lecture+03 (1)

36
440:221 Intro to Engineering Mechanics: Statics 1 Lecture 3 Vector operations Spring 2014 Based on T extbook Material: Enginee ring Mechanics Statics, 12 th Edition, R.C. Hibbeler, Pearson 2010.  Alberto Cuitino , Heather Emad y, Sara Salahi, Bere ket Yoha nnes Instructors Juan Ren, Jingji n Xie  Assistants

Upload: vatsal-pandya

Post on 03-Jun-2018

218 views

Category:

Documents


0 download

TRANSCRIPT

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 1/36

440:221 Intro to Engineering Mechanics: Statics

1

Lecture 3Vector operations

Spring 2014Based on Textbook Material: Engineering Mechanics Statics, 12th Edition, R.C. Hibbeler, Pearson 2010.

 Alberto Cuitino, Heather Emady,

Sara Salahi, Bereket YohannesInstructors

Juan Ren, Jingjin Xie

 Assistants

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 2/36

440:221 Lectures

School of Engineering, Spring 2014

Topics to be reviewed

• What is a Cartesian vector representation?

• What is a Cartesian component?• How do we add vectors using Cartesian components?

• What is a unit vector? What is a vector position?

• How do find a force along a given direction?

• What is the inner (or dot) product?

• What is the inner product useful for?

2

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 3/36

440:221 Lectures

School of Engineering, Spring 2014

Scalar Notation – 2D

3

F  Rx = F cos  

F  Ry = F sin  

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 4/36

440:221 Lectures

School of Engineering, Spring 2014

Cartesian Vector Notation – 2D

4

• Resolve vectors into components

using the x and y axis system.

• Each component of the vector is

shown as a magnitude and a

direction.

• The directions are based on the xand y axes.

• We use the “unit vectors” i and j to

designate the x and y axes.

F = F  x i + F   y   j

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 5/36

440:221 Lectures

School of Engineering, Spring 2014

• Step 1 is to resolve eachforce into its components.

 Adding Vectors using Cartesian Components

5

• Step 3 is to find the magnitude

and angle of the resultant

vector.

• Step 2 is to add all the x-

components together, followed byadding all the y components

together. These two totals are

the x and y components of the

resultant vector.

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 6/36

440:221 Lectures

School of Engineering, Spring 2014

 Adding Vectors using Cartesian Components

6

Break the three vectors into components, then add them.

FR = F1 + F2 + F3

= F1x i + F1y j   F2x i + F2y j + F3x i   F3y j

= (F1x  F2x + F3x) i + (F1y + F2y  F3y) j

= (FRx

) i + (FRy

) j

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 7/36

440:221 Lectures

School of Engineering, Spring 2014

Examples

7

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 8/36

440:221 Lectures

School of Engineering, Spring 2014

Examples

8

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 9/36

440:221 Lectures

School of Engineering, Spring 2014

Cartesian Vectors 3D

9

A = Ax   Ay   Az

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 10/36

440:221 Lectures

School of Engineering, Spring 2014

Characteristics of a unit vector :

a) Its magnitude is 1.

b) It is dimensionless (has no units).

c) It points in the same direction as the original

vector ( A).

For a vector A, with a magnitude of A, an

unit vector is defined as

u A = A / A .

The unit vectors in the Cartesian axis systemare i,  j, and k. They are unit vectors along the

positive x, y, and z axes respectively.

Cartesian unit vectors

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 11/36

440:221 Lectures

School of Engineering, Spring 2014

Consider a box with sides AX, AY, and AZ meters

long.

The vector  A can be defined as

 A = ( AX i + AY j + AZ k)

The projection of vector  A in the x-y plane is A´. The magnitude of A´ is

found by using the same approach as a 2-D vector: A´ = (AX2 + AY

2)1/2 .

The magnitude of the position vector  A can now be obtained as

 A = ((A´)2 + AZ2) ½ = (AX

2 + AY2 + AZ

2) ½

Cartesian vector representation

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 12/36

440:221 Lectures

School of Engineering, Spring 2014

These angles are

measured betweenthe vector and the

positive X, Y and Z

axes, respectively.Their range of values

are from 0° to 180°

The direction or orientation of

vector A is defined by theangles , β, and γ.

Direction of a Cartesian vector 

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 13/36

440:221 Lectures

School of Engineering, Spring 2014

Using trigonometry, “direction cosines” are found using

These angles are not independent.

They must satisfy the following equation:

cos ² + cos ² + cos ² = 1

Direction of a Cartesian vector 

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 14/36

440:221 Lectures

School of Engineering, Spring 2014

This result can be derived from the

definition of a coordinate direction angles

and the unit vector. Recall, the formula

for finding the unit vector of any position

vector:

Direction of a Cartesian vector 

or written another way,

u A = cos  i + cos  j + cos  k

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 15/36

440:221 Lectures

School of Engineering, Spring 2014

For example, if 

 A = AX i + AY  j + AZ k and

B = BX i + BY  j + BZ k , then

 A + B = (AX + BX) i + (AY + BY) j + (AZ + BZ) k

or 

 A  – B = (AX - BX) i + (AY - BY) j + (AZ - BZ) k .

Once individual vectors are written in Cartesian form, it is

easy to add or subtract them. The process is essentially

the same as when 2-D vectors are added.

 Addition of cartesian vectors

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 16/36

440:221 Lectures

School of Engineering, Spring 2014

Examples

16

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 17/36

440:221 Lectures

School of Engineering, Spring 2014

Examples

17

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 18/36

440:221 Lectures

School of Engineering, Spring 2014

Vector Position

18

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 19/36

440:221 Lectures

School of Engineering, Spring 2014

Vector Position

19

 A position vector is defined as a fixed vector that locates a

point in space relative to another point.

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 20/36

440:221 Lectures

School of Engineering, Spring 2014

Vector Position

20

The position vector directed from A to B, r  AB , is defined as

r  AB = {( XB  – X A ) i + ( YB  – Y A ) j + ( ZB  – Z A ) k }

Please note that B is the ending point and A is the starting

point. ALWAYS subtract the “tail” coordinates from the “tip”

coordinates!

Consider two points, A and B, in 3-D space.

Let their coordinates be (X A, Y A, Z A) & (XB, YB, ZB ),

respectively.

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 21/36

440:221 Lectures

School of Engineering, Spring 2014

Example

21

Direction from A to B

Distance

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 22/36

440:221 Lectures

School of Engineering, Spring 2014

Example

22

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 23/36

440:221 Lectures

School of Engineering, Spring 2014

Example

23

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 24/36

440:221 Lectures

School of Engineering, Spring 2014

Force Vector Directed Along a Line

24

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 25/36

440:221 Lectures

School of Engineering, Spring 2014

Force Vector Directed Along a Line

25

If a force is directed along a line, then we can represent the force vector

in Cartesian coordinates by using a unit vector and the force’s

magnitude. So we need to:

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 26/36

440:221 Lectures

School of Engineering, Spring 2014

Force Vector Directed Along a Line

26

Procedure

1) Find the position vector, r  AB ,

along two points on that line.

2) Find the unit vector describing

the line’s direction, u AB =

(r  AB/r  AB).

3) Multiply the unit vector by the

magnitude of the force, F = F

u AB .

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 27/36

440:221 Lectures

School of Engineering, Spring 2014

Example

27

Find Force at A

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 28/36

440:221 Lectures

School of Engineering, Spring 2014

Example

28

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 29/36

440:221 Lectures

School of Engineering, Spring 2014

Example

29

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 30/36

440:221 Lectures

School of Engineering, Spring 2014

Dot Product

30

    

 A

B

 A ▪ B = A B cos 

 A▪

B = B▪

 A Commutativea ( A ▪ B) = (a A)   ▪ B = A ▪ (a B) Multipl ication by a scalar 

 A ▪ (B + D) = ( A ▪ B) + ( A ▪ D) Distributive Law

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 31/36

440:221 Lectures

School of Engineering, Spring 2014

Dot Product

31

    

 A

B

 A ▪ B = Ax Bx + Ay By + Az Bz

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 32/36

440:221 Lectures

School of Engineering, Spring 2014

Dot Product Applications

32

    

 A

B = cos-1 ( A ▪ B / A B)

1) Angle between two directions

2) Components parallel and perpendicular to a line

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 33/36

440:221 Lectures

School of Engineering, Spring 2014

Example

33

Find Projections parallel

and perpendicular to AB

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 34/36

440:221 Lectures

School of Engineering, Spring 2014

Example

34

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 35/36

440:221 Lectures

School of Engineering, Spring 2014

Example

35

440 221 L

8/12/2019 Lecture+03 (1)

http://slidepdf.com/reader/full/lecture03-1 36/36

440:221 Lectures

School of Engineering, Spring 2014

Take-home message

• Addition using Cartesian components is simple

 – Add all components in each direction using scalar addition

 – Similar procedure for 2 and 3 dimensional cases

 – Quite practical for 3D problems

• The direction from A to B is easily determined by

 – r  AB = {( XB  – X A ) i + ( YB  – Y A ) j + ( ZB  – Z A ) k }

• The inner (dot) product can be easily computed by

 –  A ▪ B = Ax Bx + Ay By + Az Bz

• The inner product is useful to find

 – Angles between directions

 – Projections of forces along directions

36