lecture19222
DESCRIPTION
a supplemental resource for studentsTRANSCRIPT
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The Properties of Mixtures:
ConcentrationLecture 19
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Concentration
is the measure of how much of a given substance there is
mixed with another substance.
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Concentration
applies to any sort of chemical mixture, but most frequently to homogeneous
solutions.
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Concentration =
amount or mass or volume of solute=
--------------------------------------------------
amount or mass or volume of solution or solvent
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Concentration =
amount or mass or volume of solute=
--------------------------------------------------
amount or mass or volume of solution or solvent
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Molarity (M) =
amount (mol) of solute---------------------------
--------volume (L) of solution
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Concentration =
amount or mass or volume of solute=
--------------------------------------------------
amount or mass or volume of solution or solvent
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Molality (m) =
amount (mol) of solute---------------------------
----------mass (kg) of solvent
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A sample problem
on calculating molality.
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Another sample problemWhat is the molality of a solution prepared by dissolving 339.8 g of silver nitrate in 4000. g of water?Amount of AgNO3=339.8/169.91 = 2.000 molMass of water=4.000 kgMolality of solution= 2.000/4.000=0.500 m AgNO3
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Another sample problemWhat mass of sodium phosphate is needed to prepare 0.750 m solution by dissolving it in 800. g of water?Mass of water=0.800 kgAmount of Na3PO4=0.750/0.800=0.938 mol
Mass of Na3PO4= 0.938x163.94=154 g
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Another sample problemWhat mass of water is needed to prepare 0.250 m solution by dissolving 1 kg 382 g of potassium carbonate?Mass of K2CO3=1382 gAmount of K2CO3=1382/138.21=10.00 molMass of water=10.00/0.250=40.0 kg
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Mass percent (%w/w) =
mass of solute= ---------------------------------------------- x 100% mass of solute + mass of solvent
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A sample problemWhat is mass percent of magnesium sulfate in solution containing 43.5 g of solute in 0.348 kg of solution?Mass of solution=348 g%w/w MgSO4=(43.5/348) x 100%=12.5%
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Another sample problemWhat is the mass of manganese (II) chloride in 640. lb of its 30.0% solution?Mass of MnCl2 =(640x30)/100=192 lb
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Another sample problemWhat is the mass of 45% solution containing 9.00 kg of potassium iodide?Mass of solution=(9.00/45%)x100%=20.0kg
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Volume percent (%v/v) =
volume of solute= -------------------------- x 100% volume of solution
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Mole fraction (X) =
amount (mol) of solute---------------------------------
------------------------amount (mol) of solute + amount (mol)
of solvent
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Mole percent (mol %) =
mole fraction x 100%
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A sample problemWhat is the mole fraction and mole percent of 157.55g of nitric acid in mixture with 900.8 ml of water?Amount of HNO3=157.55/63.018 = 2.5000 molAmount of H2O=900.8/18.016=50.00 molTotal amount = 2.5000+50.00=52.50 molX HNO3=2.5000/52.50=0.04762
mol % HNO3= 0.04762 x 100%=4.762%
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A sample problem
on expressing concentration in parts by mass, parts by volume, and
mole fraction.
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A sample problem
on converting concentration units.
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THE END