leverrule

16
LEVER RULE Prof. H. K. Khaira Professor in MSME Deptt. MANIT, Bhopal

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just keep some basic in mind, its give u enough information about this topic.

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Page 1: Leverrule

LEVER RULE

Prof. H. K. KhairaProfessor in MSME Deptt.

MANIT, Bhopal

Page 2: Leverrule

Lever Rule

• The compositions of the two coexisting phases at a point in a two phase region is given by the points of intersection of the tie line from that point with the boundaries of the respective phases.

• The relative amounts of two coexisting phases at a point are INVERSELY proportional to the distances of the point from intersection points of the tie line from the point with the phase boundaries.”

2

Page 3: Leverrule

Lever Rule• It is also possible to determine how much of each phase exists at the

given temperature using the lever rule.• It is important to know the amounts of each phase present because

the properties of the alloy depend on the amount of each phase present.

• The lever rule uses the tie line and the basic scientific principle of the conservation of mass to determine the ratio of the two phases present.

• The tie-line gives the chemical compositions of each of the two phases, and the combined amounts of these two compositions must add up to the alloy's overall composition (Co), which is known.

• In other words, Co must be composed of the appropriate amount of α of composition Cα and of liquid of Cliq.

Page 4: Leverrule

Lever Rule1. Simply by looking at a phase diagram it is possible to tell what phase or phases an alloy will have at a given temperature.2. But, it is also possible to get quantitative information from the diagram.3. Consider the alloy at the temperature shown on the phase diagram. It is easy to see that at this temperature, it is a mixture of alpha and liquid phases.

Page 5: Leverrule

Lever Rule4. It is easy to see that at this temperature, it is a mixture of alpha and liquid phases.5. Using a tie lin,e it is also possible to determine the composition of the phases at this temperature. 6. A tie line is an isothermal (constant temperature) line drawn through the alloy's position on the phase diagram when it is in a two phase field.

Page 6: Leverrule

Lever Rule7. The points where the ends of the tie line intersect the two adjacent solubility curves indicate the compositions of the two phases that exist in equilibrium at this temperature.8. In this example, the tie line shows that the alpha phase is 5.2%B and the liquid phase is 34.5%B at this temperature.9. It is important to keep in mind that the tie rule addresses the determination of the compositions of the constituent phases within the sample and it does not address the overall chemical composition of the sample, which remains unchanged.

Page 7: Leverrule

Lever Rule• So basically, the proportions of the phases present are given by the

relative lengths of the two sections of the tie line. • The fraction of alpha phase present is the given by the ratio of the Co

to Cliq portion of the tie line and the total length of the tie line (C liq to Cα). Mathematically the relationships can be written as

fα = (Cliq – Co)/(Cliq - Cα).

• The fraction of liquid phase present is given by the ratio of the Co to Cα portion of the tie line and the total length of the tie line (C liq to Cα). Mathematically this relationships can be written as fliq = (Co - Cα)/(Cliq - Cα).

• Of course, the two values must total to equal one.

Page 8: Leverrule

Lever Rule

• Note that the right side of the tie line gives the proportion of the phase on the left (α phase in this example) and left side of the tie line gives the proportion of the phase to the right (liquid phase in this example).

• It is easy to keep this relationship straight by simply considering what the ratio would be near one of the tie line intersect points.

• For example, if Co were near the liquidus line the ratio of the liquid section of the line to the total length of the line will be nearly one.

Page 9: Leverrule

Lever Rule

Page 10: Leverrule

A + B

Translating This Statement

• “two coexisting phases”Means you are in a 2 phase region.

A B

A + LB + L

L

C

• Pick an arbitrary point C.• There are two phases at point C. • These phases are A an B• Hence Phases A and B will be in equilibrium at point C

P Q

Page 11: Leverrule

Tie Lines

The line from A to B through C is a tie line.

A tie line is,• An isothermal line• That connects two equilibrium phases

Page 12: Leverrule

A + B

Compositions of Phases Present

The tie line from point C intersect boundaries of phase A and B at 0% A and 0% B respectively.

Hence the composition of phase A will be 0% B or pure A.

Similarly, the composition of B will be pure B or 0% A.

A B

A + LB + L

L

C

Page 13: Leverrule

A + B

Amounts of Phases Present

“The intercepts of the tie line with the phase boundaries A and B are PC and CQ respectively.

“The amounts of phase A and B are inversely proportional to the intercept of tie line with the phase boundaries.

• “The amounts are inversely proportional” Means

• PC / PQ is the fraction of B And,

• CQ / PQ is the fraction of A

A B

A + LB + L

L

CP Q

Page 14: Leverrule
Page 15: Leverrule

A + B

A Sample Calculation

A B

A + LB + L

L

C

• Draw a horizontal tie line through the point.

D

• Measure its length

• Measure the length of each side

AD = 1 cm

AC = .75 cm CD = .25 cm

• Calculate the amounts A & L

%25cm1

cm25.A %75

1

75.L

• Identify the phases.

A (solid)

L (liquid)

Page 16: Leverrule

Summary

• The lever rule is used to determine the compositions of the phases present.

• The lever rule is also used to calculate the relative percents of each phase when 2 or more phases are present.

• The first step in lever rule calculation is to draw a tie line through the composition.

• The points of intercepts gives the compositions of the phases• Next one measures the lengths of the tie line, and the distance

from the composition to each phase.• The relative amounts of a phase is proportional to the distance

from the other phase to the composition, divided by the length of the tie line. (Opposite length / total length)