major test 1 paper 1

8/13/2019 Major Test 1 Paper 1

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_________________________________________________________________________________________

INSTRUCTIONS

Do not break the seal of the question paper booklet before instructed to do so by the invigilator

In each part of the paper, Section-A contains 14 questions, Section-B contains 1 question & Section-C contains 5

questions. Total number of pages are 24. Please ensure that the Questions paper you have received contains ALL

THE QUESTIONS in each section and PAGES.

SECTION - A

1. Q.1to Q.6has four choices (A), (B), (C), (D) out of which only one is correct& carry 3 markseach. 1 markwill be deducted

for each wrong answer.

2. Q.7 to Q.8 are Reasoning type questions, contains Statement-1 (Assertion) & Statement-2 (Reason). Each Questions has

4 choices (A), (B), (C), (D) out of which only one is correct& carry 3 markseach. 1markwill be deducted for each wrong

answer.

3. Q.9 to Q.11 are based upon a Paragraph. Each Question has four choices (A), (B), (C), (D) out of which only one is correct &

carry 3marks each. 1 markwill be deducted for each wrong answer.

4. Q.12to Q.14has four choices (A), (B), (C), (D) out of which one or more than one is/are correct& carry 4 markseach.

1 markwill be deducted for each wrong answer.

SECTION - B

1. Q.1 is Matrix match type questions. Column-Icontains Three (A,B,C) entries and Column-II contains Four (P,Q,R,S)

entries. Entry of Column-Iare to be matched with Only one entryof Column-II. 2 mark will be awarded for each part of

Column-I.NO NEGATIVEmarking for this section.

SECTION - C

1. Q.1to Q.5are Integer answer type questions(whose answer are upto 4 digits) & carry 5 marks each. NO NEGATIVE

marking for this section.

NOTE : GENERAL INSTRUCTION FOR FILLING THE OMR ARE GIVEN BELOW.

1. Use only HB pencilor blue/black pen (avoid gel pen)for darkening the bubble.

2. Indicate the correct answer for each question by filling appropriate bubble in your OMR answer sheet.

3. The Answer sheet will be checked through computer hence, the answer of the question must be marked by shading the

circles against the question by dark HB pencil or blue/black pen.

4. While filling the bubbles please be careful about SECTIONS [i.e. Section-A (include single correct, Reasoning Type,

comprehension type & Multiple Correct type), Section-C (include integer answer type)].

For example if only 'A' choice iscorrect then, the correct method

for filling the bubble is

For example if only 'A & C'choices are correct then, thecorrect method for filling thebubble is

the wrong method for filling thebubble are

The answer of the questions inwrong or any other manner willbe treated as wrong.

For example If Correct match

for (A) is P; for (B) is R, S; for(C) is Q; for (D) is Q, S, T then

the correct method for filling

the bubble is

Ensure that all columns are filled.

Answers, having blank column will betreated as incorrect. Insert leading zero(s)

if required :

0 0 0 0

1 1 1 1

2 2 2 2

3 3 3 3

4 4 4 4

5 5 5 5

6 6 6 6

7 7 7 7

8 8 8 8

9 9 9 9

'6' should be

filled as 0006

'86' should be

filled as 0086

0 0 0 0

1 1 1 1

2 2 2 2

3 3 3 3

4 4 4 4

5 5 5 5

6 6 6 6

7 7 7 7

8 8 8 8

9 9 9 9

0 0 0 0

1 1 1 1

2 2 2 2

3 3 3 3

4 4 4 4

5 5 5 5

6 6 6 6

7 7 7 7

8 8 8 8

9 9 9 9

0000A

1B 1 1 1

2C 2 2 2

3D 3 3 3

4E 4 4 4

5F 5 5 5

6G 6 6

7H 7 7 7

8I 8 8 8

9J 9 9 9

A B C D E

A B C D E

P Q R S T6

Booklet

0 0000

1 1 1 1 1

2 2 2 2 2

3 3 3 3 3

4 4 4 4 4

5 5 5 5 5

6 6 6

7 7 7 7 7

8 8 8 8 8

9 9 9 9 9

6 6

Test Code Batch

10+1

10+2

10+3

Crash

Paper

Paper 1

Paper 2

Roll Number

Name

Test Date D D M M Y Y

N A M E M I D D

L E N A M E L A S T N A M E

D 1 0 0 1 10+1

1

2 83 2 3

F I R S T

394 - Rajeev Gandhi Nagar Kota, Ph. No. 0744-2209671, 93141-87482, 93527-21564

IVRS No. 0744-2439051, 0744-2439052, 0744-2439053 www.motioniitjee.com, [email protected]

TARGET IIT - JEE

MAJOR TEST (ADVANCED)

CLASS XI BOOKLET CODE : A

PAPER I

Date : 07- 02 - 2013 Duration : 3 Hours Max. Marks : 228


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394,50 - Rajeev Gandhi Nagar Kota, Ph. No. : 93141-87482, 0744-2209671

IVRS No : 0744-2439051, 52, 53, www. motioniitjee.com , [email protected]

(SPACE FOR ROUGH WORK)

PART I [MATHEMATICS]MAJOR TEST ADVANCED) MATHEMATICS)

SECTION ASTRAIGHT OBJECTIVE TYPE

Q.1 to Q.6 has four choices (A), (B), (C), (D) out of which ONLY ONE is correct

1. If f(x) is an even function and satisfies the relation x2f(x) 2f !"

#$%

&x1

= g(x) where g(x) is an odd

function then f(5) equals

(A) 0 (B)32

(C)7549

(D) none of these

;fn f(x) ,d le Qyu gSrFkk laca/k x2f(x)2f !"

#$%

&x1

=g(x) dkslarq"V djrk gS] tgkg(x) ,d fo"ke Qyu gSrc f(5) cjkcj gS

(A) 0 (B)32

(C)7549

(D) buesa ls dksbZ ugha

2. If f(x) is polynomial of degree n such that f(0) = 0, f(1) =21

, .......... f(n) =1n

n'

then f(n + 1) is

(A) 1 if n is odd,2n

n'

if n is even (B)2n

n'

if n is odd, 1 if n is even

(C)2n1n

''

(D) none of these

;fn f(x) ,d n ?kkr dk cgqin bl izdkj gS fd f(0)=0, f(1)=21

,... f(n)=1n

n'

rc f(n+1) gS

(A) 1 ;fn n fo"ke gS, 2n

n

' ;fn n le gS (B) 2n

n

' ;fn n fo"ke gs, 1 ;fn n le gS

(C)2n1n

''

(D) buesa ls dksbZ ugha


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MAJOR TEST (ADVANCED) (MATHEMATICS)

3. sin1(sin 5) > x2 4x holds if

sin1(sin 5) > x2 4x vfLrRo esa gS ;fn

(A) x < 2 () 29 (B) x *(+, 1) ,(5, +)

(C) 1 < x < 5 (D) x *( ()) 292 , ()' 292 )

4. The number of solutions of the equation sin (x = |log |x|| is(A) infinite (B) 8 (C) 6 (D) 0

lehdj.k sin (x = |log |x|| ds gyksa dh la[;k gS

(A) vuar (B) 8 (C) 6 (D) 0

5. f(x) and g(x) are two quadratic polynomials such that |f(x)|-|g(x)| . x *R. Also g(x)=0 has real

roots then(A) Sum of roots of f(x) = 0 is not equal to sum of roots of g(x) = 0(B) Roots of f(x) = 0 can be different than roots of g(x) = 0(C) f(x) is divisible by g(x)

(D) Nothing can be said by given dataf(x) rFkkg(x) nks f}?kkrh; cgqin bl izdkj gS fd |f(x)|-|g(x)| . x *R. rFkk g(x)=0 okLrfod ewy Hkh j[krs gSrc

(A)f(x) = 0 ds ewyksa dk ;ksx g(x) = 0 dsewyksa ds ;ksx ds cjkcj ugh gS

(B) f(x)=0 ds ewy g(x)=0 ds ewyks ls fHkUu gks ldrs gS

(C) f(x), g(x) }kjk HkkT; gS

(D) fn;s x;s vkadM+ksa ls dqN Hkh ugh dgk tk ldrk gS

6. A line through the origin divides parallelogram with verticies (10, 45), (10, 114), (28, 153) and(28, 84) into two congurent pieces. Then the slope of line is

ewy fcUnq ls xqtjus okyh ,d js[kk lekUrj prqHkq Zt ftlds 'kh"kZ (10, 45), (10, 114), (28, 153) rFkk(28, 84) gS dks nks lokZxle Hkkxksa esa foHkkftr djrh gSA rc js[kk dh izo.krk gS

(A)5919

(B)1999

(C)199

(D)9

19


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[RE SONING TYPE]Q 7 to Q 8 is Reasoning type question, contains Statement-1 Assertion) and Statement-2 Reason) Each questionshas urchoices A), B), C), D) out of which ONLY ONEis correct(A) Statement (1) is correct and statement (2) is correct and statement (2) is correct explanation for (1)(B) Statement (1) is correct and statement (2) is correct and statement (2) is NOT correct

explanation for (1)(C) Statement (1) is true but (2) is false(D) Statement (1) is false but (2) is trueOn the basis of above information, answer the following question :(A) dFku-1 lR; g] dFku-2 lR; gA dFku-2, dFku-1 dk lgh Li Vhdj.k gA(B) dFku-1 lR; g] dFku-2 lR; gA dFku-2, dFku-1 dk lgh Li Vhdj.k ugh gA(C) dFku-1 lR; g] dFku-2 vlR; gA(D) dFku-1 vlR; g] dFku-2 lR; gAij nh xb lwpuk ds vk/kkj ij] fuEufyf[kr i'uk ds mkj nhft,&

7. Statement-I :Inserted three geometric means between 4 and41 , so middle geometric means is 1.Statement-II :In a finite GP, the number of terms be odd then its middle term is GM of first andlast term.d ku-I :4rFkk 41 ds e/; rhu xq.kkkj ek/; ifo V djk, x, g] vr% e/; xq.kkkj ek/; 1 gAd ku-II :fuEu vuar xq.kkkj Js.kh es ink dh la[;k fo ke gkxh ;fn bldk e/; in iFke rFkk vfUre in dk xq.kkkj ek/; gA

8. Statement-I :The expansion 56 1/01234 ) +52 6x x 11) )2 /0 is a polynomial of degree 14.

Statement-II :(x + y)n+ (x y)n= 2[nC1xn1y1+nC3xn3y3...]

d ku-I :56 1/01234 ) +

52 6x x 11) )2 /0 ,d 14 ?kkr dk cgin gd ku-II :(x + y)n+ (x y)n= 2[nC1xn1y1+nC3xn3y3...]


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[COMPREHENSION TYPE]Q.9 to Q.11 are based upon a paragraph. Each questions has four choice (A), (B), (C), (D) outof which ONLY ONE is correct

Paragraph for Question Nos. 9 to 11If 25 identical things be distributed among 5 persons then;fn 25 leku oLrqvk dk 5 O;fDr;k ds chp ckVk tkrk g

9. The number of ways if each receives atleast one is(A) 24C4 5 (B)24C4 5 .13C4 (C) 24C4 5 .13C5 (D) 24C4;fn iR;sd de ls de ,d ikIr djrk g] rk ckVus ds idkjk dh la[;k g &(A) 24C4 5 (B)24C4 5 .13C4 (C) 24C4 5 .13C5 (D) 24C4

10. The number of ways if each receives odd number of things(A) 14C4 (B) 15C4 (C) 16C4 (D) none of these;fn iR;sd ds ikl oLrqvk dh la[;k fo ke g rc ckVus ds idkjk dh la[;k g &(A) 14C4 (B) 15C4 (C) 16C4 (D) bues lsdkb ugh

11. The number of ways each receives at least one thing but not more than eleven is(A) 24C4 5 .12C4 (B) 24C4 5 (C)24C4 5 .13C4 (D) none of these;fn iR;d de l de ,d ikIr djrk g yfdu ,d 11 l T;knk ugh ikIr djrk g] rc ckVu d idkjk dh l[;k g &(A) 24C4 5 .12C4 (B) 24C4 5 (C)24C4 5 .13C4 (D) bues lsdkb ugh


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MULTIPLE CORRECT NSWERS TYPEQ.12 to Q.14 has four choices (A), (B), (C), (D) out of which ONE OR MORE THAN ONE is correct

12. For positive integer n,let a(n) = 1 + 2

1 + 31 + 4

1 +..... + 11

n ) then(A) a(100) < 100 (B) a(200) < 200 (C) a(200) > 100 (D) a(100) < 200/kukRed i.kkd n ds fy,,ekuk a(n) = 1+ 21 + 31 + 41 +....+ 11n ) rc(A) a(100) < 100 (B) a(200) < 200 (C) a(200) > 100 (D) a(100) < 200

13. The number of ways of choosing triplet (x, y, z) such that z 5max {x, y}and x, y, z *{1, 2, 3, ....n} is(A) n+1C3+n+2C3 (B) n+1C2+ 2(n+1C3) (C) 12+ 22+ .... + n2 (D) 2. n+2C3n+1C2(x, y, z) puus ds idkjk dh la[;k tcfd z 5vf/kdre {x, y} rFkk x, y, z *{1, 2, 3, ....n}g(A) n+1C3+n+2C3 (B) n+1C2+ 2(n+1C3) (C) 12+ 22+ .... + n2 (D) 2. n+2C3n+1C214. The locus of the point of intersection of the tangents at the extremities of a chord of the circlex2+ y2= b2which touches the circle x2+ y2 2by = 0 passes through the point

(A) #$%&

2b, (B) (0, b) (C) (b, 0) (D) #$%

& 02bo k x2+ y2= b2dh thok ds vfUre fcUnqvk ls xqtjus okyh Li'k js[kkvk ds ifrPNsn fcUnq dk fcUnq iFk tk fdx2+ y2 2by = 0dk Li'k djrk g rFkk fcUnq lsxqtjrk g(A) #$%

&2b, (B) (0, b) (C) (b, 0) (D) #$%

& 02b


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SECTION B[MATRIX MATCH TYPE]

Q.1 is "Match the column" type. Column - I contains Three (i.e. A,B,C) entries and column - IIcontains Four (i.e. P,Q,R,S) entires. Entry of column - I are to be matched with ONLY ONE ENTRYof column - II.

1. Column I Column II

(A) Possible integers satisfing x2 |x + 2| + x > 0 is/are (P) -2

(B) a,b,c are in A.P : a2,b2,c2are in G.P., a + b + c = 3/2 then (Q) 1 [2a] can be equal to ([*] represents Greatest Integer Function)

(C) Number of ways of selecting atmost n things from (2n + 1) (R) 3 different things is 63, n may be equal to (selecting atleast one)

(S) 1

LrEHk I LrEHk II

(A) laHko iw.kkZad tks x2

|x+2|+x>0dks larq"V djrs gSa (P) -2

(B) a,b,c lekUrj Js.kh esagS : a2,b2,c2 xq.kkskj Js.kh esa gS, a + b + c = 3/2 (Q) 1 rc [2a] ds cjkcj gks ldrk gS([.] egke iw.kkZad Qyu iznf'kZr djrk gS)

(C) (2n + 1) fHkUu oLrqvksa esa ls T;knk ls T;knk oLrqvksa dks pquus ds izdkj 63 gS (R) 3 rc n ds cjkcj gks ldrk gS

(S) 1



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SECTION CINTEGER ANSWER TYPE

Q.1 to Q.5 are INTEGER ANSWER TYPEQuestions. (The answer of each of the questions are upto 4 digits)

1. Find number of integral values of x satisfying the equation 1x43x ))' + 1x68x ))' =1

lehdj.k 1x43x ))' + 1x68x ))' =1dks larq"V djus okys 'x' ds ekuksa dh la[;k

2. If a be one A.M. and G1, G2be two G.M. between b and c then value of abc

GG 3231' is ...

;fn a, b rFkk c dk rFkk G1, G2b rFkk c ds chp dsxq.kkskj ek/; gS rc abc

GG 3231' dk eku ds cjkcj gS

3. If Sn= 1+ 21

+ 22

1+....+ 1n2

1) . Calculate the least value of n such that 2 Sn< 100

1.

;fn Sn= 1+ 21 + 22

1 +...+ 1n21) . n dk U;wure eku ftlds fy, 2 Sn< 100

1 bl izdkj gS

4. How many rectangles can be made by joining verticies of regular octagon.,d fu;fer v"V~Hkqt ds 'kh"kksZ feykus ij fdrus vk;r cuk, tk ldrs gSA

5. Number of proper factors of sum of all rational terms in the expansion of (31/5+ 21/3)15are........(31/5+ 21/3)15dsfoLrkj esa lHkh ifje; inksa ds ;ksx ds proper xq.ku[k.Mksa dh la[;k gS .......



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MAJOR TEST (ADVANCED) (PHYSICS)

PART II [PHYSICS]SECTION A

STRAIGHT OBJECTIVE TYPE


1. Fig shows a light ring with three rods each of mass M weldedon its rim. The rods form an equilateral triangle. The rigidassembly is released on a rough inclined plane. Determine theminimum value of the coefficient of static friction that willallow pure rolling of the assembly. (a)

fp=k esa ,d gYds oy; ls rhu NM+s ftuesa izR;sd dk nzO;eku M gS] blds fje ls tqM+h gSA NM+s ,d leckgq f=kHkqt cukrh gSA bln < fudk; dks ,d [kqjnjs ur ry ij NksMk tkrk gSA bl fudk; dh 'kq) ykSVuh xfr ds fy;s vko';d LFkSfrd ?k"kZ.k xq.kkad dsU;wure eku dh x.kuk dhft,A

(A)1

tan3

6 - 7 (B)1

tan3

6 5 7 (C) tan6 - 7 (D) tan6 5 7

2. A smooth ring is kept on a smooth horizontal surface is fixed. From a point P of the ring a particle is

projected at an angle 8to the radius vector at P. If 'e' is the coefficient of restitution between thering and the particle then the particle will return to the point of projection after two reflections ifcot28is (Given e = 1/2 ):,d fpduk oy; ,d fpdus{kSfrt ry ij fLFkj gS A oy; ds fcUnq P ls ,d d.k dks P ij fLFkr f=kT;k lfn'k ls 8 dks.k ijiz{ksfir fd;k tkrk gSA ;fn d.k rFkk oy; ds e/; izR;kLFkrk xq.kkad 'e' gks rks d.k nks ijkorZuksa dsi'pkr iqu% iz{ksi.k fcUnq ijigaqp tk;sxk ;fn cot28 gks& (fn;k gSe = 1/2 ):(A) 14 (B) 18(C) 20 (D) None of these (bueas ls dksbZ ugha)

3. A block of mass m is suspended by means of an ideal spring of forceconstant k from ceilling of a car which is moving along a circular pathof radius 'r' with acceleration 'a'. The time period of oscillation of the

block when it is displaced along the spring will bemm nzO;eku dk ,d CykWd cy fu;rkad k dh ,d vkn'kZ fLizax ls ,d dkj dh Nr lsyVd

jgk gS] tks 'r' f=kT;k dso Rrh; iFk ij 'a' Roj.k ls xfreku gSA CykWd dsnksyu dk vkorZ dkyD;k gksxk tc blsfLiaz x ds vuqfn'k foLFkkfir fd;k tkrk gSA

(A)k

mamg2

'( (B) 22 agk

m2

'( (C)

km

2( (D) 222 agk

m2

''(


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4. In the figure shown AB is a rod of length 30 cm and area of cross-section 1.0 cm2and thermalconductivity 336 S.I. units. The ends A & B are maintained at temperatures 20oC and 40oCrespectively. A point C of this rod is connected to a box D, containing ice at 0oC, through a highlyconducting wire of negligible heat capacity. The rate at which ice melts in the box is : [ Assumelatent heat of fusion for ice L = 80 cal/gm]

20CA C B

20cm10cm

40C

highly conducting wire

D0C

Ice

iznf'kZr fp=k esaAB ,d NM+gS ftldh yEckbZ 30 cm, vuqizLFk dkV dk {ks=kQy 1.0 cm2rFkk m"ek pkydrk 336 S.I. ek=kdgSA fljs A rFkkB e'k% 20oC rFkk40oC rkieku ij fLFkr gSA bl NM+ dk ,d fcUnq C ckWDl D ls ,d m"ekpkyd rkjlstqM+k gS ftldh m"ek/kkfjrk ux.; gSA ckWDl D esa 0oC ij cQZ fLFkr gSA ckWDl esa fLFkr cQZ dsfi?kyus dh nj gksxhA [ ekukcQZ dh xyu dh xqIr m"ek L = 80 cal/gm gS](A) 84 mg/s (B) 60 mg/s (C) 20 mg/s (D) 40 mg/s

5. One end of a chain attached to ceiling and released from rest from theposition given in the figure. In subsequent motion the shape of chaincan be best represented by (assume no friction anywhere)

Nr ls ca/kh gqbZ ,d tathj dks fojke ls fp=k esa fn[kkbZ fLFkfr ls NksMk tkrk gSA

bl xfr ds nkSjku tathj dk vkdkj fuEu esa ls fdl fp=k }kjk lgh iznf'kZr gSA

lHkh txg ?k"kZ.k ux.; gS

(A) (B) (C) (D)

6. Which of the following represents a standing wave?

fuEu esa ls dkSulh lehdj.k vizxkeh rjax iznf'kZr djrh gS\

(A) y = A sin (:t-kx) (B) y = A sin kx sin (:t-7)

(C) y = A e-bx sin (:t-kx+8) (D) y = A (ax+b) sin (:t-kx)


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7. Statement-1For any rigid rod that rotates about a symmetry axis, the total angular momentum isparallel to the angular velocityStatement-2The vector sum of angular moments of the individual particles is along axis ofrotation.d ku -1fdlh lefer v{k ds lki{k ?keus okyh fdlh n


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Paragraph for Question Nos. 9 to 11A sphere of radius r and mass m has a linear velocity v0directed to the left and no angular velocityas it is placed on a belt moving to the right with a constant velocity v1. If after sliding on the beltthe sphere is to have no linear velocity relative to the ground as it starts rolling on the belt withoutsliding, in terms of v1and the coefficient of kinetic friction6kbetween the sphere and the belt,determine.

vv

tc r f=kT;k ,o m nzO;eku ds xky ftldk js[kh; ox v0ckb vkj fn V g] dk fu;r ox v1ls nkb vkj xfreku cYV ij j[kktkrk g rc mldk dk.kh; ox 'kU; gA ;fn cYV ij fQlyus ds i'pkr xky dk /kjkry ds lki{k js[kh; ox 'kU; g rk tSls gh;g fQly fcuk cYV ij y


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12. The particle A and B each of mass 'm' is attached by a lightinextensible string of length 2 .The whole system lies on asmooth horizontal table with B initially at a distance from A. Bis given velocity 'u' as shown in figure. Then just after thejerk.

ud.kArFkkBftues iR;sd d.k dk nzO;eku m g] ,d gYdh vfoLrkfj; 2 yEckb dh Mkjh ls tqM gA ;g ijk fudk; ,d fpdus{kfrt est ij bl idkj j[kk g fd ikjEHk es B ]Als nwjh ij gA B dk fp=kkuqlkj 'u' ox fn;k tkrk gA rc >Vds ds rqjarckn &(A) A u 3V 4; (B) B u 3V 4;(C) Component of VB along AB isu 34 (ABds vuqfn'kVBdk ?kVd u 34 gA )(D) Component of vB perpendicular to AB u2

(ABds yEcorVBdk ?kVd u2 gA )13. A particle of mass m, attached to a string, describes a horizontal circle of radius r on a rough table.After completing one full trip around the circle the speed of the particle is halved.(A) The energy dissipated by friction during one revolution is (3/4)mv02

(B) The coefficient of friction is2016 gr

(C) The energy dissipated by friction during one revolution is (3/8)mv02

(D) The coefficient of friction is20v16 gr

Mkjh ls tqMk m nzO;eku dk ,d d.k ,d [kjnjh est ij r f=kT;k ds {kfrt or es xfr dj jgk gA or dk ,d pDdj ijk djusds i'pkr d.k dh pky vk/kh jg tkrh gA(A) p.k ds nkjku ?k k.k }kjk O;; tk (3/4)mv02 gA (B) ?k k.k xq.kkd

2016 gr gA

(C) p.k ds nkjku ?k k.k }kjk O;; tk (3/8)mv02 gA (D) ?k k.k xq.kkd20v16 gr gA


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14. Which of the following graphs illustrate/s SHM, where 'x' is displacement, t is time, u is potentialenergy and v is velocity

fuEu esa ls dkSuls xzkQ ljy vkorZ xfr dks iznf'kZr djrs gSaA ;gka x foLFkkiu] t le;] u fLFkfrt mtkZ rFkk v osx gSA

(A) tO

x

(B) tO

u

(C) x

O

u

(D) x

O

v



1. For an ideal gas a process PV diagram is a circle. An adiabaticfrom A passes through C. An isotherm from A passes throughB. We take a part of the circular cyclic process. Comment onthe sign of the quantity of column-I.

A

D

C

B

V

P

Column-I Column-II

(A) Heat given to the gas in going from A to C along circle (P) Positive(B) Heat given to the gas in going from B to C along circle (Q) Negative(C) Heat given to the gas in going from C to D along circle (R) Zero

(S) cant be said

fdlh vkn'kZ xSl ds fy;s PV xzkQ ,d or gSA ,d :)ks"e ize A lsizkjEHk gksdj C ls

xqtjrk gSA ,d lerkih ize A ls izkjEHk gksdj B ls xqtjrk gSA LrEHk -I dk feyku

LrEHk -II ls dhft,&

A

DC

B

V

P

LrEHk-I LrEHk-II(A) o r dsvuq fn'k A lsC tkus esa xSl dks nh xbZ m"ek (P) /kukRed

(B) o r ds vuqfn'k B lsC tkus esa xSl dks nh xbZ m"ek (Q) _.kkRed

(C) o r dsvuqfn'k C lsD tkus esa xSl dks nh xbZ m"ek (R) 'kwU;

(S) dgk ugha tk ldrkA



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1. A uniform thin, cylindrical beam of length 3m and mass 10 kg is connected to the ground by africtionless hinge as shown in fig. The beam has sphere of radius 20 cm and mass 2 kg attached to

its end and is supported by a horizontal cable attached to the wall and to the mid point of thebeam. The beam is initially at rest at an angle of 53 with respect to the vertical. Find the tension(in newton) in the cable. (Give Your Answer in nearest integer)

T

53mid point

of beam

m=10kg

,d le:i iryk csyukdkj yB~Bk ftldh yEckbZ 3m rFkk nzO;eku10 kg gS] fp=kkuqlkj /kjkry ls,d ?k"kZ .kjfgr dhy }kjk tqM+h

gSA yB~Bs ds ,d fljs ls 20 cm f=kT;k rFkk 2 kg nzO;eku dk ,d xksyk tqM+k gS tks yB~Bs dse/; fcUnq rFkk nhokj ls tq M+s ,d

{kSfrt rkj }kjk larqfyr gSA vkjEHk eas yB~Bk /okZ/kj ls 53 ds dks.k ij fojke eas gS rc rkj esa ruko U;wVu esa D;k gksxk\ mRrj

lehiLFk iw.kkZad esa nhft, &

2. A wave with a frequency of 1200 Hz propagates along a wire that is under a tension of 800 N. Thewavelength of the wave is 24 cm. What will be the wavelength (in cm)if the tension is decreasedby 600 N and the frequency is kept constant?1200 Hz vko fRr dh ,d rjax ,d rkj esa lapfjr gksrh gS ftlesa ruko 800 N gSA rjax dh rjaxnS/;Z 24 cm gSA ;fn vko fRrdks fu;r j[krs gq;s ruko dks 600 N?kVk fn;k tk;s rks rjaxnS/;Z lseh esa D;k gksxh \

3. A bob of mass m = 4 kg is suspended from a massless string of lengthl.Other end of the string is fixed from the ceiling. A horizontal force F

=4

3mg is applied on the bob when bob it at rest at the lowest

position. Find maximum tension (in newton) in the string during themotion. (Take g = 10 m/s2)

F=m4

mg3

m = 4 kg nzO;eku ,d yksyd l yEckbZ dh nzO;ekughu Mksjh ls yVdk gqvk gSA Mksjh dks nwljk fljk NRk lstqM+k gS A tc yksyd

fuEure fcUnq ij fojke esagS rc bl ij ,d {kS frt cy F =4

3mg dk;Zjr gksrk gSA xfr dsnkS jku Mksjh esavf/kdre ruko U;wVu

esa Kkr dhft,A ( g = 10 m/s2)



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4. James bond is standing on a bridge above the road and his pursuers are getting too close. He spotsa flat bed truck loaded with mattresses approaching at 30 m/s which he measures by knowing thatthe telephone poles,( the truck is passing) are 20 m apart in this country. The bed of truck is 20mbelow the bridge and bond quickly calculates how many poles away the truck should be when he

jumps down the bridge onto the truck making his get away. How many poles is it ?

tsEl ckW.M ,d iqy ds ij cuh lM+d ij [kMk gS rFkk mldk ihNk djusokys cgqr lehi igaqprs gSaA og ns[krk gS fd pVkb;ksa

lsHkjk ,d Vd 30 m/s ls ckW.M dh rjQ vk jgk gS] ftldh pky dks og bl ns'k esa VsyhQksu ds [kEHkksa ds chp dh nwjh 20 mgksus dsvuqlkj ekirk gS A Vd dk fiNYkk fgLlk iqy ls 20m uhps gS] rFkk ckW.M rsth ls ;g x.kuk djrk gS fd ogka ls Vd dks

fdrus [kEHks nwj gksuk pkfg, rkfd og iqy ls Vd ij dwn dj Hkkx ldsA [kEHkksa dh la[;k D;k gS\

5. A solid uniform cylinder of mass M performs small oscillations due to the action of two springs, eachhaving stiffness k. Find the angular frequency of these oscillations in absence of any sliding

(springs have their natural length initially) (Given k = 600N/m and M = 5 kg ).

k

k

M

M nzO;eku dk ,d Bksl le:i csyu nksfLizaxksals tqM+dj lw{e nksyu djrk gSftudh dBks jrk k gSA bu nksyuksadh vko fRr fQlyudh vuqifLFkfr esa Kkr dhft,A (vkjEHk eas fLizax lkekU; yEckbZ esa gS)(fn;k gS k = 600N/m rFkkM = 5 kg).


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MAJOR TEST (ADVANCED) (CHEMISTRY)

PART III [CHEMISTRY]SECTION A

STRAIGHT OBJECTIVE TYPE


1. Which of the following nitrogen oxide does contain oxy linkage (X O X).fuEu esa ls dkSulk ukbVkstu vkWDlkbM vkWDlhfyadst j[krk gS%(X O X)(A) N2O (B) N2O4 (C) N2O5 (D) NO2

2. Correct order of heat of hydrogenation is ?gkbMkstuhdj.k dh m"ek dk lgh e gS ?(A)CH2=CH2>CH3CH=CH2>(CH3)2C=CH2 (B)CH2=CH2>CH3CH=CH2< (CH3)2C=CH2(C)CH2=CH2 p-nitroaniline > m-nitroaniline(B) Aniline > p-nitroaniline > o-nitroaniline > m-nitroaniline(C) Aniline > m-nitroaniline > p-nitroaniline > o-nitroaniline(D) o-Nitroaniline > p-nitroaniline > aniline > m-nitroanilinefuEu esa ls {kkjh;rk dk lgh ?kVrk e gksxk%(A) ,fuyhu> o-ukbVks,fuyhu> p-ukbVks,fuyhu> m-ukbVks,fuyhu(B) ,fuyhu> p-ukbVks,fuyhu> o-ukbVks,fuyhu> m-ukbVks,fuyhu

(C) ,fuyhu> m-ukbVks,fuyhu> p-ukbVks,fuyhu> o-ukbVks,fuyhu(D) o-ukbVks,fuyhu> p-ukbVks,fuyhu> ,fuyhu> m-ukbVks,fuyhu

6. 3Mn+2


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7. Statement-1:COOH

COOH are chain isomers.Statement-2: Both compound having different no. of carbons atom in principle carbon chain withsame molecular formula.Statement-1: COOH COOH J[kyk leko;oh gAStatement-2: nkuk ;kfxd ftudk vkf.od lw=k leku g vkj eq[; dkcu J[kyk es fHkUu la[;k es dkcu ijek.k j[krs g%

8. Statement-1: The value of van der Waal constant a is higher for NH3than for N2.Statement-2: NH3molecules are associated with H-bonds.Statement-1: NH3 ds fy, ok.Mjoky fu;rkd a dk eku N2 ds eku ls vf/kd gkrk gAStatement-2: NH3v.k dk l;qXeu H-cU/k lsgkrk gA


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Paragraph for Question Nos. 9 to 11Aromatic compound are these that meet the following criteria :(i) The structure must be cyclic, containing (4n + 2)(electrons(ii) Each atom in the ring must have unhydridized p-orbitals(ii) Unhybridized p-orbital must overlap orbitals.(iv) Structure must be plannerIn anti-aromatic compound (4n() electron are delocalised, but delocalization of pi electrons overthe ring increases the electronic energy.,jkesfVd ;kfxd og gkrs g tk fd fuEufyf[kr fcUnqvk dk lUrq V djrs gA(i) lajpuk vko';d :i ls ph; gkuh pfg,] (4n + 2)(byDVkUl gkus pkfg,A(ii) oy; es iR;sd ijek.k ij vladfjr p-d{kd gkuk pkfg,A(iii) vladfjr p-d{kd vfrO;kfir d{kd gkus pkfg,A(iv) lajpuk leryh; gkuh pkfg,A,UVh ,jkefVd ;kfxd e (4n()byDVku foLFkkfir gkrh g] ijUr oy; e pi byDVku d foLFkkfudj.k l byDVkfud tk c


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12. Some water is added to a mixture of 250 ml of 0.6 M HCl and 750 ml of 0.2 M HCl to obtain 0.25 Msolution of HCl as a resulting solution. Then(A) The volume of water added is 200 ml(B) The volume of water added is 100 ml(C) Total mass of HCl in the solution is 10.95 g(D) Total mass of HCl in the solution is 18.25 g0.3 M dk 250 ml HCl vkj 0.2 M dk 750 ml HCl ds feJ.k es dqN ikuh feykus ij ifj.kkeh 0.25 M foy;u ikIr gkrkg rc(A) feyk;s x;s ikuh dk vk;ru 200 ml gA (B) feyk;s x;s ikuh dk vk;ru100 mlgA(C) foy;u es HCl dk dqy Hkkj 10.95 g gA (D) foy;u es HCl dk dqy Hkkj18.25 ggA

13. Find out the correct statement/(s) among the following(A) Order of heat of hydrogenation of following compounds is CH2= CH2> CH3 CH = CH2> CH

3CH3

(B) Order of heat of combustion of following compounds is CH2= CH2> CH3CH=CH2 >CH3 CH3

(C) is more stable alkene than

(D)

CH

CH

is more stable carbanion than

CH 2

CHCH 3H 3

MAJOR TEST ADVANCED) CHEMISTRY)


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fuEu eas ls lgh dFku pqus%

(A) gkbMkstuhdj.k dh m"ek dk e gS% CH2= CH2> CH3 CH = CH2> CH3CH

3

(B) ngu dh m"ek dk e gS% CH2= CH2> CH3CH=CH2 > CH3CH

3

(C) ;g ,Ydhu , ls vf/kd LFkkbZ gS

(D) ;g dkcZ_.kk;u

CHH

CHO

,

CH2

CHO

CH3

CH3

ls vf/kd LFkkbZ gS%

14. Select the correct statements:(A) If two gases have same reduced pressure & reduced temperature than both the gases will havesame reduced molar volume.(B) When a dominates b then ideal molar volume is less than observed molar value.(C) In Rutherfords experiment impact parameter is inversely proportional to tangent of half of angleof deflection.(D) In Rutherfords experiment number of particles deflected is directly proportional to angle ofdeflection.lgh dFku igpkfu,%

(A) ;fn nksxSl dk leku fjM;q LM (reduced)nkc vkSj fjM;q LM (reduced)rki gS rc nks uksaxSlsleku fjM;q LM (reduced)vk;ru j[krh gSA

(B) tc ls mPp gksrk gSa rc vkn'kZ eksyj vk;ru izkIr eksyj eku dh de gksrk gSaA

(C) jnjQksMZ iz;ksx esa izHkkoh iSekuk fopyu ds v)Z dks.k ds Li'kZ T;k ds O;qRekuqikrh gksrk gSaA(D) jnjQksMZ iz;ksx esafopfyr d.kks dh la[;k fopyu ds dks.k ds lekuqikrh gksrh gSaA



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1. Match the compounds in column - I with column - IIColumn - I Column - II

(Reaction) (Equivalent wt. of underlined substance)

(where M is the molecular weight of the underlined sub-stance)

;kSfxdksa esa LrEHk I ds lkFk LrEHk II dk feyku djs%

LrEHk- I LrEHk- II

(vfHkf;k) (jsf[kr f;kdkjd dk rqY;kadh Hkkj )

(tgk M jsf[kr f;kdkjd dk v.kqHkkj gSa)

(A) Ba(SCN)2 =


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1. The no. of carbons lineary arranged in the compound CH3 C >C C >C CH3is :

;kSfxd CH3 C >C C >C CH3esa js[kh; foU;klhr dkcZuksa dh la[;k gSA

2. An oleum sample is labelled as (100 + x)% and it contain %3

80free SO3by weight. Hence, x is

,d vksfy;e uewuk ftl ij (100 + x)% vafdr gS vkSj ;g Hkkj dk %3

80eqDr SO3j[krk gS rc x gS%

3. Find out the double bond equivalent (DBE) value of the following compoundfuEu ;kSfxd esa f}ca/k rqY;kad dk eku crkb,s %

O

NH2

C NO

O

4. 4.3 g of a saturated hydrocarbon )HC( 2n2n ' is burnt completely and all CO2were absorbed in

aqueous NaOH solution. A 300 mL 2 N NaOH solution was required to neutralise all CO2. Hence,value of n is

4.3 g lUr Irk gkbMksdkcZu )HC( 2n2n ' dks iw.kZ tyk;k tkrk gSvkSj iw.kZ CO2tyh; NaOH foy;u }kjk vo'kksf"kr dj yh tkrh

gSA iw.kZ CO2 dks mnklhu djus ds fy,300 mL 2 N NaOH foy;u dh vko';drk Fkh bl izdkjn dk eku gS%

5. Total no. of structural isomers of C4

H10

O are ?C4H10O ds dqy lajpuk leko;oh crkb,s?



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major test 1 paper 1

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