 gSA 10

oha Qsad esa

5oha ckj y; Hksnus dh izkf;drk gS -

(1) 102

5 (2)

92

63

(3) 10

510

2

C (4)

104

10

2

C



PHYSICS

Q.81 A sphere of radius R carries volume charge

density ρ proportional to the square of the

distance r from the centre such that ρ = cr2,

where c is a constant. At a distance 2

R from the

centre, the magnitude of electric field is -

(1) 0

3

20

cR

∈ (2)

0

3

10

cR

∈

(3) 0

3

5

cR

∈ (4) None

Q.82 A circular loop of diameter d is rotated in a

uniform electric field until the position of

maximum electric flux is found. The flux in this

position is measured to be φ. What is the electric

field strength ?

(1) 2d

4

πφ

(2) 2d

2

πφ

(3) 2dπ

φ (4)

4

d2πφ

Q.83 For refraction through a small angled prism, the

angle of minimum deviation

(1) increases with increase in refractive index of

a prism

(2) will be 2δ for a ray of refractive index 2.4 if

it is δ for a ray of refractive index 1.2

(3) is directly proportional to the angle of the

prism

(4) will decrease with increase in refractive

index of the prism

Q.81 R f=kT;k dk ,d xksyk ρ vk;ru vkos'k ?kuRo j[krk

gS tks dsUnz ls nwjh r ds oxZ ds lekuqikrh bl izdkj gS

fd ρ = cr2 gS] tgk¡ c ,d fu;rkad gSA dsUnz ls 2

R nwjh

ij] fo|qr ks=k dk ifjek.k gS -

(1) 0

3

20

cR

∈ (2)

0

3

10

cR

∈

(3) 0

3

5

cR

∈ (4) dksbZ ugha

Q.82 d O;kl dk ,d oÙkh; ywi ,dleku fo|qr ks=k rc

rd ?kw.kZu djrk gS tc rd vf/kdre fo|qr ¶yDl

dh fLFkfr izkIr ugha gks tkrh gSA bl fLFkfr esa ¶yDl

φ ekik tkrk gSA fo|qr ks=k dh rhozrk D;k gS ?

(1) 2d

4

πφ

(2) 2d

2

πφ

(3) 2dπ

φ (4)

4

d2πφ

Q.83 vYi dks.k ;qDr fizTe ls viorZu ds fy;s] U;wure

fopyu dks.k

(1) fizTe ds viorZukad esa of) ds lkFk c<+rk gS

(2) 2.4 viorZukad ds fizTe ij vkifrr fdj.k ds

fy;s 2δ gksxk ;fn og 1.2 viorZukad ds fizTe

ij vkifrr fdj.k ds fy;s δ gks

(3) fizTe dks.k ds lekuqikrh gksrk gS

(4) fizTe ds viorZukad esa of) ds lkFk ?kVsxk



Q.84 A galvanometer is connected as shown in figure.

It has resistance of 100 Ω. What should be the

resistance connected to it in parallel so that its

deflection is reduced to half.

G R = 1KΩ

100 Ω

2V

S

(1) 100 Ω (2) 99 Ω

(3) 91 Ω (4) 90 Ω

Q.85 A potentiometer wire is made of constantan or

maganin as it has -

(1) high ρ, low α (2) low ρ, high α

(3) low ρ, low α (4) high ρ, high α

Q.86 Experimental verification of newton's law of

colling is valid for :

(1) Large temperature difference 30°C to 85°C

between hot liquid and surrounding

(2) Very large temperature difference 5° to 95°C


(3) Small temperature difference 30° to 35°C


(4) Any temperature difference

Q.87 Potentionmeter wire is 50 cm long. When

AD = 20 cm no deflection occurs in the

galvanometer then R will be

Q.84 ,d xsYosuksehVj ds fp=kkuqlkj tksM+k x;k gSA mldk

izfrjks/k 100 Ω gSA mlls lekUrj Øe esa fdruk

izfrjks/k tksM+uk pkfg;s rkfd mldk foksi vk/kk gks

tk;s -

G R = 1KΩ

100 Ω

2V

S

(1) 100 Ω (2) 99 Ω

(3) 91 Ω (4) 90 Ω Q.85 foHkoekih rkj dkWUlVsUVu ;k eSXuhu dk cuk;k tkrk

gS D;ksafd og j[krk gS - (1) mPp ρ , fuEu α (2) fuEu ρ , mPp α (3) fuEu ρ , fuEu α (4) mPp ρ , mPp α

Q.86 U;wVu ds 'khryu ds fu;e dk lR;kiu iz;ksx fuEUk

ds fy;s ekU; gksrk gS :

(1) xeZ nzo rFkk ifjos'k ds e/; mPPk rkikUrj 30°C

ls 85°C

(2) xeZ nzo rFkk ifjos'k ds e/; mPp rkikUrj 5° ls 95°C

(3) xeZ nzo rFkk ifjos'k ds e/; vYi rkikUrj 30° ls 35°C

(4) fdlh Hkh rkikUrj Q.87 foHkoekih rkj 50 cm yEck gSA tc AD = 20 cm gS

rks xsYosuksehVj esa dksbZ foksi izkIr ugha gksrk gS] rc R

gksxk



16Ω

G

D B

R

A

(1) 8 Ω (2) 12 Ω (3) 16 Ω (4) 24 Ω Q.88 A plane polarised beam of intensity I is incident

on a polariser with the electric vector inclined at 30° to the optic axis of the polariser. Light coming out of the polariser passes through an analyser whose optic axis is inclined at 30° to that polariser. Intensity of light coming out of the analyser is –

30°30°

E

P

A

(1) 16

9 I (2)

4

3 I (3)

4

1 I (4)

2

3 I

Q.89 Which of the following statements, about long a solenoid are wrong ?

(1) When a current flows through a solenoid, it has a tendency to increase its radius if no external magnetic field exists in the space

(2) When a current flows through a solenoid, it may have tendency to increase its radius if an external magnetic field exists in the space

(3) When a current flows through a solenoid, it may have a tendency to decrease its radius if an external magnetic field exists in the space

(4) None of the above

16Ω

G

D B

R

A

(1) 8 Ω (2) 12 Ω (3) 16 Ω (4) 24 Ω

Q.88 I rhozrk dh ,d lery /kzqohr iqat ,d /kzqod ftldk fo|qr lfn'k /kzqod dh izdkf'k; vk ls 30° ds dks.k ij >qdk gqvk gS] ij vkifrr gksrh gSA /kzqod ls vkus okyk izdk'k ,d fo'ys"kd (analyzer) ftldh izdkf'k; vk ml fo'ys"kd ls 30° ij vkufrr gS] ls xqtjrk gSA fo'ys"kd ls fudyus okys izdk'k dh rhozrk gS –

30°30°

E

P

A

(1) 16

9 I (2)

4

3 I (3)

4

1 I (4)

2

3 I

Q.89 yEch ifjukfydk ds lUnHkZ esa fuEu esa ls dkSulk dFku xyr gS ?

(1) tc ifjukfydk ls /kkjk izokfgr gksrh gS] rks og viuh f=kT;k esa of) dh izd`fr j[krh gS ;fn vUrfjk esa dksbZ cká pqEcdh; ks=k mifLFkr ugha gks

(2) tc ifjukfydk ls /kkjk izokfgr gksrh gS] rks og viuh f=kT;k esa of) dh izd`fr j[k ldrh gS ;fn vUrfjk esa cká pqEcdh; ks=k mifLFkr gks

(3) tc ifjukfydk ls /kkjk izokfgr gksrh gS] rks og viuh f=kT;k esa deh dh izofÙk j[k ldrh gS ;fn vUrfjk esa cká pqEcdh; ks=k mifLFkr gks




Q.90 A charge enters in uniform magnetic field as

shown. Where a > r and b = 2

r3 , r = radius of

path of particle. The deviation of particle is - × × ×

× × ×

× × ×

b

a (1) 120° (2) 90° (3) 60° (4) 150°

Q.91 A voltmeter of resistance 600 Ω is used to

measure potential drop across the 300 Ω resistor. Then :

600 ΩV

300 Ω 200 Ω

100V

(1) the main current from the battery is 1.25 A (2) the main current from the battery is 0.50 A (3) the reading of the voltmeter is 50 V (4) the reading of the voltmeter is 100 V Q.92 The orbital velocity of an artificial satellite in a

circular orbit just above the earth's surface is v. For a satellite orbiting at an altitude of half of the earth's radius, the orbital velocity is -

(1) 2

3v (2)

2

3v (3)

3

2v (4)

3

2v

Q.90 ,d vkosf'kr d.k ,dleku pqEcdh; ks=k esa n'kkZ,

vuqlkj izos'k djrk gSA tgk¡ a > r rFkk b = 2

r3 gS ,

r = d.k ds iFk dh f=kT;k gSA d.k dk fopyu gS - × × ×

× × ×

× × ×

b

a (1) 120° (2) 90° (3) 60° (4) 150°

Q.91 600 Ω izfrjks/k ds ,d oksYVehVj dk mi;ksx 300 Ω

izfrjks/k ds fljksa ij foHko iru ekius esa fd;k tkrk gSA rc :

600 ΩV

300 Ω 200 Ω

100V

(1) cSVªh ls eq[; /kkjk 1.25 A gS (2) cSVªh ls eq[; /kkjk 0.50 A gS (3) oksYVehVj dk ikB~;kad 50 V gS (4) oksYVehVj dk ikB~;kad 100 V gS

Q.92 iFoh ds i"B ij oÙkh; dkk esa fdlh d`f=ke mixzg

dh dkh; pky v gSA iFoh dh f=kT;k dh vk/kh Å¡pkbZ

ij ifjØe.kdkjh mixzg dh dkh; pky gksxh -

(1) 2

3v (2)

2

3v (3)

3

2v (4)

3

2v



Q.93 A particle of mass m is tied to a light string and

whirled with a speed v along a circular path of

radius r. If T is tension in the string and mg is

gravitational forces on the particle, then the

‘actual’ forces acting on the particle are :

(1) mg and T only

(2) mg, T and an additional force mv2 directed

inwards

(3) mg, T and an additional force mv2/r directed

outwards

(4) only a force mv2/r directed outwards

Q.94 Two blocks A and B are placed, one on the top of

the other, on a smooth horizontal surface, as

shown. The maximum horizontal force that can

be applied to B, so that both A and B move

together is 49 N. The coefficient of friction

between A and B is :

3kg

7kg F

A

B

(1) 0.2 (2) 0.3 (3) 0.5 (4) 0.8

Q.95 In adiabatic expansion, the product of P & V (1) decreases (2) Increases (3) remain constant (4) first increase then decrease

Q.96 If heat capacity of an object is 42 J/°C then water equivalent -

(1) 42 gm (2) 10 gm (3) 1 kg (4) 4.2 gm

Q.93 m nzO;eku dk ,d d.k ,d gYdh Mksjh ls ca/kk gS

rFkk r f=kT;k ds oÙkh; iFk ds vuqfn'k v pky ls

?kwerk gSA ;fn T Mksjh esa ruko gS rFkk mg d.k ij

xq#Roh; cy gS] rks d.k ij dk;Zjr okLrfod cy gS :

(1) dsoy mg o T

(2) mg, T rFkk vUnj dh vksj funsZf'kr ,d vfrfjDr

cy mv2

(3) mg, T rFkk ckgj dh vksj funsZf'kr ,d vfrfjDr

cy mv2/r

(4) ckgj dh vksj funsZf'kr dsoy ,d cy mv2/r

Q.94 nks xqVds A rFkk B ,d nwljs ds Åij] ,d fpdus kSfrt

ry ij j[ks x;s gSA og vf/kdre kSfrt cy B ij

yxk;k tk ldrk gS] ftlls fd A rFkk B nksuksa ,d lkFk

pysa 49 N gSA A rFkk B ds chp ?k"kZ.k xq.kkad gS :

3kg

7kg F

A

B

(1) 0.2 (2) 0.3 (3) 0.5 (4) 0.8

Q.95 #)ks"e izlkj esa P o V dk xq.kuQy (1) ?kVrk gS (2) c<+rk gS (3) vifjofrZr jgrk gS (4) igys c<+rk gS rFkk fQj ?kVrk gS

Q.96 ;fn ,d oLrq dh Å"ek /kkfjrk 42 J/°C gks rks ty rqY;kad gksxk -

(1) 42 gm (2) 10 gm (3) 1 kg (4) 4.2 gm



Q.97 Match the following column : Column –I Column-II (A) Charle's law (P) n R d T (B) Average KE. (Q) V ∝ T per molecule per degree of freedom (C) Adiabatic process (R) dW = –dU (D) Work done in (S) P ∝ Tγ/γ–1 isobaric process (T) 1/2 KT (1) A → Q ; B → T ; C → R,S; D → P (2) A → P ; B → T ; C → R,S ; D → Q (3) A → R ; B → T ; C → R ; D → P (4) A → S ; B → T ; C → R,S ; D → Q Q.98 A point particle of mass 0.1 kg is executing SHM

of amplitude 0.1 m. When the particle passes through the mean position, its KE is 8 × 10–3J. The equation of motion of this particle, if its initial phase of oscillation is 45° is :

(1) y = 0.1 sin

π+44

t

(2) y = 0.1 sin

π+42

t

(3) y = 0.1 sin

π−4

t4

(4) y = 0.1 sin

π+4

t4

Q.99 Select the correct statement : - (1) Matter waves produced by moving neutron is

not a mechanical wave because mechanical waves are produced only by charged particle

(2) Standing wave produced over a string is not a mechanical wave because it cannot propagate energy and mechanical waves always propagate energy

(3) transverse and longitudinal waves both can propagate in air

(4) None of these

Q.97 fuEu LrEHk dk feyku dhft;s : LrEHk –I LrEHk-II (A) pkyZ dk fu;e (P) n R d T (B) vkSlr xfrt (Q) V ∝ T ÅtkZ izfr v.kq izfr Lor=kark dh dksfV (C) #)ks"e izØe (R) dW = –dU (D) lenkch; izØe (S) P ∝ Tγ/γ–1 esa fd;k x;k dk;Z (T) 1/2 KT (1) A → Q ; B → T ; C → R,S; D → P (2) A → P ; B → T ; C → R,S ; D → Q (3) A → R ; B → T ; C → R ; D → P (4) A → S ; B → T ; C → R,S ; D → Q

Q.98 0.1 kg nzO;eku dk ,d fcUnq d.k 0.1 m vk;ke ls SHM dj jgk gSA tc d.k ek/; fLFkfr ls xqtjrk gS rks mldh xfrt ÅtkZ 8 × 10–3J gSA bl d.k dh xfr dh lehdj.k ;fn mlds nksyu dh izkjfEHkd dyk 45° gS :

(1) y = 0.1 sin

π+44

t

(2) y = 0.1 sin

π+42

t

(3) y = 0.1 sin

π−4

t4

(4) y = 0.1 sin

π+4

t4

Q.99 lgh dFku dk p;u dhft;s : - (1) xfr'khy U;wVªkWu kjk mRlftZr nzO; rjaxs ;kaf=kd

rjaxsa ugha gksrh gS D;ksafd ;kaf=kd rjaxsa dsoy vkosf'kr d.k kjk mRiUu gksrh gS

(2) ,d Mksjh esa mRiUu vizxkeh rjax ,d ;kaf=kd rjax ugha gksrh gS D;ksafd og ÅtkZ lapfjr ugha dj ldrh gS rFkk ;kaf=kd rjaxsa ges'kk ÅtkZ lapfjr djrh gS

(3) vuqizLFk rFkk vuqnS/;Z rjaxsa nksuksa ok;q esa lapfjr gks ldrh gS




Q.100 Ratio of speed of sound in helium and oxygen is (at same temperature) :

(1) 21

200 (2) 22 (3) 4 (4)

21

100

Q.101 At any instant the ratio of the amount of

radioactive substance is 2 : 1. If their half-lives be 12 and 16 hours respectively, then after two days, what will be the ratio of the substance ?

(1) 1 : 1 (2) 2 : 1 (3) 1 : 2 (4) 1 : 4 Q.102 If mass of U235 = 235. 12142 amu, mass of

U236 = 236.12305 amu and mass of neutron = 1.008665 amu, then the energy required to remove one neutron from the nucleus U236 is nearly about -

(1) 75 MeV (2) 6.5 MeV (3) 1 eV (4) 0

Q.103 Match the column – Column-I Column-II

(A) Work function of (P) 13.6 2

2

n

Z eV

copper is 4eV. If two photons each of energy 2.5 eV strike an electron of copper emission of electrons

(B) Cathode rays are (Q) 13.6Z2 eVn

1

n

122

21

−

deflected by (C) ionisation energy (R) Both electric and

of H like atom is magnetic field

(D) greater wavelength in (S) 1H1

transition from n = 2 (T) 1H3

to n = 1 is for (U) Not possible

(V) possible

Q.100 ghfy;e rFkk vkWDlhtu esa /ofu dh pky dk vuqikr gS (leku rki ij) :

(1) 21

200 (2) 22 (3) 4 (4)

21

100

Q.101 fdlh Hkh k.k ij jsfM;kslfØ; inkFkZ dh ek=kk dk

vuqikr 2 : 1 gSA ;fn mudh v)Z-vk;q Øe'k% 12 rFkk

16 ?k.Vs gks] rks nks fnu ckn] inkFkZ dk vuqikr gksxk? (1) 1 : 1 (2) 2 : 1 (3) 1 : 2 (4) 1 : 4 Q.102 ;fn U235 dk nzO;eku = 235. 12142 amu, U236 dk

nzO;eku = 236.12305 amu rFkk U;wVªkWu dk nzO;eku= 1.008665 amu gks] rks U236 ukfHkd ls ,d U;wVªkWu fudkyus ds fy;s vko';d ÅtkZ yxHkx gksxh -

(1) 75 MeV (2) 6.5 MeV (3) 1 eV (4) 0

Q.103 LrEHk feyku dhft;s – LrEHk-I LrEHk-II

(A) rkacs dk dk;ZQyu (P) 13.6 2

2

n

Z eV

4eV gSA ;fn izR;sd 2.5 eV ÅtkZ ds nks QksVkWu rkacs ds mRltZu ds bysDVªkWu ls Vdjkrs gS

(B) dSFkksM+ fdj.ksa fopfyr (Q) 13.6Z2 eVn

1

n

122

21

−

gksrh gS (C) H-ln'k ijek.kq dh (R) nksuksa fo|qr rFkk vk;uu ÅtkZ gS pqEcdh; ks=k (D) n = 2 ls n = 1 laØe.k (S) 1H

1 esa vf/kdre rjaxnS/;Z (T) 1H

3 gksxh (U) vlaHko

(V) laHko



(1) A → U; B → R; C → P; D → S

(2) A → V; B → R; C → P; D → S

(3) A → U; B → P; C → R; D → S

(4) None of these

Q.104 A ball A has twice the diameter as another ball B

of the same material and with same surface

finish. A and B are both heated to the same

temperature and allowed to cool radiatialy; then

(1) rate of temp. falling of A is same as that of B

(2) rate of temp. falling of A is twice that of B

(3) rate of temp. falling of A is half that of B

(4) rate of temp. falling of A is four times that of B

Q.105 A set of n identical resistors, each of resistance R

ohm when connected in series has an effective

resistance of x ohm. When the resistors are

connected in parallel, the effective resistance is y

ohm. What is the relation between R, x and y ?

(1) R = )yx(

xy

+ (2) R = (y – x)

(3) R = xy (4) R = (x + y)

Q.106 The terminal voltage of a battery is

(1) always equal to its emf

(2) always greater than its emf

(3) greater or less than its emf depending on the

direction of the current through the battery

(4) greater or less than its emf depending on the

magnitude of its internal resistance

(1) A → U; B → R; C → P; D → S

(2) A → V; B → R; C → P; D → S

(3) A → U; B → P; C → R; D → S


Q.104 ,d xsan A leku inkFkZ dh rFkk leku lrg okyh

nwljh xsan B ds O;kl dk nqxquk O;kl j[krh gSA

A rFkk B dks leku rki rd xeZ fd;k tkrk gS rFkk

fofdj.k ls B.Mk gksus fn;k tkrk gS rc

(1) A ds rki ds fxjus dh nj B ds leku gksrh gS (2) A ds rki ds fxjus dh nj B dh nqxquh gksrh gS (3) A ds rki ds fxjus dh nj B dh vk/kh gksrh gS (4) A ds rki ds fxjus dh nj B dh pkj xquk gksrh gS

Q.105 izR;sd R ohm izfrjks/k ds n le#i izfrjks/kdksa dk ,d

;qXe tc Js.kh Øe esa tksMk tkrk gS rks x ohm dk

izHkkoh izfrjks/k j[krk gSA tc izfrjks/kdksa dks lekUrj

Øe esa tksM+k tkrk gS] rks izHkkoh izfrjks/k y ohm gSA

R, x o y ds e/; lEcU/k D;k gS ?

(1) R = )yx(

xy

+ (2) R = (y – x)

(3) R = xy (4) R = (x + y)

Q.106 ,d cSVªh dk VfeZuy oksYVst

(1) ges'kk mlds fo-ok-cy ds cjkcj gksrk gS

(2) ges'kk mlds fo-ok-cy ls vf/kd gksrk gS

(3) mlds fo-ok-cy ls vf/kd ;k de cSVªh ls izokfgr

/kkjk dh fn'kk ij fuHkZj djrk gS

(4) mlds fo-ok-cy ls vf/kd ;k de mlds vkUrfjd

izfrjks/k ds ifjek.k ij fuHkZj djrk gS



Q.107 Which pair of following quantities has

dimensions different from each other.

(1) Impulse and linear momentum

(2) Plank's constant and angular momentum

(3) Momentum of inertia and moment of force

(4) Young's modulus and pressure

Q.108 A particle is thrown upwards from ground. It

experiences a constant air resistance which can

produce a retardation of 2 m/s2 opposite to the

direction of velocity of particle. The ratio of the

time of ascent to the time of descent is :

[g = 10 m/s2]

(1) 1 : 1 (2) 3

2

(3) 3

2 (4)

2

3

Q.109 The ratio of angular speeds of minute hand and

hour hand of a watch is - (1) 1 : 12 (2) 6 : 1 (3) 12 : 1 (4) 1 : 6

Q.110 A bomb of 12 kg explodes into two pieces of masses 4 kg and 8 kg. The velocity of 8 kg mass is 6 m/sec. The kinetic energy of the other mass is -

(1) 48 J (2) 32 J (3) 24 J (4) 288 J

Q.111 A body of mass m thrown vertically upwards attains a maximum height h. At what height will its kinetic energy be 75% of its initial value ?

(1) h/3 (2) h/4 (3) h/5 (4) h/6

Q.107 fuEu jkf'k;ksa dk dkSulk ;qXe ,d-nwljs ls fHkUu

foek,sa j[krk gSA

(1) vkosx rFkk js[kh; laosx

(2) IykWd fu;rkad rFkk dks.kh; laosx

(3) tM+Ro vk?kw.kZ rFkk cy vk?kw.kZ

(4) ;ax xq.kkad rFkk nkc Q.108 ,d d.k dks /kjkry ls Åij dh vksj QSadk x;k gSA

og fu;r ok;q izfrjks/k tks d.k ds osx dh fn'kk ds

foijhr 2 m/s2 dk eanu mRiUu dj ldrk gS] vuqHko

djrk gSA Åij tkus ds le; rFkk uhps vkus ds

le; dk vuqikr gS : [g = 10 m/s2]

(1) 1 : 1 (2) 3

2

(3) 3

2 (4)

2

3

Q.109 ?kM+h ds feuV lwbZ rFkk ?k.Vs dh lwbZ dh dks.kh;

pkyksa dk vuqikr gS - (1) 1 : 12 (2) 6 : 1 (3) 12 : 1 (4) 1 : 6

Q.110 12 kg dk ,d ce 4 kg rFkk 8 kg nzO;eku ds nks

VqdM+ksa esa VwVrk gSA 8 kg nzO;eku dk osx 6 m/sec gSA

nwljs nzO;eku dh xfrt ÅtkZ gS -

(1) 48 J (2) 32 J

(3) 24 J (4) 288 J

Q.111 m nzO;eku dk fi.M Å/okZ/kj Åij dh vksj Qsadus ij vf/kdre Å¡pkbZ h izkIr djrk gSA fdl Å¡pkbZ ij mldh xfrt ÅtkZ izkjfEHkd eku dh 75% gksxh ?

(1) h/3 (2) h/4 (3) h/5 (4) h/6



Q.112 A projectile is required to hit a target whose

co-ordinate relative to horizontal and vertical

axis through the point of projection are (α, β).

If the gun velocity is αg2 , it is impossible to

hit the target if-

(1) β ≥ 4

α (2) β ≤

4

3 α

(3) β ≥ 3

4 α (4) β >

4

3 α

Q.113 The spring balance A reads 2 kg with a block m

suspended from it. A balance B reads 5 kg when

a beaker filled with liquid is put on the pan of

the balance. The two balances are now so

arranged that the hanging mass is inside the

liquid as shown in figure. In this situation-

A

B

m

(1) The balance A will read more than 2 kg

(2) The balances A and B will read 2 kg and 5

kg respectively

(3) The balance A will read less than 2 kg and B

will read more than 5 kg

(4) All of above

Q.112 fdlh y; ds Hksnu ds fy;s ,d izksI; dh

vko';drk gS ftlds izksI; fcUnq ls kSfrt rFkk

Å/oZ vk ds lkisk funsZ'kkad (α, β) gSA ;fn xu dk

osx αg2 gks] rks y; dks Hksnuk vlEHko gksxk

;fn -

(1) β ≥ 4

α (2) β ≤

4

3 α

(3) β ≥ 3

4 α (4) β >

4

3 α

Q.113 fLizax rqyk A, 2 kg i<+rh gS tc mlls m nzO;eku

ds CykWd dks yVdk;k tkrk gSA rqyk B, 5 kg i<+rh

gS tc nzo ls Hkjs ,d chdj dks rqyk ds iyM+s ij

j[kk tkrk gSA vc nks rqykvksa dks bl izdkj

O;ofLFkr fd;k tkrk gS fd yVdk gqvk nzO;eku

fp=kkuqlkj nzo ds vUnj gksrk gSA bl fLFkfr esa -

A

B

m

(1) rqyk A, 2 kg ls vf/kd i<+sxh

(2) rqyk A rFkk B Øe'k% 2 kg o 5 kg i<+rh gS

(3) rqyk A, 2 kg ls de rFkk rqyk B, 5 kg ls vf/kd

i<+sxh

(4) mijksDr lHkh



Q.114 Consider the following statement: When jumping from some height, you should bend your knees as you come to rest, instead of keeping your legs stiff. Which of the following relations can be useful in explaining the statement-

(Where symbols have their usual meaning)

(1) 21 PP ∆−=∆

(2) 0)KEPE(E =+∆−=∆

(3) vmtF ∆=∆

(4) Fx ∆∝∆

Q.115 Power delivered by the source of AC circuit

becomes maximum when :

(1) ωL = ωC

(2) ωL = C

1

ω

(3) ωL = 1 – (1/ωC)2

(4) ωL = )C(ω

Q.116 Figure gives a system of logic gates. From the

study of truth table it can be found that to

produce a high output (1) at R, we must have –

R P

O

Y

X

(1) X = 0, Y = 1 (2) X = 1, Y = 1

(3) X = 1, Y = 0 (4) X = 0, Y = 0

Q.114 fuEu dFku ij fopkj dhft, : tc dqN Å¡pkbZ ls

Nykax yxkrs gS] rks vkidks fojke esa vkus ds le;]

viuh Vkxksa dks ruh gqbZ j[kus ds LFkku ij vius

?kqVuksa dks eksM+uk pkfg;sA fuEu esa ls dkSulk lEca/k

dFku dh O;k[;k djus esa mi;ksxh gks ldrk gS-

(tgk¡ ladsr muds okLrfod vFkZ j[krs gS)

(1) 21 PP ∆−=∆

(2) 0)KEPE(E =+∆−=∆

(3) vmtF ∆=∆

(4) Fx ∆∝∆

Q.115 AC ifjiFk ds L=kksr kjk nh xbZ 'kfDr vf/kdre gksxh tc :

(1) ωL = ωC

(2) ωL = C

1

ω

(3) ωL = 1 – (1/ωC)2

(4) ωL = )C(ω

Q.116 fp=k rkfdZd xsVksa dk ,d fudk; nsrk gSA lR;

lkj.kh ds v/;;u ls ;g ik;k tkrk gS fd R ij

mPp fuxZr (1) mRiUu gksrk gS] ge j[ksxsa –

R P

O

Y

X

(1) X = 0, Y = 1 (2) X = 1, Y = 1 (3) X = 1, Y = 0 (4) X = 0, Y = 0



Q.117 An electron is moving with a velocity of

6.6 × 105 m/s. Its de Broglie wavelength is :

(1) 1.1 × 10–9m

(2) 1 × 10–5m

(3) 1 × 10–7m

(4) 1 × 10–10m

Q.118

15Ω

20Ω7.5ΩC=2µF

V=5volt 5Ω

Find current in circuit after a long time.

(1) 3

1 amp

(2) 4

1 amp

(3) 2

1 amp

(4) None of these

Q.119 If a magnet is suspended at an angle 30° to the

magnetic meridian, the dip needle makes an

angle of 60° with the horizontal. The true value

of dip is -

(1) tan–1 (2/3) (2) tan–1 (3/2)

(3) tan–1 (3) (4) tan–1 (2)

Q.117 ,d bysDVªkWu 6.6 × 105 m/s ds osx ls xfr'khy gSA

mldh Mh-czksXyh rjaxnS/;Z gS:

(1) 1.1 × 10–9m

(2) 1 × 10–5m

(3) 1 × 10–7m

(4) 1 × 10–10m

Q.118

15Ω

20Ω7.5ΩC=2µF

V=5volt 5Ω

yEcsa le; ckn ifjiFk esa /kkjk Kkr dhft;s

(1) 3

1 amp

(2) 4

1 amp

(3) 2

1 amp


Q.119 ;fn ,d pqEcd dks pqEcdh; ;kE;ksRkj ls 30° dks.k

ij yVdk;k x;k gS] ufr lwbZ kSfrt ls 60° dk dks.k

cukrh gSA ufr dk okLrfod eku gS -

(1) tan–1 (2/3) (2) tan–1 (3/2)

(3) tan–1 (3) (4) tan–1 (2)



Q.120 A rod PQ of length L moves with a uniform

velocity v parallel to a long straight wire

carrying current ‘i’ The emf induce across the

rod is –

v

Q P

L

I r

∞

–∞

(1) π

µ2

Iv0 loge

L

r

(2) π

µ2

Iv0 loge

+r

Lr

(3) r2

Iv0

πµ

loge

+ Lr

r

(4) No emf is induced in rod

Q.120 L yEckbZ dh ,d NM+ PQ ,dleku osx v ls ‘i’

/kkjkokgh lh/ks yEcs rkj ds lekUrj xfr djrh gSA

NM+ ls fljksa ij izsfjr fo|qr okgd cy gS –

v

Q P

L

I r

∞

–∞

(1) π

µ2

Iv0 loge

L

r

(2) π

µ2

Iv0 loge

+r

Lr

(3) r2

Iv0

πµ

loge

+ Lr

r

(4) NM+ esa fo|qr okgd cy mRiUu ugha gksrk gS

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